0 like 0 dislike
2.7k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 2.7k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
****** *** ** *

main()

{
*** * ** *** * * i,a,b,c;
** * * ** *** ** * ** * * * * * * * ** * *
* *** * * *** * * *

{
* *** ** * * * *** ** **** *

{
* * *** ** **** * * ***** ");

}
* * ** * * * *** **

{
** * * * ** ** * ***

{
* * * * * * ********* ***** ** * * *

}

}
** * * * * * ********** *** * * * * *



}


**** *** * * *** * ** * * **** * * *
* * *** * * * * ** * 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
**** *** *** * ** ** *** *** &num);
* ** *** * i = 1;i <= num;i=i+2)

   {
* * **** ** * * * * ** * *** * ******* *** *** ** * * * ");
*** * * * ****** *** ** * ** *** **** * * \n");
** * * *** * * *** ** *** ** * ** * ***** k =1;k<=num-(i/2);k++)
* ** * * * *** *** **** * * * ** **
* * * *** * *** *** * ** * * *** * ** * ** *** * ** * ** ");
** *** * * ** * *** * * * * *** **** *
***** * **** ** ****** **** * * ** ** * * * *** ***** * **** * ****
** *** * * *** * *** * ** ** * * *** * * ** j = 1;j <= i;j++)
** ** * * *** * * * *** ** ** *** * **
* * *** * * **** * * ***** ** * * *** * * *** ** ** * ** * * ** ** ***  
** * * * * * ** ** *** *** *** * * ** * ** ***** * ** * *** ** * * ***** * ******* * ** ** * * * * **** * * ****** ****** ** * * * *** * * ***** ** *** * ** *
** ** *** * ** * *

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
* * **** ***** ** a, b, i;
* * * * * * ** ***** ** **** *
**** *** * * **** ** *** * ** ***** *** ** *
*** *** * * **** **** ** ***
* **** * ** * ********* * ** * ** * * ** ** ** **** **** * * * *
** ** * ** **** * *** ** * * ** * * * * ");
* **** *** *** ** * ** * * ** * ** ** * *** * *** *** * *** **** *
** *** ***** ***** * ***** * ***** * * * **** ** * ** ** *
* * * * ** * ** * * **** **** * * * * ** * * **** * *** *
* ** * ** * **** **
** ** * ** ***** * ** ** ** ** ********* * * *
*** ** * * * * ** * **** ***** *** 0;
* *** **** * * *** *
* ** ** ** *** * **** *
****** ** ** *** * *

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
* *** * * * **** *
** ** ** * ***



int * *

{
** a, j, k;
** * *** * ** * *
** = 1;j ** * a / 2 + 1;j ++)

{
* ** ** ** * ** * * = 0;k * ** a / 2 - j +1;k ++)
* * * * * * * **** *** * ** * ****
* * *** * *** *** **** = 0;k * * ** * 2 + 1 ;k ++)
* * *** ** * ** ***** ** * *** * *
* *** * *** * * * ** * ***** * * *** ** **

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include * * *** ***

#include * * * **** *



int main()

{
* * ** * ***** x,y,z;
** * * ** ** ** * ** ** ** *
*** * * * * * *** * = 1;x <= (z+1)/2;x ++)
* *** ***** *
**** * ** ******* * ** ****** * = 1;y <= (z+1)/2 - x;y ++)
**** ***** * *** * ** * * * * * *** *** **** ** * ** * * ");
** * ** *** *** * * ** **** * ** = 1;y <= (x*2)-1 ;y ++)
*** **** * * * ** * *** * * *** *** *** *** * * * ** ** ****** *** * ****
** * * *** ** * * *** ***** * * * *****
** * ** **** ***


* *** ** * ** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include * * * ** *

#include * ** ***



int main()

{

int a, j, k;
*** **** ** *** * *****
** * * / 2+1; j++)

{
** ** ** * * * * a/2 -j +1;k++)
**** * * **** **** *** * *** * * * **
* * * ** * * ** ** * ** * * ** **** * **
*** * * * * * * * ***

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
* * ** * * ** * ** **** *** ** ** * ** * * ******* *** *** *** * * * *** ** * *** * * * ** ** ** ** ** *** * * *
* * * ** ***** ** **** **** * **** * * **** * * * * * ***** *** * * **** ** * **** ** * * ** *** * ** *** * * ** * ****** * **
** ** ** ** ** ******** * * *** * **** * ** ***** * * ** * ** ** ******* * *** * * ** * * * *** ** * * * *** * * ** ");
** * * ** *** ** ** ** ***** ** * ** *** ** * * *** * ** ** ** * ***** * **** * * * **** * ** *** * * ** * * **
* * * ** ****** * ** ** **** ** ** * * ** * * ** *** * **** ** * * ** * * ** ** ** ** *** * * *** * * ** * *
*** *** * ** * * ** * ****** * * ** * * ** *** * ******* * ** * **** * ** * * * * * * *** * *** * * ** * ** ** * *
* * **** * *** ** ** * ** * * * * **** ** * *** **** ***** * * * * ** * ** ** * **** *** ** * * ** ** * * * ***

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include *** * *

#include * ** ** * **



int main()

{
* * * * * * ** ** *** num, n, p;
** **** * ** *** * * * ** *** ** * &num);
* ** * * ** * * ***** (n = 0; (2 * n) + 1 <= num; n++)
*** *** * * * * **
***** ***** * *** * *** * * * * ** * (p = 0; p <= (num / 2) - n - 1; p++)
* * * **** ** ******** * ***** *** *** ** ** * * * *** * ** * * ");
* *** ** ***** * ** * * (p = 0; p <= (n*2); p++)
* ** * **** *** * *** * * ** * * ** * * *** * **** * ** * * * * ** *** ******
**** **** * ** * ****** *** *** * *** * *** * *** *
* ** * * ** ** * * * *** *


******* ** ** ** ******* ** * 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** * ** *** * * *



int main()

{
*** ***** ******* * a, b, c;
** * ** ** * *** * *** * ** **
* *** ** * **** ** ** * * ** c <= a; c+=2)
* * * ** * ***** * **
** ** * * **** ** * ** ** b <= (a-c)/2; b++)
* * ** ** **** **** ** * * * ** * * * * ");
** ** * * ** **** * * ** * *** * * b <= c; b++)
*** * * * * * **** ** * ** ** * * * **** * **
* * ** ** * ** * * * * *** * * **** ** ***
* ** ** ** ** * ** *
*** ** **** * * **** *** 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* ** *** *** *** *** * a ;
* **** ** *** * * * *** *** i , j ;

    
***** * * ******* * * ** ** * ** * &a);


* * ***** * ** ** * ** * * * ** ***

    {
* **** **** * * * * * *
*** * ***** ** * * * *** * ** ** * * *** * * * *
* * * ** * ***** * ** * ** *** * **
* * **** ** *** * **** *** * ** *** * * **** **** ** * ");  
****** * * **** ***** * * ****
** ***** ** ** * **** **** * * * **** ** * * * * ** * ** ***** ** * * ** ******* *** * * ** ** ***** ***** * *** *
* * * * * ** * * * **
*** * ***** **** ** ** ******* ** *** ** ** * * * ** * **** * * **** * ** * ** * * * * ** *** * * ** ***** **** ** * * * * * * ** * * * ***** * ** * * * * ***** ***** * ** ***** ** * * ***** ** * * ***** *
* ** *** ****** ** ** ** **** ** **


**** * ** * ** * * * ** * *
** ****** *** * * ******* *** * *** ** ** **** **** **** ** * ***

    }

   

    
*** ** * ** ** * * * * ** * **** * **
*** * *** ***** * * ****** 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.220
©2016-2025

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 1.6k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 3.5k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 2.6k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 3.3k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users