0 like 0 dislike
8.2k views

(20%)費式數列中,除了第一項第二項是一之外,之後的每一項皆為前兩項的和,請撰寫一程式,由使用者輸入N代表費是數列的第N項,程式會輸出第N項的值。

 

輸入說明:

輸入一個正整數N,代表要計算出費式數列的的N項,N大於0

 

輸出說明:輸出費式數列第N項的值。

輸入範例:
 

5



輸出範例:
 

5

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43450 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 8.2k views

19 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
*** * *** * * ** x=1,y=1,z=0,n=0;
* **** ** *** * ** * * * * * j;
**** *** * * ** * *** * * * * *** * ** ***
* * * * *** * * * * == 1)
*** *** ** ** * * ** * * * * = x;
* ** * * ** * *** *** * if (n == 2);
***** * * ** * ** *** = y;
* * ** ** * * ** * ***** (j=2;j<n;j++)
** *** * **** **** **
**** * * * ** * * * *** * **** * = x + y;
* ** **** ** * ** *** ** *** **** = y;
* * * * * *** *** ** * ** ** ** * * = z;
* ** * * * * * ** * ***
* ** ***** ** ***** *** ** *** * *** ** *

* * **** *** ***** * 0;
}
answered by (185 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
** * ***** ** ***** * * * x=1,y=1,z=0,n=0;
* **** ** * ** ** ** ** j;
** ** *** * ******** * * * **** * ** * *
** * ** *** ** * ** == 1)
* ** ***** * * * * ** = x;
*** ** ** * * * * * * if (n == 2);
*** *** **** * * * ** ** ** = y;
** * **** ** ***** * * (j=2;j<n;j++)
******* * ** ** ** * *
* *** ***** ****** ** * * ******** ** ** * = x + y;
* * **** ** *** * *** * *** ** * = y;
*** **** * * * * ** * * * * * ** * ** ** = z;
* *** * ** * * ***** * *
* * ***** *** * *** ** * * ** *** *

** * * * * *** *** ** 0;
}
answered by (190 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
*** * *** * * * x=1,y=1,z=0,n=0;
* * * ***** * ***** * * j;
** * ** ****** * ** *** ***** ** * * * * * *
* * **** ** ******* ****** ** == 1)
*** ** * * ** *** * * = x;
* *** * ***** * * **** if (n == 2);
***** * ** ** ** *** = y;
* ** ** **** * ** * *** (j=2;j<n;j++)
* ****** ** * **
** **** ** * * ***** * **** * * = x + y;
* * * ** * ** *** ** * * * * ******* * ** * = y;
***** * *** * * * * * * * **** **** **** = z;
** * ** *** *** ** ** **
* ** * * * ****** **** ** * * ***** ** *

** * ** ** * * * * * ** 0;
}
answered by (209 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n;
*** * ***** *** **** ** ****** *** ** ** * * * * ****** *
    {
** ** ** * ** *** * *** * ** *** ** * * * **** * arr[1000]={0};
* * ** * * * * *** *** * *** **** * * * *** ***
** ** * ** ** *** *** * * **** * *
* * ***** ** ** ** * * * * * * **** **** i;
** * ** ** *** * ***** * ** * *** *** * ** * ****** *** *** * * ** *
* ** * * *** * *** * ** * * * **** *** ***
* ****** ** * ** *** * ** * * ** * * * * *** **** *** * ** ** ********* *
** ** **** * *** * * * ******* ** ** ** *
* * ** * * *** ***** * **** ** * ** * * * * * ** ** *** *** *
    }
}
answered by (100 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
** * **** ** * ** N,b,c,d=1,e=1;
* * * * ** * ** **** *** * ******
*** * * * * *** *** ** *
** ** *** * * * * * ** * * ** *
* ***** ** ******* ** *
* * * ** ** ***** }
** **** * *** * *** * ** ** ******** *
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
******** * * ** ***** * * fay[1000]={0},n,i;
    
** ** * **** ***** *
** * ** * * * * * * *
** ** * *** * * * **** * * ** *
* * * * ******** *** * ** ** *
* ** ** * *** ** **
* ** ** * * * * * *** ** *** * ** ******
** * * ** * ** * *** * * **** ** ****** *
* ** ** * * ** ** * *** ***** *** **
}
answered by (192 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
* ** ** **** *** * a=1,b=1,n=1,N,J;
    
*** *** *** **** *** **** *** **
* * * *** **** * ** * *
*** * * ** ** * *** *** * * *** *
**** *** *** * * **** *
*** ****** ****** *** ** * *** ** * * ** ** * * *
* ** ***** *** ** * * * * * * * * * * ***
* * * ** * *** * * * ** ** ** *** ** *
*** * ** * ** * *
* **** *** *** ** * * * **** ****** * **** **
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
***** *** *******
int main()
{
***** ** *** int N, n=2, * *
*** ** * * * * * * * ****** **** *
** * *** * * * *
** * * ** {
* *** ***** * *** * * k=i+j;
** * ** * * * * ** *** n++;
**       * ** * * * * ** * ** *** *
** ****   *******   i=j+k;
**** * *** ** * * * * n++;
* ** * * **** * * * * * *** ** **** * * * ****** *
** *** *** * ** ** *** * **** j=k+i;
******** * **** ** *** * n++;
* * * * * ** * * * *** ** ** * ** * * *
** * * *** ****** **** }
** ** ** ** *** * **** **** 0;
* *   }
answered by (164 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
***** *** * * ***

int main()
{
int n=1,n1=1,n2=1;
int N,j;
* *** * * * **
for(j=3;j<=N;j++)
{
n=n1+n2;
n2=n1;
n1=n; ** ** * ** * * ** ** ********* * ** *** * * * * ** * ** *** * * ****** **** * **
***** ** * **** ** * * *** ** * * * **** ** ** ** *** ** ** * * *
} ** ***** * * *
* ** * * * *
* ****** * * * * *
}
answered by (174 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 4.4k views
1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 4k views
1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 5.9k views
2 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 4.3k views
1 like 0 dislike
23 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 3.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users