0 like 0 dislike
4.1k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 4.1k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
* * *

main()

{
** * * ** ****** **** i,a,b,c;
* * * *** **** ** * *** * **
** ** * **** ****** * * * *

{
** ** *** * ** * **** ** ***

{
*** * * *** ***** ");

}
** * * ** * * ******

{
* ** * ** **** * * * ** **

{
***** ** * **** * * *** * * **

}

}
*** * * * ** * * ** ** *** *



}


*** ** **** *** *** ** * * ****
* * * * * * ** 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
***** * * * * *** * **** ** * * &num);
** * *** ** ****** i = 1;i <= num;i=i+2)

   {
* * ****** * * ** *** ****** * * ******** * ** ** ");
***** ** * ** * **** * * * * * * * * ** ** \n");
* ** ** * ** * ** * *** **** * * * k =1;k<=num-(i/2);k++)
* ******* * ** * * * ** ** * ** ****** *
** ** ** *** *** * ** * ** ** * * ** ***** ****** * * * ");
* * ** ** * ** * * * * *******
* * *** * * * * * * * ** **** * **** ** * ** *** *** **** * ** *
* ** * ** ****** * * * * *** ** ** j = 1;j <= i;j++)
*** * ** ** ** * ***** * * *** ** * * * *
***** *** * ***** * * * * * *** * ** * * * * **** **** * ***** *** ** * **  
* * * * **** *** ******* * *** ** ** *** * * ** * *** ***** ** * **** * * * ** * **** * ** ** * *** * * *** * *** * * *** * * * * *** ****** * ***** ** ** * * * *** * ** * ** ****
******** *** * * * * *

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
* * * ** * ** ** * a, b, i;
***** *** * ** ** ** ** * * ** ***
** * *** ** * * *** *** ** * ** *
* * * ** * * * ** *
* ****** * * ** ** ** *** **** **** * * ** * * **** ** *
* ** **** ** * ** *** * *** * * ** * * ** ");
* * **** ** *** ** *** ** * ** *** ** * * ** * ** ** * ** * *** **
* *** ** ** * * * *** ** *** ** * * * *** **** **** * *
** ** ** ** *** ** **** **** ** * ** *** ** ** * ** ** *****
* * *** ** * * ** *
**** *** * **** * ** * * * ** ** *** ***
* * * * ** * * * * 0;
** ****** * ** * *
** * ** ** * * *
** * * * * * * *

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
* ** * * * *
***** * *** ** *** * * **



int *

{
* a, j, k;
** * * **** **** **
* = 1;j ** * * a / 2 + 1;j ++)

{
** ** * **** * * * * * = 0;k ** a / 2 - j +1;k ++)
*** * **** * * * ** * *** ***
* * *** ** * * *** ** * = 0;k **** * * 2 + 1 ;k ++)
* ** * ** ** ** *** *** *** ****** ***
** *** *** ** * * * ** * ***** * * *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include * ** ****

#include ** * ** *



int main()

{
**** * ** * * x,y,z;
*** ** * *** ** *** * * * * ***** ** ** **
**** *** ** * ** = 1;x <= (z+1)/2;x ++)
* * * ** *** * * *
* ** * * * ** * *** ** * ** * = 1;y <= (z+1)/2 - x;y ++)
* *** ** ** * * *** * ** * * * ** * * ********* * *** ");
*** ** * ** * * * **** * ** = 1;y <= (x*2)-1 ;y ++)
* * * * ** * * * * * * ** * ** *** ** *** * * * * *** * *** *
** * ** ** * ** *** * ***** * * * **** *
* * ** ** * *


*** * * **** ** * 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include *** * * ***

#include * * *** * ****



int main()

{

int a, j, k;
* * * * * * * * *** * * *
*** * * / 2+1; j++)

{
* *** * * * * *** ** * * * *** a/2 -j +1;k++)
** **** * **** *** ** *** * * * * *
* **** ** * *********** ** ** * * ***
** ** ** * * ** * * ** * * * ** **

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
* *** * ** * *** ** * ** ** ** * *** ** ** *** ** * ******* *** * * ** * ***** * ** ** ** * * *
*** * ** ** ** * *** * * ******* * * ** * * * ***** *** * * ** ***** ****** ** * **** * * * ** * *** ** ** ***** * * * ***
* **** * * * * * * ** * **** * * *** ******* ****** * ***** * ** * ** *** * * *** ** * * ** * * ****** * * * *** * ");
* **** * * * * * * * * ********* * ** **** ** ** ** ** * * ** ** *** * * * ** **** ** * ** ** ***** * * * *** * *
*** * * ** *** * ** ** * * * * ** ** * * * *** *** * * * *** *** **** ** * * * ** ** * * * *** * * ** * * * *** ** ***** * *
* ** * * * * ** ** * * * * ** ** * *** * ** *** ** **** ** ** ** * ** * * * * ** * * * ** ** * ** * * * * *** ** *** * * ** *
* * * * *** * * *** * * **** ** ** ****** * *** ** * * ***** **** ***** * * *** * * *** * * ** **

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include * * ** ****

#include ** *** * **



int main()

{
* * * ** * **** *** num, n, p;
*** ** *** * *** * *** * ** * * ** ** * &num);
** * *** ** *** ** * * * (n = 0; (2 * n) + 1 <= num; n++)
** * * ** * *******
* ***** * *** * ** *** * *** *** * ** ** * ** (p = 0; p <= (num / 2) - n - 1; p++)
****** ** * ***** * * *** * ****** * * * * * * ** ** ** * * * * *** ");
* *** ** * * * ** * * * * ***** * * * * * ** (p = 0; p <= (n*2); p++)
***** * ** *** * **** **** * ** * *** * * * ** ** * * * * * *
* * * * ** * * ** ** * * ****** * ***** * * * ** * ** * * **
* * ****** * * **


* * ** **** ** * ** 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** * * * * *



int main()

{
* ** * ** ** ***** a, b, c;
** * *** * ** * * ******* *** * ** ** ****
* * * * * ** **** * *** * c <= a; c+=2)
** * ***** * * ** ***** *
* * * ** **** ** *** b <= (a-c)/2; b++)
** * *** * * * *** * * * * ******** * * ");
** * **** **** ** ** ** * ****** * * b <= c; b++)
*** * ** **** *** *** ***** * * ** * * ** *
** *** * *** **** *** * *** * * ***
* * * * * ** * *
** * ** * *** * * *** 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* * *** * ** * * *** a ;
** ** * * * * * * ** i , j ;

    
** ** **** * ** *** ** ** * ** * * &a);


* *** ** * * * **** ** * * ** ***

    {
*** **** ** ***** * * *** * *****
** ** * ** * ** *** ** ** ***** * * * * *
* *** * * ** * ** * *** * * * ** *
*** * ** ***** * ** ** * ** * * * ****** * * ** ");  
* ****** ** ***** * * ** ** * ****
** * **** **** * ** * ** ** ** *** ** * * *** *** *** * * * * * ***** *** * * ** **** * * ** *** * * **
* * * ******* ** * *** * * * ** * *
* * * * **** * * * * * ** * * ** * * ** * ** **** *** * * * * ********** * ** * * * * ** ** * ******* *** * ***** *** * * * **** * ** ****** * *** ** ** * ** * * * ** * * * * * * **** **** ** ** * ** * * * **** * *** ** * ***
*** * **** * * * ** ** *** **** *


** *** *** * **** *** * ** ****
** * * **** * **** * * * * * ** *** *** * ** ** ** ***

    }

   

    
* *** ** * * * *** *** * * * * * * *** * *
* * * ** *** * ** * ** 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.213
©2016-2025

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 2.5k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 5.2k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 3.6k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 4.8k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users