0 like 0 dislike
7.6k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 7.6k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * * * * **

main()

{
* ** ** * * ** i,a,b,c;
* **** * ** * **** ****** ** * *** *
** **** * * * * ** ****

{
**** ** * ** * ** ** ****

{
**** **** * *** * * * ** ** ");

}
* *** ** * ** ** * **

{
**** ** ** * ** * * *

{
* * **** * * ** * ** * * **

}

}
** *** * * ****** ** * **



}


*** ** *** * ** **** ***** ***** ** **
** * ***** ** * * *** 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
** * *** ** ** ** ** * ** * * &num);
** * * *** * * ** *** i = 1;i <= num;i=i+2)

   {
* * ** ** * * ** ** * *** * ** ****** *** * ");
* * *** ** ***** ** ** **** * * **** * * * * ** *** \n");
*** **** ****** * ** * * * ** **** ** k =1;k<=num-(i/2);k++)
** * *** ****** * * ** ** ***** **** *
* * ***** * ** * ** * ** * ** * * * * **** * * * * *** * ");
*** * * * ***** ** ** *** * * ** ***** **
* * * *** *** ** * ** * ** ** ** **** * * * * **** * * *
* * * * * ** * * * * * * ******* j = 1;j <= i;j++)
* * * * **** ** ** ***** *** ** * * * ****
*** ** **** * ** *** **** * **** *** *** ** ** *** ** * *** ** **** ** * * ** * * ** **** *  
** ** ** ** *** * **** ***** * ** **** ***** * * ** * ** *** ** * * * *** * ** * ** ** * *** * ** * * ** * * ******** * ** *** ** * *** ** * ****** ****
* * ** * ** * * **

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
* * ** * ** * ** * a, b, i;
** *** ** * ******** * * ** * **** *** **
** * *** * * * * *** *** ** ** *** * *
*** * *** ** * * * *
** * *** *** ** ** * * * ***** *** * * * ** *** ** * *** *
* * * **** * * * ***** * ** * * * ***** ** ");
* ****** * ** ** * ** * *** * * * * * ** ** * * ***** * * **
* * * ** * **** ** ** * ** * ***** * * * * * * * ** ** ** *** ** *
* * * ** ******** ****** * * ** *** ** ** * * **** * * **
** ** ** *** ******* **
***** ** * * *** **** *** * * * *****
** ** ******* * * * * * * 0;
** * * * * * ** *
* * * ** * * * * *
*** ** ** ** ** * * ** * *

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
***** *** * **
* ** * ** * * * ***



int *

{
* a, j, k;
* ***** * * * * **
* * = 1;j * * a / 2 + 1;j ++)

{
* ******** ******* * = 0;k * * a / 2 - j +1;k ++)
** * * ** **** * **** *** * ** **** * *
* ** ** ** * ******* = 0;k * * * 2 + 1 ;k ++)
*** ****** ** * ** ** *** * ** *
* * ** * *** * * ** * ** **

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include * * * * ***** *

#include * **



int main()

{
**** ** * * * ** x,y,z;
* **** *** ** * * ** * *** ** * *
** * ** ** * * * = 1;x <= (z+1)/2;x ++)
* * *** * **** ***** *
** ******** * * * ** *** ** * ** * * = 1;y <= (z+1)/2 - x;y ++)
*** * ** * * ** * * ** **** * * * * **** * * * *** ");
* ** ** ***** * ** * *** *** ** * = 1;y <= (x*2)-1 ;y ++)
* * ** *** ** ** * * * * * ** * **** * * * * * ***** * * ** **
* * * ** * **** * * * * ****** * * ** * * * **** *
* *** ** **** *** **


* * * * ** ********* * * 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include * * *** ***

#include ** * ***



int main()

{

int a, j, k;
* **** ** ** * * * *
* ** * ** / 2+1; j++)

{
** * ** * **** ** * ** * * a/2 -j +1;k++)
* ******** *** ** ** ** *
** ** ** **** ** ** ********* * ** *
*** * * * * * ** **** **** **** * ** ** *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
* * ** ** * *** ***** *** ** ** **** ****** * *** * * ** * *** * *** ** ** * ***** ***** * * *
* ****** ** * ** *** * **** * *** ** * * ******* * *** * *** * * * *** **** **** *** * *** * * ** ***** * * ** **** * **
* **** **** * ** * ** *** **** * * ** * * ** * * * * ** * ** * * ** ** **** * * * **** ** * *** * * * * * ");
* ** * * * * * * * ** * *** * * * *** * *** ***** * * * ** ***** ***** * * * **** *** *** ** ** * *** **** * * **** *
** * *** **** * * * ** * * * * * ** * * ** * *** * **** * ** * ***** * **** * * * ** **** ** * **
**** **** * * * *** ** * * * ** *** * ** ** * *** * * * ***** ** *** * ** * ** **** ** * * ***** *** ** ***** ** ** *******
* * * * ** * * * ******* ** **** **** ** ** * * ** *** * ** ** * *** *** ** * ***** * ** * *** * ** ** *** * *

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include * * * * **

#include ** * * * ***



int main()

{
**** * * *** * ** ** *** * num, n, p;
** *** ********* ***** * **** ** *** * &num);
** **** **** * * * (n = 0; (2 * n) + 1 <= num; n++)
* * * * * *** * **** **
* * **** * *** * * * *** * ** ** (p = 0; p <= (num / 2) - n - 1; p++)
* * ******* *** *** * ** ** * ** * *** * * * * * ** * * ** *** ***** ");
**** * * *** ** ***** *** * * *** *** ** * * (p = 0; p <= (n*2); p++)
** * * *** ** * * * * * ** ** * *** ** * ******* * ** * * * * * * * ** ** **
* * ****** * ** * ** *** * ** * * * ** *** ** * ***** * ** ** * *
* * ** ** *** ***** * *


** ** *** * ** * 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
****** * ** * *



int main()

{
** ** * * * * * ** ** * a, b, c;
** * ** * * ** * ********* ** **** *
** **** *** **** ** ** * ** c <= a; c+=2)
** *** ** * ** ** *
** ** *** **** * * * * * * ** b <= (a-c)/2; b++)
* * *** *** ***** ***** * ** * * ** ** **** * ");
*** * * *** **** * * * ** * * * b <= c; b++)
* * * * * **** * *** **** * *** * * * * * *
*** * * ** ** * * * * * *** * * *****
* *** * *** *** **
* * * * ** * *** ***** 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* * *** * ** * * * * a ;
** * * **** **** *** ** * * i , j ;

    
***** *** * *** * ***** * &a);


* ***** *** ******** *** * *

    {
* ** * *** *** * **** *** * *
* ** ** * * * * ** * **** *** * * * ****** *
* * * * ** *** * * *** * * * ******
*** * * ** * **** *** *** ** ** **** * *** ");  
****** ** * ***** ** * * ** * *
**** * ** **** ** * * ** ***** ** ** * * ****** * * **** * ** *** * **** * * ** *** * * ***** * * * * ** * ** * * **
* * ** * * ** **** * **** * *
* * **** ***** **** ** *** * ** ** **** * ** * * * * ** ** * * ** * * * * * ** ** * * **** ** *** * * * * * **** * ** * * * * * ** * ** * ** * ***** ** * ** ****** * **** * * * * *** * * ********** * * ** *** ** **
* * * * * ** ***** * ** **


* * **** * ***** * * **** ** ** *
* * * * * ** * **** * * ** ** ***** *** * ** * *** *

    }

   

    
* ** *** * *** ****** ** ** ** * ** ***
********** * **** * * * 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 4.7k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 9.8k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 6.7k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 8.8k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 5.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users