0 like 0 dislike
6.1k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 6.1k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** * * *

main()

{
* * ** *** **** i,a,b,c;
* * ** ***** ** * * *** * ** * * ** *
**** ** *** ** * ** * * *

{
* * **** * ******

{
** ** * ** * * ** *** * ");

}
**** * * ** * ** *

{
*** * *** * ** **** * * ******* *

{
*** ** ** ** ***** ***** ** ***** ** *

}

}
* ***** * * **** * ** ** * *



}


*** *** ** * * **** * ****** * *
****** * * * ** 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
** ** **** * ***** **** * &num);
** ** * * i = 1;i <= num;i=i+2)

   {
*** ****** *** ** * * * * * * ***** * ** ");
** * ** * * *** * **** ** *** * * ** * ** * ** \n");
* ** *** * **** * *** * * ** ** ** *** * * k =1;k<=num-(i/2);k++)
** * * * * * * * *** * *
** **** * *** * * * ***** * * ***** ** * **** ** * * * * * * * * * ");
* * * *** * * * ** * * ** * * * *
*** *** *** * * * * *** *** * * * ** * * * * ** ** * * ** ** ** * ****
* * ** ***** * * * ** ** ** * ** ***** j = 1;j <= i;j++)
* *** * * * * * **** * * * ** *
* * * *** *** * *** ** * ** ** *** * *** ** ******* **** * * ** ** *** *** **** *  
** * ******* *** ** * * * * ****** ** *** * **** *** ** ** **** ** ** **** ** * *** ** * *** ** ** **** * * *** * *** *** * * * **** * * ** * * ** ** * *** ***
*** * * ** **

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
*** ** ** ** ** ** ** * a, b, i;
* * * * **** **** * ** * **** **** * * * * * *
**** * * *** * * * ** *** *** ** ***
*** ** *** ** * ** *****
**** * ** ** * * * * ******* *** * * ** * ** * * * *** ** ***
****** * * * * ** ***** * ** ** ***** * * * * ****** * ");
** ** * ** *** * ** * * * ** * ** **** * * * * ***
* ** * *** * * ** ** * *** * **** * * *** **** ** * * * *
** ** * * ** ***** ****** **** * * * *** ** *
**** * * ** * * * ** *
*** * *** * ***** ** ** ** ** **** *
** **** * ***** * ** *** *** 0;
****** **** ** ** * *
* ** * *** * * *** **
******* ** * * ** **** **

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
** ** * * * * * *
* *** * * * * ***



int * *

{
** a, j, k;
* ** * **** * *** ** *
** * = 1;j ** a / 2 + 1;j ++)

{
*** * ** ** ** ** * * * = 0;k ** * a / 2 - j +1;k ++)
** * * * * ** * * * * *** * ** ***
*** * * ** * * * = 0;k ** ** * 2 + 1 ;k ++)
** * ** ** * ****** *** ** * **
* * *** ** ** ** * * * * *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include ** * * **

#include ** * * * *** **



int main()

{
* ** * *** *** ***** x,y,z;
** * **** * * *** ** ** * ** * ** * * **
******* * ***** * * * * ** = 1;x <= (z+1)/2;x ++)
* **** * *** **
* ** ** *** ** ** * ** * ** ***** ** = 1;y <= (z+1)/2 - x;y ++)
* ** * *** ** * * ** * ** * ** * *** * * ******** ** ***** ");
*** ***** *** * * * ** * * ** * * = 1;y <= (x*2)-1 ;y ++)
* * * * *** * * * * * **** * ****** ** ** * ** * * *
****** * *** *** * * * ** ***** ***** * *** * * ** *** ***
* * * ** * * ***


** * * * ** * * ** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include * *** * * *

#include * ** * ** ** *



int main()

{

int a, j, k;
***** ** * ** ** * * * *
* ** * **** / 2+1; j++)

{
**** * *** ***** ***** *** *** ** a/2 -j +1;k++)
* * ** * * ** **** * ********* *** ** **
* *** * * **** * ***** * ** ** * * * *
* * * ** * ** * * ** ** *** * * * * *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
** * ** *** ** * * * * ** * ***** * * **** * * * * **** * ** ** *** ** * ** *** ** * ** * ** * * * * *
** * ** * * ** * ** * * *** **** **** * * ** **** * * ** ** * **** * * ** ** **** * * * ** *** ** ** * * * * *** * * * ** ** * *
*** ** **** * *** * ** *** * * * * * * * * *** * **** * *** ** * * ** ****** * ********* * * ***** * ****** * * * ** * ");
* ***** * *** *** ** **** * * * * ** * ** * * * *** * * * * * ***** * ** *** ** ** * * * ** **** * *** * *** * ***** * ** * ** * *
* * ** * **** * ***** * * * *** ** * * * *** * *** * * * **** * * * *** * * ** ** ** **** * *** ** ** * ** * * * *
********* * ** *** * *** * ***** * * *** * ** * ** ** * * ** *** * ** * * ** ***** ** *** *** ** ** *** *** * *** ** *
* * * * * ** ** * *** ** * * ** *** * * ******* * *** **** * **** * * ** * ** * * * * ** ** ** **** **** ****

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include ** ** **

#include * ** * ****



int main()

{
** * ** * * * *** * * * num, n, p;
* ** * ** ****** * *** * * ** * &num);
*** **** ***** * ** (n = 0; (2 * n) + 1 <= num; n++)
** *** ** * * ** *
* *** * **** * * ** * * ** *** ** * **** *** * * (p = 0; p <= (num / 2) - n - 1; p++)
** * * * * ** * *** ** * ** * * * *** * ** * * * * * * ** * * ** ");
**** * * *** ** *** ******** * ** ** * * (p = 0; p <= (n*2); p++)
**** * **** ** ** * ** ** * * * *** * * * * * ***** ** * * ********** * *** ***
* * * *** * * * *** * ** **** * *** * ***** * * ** * * *****
* ** * *** * **


* * * **** * 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** **** * *



int main()

{
****** ***** ** *** a, b, c;
* * ** *** **** ** * **** ** * ** ** *** *
* * ** ** ** ** ** * ** c <= a; c+=2)
** * ** * * **** * *
***** * * ** ** * ** *** ** * b <= (a-c)/2; b++)
* * * * * ****** *** ** * ** **** ** * ** * * ");
** * ** ****** **** ** ** **** ** b <= c; b++)
* * * * * * * * * * ** * * * * * *** **** * * *
* * ***** ** ** ***** *** ** *** * * * *
* * * * * ** ****** * **** * *
*** * ** ** * * * * ** ** 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
** *** *** ***** ** * ** ** * a ;
* * * * ** ** ** * *** i , j ;

    
** ** * ** ** *** ** ** ** ** * &a);


* * **** **** ** ** **** **** ***

    {
***** * ** *** * ** ** * *** *
** * * * * * * ** * * * * **** * *** * * ***
* ** ** * ** * * ** *** ** ***
** ** ** ** * ** * ** * * **** **** * * ** * ** *** ");  
* ** ***** ** * * * * ** * *** * **
* ** * *** * * ** * * **** ** **** ** ** *** ** *** *** *** * * ** * ** ***** ** ** *** *** * * ** * * ** *
* ** ** * ** * ***** ** *** *
* * ***** * * ** * * ** * ** * *** ** * * ******** ** ** ** * * * * * * ** * ****** ***** ** ** *** * * *** *** * * ** ** * ** *** *** * * ** * *** ** * ** * * ******** *** * * ** *** ** ** * * **
** ** * * * * * * * *


* * * *** ***** * * *** * * **
*** * ** * *** **** * * ***** *** ***** ** * *** *** *** * *

    }

   

    
**** **** *** *** ** ** * * ***** * ** *
* * ** ** * *** * ** 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.93
©2016-2025

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 3.7k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 8k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 5.5k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 7.2k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 4.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users