0 like 0 dislike
7.1k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 7.1k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * ** ***** **

main()

{
*** * * * ** * * ** i,a,b,c;
* *** * **** *** * * * ***** * *** *
* **** * *** * ****** ** * ** **

{
*** *** *** * * ** *

{
*** * *** ** * *** ****** ");

}
* * ** * * ***** * * *

{
*** * * ******** *****

{
** *** * * ******* * *** *

}

}
** *** * ** * ** *** ** ** ** *



}


* * *** *** * ** * * *** * * * **** *
** * ** ** ** * * * 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
* * * ** * * * * ** ** * * ** *** * &num);
* * * * * ***** * i = 1;i <= num;i=i+2)

   {
** * * * * * * * * ** * * ** ** * * * ");
* ** ** * * *** * * * * ** * * *** * * \n");
* ** ** *** **** **** ** * * * *** * * ****** k =1;k<=num-(i/2);k++)
*** * * * * ** ** ****** * * ** ***** ** *
** * ** * * * ***** * * ** * * * ******* **** ** ***** ** ****** ");
* ** ** * * *** * *** * ** * * * *
* ** * ** ** * ** *** * * *** * ** ********* * * * ***** * *
** ** ** * ** * * * * *** ** * **** * j = 1;j <= i;j++)
**** * ** * * ** *** **
* * * ** **** ** ** * * *** ** ** *** *** *** ** * * ** * *** *** * ***  
***** ** * **** ** * **** ** *** ** * ** * * ** * * * * * * ** ***** ***** * ** * * * *** * *** *** ** ** ** *** *** * ** * * ** * ** **** * *** * ****** * * ** *** **
* * * ** *** ********

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
** *** ** ** *** * a, b, i;
*** ***** * **** * *** * * ** ** ** * * *
* * * * * * * * * ** ** ** **
*** ** * * * * ** *
** ** **** * * *** * ** **** *** *** ** ******* **** *** *** ***
**** * * ** ** * * * * * * ******* *** ******* **** **** **** * ");
* *** ******* * * *** ** **** * ** * ** **** * *** * * * ** *
****** * * *** *** ****** * **** ** * * ***** **** * * * * * *
* ** ** ******* * * ** ** * * * ** * * *** * *** ** * * ****
* ** * *
** * * * * * ** * ** * * * * * ** *
* * *** * * ****** * * * * * * 0;
**** ** * ** *** *
* * * ** *
**** *** ** ** **

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
**** * ** ****
* * **** * *



int **

{
* * a, j, k;
* * *** * ** **** * ** *
*** = 1;j * * a / 2 + 1;j ++)

{
* * * * *** *** * = 0;k * a / 2 - j +1;k ++)
*** ** * *** * * **** * * **** *
** * * ** * * *** ** * **** = 0;k ** * * * 2 + 1 ;k ++)
** ****** ** *** * * * * *** *** *
** *** ** ** * **** * * **** * ** ***

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include * * * ***

#include * * ** * * *



int main()

{
* *** * ** ** * x,y,z;
** ***** * ** * ** ** ** * ** **** *
* * ** * * * *** ** = 1;x <= (z+1)/2;x ++)
* **** ** * ** ** *
** * * * * **** ** ****** * * *** ****** = 1;y <= (z+1)/2 - x;y ++)
**** * * * *** ** * ** * ** * * * ** * ** * * ");
* * *** ***** *** * * ** ** ** = 1;y <= (x*2)-1 ;y ++)
* * * * * * ** ** * * * ** ** ** * *** ** * * * *****
** *** * * * * ** * ** * * * **
* ** * ** *** **


** * * * * * ** * 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include *** ** *

#include * **



int main()

{

int a, j, k;
* ** **** * * *** ** *
* *** / 2+1; j++)

{
* * *** *** **** *** * ** a/2 -j +1;k++)
**** ***** * **** * * * * *** * **** **
********* ** * *** * ***** ** * ** * * ** ** * *
* ***** **** **** * * * ***** ** *** *** *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
** * * *** * * ** **** *** * ** ***** **** * ** * **** *** * * * **** ***** *** ** ** ** ** **
** ******** * * *** *** **** * * * * ** * * * * ******* * **** **** ****** * ** ** **** * * ** ** **
* ** *** * **** * * * * * ** *** * * *** * * * *** ** ** * ** ***** * * * * ** * * * ** * ** ** * * ** * ** * * ");
******** ****** * * * * ** ** * * *** * ** * * * **** * **** * *** ** * *** ** ** * * ** * ** * ** **** ***** * ** *
** ** * * * * *** ** **** * *** ** **** ** * * *** ** *** * * *** ** * ** ** ****** *** ** **** * * * *** * ** * * **** *
* * ** *** **** * * * * ** ** ****** * ** * * * * ** * * * *** * **** * * ******* **** * * * ** * * ** * *
* ** **** * * * * * **** ***** ** **** * ** * ********* * * ** ** * * * *** * ** * ** * * ** *** ** * *** ***** *** *** *

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include * ** ** **

#include ** **** **



int main()

{
* * * * * *** num, n, p;
****** ** * ** *** ** ***** **** &num);
*** ***** * * * * ** ** (n = 0; (2 * n) + 1 <= num; n++)
* ** *** ** ** * ***
* * **** ** *** ** ** ** * * * **** **** * ** (p = 0; p <= (num / 2) - n - 1; p++)
* ** * ** * * * ******** *** * ** ** * ** ****** *** * ** *** *** *** ** *** * ");
* * ** * ** * *** *** * * * *********** ** *** (p = 0; p <= (n*2); p++)
* *** * ** ** *** * * ***** ** * ** * ***** ** ** * * **** ** *** *** * * ** * * *
**** * ** ** ** ** *** * ** *** * ***** ** * * *
** *** * ** *** **


*** ** * ** * * * ** ** 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ****** * *



int main()

{
*** * *** **** *** ******** a, b, c;
* *** * ** ** **** ******* ** ****** * * **
***** * * * *** * * * * * * c <= a; c+=2)
** ** * * * * ****
* * ***** ** ** * * * * *** ** b <= (a-c)/2; b++)
* ** ** ** **** * * * * * * ******* *** *** **** ");
* ** * *** * ******* ** *** b <= c; b++)
* ** **** ***** * ** * **** * ** ** ******** * * ** * **
* **** **** ** * *** * * * ** * * ** * *** *
*** * * ** * ****** ** *
*** *** ** ** * * * ** *** 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* *** *** * ** * a ;
* *** **** * ** * ** ** i , j ;

    
** * * **** ** * * *********** ** &a);


** * ** **** ****** ** * *

    {
** ** * * * **
* * * * ** * ** **** *** *** * *** **** ******** ***
** *** **** **** * ** *
** *** ** * * ** * * *** * ** * *** ******* ** ** * ");  
** * * ** ****** ** ** ** * **
******* *** * * * * **** * * ** ** ** ***** ** ** ** *** ** ** * * * *** *** *** ** ****** ** * * *** * * * * * *** *
*** *** * *** ** * * ***** * * *** **
** ** * ** ** * **** *** * ** ** * * ***** * * * * * * * ** * ** ** * ** ** ** ** *** * ** ** * ***** *** * * * * * * ** *** ** ** ** ** *** ***** *** ** ** ** * * * *** * ** ** **** **** * * **** *** *** * * *
* ** * **** * ** * ** * * * **


*** **** *** * * * *** * ** **
* * ****** * *** * * ** * * * * *** * * ** * ** * *** *

    }

   

    
** * * * *** * * * ****** **** ** * *
*** * ** * 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 4.4k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 9.2k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 6.4k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 8.3k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 5.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users