第二次期中考補考-第二題

3 like 0 dislike
7.1k views

若一個正整數的奇數位數字和與偶數位數字和兩者差的絕對值是11的倍數，則這個正整數就是11的倍數，否則就不是11的倍數。

請寫一個程式來判斷輸入的數是不是十一的倍數。

 

輸入說明：

會輸入一個正整數N，N不會超過1000位。

 

輸出說明：

如果輸入的數字是11的倍數就在螢幕上輸出YES，否則就輸出NO。

 

輸入範例：
 

11111111111111111111111111111111111111111111111111



 

輸出範例：

 

YES
[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 38939 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 7.1k views

16 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* * **   ***   *  ***  ** **    arr[1000];
* * *    * ** * *** ** *    * even=0,odd=0,i,n,sum;
    
       * ***** *****  ***    ****  **  **  * * *  * *
    
 *  *  *  * * *  *  ** **** *  ****
** * ** *  *   **** *** * * ** 
    *****  **   ***** *   ***  **  *    *** *
    {
 ***  * ** *** ** ****  **   *  *  *** *  * **** **  ***  **   * *   **   *****     ** * *** * * ** *** *  *   * * ** *      *** ** *  
* * ** *  ** ***   *  ** * * *** **     *   * **  **    * **** **  ** **   *** ***  **   * * **   *  * **** *   *  *  ***     **  * **    
      *        *     *****  * *    **   * *  *       *** * *  * **    **     *  **  *  * ** *  *** *** *    *  *  *      * * *** ** * ****  ******* 
  *   **     ***  * ****   ****  *  *  *******    ***** **  *   ** * * ******       *   ** **** *   *          * **** *  **    **   * **   ** *   ** 
    }
    
***  *  **  *  *    *  *    **   
* * *****    * * * ** ** *** * *  **      
 ** *        **  *    ** ** ** **** **  * *** *  ****
*****  * * **  * *     * *     *** 
   ******* *   **  ** *** *     *  * ***   **  * 
    
**  *      **        *****   *    0;
}
answered by (215 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
  ** * **      *****  **  *   num[1000]={0};
    int k, even, odd, i, j;
**  ** *    ******** ******  ****   * * * ** * * * ** 
 ** *** **  *  ** ***      ** **   *
*****    * * ** *** * *  *** ** 
 *** * **   *  *** ****   ***   **** *  ***       *  **** * ****   * ****
***    ******  *   ** * *   **** * * * ** *** ***  * *   
 ** * **  *** ***     * ** *   *   * *  ** *  * 
 **   *****   **  ** * * * ** * * *  *  *  * 
 *****   *  ** *    *  *          * 
 * **   **  **  * *** **  * * * ***  * **    
 * *  * *  * ********  * *
 **     **    ***   *  **    **  *  ** ****   
*   * **    ** *       * *****    0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:23: error: expected expression before ']' token
     scanf("%d",&array[]);
                       ^
prog.c:7:5: error: 'returm' undeclared (first use in this function)
     returm 0;
     ^~~~~~
prog.c:7:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:7:12: error: expected ';' before numeric constant
     returm 0;
            ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
    char c[1000];
 * **  ** ** *  * *  ** *  * *    *  **        
    int a,i,x=0,y=0,z;
 *  * **     * *  *  * * *****
  ***      *** *   *  * *    ** * ***  *  * *
    {
   * * **** * *   * **  ****  * ** ***** * **   **   *    
    *   *  ***** *  *** *  *****   **** ** *   ** *   * 
    *  * **  ** **** ***    * **** **** ** * ****      * *** **  ***  ** * * ****  ** ** *
 *  *   ** *****    *  *   *  ** *  * ****    *  **   ** * *   *  *****  **   ** ******    *    
 **** **  * ***  * ****  ** *  ** ** **** **    *** ** ** * ** 
** *   *  ** * ***    * ** ** ** * * *    * *   **** 
* *** *** *  * **  * **** ****** *  *      *  *** **** *  * 
  * *    ***  *   *** * ****** ***  ***** *** *   ** * * * ** ***  *  *    ** * ***** * **
    **    **  * *    **** *      **** *  **  ** ****   *  **   **  ** ** * *      * *
****    **   *  ** *    *** *  *    *   * * **  *
    }
   *   ****   ** ** * **** *   *  *    
  * *  *  *       *   ** * * ** **     ** *  **** ***  * * * *** ***  **** ** *  *  *
    else
***    *  *  *** ** ** ** ** **  *    ***  ** * ***** ** **  ** ***    * *   
}
answered by (100 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main ()
{
*  **   *  * * ***  * ** ** * ** str[1000]={0};
**    * *  *  *  * * * **   j , n,sum1=0,sum2=0;
   * * *  **  *  ****   *******    *  **   ** *
**  *  ****** ** *** ***    * = strlen(str);
********* * **  *  **    * **** = 0;j < n;j++)
*  * ** * * **  ***  ** * * 
  ** * * ***  *  *  * **  *   *    ***  ****    * ** * * ***       ** == 0||j%2 == 0)
    ** *  *        ********   *   ****  **** *  *   * ***    *** * = sum2 + str[j] -48;
  *  *  ***** * * * **  *  ** * ** * **  **** * * *  ************   * * *  *  if ( j%2 != 0 )
** *****    *    * ***   ***  *** *** * * *  *** **  ** **   *********    * ***  = sum1 + str[j] -48;
  *******  * **  **   ******* * *
 ** ** * *** * * * *       (sum1 > sum2)
   ****  **   * *** * **** * *
*  ****  *  **** * *   ** **  *** * * **  *   *******  - sum2) % 11 == 0 )
* *  ****** *** ****** *    *    ** ** *  ** **   * *  *   *   *  \n");
  ****  ** * *   *    * ** *****  **  *** *   *
  ***   ****    *****      * * **   * *****  *** * * *  * * ***** * \n");
 *      **** ***** * *  *** *  * 
    ***** * *  * ****  ** *  if(sum1 < sum2)
* ** ** *   *  * ** * * *    * *
* * *** ***   * * * *  *  * *  * * ****  **** ** * - sum1) % 11 == 0 )
 **  * *       ****  * *** *  ** *** * * ** ***   *  **   \n");
 * ** ** ***    * **      ***  *** *** ****  ****    *** 
*    **     *** ** *****    *   * **   * ******* *  ***  ** * \n");
***   ** ** *** * *** ** 
*    ***    *** * **  **  **   * if (sum1 == sum2)
** ** **  *  **  **    **      ** ** *   *  * **   *  **** \n");
  ***    ***  * * * ** *     *  *  ***  ** 
*  ** **** *  ****  *  **    * *  *** 0;
}
answered by (209 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
prog.c:21:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system ("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(str);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccwAQ4Bd.o: In function `main':
prog.c:(.text+0x3c): warning: the `gets' function is dangerous and should not be used.
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 **  * * * *   ** ** **  * arr[1000];
** ********* *  **  *  even=0,odd=0,i,n,sum=0;
   
**   **  **  ** ***   *  **    ** *  ****** *
   
***   ***    ***** **  ** * ****** 
** * * *      *** *  *
   
  * ** *  **   * * **   ** * *** 
* *  ***  * * ** ** ** *
 *   *   * ** ** *** ***   ***     **     ****
 ** **   ** ** ** **   * * **    ** ** ***  **   *  **  ** * **   ** ** *  **   ** **
******     *  * *** * *  * ** *     * * ***  if(i%2!=0)
** * **  *  ***   **  *    **  **   ***  **** * ***** **  *   ***  *** **  * * *  ****    * ** * ** *     **** * *  *  *** ****  ***  *  *        * ** *
*  *       *  ***   ** **    
**  ** ***** **    ****  * *  
   
  **  *  *  * ***  **   *
*** ** **   *      ** **
 *   * *  *  *****  ***** ** * * ** **** *  * *** **** *  ***** ***** * *  *   ** *   *    *** **     *  *           ***** ** * * **** *****
   ** ** ****  *     *
 *** * * * *    *    *  if(sum%11!=0)
 * *       *    **** 
  ** *****   *  *** ** ** **** **   *** * *** ***   **  * ** *****    
*  * *   * *  *** *
   
  
***  ******* * *    ** ******  *
 **        **   **    * * * * 
}
answered by (174 points)
0 0
prog.c: In function 'main':
prog.c:8:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
    scanf("%s",arr);
            ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main(){
 *  *    *** **      ***** ** one=0,two=0,i,ans;
  *   ***      * * * *    *  ch[1000];
*** **  ****    ***      *****  *    *** *  *** ****
    
** ** * ****  *** *  **     ** **   * *     * * 
 ****   * * * *  *   *    ** * *****   *  ***
* * *  ** **    * *****  **  *** **  *    *   *****  ** **  ** *** **   ** ** **
***** *     **  * ** * *   *   **      * **  *  
     **   **  *  *** ** * ** *   * *    ****** ** * 
* * *  *   *   ** **   *  *   ****** ** *   **** **   *  * * * *  **  *     ***
  * ***   **    *******         ***    * * *** *
    }
    
   * *  *  ******   *     ***
    
** *  * *   ****    * **** *** ***   
 *    * * *  **   * *     ** * **** **  *    *** * *
* **   ***   *    **** * * ** *  * 
* *   *  * * **   *      * *  **  *  *   *  ***  * 
}
answered by (192 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.21
©2016-2025

Related questions

2 like 0 dislike
5 answers
第二次期中考補考-第五題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38942 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 2.4k views
2 like 0 dislike
18 answers
第二次期中考補考-第四題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38941 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 6.5k views
4 like 0 dislike
16 answers
第二次期中考補考-第三題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38940 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 10.1k views
3 like 0 dislike
12 answers
第二次期中考補考-第一題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38938 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 5k views
2 like 0 dislike
3 answers
第二次期中考補考題庫 -10 唐．喬凡尼
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38168 - Available when: Unlimited - Due to: Unlimited | 1.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users