0 like 0 dislike
6.1k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 6.1k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ** ** *****

main()

{
* ** * *** * ** * *** i,a,b,c;
* * * ** * * *** ** * ** ** * * * * *
*** *** **** * * * *** *********

{
* *** * ******* ** * ** * *

{
** ** * **** * * * * ** * ** ");

}
* * ** * * *** ** ****

{
* * * * ** *** ******

{
* * * * *** ** ** ** * **

}

}
*** ** * *** *** * *** **** ***



}


**** *** **** ****** ***** * **
* * * * *** ** * ** 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
*** * * * **** ** ** * **** ** &num);
*** ** * ** * * * * i = 1;i <= num;i=i+2)

   {
* * * *** * * * **** ** *** ** * ** * ");
******* * *** ** * * ** * * * *** * * *** * * ** \n");
**** * * * * ** * * ***** **** * **** k =1;k<=num-(i/2);k++)
***** ** ** *** * **** * * * * **
** * ** * * * *** * ** *** *** ** ***** *** * *** *** ** * ** * *** ");
** *** ***** ** *** ** ** *** * ******* * *
* * * * **** ****** *** * * *** **** ******* * ** * **** * **** * ** ** *** *
*** ** *** * * *** * * * ***** * * * * j = 1;j <= i;j++)
**** ** * * ** * **** * ** ** * ******
***** **** ** ** * ** ** **** *** * * * **** **** *  
** * *** **** ** * ** **** * ** * ** * *** * * * ** * *** * ** ** **** * * ** * *** ** * *** *** * *** *** ** * * *** * * * * ** * * **** *** * **** ** * * **** **** * * ** **
***** * * * ** ***** ***

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
**** **** * *** *** * ** a, b, i;
** *** *** ***** * ** ******* ******
* * * ** * ** * * * * * ** ** **
** * * * ****** * *
* * ** ** * * * ** * * ** ** ** ** *** *** * * **
** * *** *** ** *** ** **** * *** ** * *** * *** ");
**** *** ** ** * ** ****** * **** ** * **** * * *
** * * * * ** * ** * ** * *** **** ** * * * ****** ***
** * *** * * ** * * * ****** ** * ** * *** **** * * * **
** * ***** * * * * **
*** * *** ** * * * ** * * ** ****
* *** * * * ***** * * * * 0;
* * **** * * * * ******* *
** * * * *****
* **** ****** * **** ***

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
*** * **** *
* * ** * * ** * *



int *

{
* a, j, k;
*** ** * ** ** * ** * **
* = 1;j ** * * a / 2 + 1;j ++)

{
* * ** *** ** ** ***** * = 0;k ** * a / 2 - j +1;k ++)
* ***** * ** * **** * * *
* *** * * * * * * = 0;k ** * * * * 2 + 1 ;k ++)
***** * *** * * * * * *** **** ** ***
* * ** * ** * ******* *** * **

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include *****

#include ******* ** * *



int main()

{
*** * ** * ** x,y,z;
* * **** ** * ** * ** * * ****** ** *** **
** ***** * ** = 1;x <= (z+1)/2;x ++)
** **** * * * *
* ** * * ** * *** * ** * * ** * * ** = 1;y <= (z+1)/2 - x;y ++)
**** * * * * * ** ** ***** * * * * ");
* **** *** ** * **** ** ***** * = 1;y <= (x*2)-1 ;y ++)
* ** ** *** *** ** * * * ** **** *** * ** ** ** ** *** * *
* * ****** * * * * * * * * * * *
* * * ** * * * * *** *


* * * ***** * * 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include * *** **** * *

#include * ** * **



int main()

{

int a, j, k;
* ** ** * * ** ***
* ** * * / 2+1; j++)

{
* * * * ** * ** **** * ** * a/2 -j +1;k++)
** * *** * * ** **** **** ** ** **** * *
** ***** * * *** ** ** ** * ** * * * * **
* *** ** * * ** *** * * ** ** ****** *****

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
* **** * * ** * ** * * * * * * * *** * ** * ** * *** ** * * * ****** ** ** ******* ** *** ******** * *
* * * ** *** * * ** ******* ** ** **** ****** ** * * ** *** * *** * * ** * * * **** ** * ** ** * * * ** * ***
***** *** **** *** * ** * * ** * * **** * * * * **** * * * ** * * ** * * **** *** ** ** ******* * * * ** * ");
*** *** * * * *** ** **** ** ** * ****** ** * * ** * *** ********** ** *** *** * *** **** ** ** * ** ** *** **** * ** * * ** * **
* * ** ** ** *** *** *** ** * ** * **** * * * * **** ** * ** * * *** **** ** *** * ** * * * * * * * ***** * * * * *** *
**** * * * * **** **** **** *** * *** ***** * * * ** * * *** * ** ** *** *** ** ***** ** *** * * * ** ** **** ** * **
* * ***** ** ** **** * ** *** ** * ** ** ** ** *** * ** * *** *** * * ** * * * * *** ** *** ** ***

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include * *** * *

#include *** *** * ** *



int main()

{
* *** *** * ** ** *** num, n, p;
* * ** *** * * *** *********** **** &num);
******* **** * * ** ****** (n = 0; (2 * n) + 1 <= num; n++)
* * ** * * ** ***
* * * * ** * * *** * *** * * *** ** * * (p = 0; p <= (num / 2) - n - 1; p++)
** **** * ** ** * * ** * *** *** * * * ** * * ****** ** * *** * ");
** * **** *** * * ***** * **** ** ** (p = 0; p <= (n*2); p++)
**** ** *** * *** *** ****** ** ** * * * * ** * ********** * * ** ***** * * * * ** *
* *** * * ** ** *** *** * * * ** * * * **** ****** ** *
** *** ** * *** * *


** * * **** * *** * *** 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** ** * * *



int main()

{
* ** ** ** * *** a, b, c;
** *** * ** ** ** * ** **** * * **
* * * **** * * *** * * * * c <= a; c+=2)
*** * * * ***** *
**** * *** *** * ** ** b <= (a-c)/2; b++)
** * * ******* * * * ** * **** ****** ** * **** ");
* ** * * * ** ** * * ***** * b <= c; b++)
***** **** *** *** ** * * * ****** * **** *** **** **
** **** **** * *** ** ** ** * * * ** **
*** ** * ** * * *** **
** * ** ** ** * ** * * 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* * * * ** * * *** a ;
* * ** ** * * ** * * i , j ;

    
** ** * * ** * *** * ****** *** * **** ** **** &a);


* *** *** **** * * * * * * * * * *** ***

    {
* ** * * *** ** ** * *** ** * *
* **** * * *** * **** *** * ** *** * *** ****
*** **** * * * *** ** *** * ***** * *
* ** *** * * * ** * * * *** * ***** * **** ");  
** * *** * * * * **** ***** * **
*** *** **** ** * * * ** * ** * ** * ** **** * ** ** ** **** * * ** ** * ** **** *** * * ** * * ** * ** * * * *** *
* ** ** * * *** ***** ** * ***** * *
* * * * *** * *** ** *** *** ** * ** * * * ***** ** ** ** ** ** * * * *** **** **** * ** *** ** *** ** ** ** * * ** ***** * ** ** *** * ***** *** ****** *** * * * * ** **** **** * **** * ** * * * * *** ** **** * **** *
** ** * ** **** * *** * * **


*** *** *** * * *** * ** * * ***
*** ** ***** * ** ** ***** * *** * *** ** *

    }

   

    
* * * * ** **** ** ** ***** * * * * *
****** * * * * ** * * 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.39
©2016-2025

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 3.7k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 8k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 5.5k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 7.2k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 4.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users