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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
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Dec 1, 2016
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Shun-Po
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Hidden content!#include <stdio.h>
#include * * * ** *
#include <ctype.h>
#include <math.h>
#include *** ** * * *
int main(){
* * * * * ** * * * * * **** * h,m;
** * ** * * ** * * * *** * ** * * *** * * * *** * *
* * * * * * ** * arch,arcm,sum=0;
** * * ** * ** * ** ** **
* * ** * * * * *** ** **** = m * 6;
** * * * ** ** ** = h * 30 + m * 0.5;
* * * ** * * * * * * * ** * ** * > arch){
* * * * ** * * *** * * * **** ** * **** * * * = arcm - arch;
** * * * * * * *** ** * ** * * * ** * * * * ** * * ** * * * *** * *
* * **** * * ** ** * * **
**** ** * * ** * * * *** * * < arch){
* * * *** ** * ** ** ** *** *** * * ** *** ** * * ** = arch - arcm;
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* **** * * * * * **** * * * * ** * * * * * ** *** * * *** * *
* * * * * * * **
**** * ***** ** * * ** * 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include * * ** * *
#include ** * ** * * * *
#include <ctype.h>
#include <math.h>
int main()
{
* ** * *** * * ** a,b,c,d,e;
* * * * * * * * * ** ** * * ** ** * * *
* * ** * * * * * ** * * * * * **** * * *** * *** *
* ** ***** * *** * ** ***** * ** *
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* * * ** * * * * *** * * * (c>=d)
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* * ** ** *** * * * * * * (e>180)
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* * * ** **** * * **** ** * * 0;
}
answered
Dec 1, 2016
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410523016
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Hidden content!#include * * * * ** *
int main()
{
* * ** * * * * * ** * * * ** * * * ,j ,n=0;
** * * *** ** * * * * i;
* * ** * * * * * * * * *** * *** ** * * * ***
** * * * * ** = i % 12 ;
****** ** * ** * * =( i * 30 )+( j / 2) ;
* ** * * * ** * * *** = j * 6 ;
* ** * * * ** ** *** =k-l ;
if(m < 0)
* *** * * * *
** * * * *** ** * * ** * * = - m;
* * * ** ** **
* * * *** * * * ** if(m > 180)
* * * * * **
** * *** ** *** * *** * * *** ** * * ** * * = 360 - m ;
* * ** * * * * * ** *
* * ** ** * *** * * * * * * * * *
* * * * * *** 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** **** ** * * h,m;
** * *** ** ** ang1,ang2;
** ** ** * * * ** * * * * * * * * ***** * ** ** *
* * * *** * *** * * *** ((30*h+0.5*m)>6*m)
* * ** * * **** *
* * * ** * * * * *** * ** * * * * * = (30*h+0.5*m) - 6*m;
* ** * * * * * *** * * * * * * = 360 - ang1;
* ** * * * * ** * * * ** ** * ** ** (ang1 > ang2)
* * * * *** ** * * * * * * * * * * * * * ** ** ** * * *
* * * * * * **** * * ** * * * * * *
* * **** * * ***** * * ** * * * * * * * * * * * * *** * * *
* * * **** * * * *
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** * * * * ** *
** * * * * * **** * * * * * *** * = 6*m - (30*h+0.5*m);
* ** * *** * ** * **** * * * * ** * * * = 360 - ang1;
* *** * * **** * * * * * * ** ** * (ang1 > ang2)
* ** * ** * ** * * * ** * * * * * ** ** * * * ** *** ** * *
* * ** ** * * *** * *** ** * ** * ** * * *
* * * * *** * * *** * * *** ** * *** * * * * ** *****
}
** ** * * * * * * * * 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include * *** * * * * *
** * * * ** * * *
int * * ***
*** *** ** * * * * a ,b ,i;
* * * * ** ** ** * ** ** c;
* **** * * * * * *** * * * * * ** * * *
*** * *** * * **** * * * ** * * * ** *** *
* * * * ** *** != 12)
** * ** * * * * * * * = b*6 - b*0.5- a * 30;
* *** * * * **
* ** *** ** ** = b*6 - b*0.5;
* * ** ** * ** * * c *** 0 )
* ** ** * * = -c;
*** * * ** *** ** * ** * * * *** c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include * * * *
int main()
{
* * * ** ** ** m=0,k=0,l=0 ,j ;
* * * ***** * * * i;
* ** * * * ** * * ** ** ** * *** * * ** * * * ** *
* ** ** * * = i % 12 ;
** * ** * * =( i * 30 )+( j / 2) ;
* *** * * ** * * * = j * 6 ;
** * * * * ** * * * =k-l ;
* * * * * * *** < 0)
* **** ** **
*** * * *** * * * * * * * ** * = - m;
* * * * * * * * * * *
* * * * * ** ** if(m > 180)
* **** * * *
* * * * * ** * * * *** * * *** * * * * = 360 - m ;
* * *** * * *** **
* *** * * *** * ** ** * * * *** *
*** * * * * ** * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * * * * ** * ** *** a,b=0;
* * ** ***** * * ** ** * * c,d=0;
*** * * * * * **** ** * * * ** ** ** ** * * * *
* * **** *** ** ** ****** * ** * * * * * * *
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* * * * ** * * * * * * * *
* * * * * * ** * **** ** **** * *** ** * * * * ******* * ** ** * * * ** * *
}
*** * ** * ** * ** * *** ** *
* ** * * * * ** * * * *** * ** ** * *** * * * * ****** **
}
*** * * * * *** * * * * 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** * * * * * ** hour,min;
** * *** ** * * * * * * ** * d,k,a1,a2;
* * ** * **** ** * ** ** * * *** * *** ** * * ** ** ** **
* * * * * * * * ** * **** * (hour==12)
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** * * * * * * ** ** * * *
**** * **** * ** * * * * * * 0;
*** * *** * * ** ** ***
* * * *** * * * * ***
answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * * * * * * a,b;
** ** * **** * * * ** ** q,w,e;
* * ** ** * * * * ** ** * * * * * ** ** *** * * ** ***
*** **** * * * * *** * * ***** *
{
** ** * * * * * * * * ** ** ** * * ** * **** * == 0)
* * * **** * * * * ** * ** *** * * ** ** = 6*b - b/2;
*** **** * ** * * * *** * * * ** * * * ** ** * ** if(b%2 != 0)
** * *** * * * * ** * * * * *** * ** ** * ** = 6*b - b/2 - 0.5;
* ** *** * *** * ***** * * * * * * ** * * * * * * * * * * * *
* * ** * * * * * *** ** * * * * * * * *** * = 360 - q;
* * ** *** * * * * * *** ** * ** * * * *** * if(q<0)
* * * * * * * * * * * * ** * **** * * = 360 + q;
}
* * * *** * ** *** *** ** *
{
* * * * * ** * * * * * * ** ** * * ** ** == 0)
*** * ** * * *** * * * ** * * *** ** * * = 6*b - b/2 - 30*a;
** *** * ** * * ** * * ** * * * * ** ** if(b%2 != 0)
* * ** * * * * ** * * * ** * * * * = 6*b - b/2 - 0.5 - 30*a;
** ** * *** **** * ** ** * * ** * ** * * * ** * * * * *
* * * * * ** ** ** * * * * * * ** *** *** * ** * = 360 - q;
* *** *** * * * * * * ** * * ***** ** ** * ** * if(q<0)
*** ** * * * * * * * ***** * * ** * ** = 360 + q;
}
* * *** * ** * * * * * * * * * * ** ******* ** * *
* * * * * ** * * ** * * * * * * * * * * * * * * * * * * * ** * * * * * **
* * * * ** ** * * * * * * * * ** * * * ** ** * if(w>q)
** **** * * * *** * * * * * * * * * * * ** ** * * * * * ****** * * * * ** * * * *
* *** ** * ** * * * * * **** * ** * * * ** * * * * * = b%2;
* * * * * ** *** ** * * * * * 0;
}
answered
Dec 1, 2016
by
410323020
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* ** * ** * * * * * * * a,b=0;
* ** * * * * ** ** c,d=0;
** * **** * * *** ** * * ** ** * ** * * * * * **
* * ** ** ***** * * ** * * * * * * * *** ** * * *
* ** *** *** * * ** * * * ***** * * ** *
* * * * ** * * *** * *
* ** * * * * *** * **** ** * * *
*** ** * * ** * ** * * * ** ** * * * * * * * * ** * * ** ** * *
* * * * * * * *** *** *
** ** ** * * ** * * **
** * ** ** * ** * * * *** * **** ** * * ** ** ** * **** * * *** **
}
** * * * * * * * ** ** ** * 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18075 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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asked
Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
Available when:
2016-12-01 18:30:00
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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Shun-Po
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ID: 18066 -
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AC 20161201 第二次期中考公告
[Resource]
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ID: 18085 -
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