0 like 0 dislike
6.5k views

(20%)費式數列中,除了第一項第二項是一之外,之後的每一項皆為前兩項的和,請撰寫一程式,由使用者輸入N代表費是數列的第N項,程式會輸出第N項的值。

 

輸入說明:

輸入一個正整數N,代表要計算出費式數列的的N項,N大於0

 

輸出說明:輸出費式數列第N項的值。

輸入範例:
 

5



輸出範例:
 

5

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43450 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 6.5k views

19 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
* ** * * *** ***** * x=1,y=1,z=0,n=0;
* ** ****** ** * * j;
* *** * ** ** * *** * *** ******* * * * **** *
* * * * ****** == 1)
*** * *** ******* ** * * = x;
**** * *** * * ***** * ** if (n == 2);
**** ** *** * *** = y;
** ** * * * ** (j=2;j<n;j++)
** * * ** * ***** **
***** *** * * * * ***** **** * ** = x + y;
* ***** ******** ** ** ** ** ** ** * * * * = y;
**** ** * ** ** ** ***** * * * * ********** = z;
*** * * ** ** **
* ** ** * **** * ** ****** *** **

* * ** *** ** ** ** 0;
}
answered by (185 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
* * * * * *** * **** x=1,y=1,z=0,n=0;
** ** *** * ***** * * j;
** * * **** ** ****** * * * * * * * *** **
** *** ** * ** **** **** **** == 1)
** * * * ** * * *** = x;
* **** * * ** if (n == 2);
** ** **** * * * = y;
** ** * ** *** ** * * * (j=2;j<n;j++)
** * ** * **** * * ******* *
* * ** **** ***** * * * * *** * *** = x + y;
* **** *** ** * * * *** *** * = y;
** * ** *** * *** *** ** **** ** * = z;
** *** * * * **** *
* * * ** *** ******* * *** * * *** * ** *****

* * **** * * **** ** ** * 0;
}
answered by (190 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
**** **** * *** ** * ** ** x=1,y=1,z=0,n=0;
* * *** *** * * * j;
*** ** ** **** ** ******** * * *** *** * ** **
** ** ** * * **** * == 1)
*** * ** * ****** ** = x;
* ** * ** *** * ** * * if (n == 2);
*** *** * * **** ** = y;
** * * ** ** ** * * **** (j=2;j<n;j++)
** *** * ** * * ** *
**** * ** * ** * *** *** ** * *** * = x + y;
*** * * ** ** ** * * *** ********* * * = y;
** *** *** ** * * * ** **** *** = z;
** * **** * * **** *** *
* * * * * *** **** **** * * ** * *

***** *** * * * * ** * * * **** 0;
}
answered by (209 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n;
* * * * * *** * *** ****** ** * *** ***
    {
**** ** * ** * ** *** * ** ** * ***** **** * ****** *** arr[1000]={0};
* * *** * * ** * * ** *** ** ******* * * *** ** ******
* * ** * * ** ** * ***** * * * ** *** * *
*** ** * * * **** * * * * * ** *** * *** * i;
* * ** *** *** * *** ****** * * * * * ***
**** *** ** **** * * * * ** **** * * * ** * *** *
** * ** ** * *** ***** ** * * * *** ** * ** * *** ** * * * ** ***
*** * **** * * * ** * * ** ** **
** **** * * ** ** * **** * ** ** * * * * ** * ** ** *** *** ****
    }
}
answered by (100 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
* * **** * * * * * ** *** * N,b,c,d=1,e=1;
** * * **** *** * *** * ** * *** *** *****
* * * *** ** * ** * * ** ****** * **
* * * ** * * * *****
* ****** * * * ** ******
* * * ** * * * **** * * * }
* * *** * ** ** * * *** * *** ** * *** *
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
* *** * *** ** ** *** * fay[1000]={0},n,i;
    
*** ** **** * **** ***
** ** ***** * * ** ** * **
** ** * ** ** ****** * ** **** ***
** *** ** ***** *** ** ***** * * *
** * * ** * * *
** *** * * ****** *** * ****** **** * *
* ******* * ***** ** * ** * **** ** *** * *
** * * *** * * **** * ** * ** *
}
answered by (192 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
***** * * *** * * * ** a=1,b=1,n=1,N,J;
    
* ** *** * ** ***** * * ** * * * * *
* ** * * ** ***
* * * * **** * * ***** * * ** * *
* ** * *** * **
* * ** ** *** * * ******** ** * * * * * * * * *** **
* ** ** * * * ** * ****** ** ** ** * * **** ** * *
* * * ** * *** *** * ** ** * * ** **** ***** ****
******* * * *** * ***
**** ** ******** *** *** ***** ** ** * *
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
* * * **** ***
int main()
{
*** * ** ** * int N, n=2, ** * *
* *** ** ** * ** ** * ** * **** *
** * * ** * ** *** **
* * ** ***** {
** ** *** * * * *** k=i+j;
* ** * * ** *** ** * n++;
* *       ****** ** * * * ** * * *
** * ***   *** * *   i=j+k;
**** * * ** **** n++;
** * * * * * * **** *** ** * ****** * ***
**** * * * * * *** *** *** j=k+i;
*** * * ** * *** **** * ** n++;
**** ** * **** * * * * ** ** * ** ******* *
** * * *** * * *** ** }
** * ** ** ** 0;
** *   }
answered by (164 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
* * * *** **

int main()
{
int n=1,n1=1,n2=1;
int N,j;
* * * **** *** * * *
for(j=3;j<=N;j++)
{
n=n1+n2;
n2=n1;
n1=n; *** * ** *** * * ** **** * * * * * **** *** * *** * * ** * ** * ** * *****
* ** * *** * ** ** * **** ** * *** * *** **** ***** ****** *** * *** * *** * ***** ** ** * * * **
} ** ** * ** **** ***
** * * ** * *** ****
* ** * **** * *** * * ******
}
answered by (174 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.71
©2016-2025

Related questions

1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 3.5k views
1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 3k views
1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 4k views
2 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 3.2k views
1 like 0 dislike
23 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 2.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users