0 like 0 dislike
8.2k views

(20%)費式數列中,除了第一項第二項是一之外,之後的每一項皆為前兩項的和,請撰寫一程式,由使用者輸入N代表費是數列的第N項,程式會輸出第N項的值。

 

輸入說明:

輸入一個正整數N,代表要計算出費式數列的的N項,N大於0

 

輸出說明:輸出費式數列第N項的值。

輸入範例:
 

5



輸出範例:
 

5

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43450 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 8.2k views

19 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
** * ** *** * * * * x=1,y=1,z=0,n=0;
* * * * ***** * * * * j;
**** ** * ** ** ** ** *** ** * *** **
* ** ** * *** * ** * ** * ** == 1)
* * ** * **** ** **** * = x;
* * *** ** * * ** if (n == 2);
* ** * **** *** ** * * = y;
* * ** * * *** ** * ** *** (j=2;j<n;j++)
** *** * *** *** **
*** * ** * ** * * * * ** ** * * * = x + y;
* ** **** * * *** * ** * ** ** * * = y;
** * **** * ** ** ** * ************ * ** * = z;
* * * *** * * ** *
****** **** * ** * ** ** ** ***

***** * * ** * ** ** ** 0;
}
answered by (185 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
**** * ** ** ** **** x=1,y=1,z=0,n=0;
* * * ** * ** ** * ***** * j;
*** * * *** * *** ** * * ** * ** * * **
* *** *** * * ** ** == 1)
*** * ** ** * * * * ** = x;
* **** * * ** ** * * * if (n == 2);
* ** *** * *** * * = y;
* * ** * * *** **** (j=2;j<n;j++)
** * ** ** * ***** *
* * ** * * ** * *** **** ** ** ** *** = x + y;
** * ** * ********** **** ** *** * * * * = y;
** * * * * * * *** ******* * ** * ** * = z;
* ** * * * **** * *** **
** **** * * *** *** * * * * ** *

** ** * * * * ** * 0;
}
answered by (190 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
** ** ** * * * **** *** x=1,y=1,z=0,n=0;
**** **** ** **** * *** j;
* **** * * * ** ******* *** ** *** * *
* *** * *** ** ** *** == 1)
* * ** * *** ** * *** = x;
* ** *** **** * * ****** ** if (n == 2);
*** ** * ** ******** = y;
* *** ********** *** (j=2;j<n;j++)
* * *** * * ** *
**** * * * *** * * ** * * * ** * = x + y;
* * * * **** ** * * ** ****** * *** * * ** = y;
* * *** ** *** ********* * *** ** ** ** = z;
* *** ** ** * ** *****
*** ** * * * * ** ** * *** * ** ** * * *

** * ****** ** * * * 0;
}
answered by (209 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n;
* * ** * * * ** ** **** *** ** *** * *
    {
* *** ** ** ** ** ** * **** *** ** ** arr[1000]={0};
* * ***** ** ** * * * ** * **** *** ********* * * *****
* ** * * *** ***** * *** ** *** ** ** **** **
** ***** * * * ** *** * * * **** * *** * ******* i;
** * * * * ****** * *** ** *** **** ** **** ** *
** * * ** **** ** * *** * * * * * *** *
** * * ** *** *** *** **** **** ** * ******* ** * **** * ** * * ** *** * **
* ******* ***** ** * * * ** * **** ***
******* ********* * * * ***** * * * * ***** * * ** ** ** **** *
    }
}
answered by (100 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
* **** * * **** * * N,b,c,d=1,e=1;
* ***** ** * ******* ***** ** * * * *** ***
******* * * ** * * ** * * * ***
*** * ** ** * **
*** * ** **** ** * ** *
**** * * * *** * ** }
* * ** **** * * * * ** ** ** ** **** *** ***
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
**** ** ***** * ** **** ** fay[1000]={0},n,i;
    
* * *** * **
*** *** * ***** *
***** **** ** * * *** * * * **
*** * ** * ** *** ** *** * * ***
**** * * ** * * ***
* *** * * *** * * *** * **** * ******
** * * * *** *** ** * ** * * ** * ** ** *
* * ****** ** * * * * ***** ****** ** * * * **
}
answered by (192 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
** ** * ** ** * ** * ***** ** a=1,b=1,n=1,N,J;
    
** * ** ***** * ** * ** *** * ** * * ** * ***
*** ** **** **
*** **** * * *** * *** *** * * *
* * ***** * * ** ****
* * **** * * *** **** * **** *** **
* ** **** ** * * ** ** * * * * * ***** ***
** *** * * * **** *** *** * * * **** ********
*** *** * * ***
* **** * * * ** * *** ***
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
* **** **********
int main()
{
* * ** int N, n=2, * * * *
** * * ** ** *** * ** * * ***
* ** *** * **** **
** *** ** {
* ** * ** * *** ** ** k=i+j;
* * *** * * * * n++;
      ** ** *** * ** * *
** * *   ****   i=j+k;
* *** * ** ** * * ** ** n++;
* * * * * * * * ** * * * ** ******** ** *** **** ** * **
* * * *** **** ** j=k+i;
* ** * * ** ** n++;
**** *** * *** * ** * * * * ** * **** ** ** *** ** ******
** ** * * * * * * }
** * *** * ** ** ** *** 0;
* ****   }
answered by (164 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
** *** **** * *

int main()
{
int n=1,n1=1,n2=1;
int N,j;
* * * * * * *** * * *
for(j=3;j<=N;j++)
{
n=n1+n2;
n2=n1;
n1=n; * *** ** ** * * * * * ** * **** * * * *** * * * * ** ** ** * *
* * *** * *** * ***** ** * ** *** * ** * *** *** * ** * * * ** * ***** * * ***** * ** * ** **
} * ** * ***** *** *
* * * *** * * ***
* * **** * *** * ** * * *
}
answered by (174 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.164
©2016-2026

Related questions

1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 4.4k views
1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 4k views
1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 5.9k views
2 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 4.3k views
1 like 0 dislike
23 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 3.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users