0 like 0 dislike
6.9k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 6.9k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * *

main()

{
* * *** **** ** i,a,b,c;
** * * ******* *** * ** ** * * *** ** * *
** * * * ** ****** ** **

{
******* * ***** * * * * *

{
* ** * ** * *** * ");

}
* * ** ** ************ ** * **

{
* * *** * * ***** ** * *

{
* * * *** **** * ** ***** * * * * * *

}

}
******** **** * ** ** * ** * ***



}


* * *** * * ** ** * ** *** ** *
** * ** * * 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
* * ** *** ***** ** * ** * * * * ** &num);
* * * * ** * ****** i = 1;i <= num;i=i+2)

   {
** * * * * * **** **** ***** ***** *** * ");
* ****** ** * * ******* ** ** * ***** * * * \n");
**** ** * * * * * * ** ** *** ** *** k =1;k<=num-(i/2);k++)
* * ** ** ** * * ** ******* * **
* * *** ** * **** **** **** ***** * ** **** * ** *** ** * ");
* * * * ** * * ******* * * ** * * *
* * * ******** ********* ** * **** * **** *** *** * ******* * * ***
** * * * * * * ** * ** * ***** * * ** ***** j = 1;j <= i;j++)
* * * ** * ***** ****** ****** *
* * * ** *** * ** ** *** * * ** * * ***** * * ***** ******* ** * *  
** * ** ** ****** ***** * * ***** * ** *** * **** *** ***** * ** ****** * ** ** * ** * **** ** *** * ***** ** ** ** * ** ** * * * * **** ** * * * * * * * * * ** * * **
** *** * **** * *** **

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
** * **** ** ** * ** a, b, i;
* * * * ** ** ***** ** * ** * * *** ** *
* ****** * ******* * *** ** * * * *
** *** ** **** * * * ** **
* * ** ** * * ** ***** ** **** ** * *** ****** * * * * *
* *** ** * *** * * * * *** * * ** * * ***** * ** ** ");
** *** ****** * * ******* ** * * ** * * * *** * * * ** ****
* **** ****** ****** * ** ** ** *** * * ** * * ** **** * ** * *
** * * * * * * *** * * *** ******* ** *** * * * *
*** ** *** ** ** *
*** * * ** ******* *** ** *** * ** * *
** ** ** * ****** 0;
* * * * * * ** * * *** *
* * ** *********
* ** * **** *** *** * **

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
***** * * ** **
*** ** * ** * ** * *



int **

{
** a, j, k;
** ** * ******** *** * *
= 1;j ** * * a / 2 + 1;j ++)

{
** ****** ** * * * ** = 0;k **** * a / 2 - j +1;k ++)
**** *** *** ** * * *** ******* * ***
** * * ****** ** ** ** * = 0;k * * * * 2 + 1 ;k ++)
* ** * ***** *** * *** ** * ***
* * **** * * *** *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include * ** * ** * *

#include ****** **



int main()

{
** * *** ** * * *** x,y,z;
** * ** **** * ** *** ** ** * * *
* * ** ** *** = 1;x <= (z+1)/2;x ++)
* ** *****
* * * * **** ** ** * ** * * = 1;y <= (z+1)/2 - x;y ++)
*** * * ***** ****** * ** ***** ***** * ** *** * **** * * * * ");
** ** * *** *** ** * * * *** * = 1;y <= (x*2)-1 ;y ++)
**** ** *** * * ** *** * * * * * * *** * ** * * ** * ** ** ** * * * *
*** ** ** * **** ** **** ** ** * **** **** * *
* * * ******* *


** * ** ** * ** * * 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include * ** * ** *

#include * ** * ****



int main()

{

int a, j, k;
*** * **** * * * * * ***
* * *** ***** * / 2+1; j++)

{
* * *** * * *** ***** * ** * a/2 -j +1;k++)
* * * ***** * *** * * * ** ** * **
***** * * * **** *** * ** *** * * ** ** ** * **
* ** **** * ** ** * * * * ** ** **

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
* ** * ** **** * *** *** ** * **** * * ** * ** * *** ** * **** *** * **** ** * ** *** ** * *
* ** * ****** * ** * **** **** * ** * *** * ** * ** * * * * * * ** *** ** ** * * * ** *** ** * ** * * * * * ** *
*** * * * * * ** * ** * ** *** ** ** * * * ** **** ** **** * * *** *** * * * * * ** * * **** ** * * ** ** ** * *** ");
*** *** ** *** * *** * * *** * **** * ** * *** * * ******* * * * * ** * * * * * ** ** ***** * *** * *** * * *** ** ** * * ** ****
** ** **** * ** ** * **** * ** ** ** * ** ********* ***** ** * ** ** **** * *** * ***** *** * * * *** * * ** **** * * * * * ** *
* * **** **** *** * ** * ** * * * ** *** ** ** ** ** ** *** ** *** ** * * ** * *** * **** *** *** **** *** * * ** ** *** *** ***
* * ** ***** * *** ** ** ** ** ****** ****** * ******* * **** * ** * * ** * *** * * *** **** * ***** * ** *** * **** *

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include *** * *** **

#include ** * * * *



int main()

{
* * ** * **** ** ** num, n, p;
**** * ** ***** ** ** ** * * * * * * * &num);
* ** * * ** * ** (n = 0; (2 * n) + 1 <= num; n++)
**** **** **** ** * * *
* *** ** * * * * * * *** * *** ** *** *** (p = 0; p <= (num / 2) - n - 1; p++)
* * * **** *** * ** ** *** * ** *** *** ***** ** ** * * *** ** * * *** ");
** * **** ** * ***** * *** * **** * ** ** (p = 0; p <= (n*2); p++)
* **** ***** ** * ** * * * ** **** * ** *** * * * ** * * * *** *** ** *** **** *
* * * * * ** * * ** ** **** ** * ** * * ****** * * **
* ** ** **** * ** ** ** ***


** * ** ** ******** 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ** **



int main()

{
*** ** ** ** * *** a, b, c;
* ****** * * * * *** ** ** ** * * * * **
* * * * * * ** * * *** *** c <= a; c+=2)
* **** ** **** *** * **
** ** * ** * * * * * * ** * * b <= (a-c)/2; b++)
******* * * ***** ***** * * * * ** *** * * ");
* ** * ** * *** * ***** *** b <= c; b++)
** * * * ** ****** * * **** * * * ** * ** ****** *
** ** ** ****** ** * * * * *** ** ** **
****** *** ** * * * *
* ** ****** ** * * ***** ** 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* * *** *** * ********* * * a ;
* * * ** * *** * * ** i , j ;

    
* ** * * ****** *** * * ***** *** * * &a);


* **** * ** * * ** * ** * **** * ***

    {
* * *** *** ** * * * * *** * **
* * * ** * * ***** * ** ** ** * *** * * *
* ** * **** * * * *** ** **
** * * ** **** ****** ********* * * ** *** ** ** ");  
* * * ** * ***** * ** **** **** **** **
* * ***** * *** * * * **** ** * ***** * * * * ** * * **** ** * * * ** *** ** **** ** ** * * * **** * * *
* **** **** ** * ** * * *** ** ** ** ****
** * **** * * * **** * ** ** * * * ** ******* ***** * * ** * ** * ** * ** ** ** *** * * * ** ** * ** * ** * * ***** ** * * * ** *** * * ***** ** *** * * * * ** * * **** * * ** * ** * * * * *** ** * * **** **
*** * ** * * * * ****** * ****** *


** * *** * * * ** * * * ****
* * * * * * * *** * ** * ** * * *** * * * ** ***** **

    }

   

    
** **** * *** **** * ******** **** *
* ** * ***** * 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 4.3k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 8.9k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 6.2k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 8.1k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 5.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users