0 like 0 dislike
6.1k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 6.1k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** * * **

main()

{
* ************ * * i,a,b,c;
* * ******* * * * * **** * *
* ******* ****** * * * ****

{
* * * *** ** ** *** ****** * **

{
* ******* ** * * **** * * ");

}
*** * * * ** * ******

{
* **** **** ***** ** ****** *

{
**** ***** ** ***** *

}

}
* * * * * * ** * * ** * * *



}


*** * * * * * ** * ** * ** *
** ** * * * * * 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
*** ** * ** ******** * ** * **** * &num);
** * ** * ** ** *** i = 1;i <= num;i=i+2)

   {
* ** ** * * * * ** **** ******* ** * * ");
* * ***** * *** * ** ** *** \n");
* *** * *** *** ** *** *** * * * *** k =1;k<=num-(i/2);k++)
*** ** *** * *** ** * **** * **
****** ** ******* * * * * *** * *** **** *** * *** *** ** ** * *** * * ");
** * ** * * ** * * * ** *** * ***** *
* * ** * * * *** **** *** ** ** ** * * * ***** * ** * * * * *
* * *** * ** **** * ** ** * *** * * * ** j = 1;j <= i;j++)
*** *** * * * ***** ** * * * ****
**** ** * * ** * ** * * ** ** *** * * *** * * * * * * ** *** *  
* *** *** * *** ** ** ** * ** ** ** ** *** * *** *** ***** * ** *** *** ** * ** ** * * *** *** *** ** ** * * * * ** *** ** ** * ** **** * * ***** * ***** * * * ***
**** *** ** ** ** **

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
* *** * **** ** ** * * * ** * * a, b, i;
**** **** ** * ** * *** *** * ** ** ** * *
* * **** * * ** * * ** *** * ****
* ** ** * * * *
**** ** *** * * * * * * * ** * * * * *** * **
*** * *** * **** ** * ** ** * *** * ** ** *** * * ");
* *********** * * * ** * * ** ** * *** * *** * * * * ** * *
*** ** ** * * *** * * ** * * **** * * ** * * *** * ** ** **
* * ****** * ******** * ** ***** * ***** * ** *** * * * ** * **
*** * * ** *** *****
** * ** * * ** *** ** * ** * **** * *
** ** * *** ** *** *** 0;
* **** *** * ****
****** * * ** * ***
** *** * *** * **

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
** * *** *
* * * * * * **



int **

{
a, j, k;
** * ** *** * * * *
* = 1;j ** *** a / 2 + 1;j ++)

{
* * * ** * ** ** * * * * = 0;k *** a / 2 - j +1;k ++)
***** *** *** ** * **** * * * * **
** * *** * ******* = 0;k * ***** ** * * 2 + 1 ;k ++)
** ** * ** * * * ********** ******* ** * *
* * *** * *** * * ** * * * *** * ** **

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include *** * *** * *

#include * * * *



int main()

{
****** * * ** x,y,z;
********* ** * * * * ** * ****
** ** * * * * *** * * = 1;x <= (z+1)/2;x ++)
* ****** * ** * *
* * * * **** ** * * ******* = 1;y <= (z+1)/2 - x;y ++)
*** * **** **** ** ** * **** * *** *** ** **** **** * ** * ");
** ****** ******** * * ** *** ** ** * * * * = 1;y <= (x*2)-1 ;y ++)
****** *** *** * ** * * ** ** * * *** *** * * * ** * * *
* * * * ** * * **** * ** * *** ** * *** * ** ** * ** ** *
* *** *** * ******


* ** * * ** * **** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include ** * * *

#include * * * * ***



int main()

{

int a, j, k;
* * *** *** * * * **** *
** * ** ** / 2+1; j++)

{
* * ***** * ** * *** ** a/2 -j +1;k++)
*** ** *** ** * ** ***** ** **** ***
***** ** * ** * ** ** * * * **** *
** ** ** **** ** ** *** ** ** *** ** ****

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
* *** * * * * * * * * * ** * * * ****** *** *** *** * **** * * *** ** ******* * ***** *** ** * *** * * * *** * ** *
* **** * * ** * ***** * ** *** * * ** * ** * ** *** * * *** ** * **** * * * * * * * *** ** ** ** *** * * * * ** **
* ** *** ** *** *** ** * * ** ***** ** ** ** * * * *** *** **** ** * * * * **** *** **** * ** **** ** ** * * * * * ** * ");
** ** *** * **** * *** *** *** ***** ** **** **** * ******* * ** * **** ** * ** * *** ** ** * * **** **** * * ** *** * ** ** *
* * ** *** **** * * ** **** ***** *** *** * * ***** ** * ** * * * **** * * * * * ***** ** *** ** *** * * * *****
* * * * * * * * * * * ** * *** * *** * * ** *** **** **** * *** ** ** ****** ** * ** * ** ** *** **** **** ** * ** *
** * ****** ** * **** * * ** * *** ** ***** * * * ** ** ** * * * ** * ** * * *** ** * **** ** *** ************* * **

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include *** * ** ** ** *

#include * ** * **



int main()

{
* * ** * * * * num, n, p;
* * ***** ***** * *** * ** **** * *** * * &num);
** ** ** ** ***** * ** *** * (n = 0; (2 * n) + 1 <= num; n++)
* **** *** *** *
***** * *** * ** * **** * ***** ***** (p = 0; p <= (num / 2) - n - 1; p++)
* * **** ***** *** *** * * * * ** *** * ****** * * ** * * ** * * **** * ");
* *** ** * **** * * * * ** * ** * * ** (p = 0; p <= (n*2); p++)
* * * * ** * * * ** ** * ******* ** * *** ** *** ** **** * * * ** * *
****** * * ** *** ** ******* **** ** ** * * * *
* ** ** * ** ** * **


** * * * * ** ** * * 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** * **** ** *



int main()

{
* ***** * **** a, b, c;
**** *** ** ***** * * * **** * * *** * *
**** * * ***** * * ***** * c <= a; c+=2)
* * ** * * * **
* * ******* **** *** ** * b <= (a-c)/2; b++)
* * **** * ** *** * * * ** * * * ** ** * ");
* * ** *** * *** * * * **** * * b <= c; b++)
* ******* *** **** ** * * * ****** *** ** * * ** ****
** *** * **** ** **** * *** ** **** * *** *** *
* * ** * ** * *** *
* ** * * * *** * * 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* ** * ** * ** *** a ;
** * * * * * ***** ** i , j ;

    
** ** *** ** ****** * ** * ** ** * &a);


** * ** * * *** **** ** * *** * ***

    {
*** ** ** ** * * ** * ** * *
**** *** ** ** * ****** ******* ** ** * *** * ** ****
* * ** ******* * * * ** **** *
** * ** * * ** ** * ** * * * ***** * ** * * ");  
* ****** **** * ** ** * * ** *
* **** ** ** * * ** * * * **** *** * * ** *** *** ** * ****** * ** * ** * * * * ** * * ** ** *** * * *** * ** * ** ****** ****** ****
* * *** * * ** * * ** ** **
* *** ****** * ** ****** * *** * **** * * * * * * * ** * * *** **** *** **** ** * ** * * * ** * * * * ** * * * ** ******* ** ** ** ** *** **** * * ** **** ** ** *** ** ** * * * * ** * * * * * *** * * * ** ** ** * *
* ***** ** ** **** * * * *


** * ** **** * ** * * ******* ** *
* * ** * * *** ** * * *** * ** ** * * * * * * **** * *

    }

   

    
** * * * * * * ** * **** ** **** *
**** * ** ** ***** ** * *** 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.50
©2016-2025

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 3.7k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 8k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 5.5k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 7.2k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 4.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users