0 like 0 dislike
7.1k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 7.1k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
*** **** ** * *

main()

{
* ** * **** i,a,b,c;
** ** *** ** *** **** ***** * * *
* ** **** * * *** ** **

{
** * ** * * ** ** ***

{
**** ** * **** ** * ** *** ");

}
*** **** **** * ***** ****

{
** * * * ** ******* * * ****

{
* * *** ** ******** * * * ***

}

}
****** * * ***** ** * ***



}


** ** * ** * * ** * ** ** * * * * **
** ** * * * 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
******* * *** ** ** * *** *** ** * &num);
* ** *** * ** i = 1;i <= num;i=i+2)

   {
** * * ****** ** * * * * * *** * * **** * * * ");
* *** ** ** * **** * * ***** **** ** ** ** * **** \n");
* * * * ** **** *** *** *** * * k =1;k<=num-(i/2);k++)
*** * * ** ***** * ** ** ** * *** ******
* * * * ****** ********* ** *** * ** ** ***** ** * * * *** ** ");
* * ** * ** *** * ****** **** ** ** *
* * ** * ** * ** * *** ** * * ** * * **** ** * * ****** *** * * *
*** *** * * *** ** * * * ***** * * *** ** j = 1;j <= i;j++)
**** * ** ******* *** * * ** ****
** *** * * **** * **** * * * ** * * * * ** * * * * ** ***  
** * * *** *** * ***** ********** * ** * * *** ** * ** * * * * * ** * * * * ** * * * * * ** ****** * * ***** * ** * ** ** ** * * *** * ** * * * **** ********** * * ** ******
***** **** * **** ***

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
** * ** **** * * * ** ** * a, b, i;
** * ** ** * * * * ** * * ** * * * * * * * *
* *** * * * ** **** * ***** * **** *
** * * **** * * * *
**** * ** ** * * *** ** * * * * ** * * * ** ** ** * *
*** * * ** * * ** *** * * * * * ** * ** * ** ");
** * * ** *** * * * * ********** **** * * ** * * ** * * * **
* ** * * * * * * * * * **** ** * ** ** ** *** * ** * ***** ** *
***** * * *** *** *** * * ** ** **** * ** * * *** * **** *
* *** ** * ** **** **
* ** * ** * ***** * * * * ** * *** ***
*** * *** ** * 0;
* *** ** * *** * ** *
** ** * *** * *** *
**** * * ** * **

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
**** * *** * ** *
** ****** ***



int * **

{
* a, j, k;
** * ** * * * ** * **
= 1;j ** * a / 2 + 1;j ++)

{
***** ** * * ** * *** * * ** = 0;k *** a / 2 - j +1;k ++)
*** * ***** ***** *** * ** * * * **
****** ** ** **** * * = 0;k *** * * 2 + 1 ;k ++)
* * * *** * ** *** *** * * ** * * ***
* * ** ** ***** * *** * ** ** * *******

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include * ** *** ***

#include *** * * *** **



int main()

{
**** *** * * ** x,y,z;
* * * * * ** * * ** **
* * ** ** * * = 1;x <= (z+1)/2;x ++)
** ******* * *
** * * * * * * * ** ** * *** ** ** ** ** = 1;y <= (z+1)/2 - x;y ++)
* ** *** *** ** ** ** *** * * *** * * * ** * * * * * ** * ");
* *** * *** **** * **** * *** ** = 1;y <= (x*2)-1 ;y ++)
**** * * *** * * * **** ** ** ** * ** ** * * * ** * * *****
** * *** * * ***** * * *** * * **** *** *** *
* **** ** * ** ** *


* * * ** * ** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include * ** * ****

#include ** * ** * **



int main()

{

int a, j, k;
***** * ** * * **
* ** * * ** / 2+1; j++)

{
****** ** * *** ** ** ** *** * a/2 -j +1;k++)
* * * * * **** * *** * * * * *
***** * ** *** *** * * ** * * *****
* ** * * * * * * * ** * ** *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
**** **** * ******* *** ** * * ** *** ** * **** *** *** * ** *** * * * * * * ** * * * ** * * * *** *** **
** * **** * * * ** * * ** *** * * * * *** * * * *** **** ** * ** ** *** * ** * * ** * * ** ***** * * * * ** *** *
****** * *** * *** * * ** * *** * * ** * * * ** ** * ** ***** ** * ** * *** * * * ** ** * * * ** * ** * * *** ***** ");
** * * * ** ** * * * ***** * * * * * **** ** * * ***** * *** * * ** ****** * ** *** * ** ** * * * * * * *** * *** ** *
* ** *** * * ***** ********* * ** * * * **** **** ** ** * *** ** * ** * ***** * * * * *** * * * **** *** * * * * * *
* * ** * * * * * ** * * * ** ** ******* * * * * *** ** ** **** ****** ** * * *** ** ** ** * * **** ** * * *** ** *
*** * ** * * * * * * * ***** * * ** * * *** ** ** *** ** **** * ** ** **** **** * * * * **** ** ** * ****

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include ** ******

#include ** *** * * * **



int main()

{
* * * * ****** * num, n, p;
* ** * * ** * *** ***** ** *** ************* * &num);
** * * * * * ** * (n = 0; (2 * n) + 1 <= num; n++)
* ** ******* * * *
* ****** ** * ** **** * * ** * * * ********* *** * * (p = 0; p <= (num / 2) - n - 1; p++)
*** *** **** **** * ***** * ** ** ** * ** ** * *** * * * * ** ****** * **** * * ******** ");
** **** *** ** * * ** **** * ** **** ** * * * * * *** (p = 0; p <= (n*2); p++)
****** * ** * * * *** ** *** * ***** * *** * * ** **** * ** *** * *
* * * ***** *** ** *** ** ** * * ** * ** * **** * *
**** * * *


**** ** ** ** ** ** *** 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * ** * *** *****



int main()

{
* * **** ***** * a, b, c;
* * ** ** *** * * *** * ** * ** *** *
* ** ** *** * ***** ** * c <= a; c+=2)
* ** ** ** * * **
***** *** ***** ** ** * *** b <= (a-c)/2; b++)
*** * * *** * ** * * * ** ** * *** **** ");
** **** ** * * ** **** ** * b <= c; b++)
** *** * *** * * ***** * * ** * * **** *** * * ***
*** * * * **** * ** ****** * * * *** * *
* ** * * ** ** *** * *
* * * **** *** ** * * * 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* *** ** *** * **** * * a ;
** ** *** * * * * * * i , j ;

    
** ** ** * * ***** *** * * ** *** * * &a);


* ** ** * *** **** * * * **** **

    {
* * ** ** *** * ** * *** *
*** * * ** * ** * **** * ** * ** ***** ** * * * *
* * ** ** * * ** * ** ** ** *** ***
* * ******* **** *** * ******* ** **** *** ** * ** ");  
* * *** * *** ** ** * ** *** **
** *** **** * ** ** * *** **** ** * ***** * ** ** * * * *** ** * ****** * ** * ** *** * * * ******* * * ** * *
**** * ** * *** **** **** *** * ** ***
** * * ** ** * * *** * ** * * ****** ** * * * * ** *** * *** * *** * * ** * * * ** ** * ** *** * * * * * ** ** ** * * * ** ** *** * **** * * * ** *** ** * *** * * ** * * ** * ** * * * *** ** * ** * *** *** * *
***** ** * * * * * * ***


** * *** * * ** ***** * ** ***
** ** ***** * *** ***** * * * ** * * **** ** * * ***** * **

    }

   

    
** ** * ** **** * * * *** * ***** ***
****** ** * * *** ****** 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 4.4k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 9.1k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 6.4k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 8.3k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 5.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users