3 like 0 dislike
6.9k views

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited

edited by | 6.9k views

22 Answers

0 like 0 dislike
Hidden content!
*** * * * ** *

int * ** argc, char * * {
** * * * * * ** * ** * **** */

** * * * int number;
* **** ** * * char a;
* ***** * ** **** b;
** *** *** * ** * **** *** c;
* * * * * * ** ** * d;
* *** * * ** * * ** e;
* ** * **
**** * * * * * forgert how to shift word * * ** * *** **
**** ** * * **** * * * ** * *** ***** ** * * * * * * * * **** *
*** * ****
* * * * * ** *** * the message how??
** ** * * **
* ** * * * ****** * ** ** *
* * ***
******** ** * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
**** * *

* * * ** * * {

** ** ***
* = *****
* * *
* = * *
= ** *
= ** * ** *

* = *
= **
* = * *
=

* * *
***
* *
* * * **
* * *
*
*** *
*
100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
#include * *****
#include * ***

/* run this program using the console pauser or add your own getch, *** ** * ******* * or input loop */

int main(int argc, char *argv[]) {
* *** **** * ** * * ** a;
** * * *** * ** b;
* * * **** ** *** * ** * * c;
* * **** ** *** ** ** *** d;
** * * * *** * * * ** *** e;
*** *** * * * ** **
** ******** ** ** ** * * **** ** * the words you want to * * ***
** * **** * * * * **
* ** *** ***** ** * ** * = getchar();
** ** *** **** * * * = a+3;
** ** *** * * ****** ** * *
* * ** **** * = getchar();
** * *** ***** * *** * = b+3;
*** * *** * *** ***** *** *** *
** ** ****** **** *** ** = getchar();
** ** ** * ** * = c+3;
** *** ** ** *** * * ****** * * *
** *** * ** ** **** * ** * * = getchar();
** * ******* * ** *** = d+3;
* * ** * * * ** * *** * *
* * ** ** ** *** = getchar();
* * *** ** *** * * = e+3;
* * ** **** ** * ** ** * **
*** ** ****** * * * * **** * ******* ***** ***
*** * * **** ** * ** * * * ** *** &a, &b, &c, &d, * ****
** * * * * ******** * **
** * * * ** * *** ** * the message how??
* * * * * * * ** ****
* ** * * * * *** **** ** * * ****** **** a, b, c, d, e);
* * * * *** **
** ** ** ** **** * 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
1 like 0 dislike
Hidden content!
* ** ** **** ** * *
* *** * ** *** **

int ** ** *** char ** {
/*
** * * */

* *** * *

* * *** * *** * *** * * *** * *** * * * * ** * **
a = a+3;
b = *
c = ** *
d = d+3;
e = *

*** the **** *
** * * *** ** *
* ** * ** * ** *** *** *

* * ** * *
* * ** *** ** * ** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
* *** *** ***
* ***** * * ****

/* run this * * * * ** the * ** ** or add your own * * * **** ** *** or ** */

int * * * ** char ** {
* * * * * int num, * *
* ** * * * ***
*** * **
** * * ** * * ** *** **** **** * **
* * * ******* for * = * * * ** **
{
* ** * = * * **
* * *** * * if * *
**** * **** * * = * * *
** ** **** * *
}
*** * * * * *** **** **** * * *
* * * *** ** ** 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
1 like 0 dislike
Hidden content!
** * ***** * * ** *
*
* * * * * * **

* * * ** ** * * ** * * * ** ******* * ** * * *** * *

* * ** * ** * *
*
* *

* * *** * *

* * * **** ** * **** * ** * * *** * * * ***

* =
*
* * b + *

= c +

* = d + *

* * * *

** * * ***** ****** ** * * ***

* *

100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
0 0
That's correct.
1 like 0 dislike
Hidden content!
* ** ******** **
* *** ***** * ******* *

int * * argc, char * * {
*** *** * * char * * **
* ** * *** char ** **
* * * ** * char *
** * ** * * ** char * *
* ** * * * char * *
**** ** * **
* * ****** ** * **** *** input the letter to * ** ** *
* ** * ****
** * ** * * **** **** * * *** * * *** * ** ** * *** **** * *** **** * *
* * * * * * * * * = ***** + 3;
* * * * ** * = * + 3;
* ***** * * * ** = ** + 3;
* *** letterc = * + 3;
*** ** * * = ** * + 3;
* * **
* * * *** ** * * * * * * * * * *** ** ** ** ** ** *** ** * *
* * * * * **
**** * * return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
1 like 0 dislike
Hidden content!
* * * **
* * ****** * ***

int * * argc, char *argv[]) {
** * ** ***** * char ** ***
* * ** * char letteri;
**** * ** **** * char ** *
* *** *** char * **** *
* * * * * char **
** * * **
* ** * * * * * * ** * input the letter to encode: * * * *
**** * * * * *
* ** **** **** *** * * ** **** * * * * * * *** * ** * * * ** *** ** ****
* * *** * ** ** * +3;
* *** **** ** * * *** +3;
* * * * * * *** *** +3;
* * *** *** +3;
****** **** * ****** +3;
* ** * *** *
* ** ** ** **
* ** * * ** * * ** *** ***** **** ** *** ** *** ** * * * **
* * ** ** *
*** * * ** *** return 0;
}


INPUT
* * * **** **** *
* **** *
OUTPUT
*** * * * *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
*** * * **
*** * * * *

int * * * argc, char *** {
** * * *** char * **
* * ** * * * char * ** *
** ** * ** ** * char * *
* * * ** * ***** char ** **
* * *** * char * *
** * * ** ***
* * * * * *** **** input the ** ** to ** * ** * **
** * *****
* ***** * * * * ** ***** * ** * ******* *** *** **** * * *** * * ** * *
* ** * * *
** * * * letter = letter + 3;
* * * * * = * ** + 3;
** * ** * * **** = * * + 3;
** ** * * = ** * + 3;
*** ** *** ** * * = ** + 3;
** * * ** *
* * * ** * ** ** * ****** ** letter is * * * ** * * **** * * * * * ** *** **
** ** **
****** * * return 0;
}

INPUT
** ** ******
** * * ********
** **
** ***** *********
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
#include * * * * * ****

int main(int argc, char *argv[]) {
*** ** *** ******* *** * lettera;
* ** * * ** * letterb;
* ** * * * * ***** * ***** ** letterc;
* ** ** * **** *** * **** letterd;
* ** ** *** * ***** **** * lettere;
** * ** * * * * ** *
* *** * * * ** * * * * ** * ** * * %c %c %c * * * ** **** **** ******** ** ** **** *** *** ** ** **** *
** * **** * * * * ** = lettera + 3;
* * * * **** * * * * = letterb + 3;
* *** * ****** * * * * **** * * = letterc + 3;
**** * ** ** *** * **** **** * = letterd + 3;
* *** *** ** ***** ** ** = lettere + 3;
*** **** ** * * ***** *** * *** * *
* * * * * * * * ** * * **** * %c %c %c *** *** letterb, ** ** ** ***
*** * **** * *** * * ** *
** * ***** ** * * * *** * 0;
}

***
*****
* ** * *** * **
*** **
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.185
©2016-2025

Related questions

0 like 0 dislike
2 answers
[Normal] Essay (Open question) - asked Dec 12, 2017 in Chapter 2: Syntax structure of the C language by 許哲瑋 (449 points)
ID: 37081 - Available when: Unlimited - Due to: Unlimited
| 1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users