1 like 0 dislike
16.6k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 16.6k views

37 Answers

0 like 0 dislike
Hidden content!
#include ** ** * ** * *
#include ****
int main()
{
*** ** * * * ** ** ******** A[99],B[99];
* * * **** ** *** * * ** * * * **
* ** ** ** * * * **** * * ** * * **
*** * * * * * *** * ** *** * **
*** * * * *** *** * *** **** * *** ** *** * ** * *** is a prefix of %s",A,B);
* ** ***** * ** * **
* * * * ***** * * * ** **** *** ** ** ***** ******* is not a prefix of %s",A,B);
*** **** * * ** * * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
** * * ** ** * *
**** * ** * * ** ***

int main(){
*** * * ** ** ** ** pre[100],str[100];
***** *** *** ** ** * * ******* * ** * * * **
**** *** ** **** *** flag=1;
* ** * * ** * * * **** *** * *
******* * ** *** ** ** ** **** * * * * ** * * * ** * flag=0;
*** *** ***** ** *** * *
* * * *** *** * ** * * printf("%s is a prefix of * * * * ** **
* ** ****** * **** * * printf("%s is not a prefix of * *** *** ***
* * ******* ** * ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include *** ** **
**** *** ** * *** * *

int main()
{
* *** ** ** * ** * ** * * **** ****
* *** * * * **** ** * 0;
}
answered by (-108 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main() {
*** * * ****** * * **** a[100], b[100];
** ** ** ***** ** ** i,j,len,re=0;

** * * ***** * * * * * * ***** *** ** * {
** ** * * *** * * * * ** ** *** * * ** * * * *** *
***** * * *** * *** **** ** *

* * * ** ** * * * * * *** * * ** * ** a);
** * ** * * * * ** * ** ** ** * * b);

****** *** **** ** * **** **
* * * * ** *** ******* * * * * {
*** * *** *** * * * ** * ** ***** * *** * * {
* ** * *** * ** ** * **** * **** * ***** * * **** **** * * *
* ** ** ** * ***** ** ** * * *** * *** * **** * ** *** ** * * ** **** **** **** **
* ** ** * * *** ** * * ** * * * *
    }

*** ** ****** * * ** * {
** ** *** ** * ** * * * * * ** * *** ** ** * * * * * is not a prefix of %s", a, b);
****** ****** * **
*** ** ** *** ***** * if(re==0) {
* ** * **** * * * ***** * ** *** ***** ****** * * ****** is a prefix of %s", a, b);
    }
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
# include <stdio.h>
# include **** ***
# include * * * * ***

int prefix(char p[],char s[])
{
* * *** * * * * * ******* * * *
**** ** ** * ** ** ** * * * ******* * * ** **** * * 0;
*** * ***** *** ** * ** ** ** * * * * ** **
*** **** * ** * * * **** *** ** * * 1;
**** **** ***** *
* ******* * * * * ** **** *** * ** * ** 0;
}

int main()
{
*** **** ** * * ** p[999],s[999];

* * *** **** * * ** *** *** * * **
* *** ***** ** * *** ** * ** ** * * ** *

*** * * * *** * * * ** * ***** *
* * ** * **** ** * ** * ** ** ** **** ******** is a prefix of %s",p,s);
** * * * * * * ** *
***** **** * * * * * **** * *** ** ** * *** * * * * * is not a prefix of %s",p,s);

* * ** * * *** **** * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include ** *** **
#include *** * ** * **
#include ** ** *** *
 int prefix(const char p[100],const char s[100])
 {
* ***** ******* * ** ** * ****
******** **** * * * ** ** *** *** * ** ***** * ** 1;
** * * * *** ****** *** * **** 0;
 }

int main()
{
* ****** * **** ** * * * **** **
*** ** * * * ** ** * **** * *
* * *** * * ** ** * * *** * *
** ** * ****** ******** * * **
*** ******* * * * **** * ** * is a prefix of ** * ** **
* * ** * * * *** ** * *** **
*** *** *** * * ** ** * * * * * ***** ** * * is not a prefix of ***



** * ** * * * * ** ****** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:9:8: warning: implicit declaration of function 'prefix' [-Wimplicit-function-declaration]
     if(prefix(p,s))
        ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * * ** *
#include <string.h>
int main()
{
* ***** *** * * **** * **** a[100],b[100];
** * ***** * ** * ** *** *** ** %s",a,b);
** *** ** * * **** * n=strlen(a);
***** * ** *** * ** ** ** * i,prefix = 1;

** * ** * ** ** ** * ** i<n; i++)
* *** * ** **** *
* * * * ** * ** * * * * ** * * *** * * ** **** != b[i])
* ** * * * * * * * * ** ** * ** * ** **
** *** * *** * * *** *** * * *** *** * * * * *** *** ** * * * ** * = 0;
** *** ** * ** ** * ******** * *** * *** ** * * *** * ** * ** * * *** *** * * is not a prefix of %s",a,b);
* **** * ** ***** ***** * * ** **** * ** * * * *** * *** * *** * * **** **
*** ** * **** ** * *** **** **** * ***** * * **
** *** **** ** * * * ***

*********** * * *** * * * == 1)
*** * ** * *** ** ** * ******** * * ** ****** **** is a prefix of %s",a,b);

** * * * ** * * ** * * * 0;
}
answered by (-127 points)
0 0
prog.c: In function 'main':
prog.c:8:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:8:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:8:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 15.1k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 14.3k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 17.9k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.4k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users