0 like 0 dislike
6.1k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 6.1k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** * * * ** **

main()

{
** *** * * **** ******* i,a,b,c;
* *** * * * * * * * * * *** *** *
** ****** ** *** *** * ****

{
*** * * ** * ****** * ** ** ** *

{
* ** * ** * * * * * * * ");

}
* * * *** * * ***** *

{
* **** * * ** **** ** ** * * ***

{
** *** * * * **** ** ** * * *

}

}
* *** * * *** * ***** * * * *** **



}


* ***** * ***** ******** **** ** ****
* **** ** ** * * ** * * 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
* * * **** ** **** ** * &num);
** * ** * * * i = 1;i <= num;i=i+2)

   {
** ** ** *** *** **** * * ** * * * * *** ");
** * * **** *** * *** * * ***** * **** \n");
*** **** * * *** ** ** * ** *** ********* k =1;k<=num-(i/2);k++)
**** ** * ** *** **** * * * ** *******
** ** * ** ** * ** * **** * * * ***** * * *** ** * ** * * * * ** ");
* * ** *** * *********** ** ** ***
*** * ** * ** ** ** ** ** ***** * *** * ***** ** * * **** ** * * ***
* *** ** ** *** ** * * * ** ****** ** ** * * * j = 1;j <= i;j++)
* **** * * * * ** *** *** * * * * *
*** * ** **** * ******* * * *** * ** * ****** **** * * * ** * **  
* **** * * ***** * ** * *** * * *** ** ****** * * * ** *** * * **** * * * ** ** ** * **** ** * ** * ** * * * ** * * ** ** * * * * ** * * *** ** *** ** ** * * **
* ** * * * * *

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
* ** * * *** *** ** a, b, i;
*** *** * ** * * * ** * * ** * ** ** * *
** **** ** * * * ***** * *** * * **
* ** * * * **** *
** ** ** *** ** * ** ** * * * ** * ** * * *** *** * *
*** * * ** * * * * * *** *** *** * * ** ** * * * ");
*** ** * ***** *** * * * * * * * * * ** ** ** *
* * * * * * *** * *** * ** *** *** * * ** *** **
* * *** ***** ** * ** ** * * ** * * * ** * ** * *
* * * * ** * * * *
* ** * *** ** * * ***** * ** ** ***
*** * * * * * * ** * * 0;
* * ******* * *** * *
* * ***** * ** *** * ** *
*** * *** * ** * * *

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
*** * ** *
** * * * * * **



int * **

{
** a, j, k;
* * *** * * *
* * = 1;j ***** * a / 2 + 1;j ++)

{
* ** *** * * *** * *** = 0;k ** a / 2 - j +1;k ++)
* ***** * * * * *** ** * *** *** * * * *
** * **** ** *** * * * = 0;k * * ** * 2 + 1 ;k ++)
* * * ** * * * * *** ** * ** * **
** * * **** *** *** *** ** *** **

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include * * * **

#include * ** *** * **



int main()

{
* * ** ****** x,y,z;
* * **** ** ** * * * * ** ** ** *** *
** * ****** ** ** = 1;x <= (z+1)/2;x ++)
* * * * * * **
* ** * ******** **** *** *** = 1;y <= (z+1)/2 - x;y ++)
** * * * ** ****** ** * * * ** * * ** ** ** * **** ");
* ** ******* ** ** * * *** * = 1;y <= (x*2)-1 ;y ++)
* * ** * ** **** ** ** ** **** *** *** * ** * *** * * * ******* *
* * * * * ** * ** * * * *** * * * ****** **
** ** * *** **


* ** * * ** ** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include ** * ** * ** *

#include ***** *** ** **



int main()

{

int a, j, k;
** **** *** * * * *
* **** ** * / 2+1; j++)

{
* * ** * ***** * ** * * * a/2 -j +1;k++)
* **** *** * ** ** *** ** ** * * ***
*** ** ** * ** **** * * ** ** * **
* ** * ** * **** * ** * * * **

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
* * * *** *** *** * **** * * * ********* ** ** * * * * ** * * * *** ** ***** * * *** * * ** * *
* ** * ** ******** * **** * ***** ** ****** ** **** * * *** * ** * ** ** * ** ** * * **** * * * ** * ** * * * * **** * ***
** * * * * **** * **** * ** * * ****** * *** ** ** * *** * ** ** *** ** * * ** ** ************ * * * **** * ******* * * ");
** ** * * * ** * ** * ********* ****** ****** ** * *** * ** * * ***** * * ** *** **** ** *** * ** * * ****** ** * * * * * * *
*** * * *** *** ** ***** **** * * *** ** ** ** * * ** * * ***** ****** * * * * ******* * * * * * * * ** * ** * ** **
** * ***** ******* * * ** * ** *** * ** ** * *** * * * * * * * * * * * * **** * * ** * * ***** ***** * * * * ***
***** * ** * * ** * ** *** ** ***** * ** ****** * * ******** * * * *** ** * ** ***** * * ** ** * ** *

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include *** * * ****

#include * * * ********



int main()

{
* *** ** * ** ** **** num, n, p;
* * *** * * **** * * * * * * * ******* &num);
**** *** ***** **** * ** * (n = 0; (2 * n) + 1 <= num; n++)
* *** * **** ***** *** **
* ** * *** * * **** * ** ** ** * **** ** * ** * (p = 0; p <= (num / 2) - n - 1; p++)
* * ** * ** * *** ** ** * * ** * * * *** * *** *** * **** *** ** ");
** *** * * * ** * * * * * ** *** ** ** ****** (p = 0; p <= (n*2); p++)
** *** ** *** *** ** * * * * * * ** * * * * *** * * *** * **** *** *** *
* * *** * * *** ** * * ** *** ** **** * **
* * * ** ** *


* ******* *** * * * ** * * * 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** *** * * * ***



int main()

{
***** * ** *** * * * a, b, c;
** * * * * * **** *** ** ** ********
* * * **** * * * ** c <= a; c+=2)
** ****** ** * ** *
* * *** ** * **** ** b <= (a-c)/2; b++)
* * ** ** * * * * * ** * ** **** * * ** ** * ");
* * *** ** * * * * ***** *** ** ** b <= c; b++)
* * * ***** * * * ** * ** * * * * ** **
** * ** * *** ** ** ** * *** * * * *** ***** **
* ** ** *** **** * *
* *** * * ****** ** ** * * * ** * 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* * ** * * ** ** ** * a ;
* ***** *** ** i , j ;

    
* ** ** * ** *** *** * ** ** * * ** ** * &a);


* * *** *** * **** * * * * * * * * ** * *

    {
** ******* * * **** ** ****
**** ** ** * * *** **** * * **** ** *** * **
** ** ** * ***** **
* **** * * * * *** *** * ** * * * * * * ** * ");  
* * * * * * * ** *** ** * * ***** *
* ** **** ** * * * ** * * * * * *** ***** * ******* ** * * * ** ** ********** * ***** * ******** **** * ***** * * *
** **** * * * * ** * ** *
* ** ** * ** * * * * *** ****** **** **** * * * ** ** **** ** * * ** * **** * *** * * * * * ** ** ** * **** * * * *** * * *** ** *** ** ** * *** ** * ***** *** ** *** *** ***** * * ** ** * ** * * *** ****
* * * ** ** * ** * * * *** * * *


* ** ** ** ***** * * * *
** *** ** *** ***** ** ** * * * * * ** * ** ******* ** * **

    }

   

    
**** * * ** ** * * ** * ****** * ** **
* ******** * * ** * ** * 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.92
©2016-2025

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 3.7k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 8k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 5.5k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 7.2k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 4.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users