0 like 0 dislike
5.1k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 5.1k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
************* *

main()

{
* *** *** i,a,b,c;
** * ** ** ** ** ** * * * *** ** ** * *
* * ** ** ** * * *** ** ** *

{
* ** *** * ** ** ** ** *** *

{
* ** * * * * ** * *** ");

}
** ** * *** * ** * ***

{
*** ** * ** * * * * ** **** *

{
* * ****** ** * * ** **

}

}
* * * * * ***** * ** ** * * * *



}


** *** ** ** ** * ** * ** *
**** ** *** * * *** * 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
**** * ** * * * * * * ***** ** &num);
* ** * ** * ** * i = 1;i <= num;i=i+2)

   {
** ** **** * * ***** * ** * *** * * *** ** *** ");
** * * * * ** * * ** ** ** *** ** * * ** * ** \n");
*** * *** ** * ** ** ** * ** * * ** * ** k =1;k<=num-(i/2);k++)
*** ******* * * * *** ** ** *
** ** ** * **** *** ** ***** ** * ** ** * ** * * *** **** ****** ");
* * *** ** ** * ** ** ** * **** ** * *
******* * *** ** * ** * ** * * ** * ** * * * * ***** * *
* ** *** * ** **** **** ***** * ** * ** j = 1;j <= i;j++)
* * * * ** * ** * ***** *** ****** * * * * *
* * *** *** * * **** ** * * *** * ** * * * *** * *** ** * * * ** ** *** *  
* ** ** * ** ** * * * *** * ** * ** ***** * * * *** ** **** * * ** * *** ** * * * * **** * * ** ** ******* * * ** **** ** ** *** ** *** *** * ** * ** ** *** **** **** * ***
** ** *** * * **

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
*** * ** * **** ** * a, b, i;
** **** * ** * ** *** * ** * *** ***
* * *** *** * ** *** * *** * * **
** * ********* ** * ** *
** ** *** * * * * * ** ** * ** ** *** *** * ** ****
* *** ** * ** **** *** * *** * * ***** ****** ** * * ** ");
* ** *** ** * ** * * ** ** * * ** ** **** * * ** **
** ** * * ** * * * *** * **** * * * ** * *** *
* ***** ** * ** * * * * ******** ** ** * * ** ** * * ***** ** *
****** *** * ** * * *
*** *** ** * *** *** * * ****
** *** ** ** * * * 0;
***** ** * * * *
* ** * * ** * *** ** *
** ******* * * ** * *

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
** ***** * *
* * ** * *



int *

{
* a, j, k;
* * * * * ** * * ** *
* = 1;j ** ** a / 2 + 1;j ++)

{
*** * * * **** *** ** * = 0;k a / 2 - j +1;k ++)
** ***** * * ***** * ** * *
***** * * * * *** = 0;k ** * * 2 + 1 ;k ++)
*** ** ************ *** * *** * ******** *
* ** * * * * ** * **** * *** * *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include ** * ****** * *

#include * *** ******



int main()

{
* * * ******* ** x,y,z;
* *** ** ** ** *** * * * ***** * * *
* ** ** ****** ** * = 1;x <= (z+1)/2;x ++)
**** * * * *
*** * **** * * *** * * *** ** *** = 1;y <= (z+1)/2 - x;y ++)
* * *** ** ** * * *** * * ** * * * * * ** * ** ");
** ** *** *** * * **** = 1;y <= (x*2)-1 ;y ++)
** * * * *** *** **** * *** * * *** ******* * ** *** * *
* * * *** * * * * **** * * ** * ******
*** * * ** *


*** ** ** * ** * 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include * * * *** *

#include ** ** * ****



int main()

{

int a, j, k;
** * * * ** ** *
**** * * * **** / 2+1; j++)

{
** * * **** ** * *** * * * a/2 -j +1;k++)
* * ** **** * * *** * * *** * *
** ** * ** * *** * ***** ** * * *
** * * * *** ******* ** ** *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
* ** * * * * * ** ** * ** * ** * * ** * * ** * ** *** * * ** * *** * * *** * *** * **** **** * * * ** * *
** ** * * *** * *** * ** * * ** * ** * ** *** ** * **** * ** ** * ** * * ** ** * * ***** ** *** * * *** * ** ** ** * *
* * ** * **** ***** ** ** * * *** * * * ** *** * ******** *** * ****** *** ** * * ** **** **** * * * * * ** * ");
** ** * * ** * ** *** * *** * * * ** *** * *** * **** ** * * ** ** ** *** * ** * *** ***** * * * *** * * * * * *** * *** * ** * *
*** *** **** * ** * **** *** ** * ***** *** * * * **** *** **** **** **** ** ******* * ***** ** ** * * ** ** * ***** *** * *** *
* ** * ** **** ** ** * ** * ** *** * ** * ** * ** ***** ** *** **** ** * *** ** ** * * * ** ** * * * * * * *** * ** *** *** ** **
** * * * *** ***** * * ****** ** ** ** * ** * * * * * *** * **** * * * ** * ** * ******** * ** *** * ** * * ***

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include ** * * * * *

#include **** ** ** ** **



int main()

{
** * * *** ** * * num, n, p;
* * * *** ** **** *** * * ****** * * *** &num);
***** ** *** * * * * * (n = 0; (2 * n) + 1 <= num; n++)
* ** *** *** * * * **
** ** **** ** * *** * * ******* ** *** * (p = 0; p <= (num / 2) - n - 1; p++)
**** ** **** * * ** ***** * ** **** ** ** *** *** * * * * * ** ** ** ");
*** * ** *** ** * * * ** * **** ** ** ** ** (p = 0; p <= (n*2); p++)
* **** * * ** ** ** * * ** * ******* *** ** **** * * ** * * *** *** ***
* * * * * ** *** ** ** ** ** ** * ** ******** **** ** * ** *** *
* ** * *** ** *** *** * * **


*** * * *** ** * ** * 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** * ******



int main()

{
* ** * * * ** * *** * a, b, c;
* * * * *** *** * ** ** * * ** ** * **
**** * ***** *** c <= a; c+=2)
** ** ** *** * ** *
*** * **** * ** ***** *** **** * ** * b <= (a-c)/2; b++)
* ** * * ** * *** ** * ** * * * ****** * ** * ");
*** ** ******* ****** * b <= c; b++)
** * ****** * * ** *** ** **** *** * * * * *** *
*** * **** ** * *** * * ** ** * * * ** ***
* **** * *** ** * **
** * * ** ******** ** 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* ** ** ****** * ** a ;
*** * **** * ** * * i , j ;

    
* ** * *** * *** * * * **** * * ** &a);


* *** * * ** ** * * ** ***** *

    {
* * *** *** * * * * * *
* **** ** * **** ** *********** * *** ** *** * * *
* **** * * *** * *** * * ****
*** ** * * * ** **** ** ** * * ** * * ");  
** ** * * * **** * * * *** **
** * ********* ** ** ** ****** ***** * **** * **** ** * ****** **** ****** ** * ** * * *** ** **** *** ** ** * *
* **** *** ** **** ***** ***
* ** ** * ** * * * ** ** **** *** * * **** * *** * * ***** **** * **** ** * *** **** *** * * * ***** ** ** ** * * ** ** * ****** * ***** *** * * ** ** * ** * ** ** * ** * * ******* ***** * * * * * * * **** ** ** ** * * * ** ***
** * * * ** * ** * ** * **


** * * ** **** * * ***** * ** *
* **** * * * ** *** **** * * * * ** * * **** * * *** * *

    }

   

    
* * * * * * * * * * * * ** ** *
** * * * ** * *** * * * 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.185
©2016-2025

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 3.1k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 6.7k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 4.5k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 6k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 3.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users