第二次期中考補考-第二題

3 like 0 dislike
1.4k views

若一個正整數的奇數位數字和與偶數位數字和兩者差的絕對值是11的倍數，則這個正整數就是11的倍數，否則就不是11的倍數。

請寫一個程式來判斷輸入的數是不是十一的倍數。

 

輸入說明：

會輸入一個正整數N，N不會超過1000位。

 

輸出說明：

如果輸入的數字是11的倍數就在螢幕上輸出YES，否則就輸出NO。

 

輸入範例：
 

11111111111111111111111111111111111111111111111111



 

輸出範例：

 

YES
[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 38939 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 1.4k views

16 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* **  ****   *  * * *     arr[1000];
** *   **  * ** *   ** * even=0,odd=0,i,n,sum;
    
  **  *   *  ** * ** * **  ***  *****   * ***    ** **  
    
****   *** **     * *    * *    ***   **   
****    * **     **  ***   
*  * ***     **  *** * *   * *    *  *  * * ** 
    {
 *       ****  * ** * * * *** * * * *  * * *  ****  * **    * *  ** *  * * *  *  **  ***       *  ** *   ** ** **   * * **  ** ** ***      * * *
*** * *  * * *       * ** *   ** * * **  ***  *    * *  *** ** *** ****  **  ****  *    * *** * ** * * ** * **   ******    **    ** *    * *    *******  **
 * *  **** * **  **** *  *   *    ** *    ** * **** ****   **** *****         ** *   **   **  ***    * **    *  * *  **  * *  * *** * *
   *   *** ** * **     *   ***   ** *   ** * **  **** ** *  **   *       * *  ***    * **  **   *   * **   * * * *  *   **  ***   ** *   ***** 
    }
    
** ** * ***    * *    * *   **  **
 **** ** *    ***** *   *  ****** ** * *
* **  *    ** *  *  *    * * ******  *   ** ** *** ** 
   *   *  *** *   *    *         *****
**   ** ***    * *  ** * **  * * *  *  *****
    
** **           ***** ** 0;
}
answered by (215 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
* **  ** *   ** ****  *  *      num[1000]={0};
    int k, even, odd, i, j;
  *       ** ** * ** *    * * **** ****   *  * **  ** * **  
****  *** **  *   *   ***** 
****** *        ****** * ****   *
 ** * * **  *  *  * * *   ** * *  *  * ** **** * *  *     ** *
   * * ***** **   ** *   *   ** * **     * ***  * * *   ***   *
* * * *  ***    **    *   * *** ********   **  **  * *  * *
* *** * *****  *   *****  ** ***  * ****    * ***
      *   ****   * **  *  **** * *** **  
      ***** **  *** *  **   ***  *  ** ***** * 
*  * *    * **  *      *  *
 *   ** * * *  *  ****** ** ** *  * **   **  *  * ***   
*  *  ******    *  *  * ***  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:23: error: expected expression before ']' token
     scanf("%d",&array[]);
                       ^
prog.c:7:5: error: 'returm' undeclared (first use in this function)
     returm 0;
     ^~~~~~
prog.c:7:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:7:12: error: expected ';' before numeric constant
     returm 0;
            ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
    char c[1000];
    ** ***     ********  *** *  **    ** ***  ****
    int a,i,x=0,y=0,z;
 * *    *    * *    *  ** *  * *** 
**** **       * ** * ** * ****  *  *
    {
 * **  * * ** *   ***   ***  * **    ** **** * * * **   *   *
**    ** ***   ********* *  **** **      * *  * * ** *****
 * ***  **   * ** * ** * *    **  ** *  *     *  * ** * ** ** ***    *  * *  **********   ** 
* ** * ** **  *  *  *  * ** ****  ** **   *   ****  * ***   * ***  ** ***  *   * ****
 * ******  **  ***** *** ** **  *      *   *   *     
 **  * * *    * *  **   ******  **   *  * *  **  *  *** * **  **
  ***  *   * **  **********    *  *  **    **   * *  ** 
 ** * **  *  **  *  *   *** ** ******* **  * * *   **    *  *    ** **    *    *   **** ***
 *     *** **  *  *      **   * * **      * * * ** *** ** * **  ****  ***** *   **
*  **** * *   *  *  * ** * ** *** **   ** **  **
    }
 * **   * * **** * * * ***   *** *
    ***  *   ****  *        *  * *     ** *******   ******* * *****  ** 
    else
*** ** * *  *    ** *   ** *** ***   ** **      * ** * *   *  ***  *   * * * 
}
answered by (100 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main ()
{
       * ***  ****  *** ***** ** str[1000]={0};
   *    *      ** *  *    j , n,sum1=0,sum2=0;
  **** * * ***   * ** *** *     ** ** **  * *** **
*  *** ***   ** **        *** = strlen(str);
  ** * *****  ***  **** *  *  = 0;j < n;j++)
***  * ***    **   ***   * 
**   **     ***** ** * *   ** *  * * * **  ****   ** ** * *  *    * == 0||j%2 == 0)
  ** *****  * ***   *  *** * ** *****    *  **  ** ***  * = sum2 + str[j] -48;
*****   ** * *  * **  ***  *      *   *   *  ***  ***    ***    if ( j%2 != 0 )
**** ** **** *** * * * * **  *   *    *** *** **   ** * * *** * *  *  = sum1 + str[j] -48;
*** * * * **   *** *  * * *
**   ****  *   *  * *    *   * *   (sum1 > sum2)
** ** *  *     *  *  * * **
  *** *  ** **  * * *   *  * ** *   **** **   * ** ** **** *  - sum2) % 11 == 0 )
 * *** ** *  ****** * ********  * *** * * *  **      *  *****    \n");
 * *    * * * *  ****  ** ****  **  *  ***  **  ***
*    **  ***** ** **  ****** *  **** **** * ** ** *    *   *   ** \n");
   **   ****  *  *   *  *
 **** ***   *  * **  ** *  **** if(sum1 < sum2)
 * ** *     *** * * * ***  * 
   *  * *   *** ****     ***   *  **  *** *   - sum1) % 11 == 0 )
   * ** **  *** *    * ** *      **   *   *   * *  ** ** *     * \n");
*    *** ***  * ** *  *  ****** * ** **** *  **  
*** **  *  *  * *  * * **   *   * ***     ** **  *    *  **   * \n");
 *         ***     * *   
****  ***  *** ** ** *  ** ** *  if (sum1 == sum2)
***  *** **  * *  ****  ** * **   ***   *  **     *** *  \n");
* **   **   *  * **  * ** ****  *  * *
* ***  **** * *     ***   ***  **** 0;
}
answered by (209 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
prog.c:21:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system ("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(str);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccwAQ4Bd.o: In function `main':
prog.c:(.text+0x3c): warning: the `gets' function is dangerous and should not be used.
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 ***    *  *** *     * arr[1000];
 *   ****  ***   * * *** even=0,odd=0,i,n,sum=0;
   
** **  ******** * * * * ** *  *** **  *
   
    *  *   ***********  ***** ** ** **
        **  ** * ****  
   
******** ***   ***  **    *   * * ** 
 ***  * * *      * **
 **   ************* * **  ***** * *  * * *    ** ***
**  ***** ****    *   *****   **  *****  ** ***  ** ***  **   **   *  *   ******  * *  ***    *
****      * *  *  *** * *  ** *   **  * ****** * if(i%2!=0)
   ***  * * * *  *** *   *****  ** *  **   *    *   * * ******   * ** **   * *  * **   * ****  *     **** ******* * *** *** * * ***** **  * **  *  *
   ** *  ** *  *   **     
  * **    ** * * * **   *  
   
* ******   **  *** * ***     
*  *  *   * ** ** *** *  * 
*** ***    * * ***** **** **** *  * ** * *    *   * **       *  *  * ****   * * ****   ***** *  *      *  **   * *  ***
 *** *   * **     ****
** ** *    ** ****  if(sum%11!=0)
***   *    * * ***
*  *   ***** * *** *   ***  * * * *  *  **** ***** **** *   *     * ****  **  *** * **
** * ** * ****       *
   
  
 * *   ** *  ***** ***    
 * **  *   * *  ******    *
}
answered by (174 points)
0 0
prog.c: In function 'main':
prog.c:8:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
    scanf("%s",arr);
            ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main(){
* * **   * *** * ** * ** **  one=0,two=0,i,ans;
 ** *** *   ***   * *     ch[1000];
        * * * * ***  **  *** ****    **** 
    
  ** **** *  ** *      *** *       ** * **  
 *  * ** * *      *  * *     *** ******* *     **  * * 
 *   *  *    **  ** * *   ** **** ** *       *  ** *****    * *******  ** ** * *
   ** **  *  * **  *  * *** ** ***  *  * *   
 ***** **    *    **  *    ** * **  **  *   * ****
*** *******  * *** * * * * *      * ** ** *  * * * **    ** **   *** *****   ** *****   * **
 *  * ***   ****   ***     *** **   *  **** ** * **
    }
    
* * *  *       **  * *  ** * *   **** * 
    
*** ***   * *    * *  *** **   
** * ** *** *** **  * ***** *      ** **    *** *  
* *      * ***    * ** **    **
  * *****  *  * ** *  *     *  *   *****    *  *
}
answered by (192 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.107
©2016-2024

Related questions

2 like 0 dislike
5 answers
第二次期中考補考-第五題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38942 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 383 views
2 like 0 dislike
18 answers
第二次期中考補考-第四題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38941 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 1.1k views
4 like 0 dislike
16 answers
第二次期中考補考-第三題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38940 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 1.8k views
3 like 0 dislike
12 answers
第二次期中考補考-第一題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38938 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 959 views
2 like 0 dislike
3 answers
第二次期中考補考題庫 -10 唐．喬凡尼
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38168 - Available when: Unlimited - Due to: Unlimited | 288 views
12,783 questions
183,443 answers
172,219 comments
4,824 users