0 like 0 dislike
7k views

(20%)費式數列中,除了第一項第二項是一之外,之後的每一項皆為前兩項的和,請撰寫一程式,由使用者輸入N代表費是數列的第N項,程式會輸出第N項的值。

 

輸入說明:

輸入一個正整數N,代表要計算出費式數列的的N項,N大於0

 

輸出說明:輸出費式數列第N項的值。

輸入範例:
 

5



輸出範例:
 

5

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43450 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 7k views

19 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
* * * * ** * * x=1,y=1,z=0,n=0;
** * * * * * *** j;
* ** ******** * * * ** * *** **** **** **** ** ***
***** * * * ** ** ***** ** ** == 1)
* ** **** ******** ** * ** = x;
** * ** * ** * **** * * if (n == 2);
** ** ** **** **** * * = y;
* ** ***** ** ****** *** * * (j=2;j<n;j++)
* *** ** *** **** *** **
** * * ** *** ** ***** * *** ** *** = x + y;
* * * **** * * ** * * ** *** *** = y;
** **** *** * ** ** * ** ** ***** * * = z;
** * * ** ** ** * **
**** ** ** *** * **** ** **** * *** * *** *** *

*** * *** ****** *** *** 0;
}
answered by (185 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
* * * ** ** * * x=1,y=1,z=0,n=0;
* *** ** *** * ** ** * j;
* ** * ** * * * ***** * ** **** * ****
*** *** ** * ** ** * *** == 1)
** * * * ** * * *** = x;
** **** *** ** * ** ** if (n == 2);
* * * ** **** *** ** ** = y;
** ** * ** * * ** * ***** (j=2;j<n;j++)
** *** * * * * *
* * ** * ** * ** ** * * * * * *** ** = x + y;
** * **** ***** ** ** * * * **** *** = y;
** * * ***** * **** *** * * ***** ** ** ***** = z;
* ** ** * * ** *** *
*** * ** *** * *** ***** **

* * ** * * * * * * 0;
}
answered by (190 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
* **** ** * *** * x=1,y=1,z=0,n=0;
* *** ****** ** ****** ** j;
**** * ** * ** *** * * * *** ** **
*** * ***** * * ** ** == 1)
* * * *** * ** ** = x;
* ** **** * **** * **** * * if (n == 2);
** * * * ** * ****** = y;
******* * ** * (j=2;j<n;j++)
****** * * ** *** * ****
* ** *** * *** ** * * ** ******* = x + y;
* * ** * * ** * ** * * * ***** * * = y;
* * **** **** ** *** ***** **** * ** = z;
* ** ** * * * * * ** * ** ***
*** *** ** ** **** ******* *** * ** *** * * * *

** *** **** ** * *** * ** 0;
}
answered by (209 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n;
** ** * *** * * * * ** ** * *** * * *** * *
    {
** * ***** * *** * * * *** *** * arr[1000]={0};
* * * * * * *** * * ** * ** * * * * * *
***** ** *** ** * **** * *** * ***** ** *
* ***** ** ******* **** ** *** **** * ** * ** * * i;
*** *** **** ** *** *** * ** ** * *** ***
**** * ** ** * * * * ** ****** **** **
* ** ** * *** * ** * ** * * * **** *** * ****** ** * ** ** * * * * * ** * *
* *** * * * * *** * ***
** ****** *********** ** * * *** * * ** * * ** * ***** * **** * ** *
    }
}
answered by (100 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
*** ** * **** * * * ***** ** N,b,c,d=1,e=1;
* * ** * * * ** ** * * * * ** ** ** ****
* **** ** ** *** * * * * *** *** *** * *
* *** ** * * ** *** ***
** * * ** *** ****
** * * ** *** * }
* ****** ** ** ********* * * * * *
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
*** ** ** * * ** * * fay[1000]={0},n,i;
    
* * * ** **
** ** ** * * **** *** * * *** *
* **** * * * * * * *** *** ** ***
** ** **** ****** * * * ** * ** *
* ** ** * ** * ** *
* *** ** * * ** ** * * * **** ** *** * **
** ***** ** * * *** ** * *** **** ** *
**** * * *** * ** ** *** **** * **
}
answered by (192 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
* **** * **** * *** *** a=1,b=1,n=1,N,J;
    
*** ** * *** ** * * * * *** ** * **
**** * * * ** ***** **
* * * * ** *** * *** * * *** * *
* ** ** ** * * *
****** ** * ** ***** *** ** * ** *
* * **** * * * * ** * * ** ****** * ** * * *** ***
**** * * *** ** * * * **** * * * * ** ** ***
** *** ** * * *******
* ** ** * ** * *** *** * * * * *** *
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
** * *** ** ****
int main()
{
**** * * ** int N, n=2, ** *** *
* ** * ** * * *** * *** * **** **
** * ** * * ** ** *
** * ** {
** * * * ***** k=i+j;
** ** * *** ** * * * n++;
* **       ** **** * * * ** ** *
* * * *   *   i=j+k;
*** ***** *** n++;
** * * * ** * * * ** **** ** * ** * ** ** ***
** * * * * * * ** * * j=k+i;
***** ** *** ** * ** n++;
* * * * ** * ** * ** * ** **** ** * *** *** **
** * * * ** * **** }
* * * *** * * ***** ** *** **** * *** 0;
* ** *   }
answered by (164 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
* ** ****** ****

int main()
{
int n=1,n1=1,n2=1;
int N,j;
* ** ** * *** *** * * **
for(j=3;j<=N;j++)
{
n=n1+n2;
n2=n1;
n1=n; ** ***** **** ** * * **** * *** ** ** * * * * * ****** ** * * *** * * ** *** ***
* *** ** **** ** * * * **** ** ** * * ******* ** **** *** **** ***** * **** * ** *
} * **** ** * **
** **** **** ***** **
** **** ** ** ** **** **
}
answered by (174 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.111.91
©2016-2025

Related questions

1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 3.8k views
1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 3.3k views
1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 4.6k views
2 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 3.5k views
1 like 0 dislike
23 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 3.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users