1 like 0 dislike
17.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 17.3k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * ** * ***
#include * * * *** * ****
int main()
{
***** **** * * ** * * A[99],B[99];
* **** ** * * **** * ** **** ** * * ** *
**** * ** * ** * ***** **** * * ** *
* * **** * * ***** ** * ** ** * *** **
* * ******** ****** **** * **** ** ** * *** * is a prefix of %s",A,B);
** ** * * *** * **
*** * ********** * *** * * * * ** *** *** *** is not a prefix of %s",A,B);
* * ** *** * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
*** ** * *****
** ** * ** * * *** * * *

int main(){
***** * ** ** *** ** * *** * pre[100],str[100];
*** ****** * * * * * * * * ***** ** * ** ** ** * **
** ***** * ***** * ** * flag=1;
****** *** ** **** * * * * * * ***** ******* ***
**** * ** ** * ** *** * ** * ** * * * ** * ** flag=0;
**** * ***** * ** *
* * ** ** * ** **** * printf("%s is a prefix of * **** * *
* * * ** * ** ** *** *** printf("%s is not a prefix of * * * * ** * *
** *** * **** * * * ** * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include * * * **
** ** * * * * *

int main()
{
* * *** ** * ***** * ** * * * ** * ****
** * * * * *** * **** * 0;
}
answered by (-108 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main() {
**** ** ****** a[100], b[100];
* ** * * * ** ** * i,j,len,re=0;

*** ** ** *** * *** ** * * ** {
* *** * * * * * ** ** * ** *** ** * ***** * **
* ** * * *** *** *

** * * ** * ***** * * ***** * * ***** * * a);
** ** * ** ****** * *** ** * * b);

* ** * * ** * *** * * * ****** *
***** *** * * ** * ** *** * * {
* **** * * * * * * ** * ** * * *** **** ** *** * * {
* ** * *** *** * * * ** * * * ** * ** **** * ****** * * * * *** ** * *
* ** * * * * * * * ** ** * * ****** **** * * ** * * *
* * ** * * * *** *** * ** *** **** ** ****
    }

*** * * **** ** **** * {
*** * ** ** ** * ** ** * **** *** * *** * * *** *** is not a prefix of %s", a, b);
** ***** * * * ***** **
** ** * * ***** * ** if(re==0) {
** * * ** * * ** * ** ** ** * * *** ** ** ** is a prefix of %s", a, b);
    }
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
# include <stdio.h>
# include ** * *
# include * * **

int prefix(char p[],char s[])
{
* * * * * **** **** * * ** **
* *** * ** * * *** ** *** ** * **** ** 0;
** * ** * ***** *** * * ** *** **
** ** * * * * * ***** * * ** ** * * 1;
* * ***** * * * * *
*** * * * * * ** *** ** **** ** **** * 0;
}

int main()
{
* * * * **** * ** ** * p[999],s[999];

* * ** *** * * * *** * * * * * ***
** * * * * * ******* ***** ** *** **

** ** * **** * * **** * *
*** * ** *** * ** *** ** ** **** * * **** ** ** * * * is a prefix of %s",p,s);
** *** * **** * * ***
* * *** * * ** ** * **** * *** *** is not a prefix of %s",p,s);

* * ** ** *** * * ** * ****** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include *** ** * ***
#include * * * * * *
#include *** * * * *
 int prefix(const char p[100],const char s[100])
 {
* * ** * ** * **** ** * * * ****
** * ** * * * * * ** * ** ** * ** ***** 1;
* *** ** ** **** * ** * ** 0;
 }

int main()
{
* * ** * * * *** ** * *** **
***** ******* ***** *** ** * * * *
** ** * ******* **** ** * *
* * * ** * * * ***** * *
* * ** *** ** * * ** * is a prefix of ** * ** ***
* * * * * * ** * * * * ***
* * ** * ** * ** * *** * * *** * * * is not a prefix of **** **



* * ** ** ** * ***** ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:9:8: warning: implicit declaration of function 'prefix' [-Wimplicit-function-declaration]
     if(prefix(p,s))
        ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include *** * *** * ******
#include <string.h>
int main()
{
*** * ****** * *** * ** ** a[100],b[100];
* * ** * * ** * * * * ** %s",a,b);
** ** * * ***** ** * * * n=strlen(a);
* * * ** * * ** * i,prefix = 1;

** *** * * * * ** ** **** ** i<n; i++)
*** * *********** *
**** ** * ** * ** * * **** * ** ** ** * * != b[i])
**** ***** * * *** * * * *** * ** * *
* *** *** * * * * * * * *** * ** ** *** * **** ****** ** * ***** *** * = 0;
* * * ***** ** **** ** ** *** ** * * * * * * * * * *** * * is not a prefix of %s",a,b);
* **** * * * ** * * ** * *** **** * ** ** * *** * * * * *
* ** * * *** * ** * * *** ** * *
* ** * * ** **** * * ***

* * *** * * *** ** ** * == 1)
* * * * * * * * * ** * ** *** ***** * ** **** **** is a prefix of %s",a,b);

** **** *** * *** * ***** 0;
}
answered by (-127 points)
0 0
prog.c: In function 'main':
prog.c:8:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:8:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:8:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 16k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 15k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 18.7k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users