0 like 0 dislike
3.4k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 3.4k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
**** *** * * *

main()

{
**** ******** * * ** * i,a,b,c;
* * ** *** *** *** * *** * * * * **
**** * * **** * * * ** *

{
* * ** *** * ** * * * * * *** **

{
** * * * * ** * * * * * ** ");

}
*** ** * ** * * *****

{
**** *** *** * ****** * * *

{
** *** * * ** ****** ** *

}

}
* *** * * *** ** * ** * * * *



}


* *** ** * * * ** ** * * ** * ** *
**** ** * * * * * 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
** *** * *** * **** * * * * * * ***** &num);
* *** * *** * * * i = 1;i <= num;i=i+2)

   {
* * *** * ** ****** * * * * * ** * *** * ");
* ** * * * * * **** ** ** * ** ***** * \n");
** ** * * * * * ** * * * ****** ** * * * k =1;k<=num-(i/2);k++)
**** **** * ** * *** * ** **** * **
** * ** ** * *** *** **** * *** * * ** * ** * * ******* ** ");
* * * ** **** * *** ** **** * * *** * **
* * **** * *** ***** *** * * * ** *** ** * ******* ** *** ***** * * *
** ***** * *** * *** * * ******** ** * *** j = 1;j <= i;j++)
** * *** *** * ** * * *** ** * ** **
****** * * * * *** * **** * ** ***** ** * **** * * *** ** * * * *  
* * ** ** * * ** ** ** * * * *** ** * ** * ** * * * * **** ***** ** ** * * * * ** ***** ** * ** * * **** * * * *** ** ***** * * * * ** ** * **** ****** * ** * ** ********
* *** ** * ** *******

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
** ** ** ** ****** * * * a, b, i;
* * * * * * * ** * ****** * * *** * *** ** * *
* **** * ***** ***** * * * * * * * *
*** *** ** * *****
* *** *** ** * * *** * * * ** ** *** **** *** * ** ** ** **
** ** * ** * * ** ** ******* ** * *** * * * ");
** * *** * ** * * * **** * * * * * ** * * * * * *
*** * ****** * ** * * * * * *** * ** * *** *
** ** *** * * * * * * * ** ** * * * * * * * * ** ** **
* * *** * *** ** **
* ** * * * ** ** * ** * * ** ** * *** *
** * * * ** * ** * **** 0;
**** *** * *** * ****
** * * * * *** *** ** **
** * * ** ** **

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
* *** * *** *** *
*** * ** *** * ** ** *



int *

{
** a, j, k;
* * ** * * ** * **
= 1;j a / 2 + 1;j ++)

{
* * **** * * **** *** ** * * * = 0;k *** a / 2 - j +1;k ++)
** * ** * * * * ******* * ** ** ** *
*** * * * * ******* * * = 0;k * * * * * 2 + 1 ;k ++)
** ** ******* ****** * * ** * ** * * *
** *** * *** * ** * *** *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include * * ****** *

#include * ******* * ** *



int main()

{
* ** ** ** * ** x,y,z;
** * ** * * * * * * **** * * ** *
***** ** ****** * * = 1;x <= (z+1)/2;x ++)
**** * * * **** **
* ** * * *** ** * * * * ***** * = 1;y <= (z+1)/2 - x;y ++)
**** * ******** ** * *** ** **** * * *** * ** * * *** ");
* *** *** ** * ** * * ** *** ** = 1;y <= (x*2)-1 ;y ++)
* ** ** **** * ** * * *** ******* ** *** * ***** ** * ** *
**** ***** ** * * * * * * ***** * ** ** *** * * *
** * **** **


** *** * * * ** * 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include *** * * * *

#include * * * **** ** **



int main()

{

int a, j, k;
* * ** * * * * * ** *
* * ** ** / 2+1; j++)

{
*** *** * * * * *** * ** ** a/2 -j +1;k++)
* * * * ****** * **** * *** ****
* * ** * ** * * ** ** * *
* * *** **** * ** *** *** ** ** ** * ***

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
* * *** * *** * ** * ** * * ***** ** * * * * ** *** * * **** * * ** **** * * * **** * *** ** * * *** *
* * * * ***** ** ** **** ** * * * * ***** * ** * * * * ** * *** ** ** * * ** * * *** ** * ** ** ***** ** * *
* * * ** ***** ** **** * ****** * * * * * *** ***** **** ** * * ** * * * * ** * *** * * * **** **** * * **** * * ** *** ** ** * ** ");
* *** ** * * ** ** *** **** * *** * ** ** * ** * * * * **** ** ** * * * * *** **** * * *** ** * *** ******* ** * * * **** ** * *
* *** * **** * * * * * ** * * ** *** ** * ** ** * ** ** * * * * ********* ** * *** * * * ** ** **** *** * * *****
***** * *** * * ** * * * * ** * * * * ** *** ** * **** * ** ** ** *** * ** * * * * ****** * * * * * ** ** * * * ** * *
**** ** * * * ** * ***** * ** * * ** ** * * * * ** * ** **** *** *** ** *** * * * *****

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include * * ** *

#include * *



int main()

{
** * * * ** ****** * num, n, p;
* * * *** * * ** * ** * * ** ** ** * &num);
** * * *** * ** *** * * (n = 0; (2 * n) + 1 <= num; n++)
* * * * **** * ***** * * ** *
* * ** * * * *** *** * *** *** * *** * *** * * (p = 0; p <= (num / 2) - n - 1; p++)
* ** * * *** * * * ** * * ******* *** ******* **** ** *** **** * * *** ** ** * ");
* * *** * * * * ** *** * * ****** * ** **** * (p = 0; p <= (n*2); p++)
** * ****** * ** * ** *** *** **** * ** * *** *** * *** * ** ** * * * ** ******* *
* **** ******** ** **** *** * ** ** **** ** ****** ** * *** *** **
* ** * * * ** * **** *


** * * *** * * * * 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * * ** ** * * ***



int main()

{
* ** * ** ** ** **** a, b, c;
******* *** * * * ***** ***** * ** ** *
* * *** ** * * ** * ** c <= a; c+=2)
**** * **** *** * * * ***
** ** **** *** **** * ** ** ** * b <= (a-c)/2; b++)
* * * * ** ** **** * ** ** ** * * **** * * * * ");
* * ** *** **** * ** * ** b <= c; b++)
* *** ** *** ** *** ** **** **** *** *** *** * * ** ***** * **
** * **** **** * ** * * * * **** * *
* * * * * ** * ** ** *
* ** * *** ** *** * *** 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* * * * ** ** ** * * a ;
** ****** ** ** **** * * * * i , j ;

    
** * *** * * **** * ** *** ** ** &a);


* ** * *** * * * * *** *** ** ** ** *

    {
** ** * * ** * ** * *** ** ** ***
** ** * ** ** **** ***** ** * * * ** * * ** *
**** * *** * * **** * *** **
* * *** * *** * ** ** ** ** * * * * *** ***** * * * ");  
** * * * *** * * *** **** * *
** ** **** *** * * ** **** * * * ***** ***** **** * * ****** ** * * ** ** ******** **** ** * * * * *****
* ** ** ** * * * ** * ** * * ***
* * * * * * ** * * ** ** ******* * ** ****** * ** ** ***** *** *** ******* * * * * *** ** * ** ***** * * * * * ** *** *** *** * * * ** ****** * **** ** * ** * ** * * * *** * * * ** *** **** *** * ** ** * * * ** ****** * *
*** * ** * ****** * **


* * * *** ** ** * * * ** * * ***** * ***
*** * * *** * **** ** * ** * *** ** * * * * **** ** ***

    }

   

    
* * * **** * * **** *** * * * *
* **** * * ** * ** 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.162
©2016-2025

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 2k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 4.2k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 3.1k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 4k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 2.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users