0 like 0 dislike
946 views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 946 views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
** ******* ** * *

main()

{
* * ***** ** * * *** i,a,b,c;
* * * ********** * * * * ** * ** * * *
* ** * ** *** ** *

{
*** *** ** * ****** * ** ** *

{
* **** ** *** * ***** *** ");

}
** * * * *** ** **

{
*** * ** * * * ** **

{
* * * *** ** ** * * * *** ** ****

}

}
*** ** *** * * *** * ** ** *** *



}


**** * * ** *** * *** **** * ***
** *** *** * * ** 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
*********** * **** * **** *** * ** &num);
** **** **** * ** * i = 1;i <= num;i=i+2)

   {
*** ** * ** ** * * * ** * * * * ** * ***** ** * ");
** *** *** * **** * *** * ** ** ** * * * \n");
* ** ** * **** ***** * ** ** * ** * * k =1;k<=num-(i/2);k++)
** * * **** * * ** ** ** * **
* * * *** * ** * ** ** **** * ** * * ** *** * * ** *** *** ");
* ** * *** ** ********* ** * * *** *
*** * * * * * *** ** ** * ** * ***** * * * *** ** * * ** ******** * *
** * * ** ****** * ** * * **** * ** j = 1;j <= i;j++)
** * ** ** *** * * ** * * ** **
* ** * * * * *** * ** *** * *** ** * * ** ** *** * **** ** * *  
**** ** * * * * * * ** ** *** *** *** ** * ****** ** *** ** *** *** * * ***** * ** * ** *** ** **** ** * ** ** *** ** * * *** **** * ** ** * ****** ** * ***** * *** * *** * **** ** *
****** * ** ** * * *

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
** ** * * ** *** ** * a, b, i;
*** * ** * *** *** ** * ** ** * **** * * *** * *
** ** **** * * * *** **
***** * * *** *** *
**** *** ** * *** ***** * ******** * ** * ***** * * **
*** *** * *** * * * ** * *** ** ** ");
** ** * *** ** *** * * * ** * * ** * **** **** * ****** ** **
*** * * ** * * *** **** **** *** * **** ** * * * **** *
*** * **** **** **** ** ** *** * ** * ** * * ** * ** ** ** * *
** * ** ** **** * * **
* ** * * **** ** ** ** **** **
***** ***** **** **** ** * 0;
** * * ** ** * * ** ***
** *** * ** * *
** * ** ** *

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
* ** * * * * ****
* *** ****** * *



int *

{
* a, j, k;
** ** * *** * ** ***
*** = 1;j ** a / 2 + 1;j ++)

{
** * * ** ** ** **** ** * = 0;k * a / 2 - j +1;k ++)
** ** * ** * ** * * ** ** ******* ** *
******* *** **** *** * * ** = 0;k * * ** * 2 + 1 ;k ++)
* *** * ** * *** ** ** * ** * ** *
** ***** ** * ** **** * * **** *** *** ** * **

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include ** * **

#include * * * * **



int main()

{
* * *** *** **** x,y,z;
*** * ** * ***** *** ** ** * *** *** **
* ** * * **** * ** ** = 1;x <= (z+1)/2;x ++)
* * *** * * *
*** * * **** ** * * * **** *** = 1;y <= (z+1)/2 - x;y ++)
* * *** * * * ****** * * ** ** ** ** * * ** *** ** * ");
**** *** ** * ** ** ** * *** *** ** ** *** * = 1;y <= (x*2)-1 ;y ++)
* * * *** ** * ** ** ** * *** * * ** * ** *** *** *** * * ******* * **
*** ** ** ** * ** * * * * * ** ** * *** **
* * * ** *** *


* ******** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include * * *****

#include ** ** *



int main()

{

int a, j, k;
* * * ** ** * ** * *** ** *
** * *** * / 2+1; j++)

{
** ** * *** * *** * ** * * *** ** * a/2 -j +1;k++)
* * ****** *** ****** *** ****
* ** * * ****** ** ** * ** * ** * **
**** ****** * ** * ** ** ***** * * *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
** * * ** ** * *** *** * ** ** * *** ** ** * * ** ** ** ** *** ** *** ** * * * * ********* ** ******* * *
*** ***** * * * * **** * ** *** * * * * ** ** * ** ***** **** *** ** ******* * ** * * * * * *** * ******** ** *** ***
* * * * * * ** ** * ******* * * *** ** *** ****** ** * * *** ** * *** * * ** * *** * * * ** ** * ** * * * ");
* * * * *** **** ******* *** *** * ** ** ** ******* * * ***** * ** * ******* **** * *** **** ** ** * ** * * * * * * ** ***** * *
** ** ** * *** ** ** * ** ** * * * * * ** ** * * * ** * * ** ** ** *** * * **** * * **** * * * * ** **** * *
*** * **** *** *** * ** ** * * ***** * **** ** * * ** * * ** ** **** * * * * ** **** *** *** ******* * * ** *** * ***** ** * *
**** ***** *** * * * ** *** * ** **** **** * * * * ***** * ** * * ** * ** ** * ***** * * * ** * ***

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include *** * * * **

#include ** * * *** *



int main()

{
*** * ** *** * * * * num, n, p;
* * ** ** ** *** * * * * * * &num);
* * ******** *** * ***** * (n = 0; (2 * n) + 1 <= num; n++)
* * *** * * * *
*** * ** * ** * * *** **** ** ** * * * (p = 0; p <= (num / 2) - n - 1; p++)
*** * ** * ** * * **** * * ** * * * ** ** ** * * **** ***** * ** ** * ");
** ** ** ***** * * ** *** ** ** * * * ** * ** (p = 0; p <= (n*2); p++)
* ** ** * ****** ** ****** * * ** * ** ** * ** * ** ***** ** * * *
* * * * ** * * * ****** ** * ***** *** *** * * *** ** * * *
* * * * * * *


** * *** **** * * 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** ** * * *** **



int main()

{
* **** ** ** ***** * * ** ** a, b, c;
** ** ** * ** * **** * ****** ** *
**** **** ****** ** ** * c <= a; c+=2)
* **** ** ** * * *
* * * *** ***** * * * b <= (a-c)/2; b++)
** *** * ** ** ** * ** * * *** * *** * * * ");
*** * * *** ** * * ****** *** *** * b <= c; b++)
** * * ** *** ** * ** *** **** * * * * * * * *****
* ** * ** ** * * ** * * ** * * ** *** * *
* ** *** * ** ** ** **
** * ** * *** * ** *** ** * 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* * *** * ** * *** *** ** ***** a ;
*** *** ***** * ** ** ** * i , j ;

    
* * * ** ** *** ** *** **** * * * ** &a);


* ****** ** ** * * * ** *** * * *

    {
* * * * ** ** * ** *
** * * ** * ** *** **** * * * ** * *** *
** ** *** **** ***** * *
** * ** * ** * ** ******* ** ** * ******* * * * * * ");  
* * * ***** ** ** ** * *
** * * ***** * * * *** * * * * * ** ** **** * ** *** * ** *** ***** * ** ** * * * ** ** * * *** **** **** * ** * * * * * ***
** *** * ** ** ** *** * ** *** ** *****
** ** ** *** *** * ** ** * *** * * ** ** * * * ** ** **** *** **** ** * * *** ****** * * ***** ** ** * * * * *** *** * * * * ********** * *** * * * ** * **** *** * *** * ** **** *** * ** * ** * ** * ** * **** *
* * * *** ** * ** * ** ** * ***


***** ** ** * ** * ** * ** * *
* ** ** * *** *** * * ** * * ** * * * * ** ** * ** ** **

    }

   

    
**** * * **** *** * ** * * *** * * *
* * * ** * *** * * * * * * * 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.184
©2016-2024

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 497 views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 1.2k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 1k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 1.1k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 710 views
12,783 questions
183,443 answers
172,219 comments
4,824 users