0 like 0 dislike
6.1k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 6.1k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ** ** * * *

main()

{
* ** **** ** * * i,a,b,c;
* ** ** ** * ***** **** ***** * ** **
* * * *** * * * * ** * *** *

{
** ** * * * *** * ** * **

{
* * * **** **** *** * *** **** ");

}
* * ** *** ***

{
**** *** * **** ** *** * * ***** *

{
* * ** *** *** * * ** ** * *

}

}
** * *** **** ** **** * ** *** ***



}


** ** *** * * ** *** * ** ** * ****
* * * ** **** 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
** ** ** *** *** ** ******** &num);
* * * ** ******* * **** i = 1;i <= num;i=i+2)

   {
** ***** ***** ** * * * * ********** ** * * ** ");
**** * ** * **** * *** ** *** * ** * ** ** * \n");
*** * ** * *** * *** * * **** ** **** * ** k =1;k<=num-(i/2);k++)
** * ****** ** * * * ** *** ** **
** ** * * *** * ** **** * ** ** * * *** * * *** * * ** ** ** ** * ");
**** *** * * ** ** ** * *** ** ** * **
* *** * * * * ** ** ** * * ** ** * ** * * * ** ** * ****
* * * *** * * ******** * * ** *** j = 1;j <= i;j++)
*** * ** * ** ** * *** ** * * * ** * *
** ** ** * * * ** ******* * * ****** * ** * * * * * ** ** *** * * *  
*** **** * * * ** **** ** **** ******** * * * * ** *** * * * ** * * * * ****** ** * ** * *** **** *** ** * * ** * ** * * * ** * **** * * * *****
* * * *** ** *******

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
**** * ****** * ** *** ** * a, b, i;
* ** * * * * * ** ****** *** * ***
* ** ** *** * * ***** * * * * ** *
**** ** * * ** * ******** *
** ** * **** * * * * * ** * ** ** ** * ** * * *** ** * *
* * * ** * ** *** * * * ********* * ** * * ** * *** ");
* * ** *** * * ** ** ******* * ** * * * * ** * *** ** *** ****
** ** * ** *** ** * *** ** * * ** * ** ******** * *
** * * * * * ** * * * **** * **** * * * * ** **** *
* * * ** ***** * * * * ** *
* ** ** * ** * ** *** ** ** * *
** ** *** ** ** * ** ** * 0;
****** ***** * ** ** * *
** *** ** * * ** ***
** * ** ** ** * ***** * * *

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
** * * * ** *
*** ** * **** *



int **

{
** a, j, k;
** * * ** ** *
*** = 1;j ** a / 2 + 1;j ++)

{
* ** *** * ** ** **** ** = 0;k ** *** a / 2 - j +1;k ++)
*** * ** ** * **** * * * * * *** * * *
* * *** ** * * * * * = 0;k * ** * 2 + 1 ;k ++)
* ** ** * * ** **** * * ****** *** ****
*** ** ****** * ** * ** * ** ** ******

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include ** ** ***

#include *** ** * ** *



int main()

{
** ****** *** ** * x,y,z;
********* * ** * ** ** *** * * * * ***
*** * ** * * * * = 1;x <= (z+1)/2;x ++)
* * * ** * * *
** ***** *** * * ** * * ** ** ** = 1;y <= (z+1)/2 - x;y ++)
* ***** ***** **** ** ** * * * **** ** * ** * *** * *** ** ");
**** * * ** *** ****** * * ** **** ** = 1;y <= (x*2)-1 ;y ++)
**** * ** **** * * **** *** ****** * * ** ** **** **** * ******
** * * ***** * * **** * * *** * * * ** *** * * *****
** * * ***


** ** * *** * 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include ****** ** *

#include ** ** ** * *



int main()

{

int a, j, k;
* *** ******* * *** **
* *** / 2+1; j++)

{
* ** * * * *** ** ** **** a/2 -j +1;k++)
*** ****** ******** ***** ** * * *** ** ** * **
** ** * ** *** **** * *** ** ** *
* ****** ** ******* * * * ****** ** **

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
*** **** ** ** * * * * * ** ** ** ** * ***** * * ** *** * * * ** ** * * *** ** ** * * * ** * * *
* * **** * * *** * **** * * * *** * * ** ** * * * ***** ** ** ** * ** ** * * * ** ** * * * *** ****** **** ***
* * * *** **** * ** * *** *** * ****** **** * * ** * * * ** * * *** * * **** **** ***** ** **** ** *** ** ** ");
*** *** ** ** * * **** ** * ** ** * * * ** ** *** ** * * ** * * ** * ** *** * * * ** * **** *** * **** * * * * ***** * *** *
** * *** ******* * ***** * * **** ** ** * ** ** **** * *** *** * * * * ** * *** ** ***** *** * *** *** * *** * ** * * * ** *
* * *** * ** * * ** *** ** ** ** *** * * * * * *** **** **** **** * ****** ** * * ********** * * ** ** * * * **** * ** * * *** *
* ** ** *** **** * * ** ********* *** ***** ** * * * * * ** * ** ***** *** * * * **** **** * ** *

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include * * *********

#include ** ** * ***



int main()

{
* ** * ** **** ***** num, n, p;
** * ** ****** ** *** * * *** *** &num);
*** * * * ** ** * * * (n = 0; (2 * n) + 1 <= num; n++)
*** * ******** * ***
* * * *** **** * * **** ** ** * * * * * ** * ** (p = 0; p <= (num / 2) - n - 1; p++)
**** * * **** ** **** *** ** * *** ***** ** **** ** * * * *** * ");
* * ** * ** * ** * ** * *** * * ** (p = 0; p <= (n*2); p++)
** ** * ** * * ** * * ** ****** * * ** * * * * **** * *
* * *** ** * * ** ** * * ******** * * ** * * * *
***** ** * *** * * *** *


** **** ** * * * * * * * ** 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
********* * ****



int main()

{
** **** * ** * ** * * a, b, c;
* * *** ** * ** * **** * ** *** ***** **
* * *** *** ** *** * *** * c <= a; c+=2)
*** * ** * *** ** * *** *
** * ** *** ** * * ** * ** b <= (a-c)/2; b++)
* ** ***** **** * * **** ** ** * ** * *** ** * * ");
***** **** * ** ** *** ** ** * * * b <= c; b++)
* ** * * *** * ** * * ** * * * * * * * ***** **
***** ***** ****** * *** * *** **** **** ** *** *** *****
* ** ** * * * * * * **
* *** *** ** *** ** *** 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* * ***** ** ** ** a ;
** ** *** * *** *** ** ** i , j ;

    
* * * *** * ** ****** * *** * * ** * &a);


* * * * ** **** ** ** * ** *** * ** ***

    {
* ******* * *** ** ** * **** *
*** * * * ** *** * ** ** * * *** ** * ** * *
** **** ** * ** *** ***** * *
*** ****** * * *** ** ** * ** ****** * ** ** * ");  
*** * * *** *** * ** ** * *** * * **
*** * * ** *** * * ** ** ** * **** * ** ******* ** * * * * * ** * *** ** * **** * ** ****** * * ****** ** ****** * *
******** * * * ** * * ***** *** *
*** ** ***** ***** * * * *** * ** * ****** * ** * * * *** ** * ** *** ****** ** * ****** **** * * *** * * * ** ** *** ** **** ** ***** *** *** ** ** ** * ** * * ***** **** ******** ** ** * * * ** **** * * ** ** *** * * * ** * * *** * *
***** *** * * *** * * * ** ** *


* **** *** *** * ** ** ** ** * *
* * ** * ** * ** ** * * *** * * ** ***** *** * *** **** *

    }

   

    
* * * ** **** ** *** * ** * *** * * **
** * * ** * *** * ** 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.97
©2016-2025

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 3.7k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 8k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 5.5k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 7.2k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 4.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users