0 like 0 dislike
2.8k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 2.8k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * * * *

main()

{
** * * * * * * i,a,b,c;
** * * * * * ** * * * * ** ** *** * **
** ** * ** * * * * * ** **

{
* ** ** * * * *** *

{
* * *** ** **** **** * *** *** * ");

}
* ** * * ***** ***

{
* *** * * * * **** ** ** **

{
* * * * * ** * ** * *******

}

}
* * ** * * *** * ** ** ** **



}


* ** ** * * * ** * * ** **
* * ****** ** * *** 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
****** ***** ***** * * ** * * * **** &num);
* * * **** i = 1;i <= num;i=i+2)

   {
**** * * * * * ** * * **** ** ** ** ** ");
* * ** * * *** * * * * ** * * * ** * **** \n");
* * ** ** * * * **** ** * * * k =1;k<=num-(i/2);k++)
* ** ** **** ** * ** * * *** * **
*** ** * **** * * * * * ** ****** * ***** * ** * ** * **** ** ** * * ");
* ** * ** * *** * ** *** ** * ** ****
* ** ** ** *** **** ** ** * * ********** ** * * *** * ** * * *
* **** **** ** * * **** * * ** * **** * j = 1;j <= i;j++)
***** * *** ** ******* * **** ***
*** ** * * ** *** * * ** ** ** ** **** ** ******* * ** * **** ** ** * **** *  
** **** * ** ********** ** * *** * ** ** * *** ** * *** ** * ** **** * *** * ** ** *** ** * ** ** ** ** ** * * ** ***** ** **** * *** *** **** * ** * * ** *** * * ****** * ** * *
** * **** * *** * ** * *

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
******** ** * * * * ** a, b, i;
*** * * * * ** *** *** * **** ***** *** *
* *** * ** ** * * ** * ** * **
* * ** * *** ***** *
* ** ***** * ** * *** * ******** ***** ** ** * ** ** *****
* * **** * *** * * ** ****** ***** * * *** ** ");
* ** ** * ** * ** * **** * ** ** * * * * * * * *** ** * ** *
***** ** * ** * * ** *** * * ** * * * ** ***** * **** *
** *** * * ** *** ** * * ** * * * * **** * * * **** *
* ****** * * * * **
** * *** * ** *** * ** **** *** * * *
* * * ** * * ** * * 0;
* *** *** * ** * * *** *
* * ** ** **** ** * * * *
* * ** ** ** * **** *

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
** ** **** * ** * *
** ** * *** *********** *



int ***

{
a, j, k;
* *** * * ** ***** *
* = 1;j * * a / 2 + 1;j ++)

{
* * * * * *** *** **** = 0;k ** a / 2 - j +1;k ++)
* *** ** * * * **** ** * **** ***** *
****** * ** * * * * ** ** ** *** = 0;k ** * * * 2 + 1 ;k ++)
*** * * * *** * ** * * ** * ** ** ** * *
**** ** * *** * *** * * ** * *** ***

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include * ** * * *

#include **** ** ****



int main()

{
* * * * ** * * * x,y,z;
* ** ** ** * ** * *** * *** *** * * *
* * * * * * * ** * = 1;x <= (z+1)/2;x ++)
*** * ** * *
* ** *** *** ** ** *** ** * *** = 1;y <= (z+1)/2 - x;y ++)
** ***** ** ** * * ** *** * * * ** ** * *** * ** * * ");
* * **** * ** * ** * * ** * * **** * * = 1;y <= (x*2)-1 ;y ++)
**** *** * * ****** *** * * * * ** **** * * * * * * **** **
******* * * * ** ** *** * * * * * * * * *** *** * **
* ** * * * ** *


* * * * *** *** * * 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include ** *

#include * ******* *



int main()

{

int a, j, k;
** *** * * ** * * ***
* * * * * * / 2+1; j++)

{
* *** ** *** ** * ** **** a/2 -j +1;k++)
**** * *** * ** **** ** * * * ****** * **
* ** *** * * ** ** * *** * *** * **
** * ** * * ** ***** * * ** ** * * *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
*** ** **** **** ** ** ** * * *** * * ** * * * ** ***** ** * *** * **** ** * * ** * * * ****** * ** * * **
* * ** * ** * ** * ********* ** * * * *** ******* * ** * * * * * * ** * *** ****** * * ** ****** * * *** ** * *** ** *****
***** * ***** ** **** * ** ** *** * * ** * ** ** ** * ** *** * * ***** ***** * * **** ** * *** * ** *** * ");
* * * *** **** * * * ** ** ** * ***** * * * * * * * * ** * **** * *** * ****** * * ** *** ** *** * **** ***
**** *** * * ****** * * * * * * * ** *** * * *** * * ** * ******* ** ***** ** * ** *** ** ***** ** * ***
* * * ** ** *** * * ** *** *** * *** **** ** * ****** ** * * * ** ** ** * ******** * * *** * ** **** * ** ** ****** *
** * ****** *** * * * * ** * *** * * * * ** * * ** * * * *** * ** * ****** * * ** ** **** ** * ** * **

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include *** * ** *

#include ** *** * * * *



int main()

{
* * * * *** *** num, n, p;
* * * ******* ** ** * * * * * &num);
* ** * * * * * ** ***** (n = 0; (2 * n) + 1 <= num; n++)
*** * **** ** ** * * **
* ** * *** ******* * *** * ** * * *** *** ***** ** (p = 0; p <= (num / 2) - n - 1; p++)
* ** ************** * * ***** * * ********* * ** * ** *** ** * * ** *** **** **** ** **** ");
* ****** * *** ** * *** * * *** * ** * ** * ** (p = 0; p <= (n*2); p++)
* ** * **** *** * ** * * * * ** * * * *** ** * ** * * * ** **** *
* *** *** *** *** ** ** * * * * ** ** ** * ** * * * ** ** * ** * *
* ** * * * ** ** * **


*** * * * * * ** **** * 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
***** ** * **



int main()

{
* * ** * ** * ** ** ** a, b, c;
**** ** **** * *** * * * *** *** * ** ***
** ** * ** * * * * ** ** c <= a; c+=2)
** * * * ** *** *
* ** * ** * *** ** b <= (a-c)/2; b++)
* * * ***** **** * * ** * * ** ** * * * * ");
* * ** * ** * * ** * ** * b <= c; b++)
* ** ** *** ** ** * ** *** ****** * *** ** * * * ***
** ** ** **** * * ** ** ** ** * ** *** *** **** *
* ** * *** ** * **
** *** * * ** * * * **** 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
***** ** ****** * a ;
* ** * * * * * i , j ;

    
** *** * * **** * * * *** * * &a);


* * ** * * * * ** *** *** * * ** ***

    {
* ** ** ** **** * * * * ** *
*** * * * ******* * * ** *** * ** *** * *** * **
* * * * * * ********** * * * ****
* * * ** *** ** *** * * * * * ** * * * * **** *** ");  
** ** ***** ** * * ** ** * *
* * ** ** * * * ** * * * ** ***** * ** * ****** ** ** * * *** ** ** *** ***** ** ** **** **** **** **** **** * **
* * ** *** * ****** *** * * * ** * *
* * * * ** **** * ** * **** ** * ************** ** ** ** ** *** *** * * ** * *** * ***** ***** ** ** * * * * ** *** *** * * * ** * ** ** * * ** * * * ** ** ***** *** *** *** * * * ** * * * * **** *** * ***
*** ** ** ** ***** ** ** * *** ***


* ***** ** ** *** *** ***** * *** *
*** **** * * * * ** ** ** * *** * * * **** * ** * * *

    }

   

    
* * ** * * * *** ** ** *** *
* * * ** * ** * * ** * ** 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.217
©2016-2025

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 1.6k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 3.5k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 2.6k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 3.4k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users