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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
reshown
Dec 1, 2016
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Shun-Po
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Hidden content!#include <stdio.h>
#include * * * ** * *
#include <ctype.h>
#include <math.h>
#include ** * ** ** ** **
int main(){
* * * * * *** * ** h,m;
** *** * *** * ** * * * * * * * * * * ** * ** ** *** * * *
**** * *** ** * * ** *** *** arch,arcm,sum=0;
** *** * * ** * ** * * * ***
*** * * * * ** * * * * ** * = m * 6;
*** * ** ** * ** * * * * * * = h * 30 + m * 0.5;
* * ** ** ** * ** *** **** * * ** * > arch){
* ** * * ** * ** * * ** * * * * * ** * ** * ** = arcm - arch;
* ** ** *** ** ** ** *** * * ** * * * *** * ** * * ** ** * * * *
*** * ** * * ** *
*** * * * ** * * * ** * < arch){
* ** * ** * * ** * * * * * ** ** **** ** * *** * * * = arch - arcm;
* *** * * * * ** * *** * * * * ** ** ** *** ** * ** * * ** * *** * * **
**** * * * * * * * *
*** *** ** ** * *** ** == arch){
** * * * **** * **** * * * * * ** * * * ** ** ** * * **
* * * * ** *
* ** * * * ** * * **** * 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include ** * ** * * *
#include * * *
#include <ctype.h>
#include <math.h>
int main()
{
* * ** * * ** ** * * * * * * a,b,c,d,e;
*** * ** * *** * ** ** ** * **** ** * * *** * * * * *
* * * * * ** * ** *** * * * * * *
** * * * * * * * * ** * * * *
** * * ** * * ** * * **
* * * * ** ** * * *** * *** *** * * * *
* * *** **** * **** * ** * (c>=d)
* * * ** * ** * * * ** *
* * * * ** * * * * * (c<d)
* * * ** ** * ** ** ** **
* * * * * * ******** (e>180)
* * * ** * * * ** * *
* * ** ** * * * ***** * * *** * ** * * * * *
* ** * * * ** * * * * * 0;
}
answered
Dec 1, 2016
by
410523016
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Hidden content!#include * ** *** **
int main()
{
* * * **** ** ** * * * * **** * ,j ,n=0;
*** * * ** * * * i;
**** * ** * ** * * * * * * * ** * * * *
* *** ** * * = i % 12 ;
* *** * * ** *** **** * =( i * 30 )+( j / 2) ;
* ** * * ** * *** * = j * 6 ;
** * * * * *** * * * ** =k-l ;
if(m < 0)
* * * * * *
*** * * * * * ** * * * * *** * * ** ** = - m;
* *** * ** * ***
*** * ** * * *** ** * ** * if(m > 180)
* * ** * ** * ***** *
* * * ** * ** ** * * * * * = 360 - m ;
* ** ** * * * ** *
* * * * * *** * **** ***
* * * ** * * *** * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * *** * * h,m;
* * * *** ang1,ang2;
* * *** * ** * * * * ** * ** ** * ** ** * *
*** ** * ** * * ((30*h+0.5*m)>6*m)
* *** ** * * * * * *
* * ** * *** * * * * * *** * * * ** ** = (30*h+0.5*m) - 6*m;
* * * * ** **** * * * * * * ** ** * * * = 360 - ang1;
***** * * * * * * * ** * * * ** (ang1 > ang2)
* * * ** * * * * * ** * * * * * ** * * ** ** ** *** * ** **
** * ** * * * * * * * *** *** * * *
*** * * ** * * * * * * ** ** * * ** * ** *** ** * * * ** * ** ***
* * ** ** **** *
* ** * * * * *
* ** * ** * ** * ****
* * ** * *** * * * *** ** * * * = 6*m - (30*h+0.5*m);
* * * ** * * * * ** * * ** ** ** = 360 - ang1;
* ** * * * * * * * * *** ** * (ang1 > ang2)
* *** * * * * * ** * * * * * * * **** * * * * * ** *
* **** * * ** *** * * * * * * ***
** ** ** * * * * * * **** ** * * * ** ** ** *** * *** * * * * *****
}
* * * * *** * * *** * ** * 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include * * * * ** *
* * * * * **
int * ** *
* * * ** * * ** * ** * a ,b ,i;
** ** * * * * * * * * c;
** * ** * * * * *** * * * * **
* * ** * * * * ** ** * ** ** *** * ** *
* *** * * * *** != 12)
*** * * * * * *** = b*6 - b*0.5- a * 30;
* * * ** * **
* ** * * * ** ** = b*6 - b*0.5;
* * ** ******* * * c * * * 0 )
* ** ** * *** *** = -c;
* * * * ** * * **** * * * * * * * * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include * ** * * *** *
int main()
{
* * * * * ** * * m=0,k=0,l=0 ,j ;
** ** * * * * i;
* ** * * *** ** ** ** ** **** * * * * **** * **
** * ** * ** * * ** * = i % 12 ;
* ** * * *** * * ** =( i * 30 )+( j / 2) ;
* * * * * ** ** * * = j * 6 ;
** ** ** * * * * * * * =k-l ;
* * * * * * * < 0)
* * *** * * * *
*** * ** * * * * * ** * * = - m;
* ** ** * * * * *
* ** * ** * * * ** if(m > 180)
* ** ** * * ** * * * *
* * * * * *** * * *** *** * ** = 360 - m ;
* * * * ** * * *
** ** * * ** * ** * * *** * ** **
* * * **** * * * * ** 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * * ** * ** ** * * * a,b=0;
** * * * * * ** * * * * *** * ** c,d=0;
* ** * ** * *** * * ** * * * * * * * * * *
** ** * ** ** ** * * ** * *** ** * ** * *** * ** *
* * * ** * ******* * ** *** * * ** **
* * *** * * * * ** * * *
* ** * * * * * * **
* * * * * * * * **** ** * * * *
** * * * * * * * ** * * ** * * * *** * * * * * * * * ** *** *
}
* * *** *** * * ** ** * * ** *
* * ** ** * * * * * * * ** * ** ** * * * * * * * ** * ** *** *
}
* * *** * * * * * **** * ** ** 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * ** ** ** * *** ** hour,min;
* ** ****** * * * * * * d,k,a1,a2;
** * * * * * * * * * * * * ** ** ** * **** * * * *** * ** *
** * ***** ** * ** **** (hour==12)
* * * ** * ** ** * ** * * **
* * * ** * * * * * * **
* * ** *** ** *** * ** ** * * * ** ***
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* * * * *** * * * * * *
* * * * * * * * ** * * * 0;
* * * * * * * * *** ** ** *
* ** * * ** * * *** *
answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * ** ** ** **** ** *** * * * a,b;
* * ** *** * * ** ** * q,w,e;
** * *** * * * * * *** ** * * * * * * * * * * * * * *
* ** * **** * * * * ** **** * **
{
** ** * * ** * * * ** * * ** * *** * * * ** * * * == 0)
* * * * * ** ** * ** * * * * * * * * * * ** ** * * * * = 6*b - b/2;
* ** * * * * * * * * * * * * * *** * * * * if(b%2 != 0)
* * * ** * * * * * **** * ** ** * ** * * = 6*b - b/2 - 0.5;
* ** * ** * *** * ** ** * * * *** ** * * *** * * *
* *** ***** * * * **** * ** ** * * * ** ** ** * = 360 - q;
** * * ***** * ****** * * *** ** * *** *** ** * * * ** * if(q<0)
** ** * * * * * * * * * *** * * * * = 360 + q;
}
** * * * ** *** * ** ***
{
* * *** * * * * * ** ** ** * * * * * ** * ** * * * == 0)
** * * ***** * * ** * * * * ** * * * * * * * * * * = 6*b - b/2 - 30*a;
** * * * * * *** * ** * * * * * *** * ** if(b%2 != 0)
* * ** * * * * * ** ** * * * ** * ** * * * * = 6*b - b/2 - 0.5 - 30*a;
* ***** * * **** ** ** * ** * ** * **** * * * * * * * ** *
* * *** * * ** * *** * * * * * * *** * * * ** = 360 - q;
* *** * * * ** * * * * * *** * ** * * * * ** * if(q<0)
* * * * * * * **** * * * * * * * * **** * * * ** = 360 + q;
}
* * * ** * *** ** * * ***** * *** * * * * ** *** * ** *
* * * * * ** * ** * *** * **** * * * * * * * * * * * * ** *** * ** ** * * * * ** *
* ** * * * ** * * ** * * * * ** *** * * * *** ** * * if(w>q)
* ** * *** ** * ** ** * * * * ** * * **** * ** * * *** * ** * * * *** * * * *
* * * * * ** * * * * ***** * *** * ** * ** * = b%2;
** ** ** * * * * * *** * 0;
}
answered
Dec 1, 2016
by
410323020
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * * * * * * * * * * * * * * a,b=0;
* * * * * * * * * * c,d=0;
*** * * * * * ** * * * * * ** * * * * * * * *
* * * ** * ** * ** * **** ** * * ** *** ** * * * **** * * **
***** * * * * * * * * * ** * * * * *
* * ** * * *** * * *
* * ** * ** ** *** * * ** ** ** *
*** * * * * * ** * * * * * * * * * ** ** **** * * * ***** * ***
** ** * * * * ** * *
** ** * * ** ***** * * ** ** * *
** * * ** ** * * * *** * * ** * * * * * * * * * * *** * * * *
}
* ** * * ** ** ***** ** * * * 0;
}
answered
Dec 1, 2016
by
SRFX
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-140
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18075 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
Available when:
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18066 -
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AC 20161201 第二次期中考公告
[Resource]
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ID: 18085 -
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