0 like 0 dislike
2.3k views

(20%)費式數列中,除了第一項第二項是一之外,之後的每一項皆為前兩項的和,請撰寫一程式,由使用者輸入N代表費是數列的第N項,程式會輸出第N項的值。

 

輸入說明:

輸入一個正整數N,代表要計算出費式數列的的N項,N大於0

 

輸出說明:輸出費式數列第N項的值。

輸入範例:
 

5



輸出範例:
 

5

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43450 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 2.3k views

19 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
* ***** ****** * *** *** x=1,y=1,z=0,n=0;
***** * * * ** * ** j;
*** ****** * ** ** **** * * * * * **** * * *
** * * * * *** ****** == 1)
** * * ***** * ** ** ** = x;
* * * * ** ** * **** * ** *** if (n == 2);
*** **** ** * **** *** * = y;
* ** * * ** * **** (j=2;j<n;j++)
** ** * ** * ** ** *** *
* *** *** ** * * ** **** * ** *** * *** * * ** = x + y;
** **** *** * ** *** * ** * * * **** = y;
* * * * * ** * * * * * * *** = z;
*** ** *** * ** *
** ** * * * *** * ****** ** * ** * ******* * * ** * **

** *** * * ***** * ******* 0;
}
answered by (185 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
* * * ** *** * *** * x=1,y=1,z=0,n=0;
** **** ** * ** **** * ** * j;
* ** * *** * **** * ** ** * * ****
*** * ** ** ** ** == 1)
* * * * *** ** ** * * * ** = x;
** * * * *** * **** **** if (n == 2);
* ******* * * *** ** = y;
* ** *** ** ** ** ** * * (j=2;j<n;j++)
* ** **** ****** **
* * ********** *** **** * ******* *** *** = x + y;
* ** * * ****** *** *** ****** * *** = y;
* ** * ** ***** ****** * *** * ** *** ***** *** ** * = z;
*** * * ** ** * * * * *
** ** * * ** * * ** ** ** * ** **

** **** ****** ***** * *** * * 0;
}
answered by (190 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main ()
{
** ** ** *** * ****** x=1,y=1,z=0,n=0;
* ** * * ** * **** j;
* * * * ** * * *** *** * * ** * ** *** *** * **
* * **** * *** * == 1)
*** ** ** * * ** *** = x;
*** * ***** ** ** ** *** * if (n == 2);
* ** *** * * **** ** = y;
* * *** * * *** * ** (j=2;j<n;j++)
* *** ** * ** * * * *** *
* ** **** * * * * * ** ********* *** * ** = x + y;
* * ** * *** ** * * ** ** * ** * * = y;
* **** * *** ** * ***** * *** * * * = z;
* * ** ******** * * *******
* *** * ** ** * * * * *** ********* ** **

** *** ** ******* *** ** * 0;
}
answered by (209 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n;
* * ************** ***** * ** * * * * ***** * *
    {
* * ** **** * * *** * *** *** * ******* * * arr[1000]={0};
* **** * ***** * ** *** * ** * * * * * ******
* * ** ** * **** *** * ** * ** * * * **** ** *
** * * ** * * **** * **** * ** *** * ** ** ******** i;
**** * * *** * ** ** * * * ** ***** **** ***** ** *
*** * ** * * ** * ** ***** *** * ** ** ** ** *
* * * ** * * * * * * ** * *** ** *** * ***** ** **** * * *** * ****** * **
* *** **** * ** ** * ** * * * ****** *
* * * * ****** ** ** * * * * * * * ** ** * ** * * * ** *
    }
}
answered by (100 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
** *** * * ***** * ** N,b,c,d=1,e=1;
**** * ****** * *** ** ** * ** * * * * *
* ** * * ***** *** ******* ** * **
* * ****** * ******* * ***
***** * *** * **** *** ***
** * ** * ** * * ** * }
** *** **** ** ** * **** ** ***** * **** *
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
*** ** * *** * *** ** fay[1000]={0},n,i;
    
*** * *** *** *** *** * * * *
** ** *** * ** ** ** * * *
* * *** * * *** ** ******** * *
**** * * * * *** * ** * ** *
* * * * ** ***** ***
** ** * ********* ** *** * ***** * * * * *
* * ** * * * ** **** ** ** **** * *
* * * ** * * *** * ***** * * * * *** *** ** **
}
answered by (192 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
* **** * * ** * a=1,b=1,n=1,N,J;
    
*** * * **** ** ******* **** ***** * ** * * *** *
* * *
** ** * * * * * * * *
* ** *** ** ***
*** ** * ***** ** ****** * * *** * *** * * *
* ** **** *** * ** **** **** ** * * ** * * *
*** ** *** ** **** **** * **** * * ** *** ** *
* * ** * * * ** ****
**** * **** * * ** ** *** ** * * ** *
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
***** ** ** *
int main()
{
* ** * ** int N, n=2, ***** *
*** ** * ***** ** ** ***
* ** * * * * ** ** ***
* **** * * * * {
* * *** * * * * * k=i+j;
** * * * ** * * ** * *** n++;
***       * * **** *** * *****
** * *   ** * *   i=j+k;
* * * ** * ** * ** * * n++;
* * ** * *** * * * ** * * * * ***** * **** * ***
* * ** * * * ** j=k+i;
* **** ****** ** ** * n++;
** *** ****** * * *** * * ** ***** * * *
* * * * * * * * ** }
* ** ****** * * * *** ** 0;
***   }
answered by (164 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
* **** ** * ** **

int main()
{
int n=1,n1=1,n2=1;
int N,j;
* ** * * ******* * * *
for(j=3;j<=N;j++)
{
n=n1+n2;
n2=n1;
n1=n; * * * *** ** * * ** ** ** * * * * * ****** ***** **** ******* **** *
* * * * ** ******** * *** ** *** ** * **** * * * * *** * * * ******* * *** * * * * * **
} *** ** ** ** * *
* **** *** ** ** ** * **
** ** * *** ****
}
answered by (174 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.28
©2016-2024

Related questions

1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 1.5k views
1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 1.4k views
1 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 1.5k views
2 like 0 dislike
24 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 1.4k views
1 like 0 dislike
23 answers
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
| 1.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users