0 like 0 dislike
6.9k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 6.9k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
* ***** *** **

main()

{
*** * ** ** * * ** i,a,b,c;
* ** * *** * *** **** * * * **** * * **
* * ** **** *** *** ** ** **

{
** * * *** * * *** ** * *

{
* * * * * ****** **** *** ");

}
* * **** * * * * *****

{
* *** ** ** **** **

{
* ** ** * * ******** * * ** ** **

}

}
*** * * ** ******* * * *



}


* * ** *** ****** * * ** *** * ** ** ** *
***** ** **** * * ** 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
* * * *** * *** * * &num);
*** * * * ****** * * * * i = 1;i <= num;i=i+2)

   {
* *** ** ********* * * *** * * * * *** ** ");
* * * * * *** * * *** ** ** * * * * ***** ** \n");
*** **** * *** * * * * * *** ** **** * ** k =1;k<=num-(i/2);k++)
* * ** *** *** ***** * * * * *
** * **** ** ** * * ** * * * ** *** * *** ** * **** * * * * **** * ** ");
** *** ** ** *** ** * * ** * ** **
* * ** * ** * ** * * ** ** * * * * * * ***** *** * ** **** *
* *** * * ** ***** * *** * * ** *** ** * *** j = 1;j <= i;j++)
* * * ** * * **** * * ** *** * *
** *** ***** * * ** **** * * * * ** * * * * * * * **** ** *** *** * *******  
** * * * * * * ** * ** *** * ** * * * * ** ** *** ** * * * ***** ** * * *** * ****** * ***** **** * ** * ** * ****** * * * * * * *** * * * *** ***** * *** * *** **
* * ********* *******

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
* ** * * ** * * * a, b, i;
* *** *** * *** * ** * * * ** **** ***
* * * **** ** * * ****** * * *
** ** * ** ***** *****
** * **** ** * * ** * ****** *** ** *** ** *** * ***
* ** ** ** * *** *** * * ** * * ** ******* *** ");
** **** * **** * ****** * * * ** * * * *** ***** *
* ** *** ***** ** *** **** * * * * *** * **** ** **
* * ** *** *** * * *** ** ** ** *** *** ** ** *** * * ****** **
****** ** * **** * * *** *
*** ***** ***** ** * * ** **** * * * ***
* ** ** ** ** *** ** ** 0;
* * * * * *** ** ** *
***** * ***** ****
* ******* ** * **

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
***** *** *****
*** *** ** ****



int **

{
** a, j, k;
* *** ** * * * *** * **
* ** * = 1;j * * a / 2 + 1;j ++)

{
* * ** ** * ** ***** ** = 0;k * ** *** a / 2 - j +1;k ++)
* ** ** ** ** * *** * ** * * *** **
* ** ** ** * **** * *** = 0;k * *** * * 2 + 1 ;k ++)
* * ** **** ** * * ******* * * ** * **
* ** * * *** ** * *** ** * * * * **

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include ** * * * *

#include **** *** **



int main()

{
* ** * * * ** x,y,z;
** *** * **** * ** ****** ** * * * *
** *** ** * ******* = 1;x <= (z+1)/2;x ++)
* * ** * * ***
* * ** * ** * **** * * * ** = 1;y <= (z+1)/2 - x;y ++)
* * * * ** * * * * ** * ** * ** * * * * * * ** ");
* ** * * * * * * ** * ** ****** = 1;y <= (x*2)-1 ;y ++)
***** *** * * * * **** ***** ** **** **** * **** *** ** *** **
**** ****** * ** **** ** * * ** ** *
* ** * ** ***


****** * * * *** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include * * *** *

#include * **** ** ** **



int main()

{

int a, j, k;
** * *** * * * ****
** * * * * ** / 2+1; j++)

{
* * *** ***** * **** * * a/2 -j +1;k++)
* * * ** * * *** ** * ****
** * * * * ** * * * * * * ** ****
**** *** * *** ** **** **** ** *** *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
* * ** * * * * *** ***** * * ** * ** ********* **** ** * * ** **** * * * * ** ** * * **** ** * ** *
* * * *** * ***** * * * ***** * *** * * * * * ***** * * *** * ** **** ******* ** * **** * ** * * ******* * ***
* ** * *** * * ** ** **** *** ** *** * * * ** * ** ** **** *** ** ** * *** ** * * ** * **** ** ** * * * ");
** *** * * * * **** * ***** ** *** * * * ** ** * * ** * *** * * * ****** *** * ** ***** *** **** *** * * * * ***** **
** **** * * ****** * **** * ** * * *** *** ********* * ** ** * * * * * ** ** ** * * ** * * ****** ********** *** * ****
* * * * * * ** *** * *** * ** * * *** ** * **** ****** * ** ** * * ** ***** *** * * *** ****** ** *** * * * *** *****
* *** * * * ** *** ** ** * * *** *** ** *** * ** * ** ** * *** * * * *** * **** ** * ** * * ** ** ***

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include * * *** *

#include * * * **



int main()

{
* ** * * ** ** * ** * num, n, p;
*** * ** * * * * * ** ** * ******* &num);
*** ** * ***** * * * (n = 0; (2 * n) + 1 <= num; n++)
** * * **** * ** * ***
** * * * ** * * ***** * * *** * ***** * * (p = 0; p <= (num / 2) - n - 1; p++)
* * ** * * ** *** ******* ***** ** * *** *** * * ** * *** * ** * * **** ");
* ** ** * ** * ** * ********* * ** *** (p = 0; p <= (n*2); p++)
** ** ** *** * ** ** **** * **** * * ** *** **** * * ** * ** * ** ****** ** *
** * **** * * * * ** * *** * * * * * **
* * ** * ** *** ** * *


* * ** ** * * ** * * 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** * *****



int main()

{
* * * * ** * * * * ** * * a, b, c;
*** ** ***** *** *** * * ** ** * ** ** ***
** * * * * ** * * * * c <= a; c+=2)
* ** * * * ** * * ** *
* * * * * * *** * * * *** b <= (a-c)/2; b++)
** * ** * *** ** * * * * * ** * *** * ");
* ********* * * ** * * b <= c; b++)
* ** * ** * ** *** ** *** ********* * * * * * ** **
*** * * * *** * * * *** ** * * * * **
**** ** * ** * * * **** *
* * * *** * ******* ** * ** ** * 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* **** * *** * * *** * a ;
* * * * ** ** * * * i , j ;

    
**** ** ** ** ***** *** *** **** ** * &a);


* *** * * * *** * *** ** * * **

    {
* ** * * * * * * * *** ** ** *
* * * * * ** *** * * ** ** ***** * * * *** * ** * *
* ** * ** * ** ** ** * ****** * ****
**** * * ***** * ** * * ** * * * **** * * ");  
*** * * **** *** ** **** * ** *** *
* * *** ** ** * * * ** * * **** * ** ** *** * * ** * ** ** ** ** * ** ********* * **** * ***** * *** * * * * ** *** **** **
* * ** * ***** *** *** ****** * *
* ** *** * * ** * ****** ** ** * **** * *** * * **** * * * ***** ** * * ** * *** * * ****** **** ** * ** ** * * **** *** * *** *** *** **** * * * *** ***** * * *** * * ** * * ** *** **** *** * *** ** * * * **** *
* * ** * *** * ** * *** ** ** ***** *


* ** * * * * ** ** * *
* **** * *** * ** ** ** * **** * * * * * ** *** **** ** *

    }

   

    
****** * * ****** *** * *** *** * * ** * *****
*** * ** **** * *** * * ** * 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 4.3k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 8.9k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 6.2k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 8.1k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 5.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users