第二次期中考補考-第二題

3 like 0 dislike
2.7k views

若一個正整數的奇數位數字和與偶數位數字和兩者差的絕對值是11的倍數，則這個正整數就是11的倍數，否則就不是11的倍數。

請寫一個程式來判斷輸入的數是不是十一的倍數。

 

輸入說明：

會輸入一個正整數N，N不會超過1000位。

 

輸出說明：

如果輸入的數字是11的倍數就在螢幕上輸出YES，否則就輸出NO。

 

輸入範例：
 

11111111111111111111111111111111111111111111111111



 

輸出範例：

 

YES
[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 38939 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 2.7k views

16 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*   *  ** *  ** ****  *  * * *  arr[1000];
 **  * *  *** ** ** ** ** even=0,odd=0,i,n,sum;
    
*** ** * **    *  *  * * *   *** ***    ***** ***  * * *
    
  **  * *  ****     *****      *  * *  *
 * ******   *  *    * **
 **** *   *** ***  ******** * ***** * **   *
    {
* ** *    *** ****   * *** *    *   **** *****   *  *  ** *  **      *    ****** * **   * * ***     *       *  *  *  *  * *** *  * * ******  *  **** 
  ****     ***    ***** ****  *  ***   ***** * *   * *  * **  *      * *******   *  * *        * *** * * *** *** ***  **** *  *  *  *      
 * * *** ***    *   ***   * * * *    *     *  * *   ****   *     **  *     ** ***   *  * * * *     *** **    ** ******      *   ** *    ** * 
 ***  *********** * * * * ***  *** * ** **     *  *     *     *  *   *     *      * * * * **  *  **  ** * *  *    * **   *  *  * ** ***  *** ***  *  ****** *
    }
    
* ** *  *  * **** *    *   ***** *** *  * 
 ***  **   *   *****  **  ***** **** *   
* * ***   **** *** ** * *  ***   * ***   *** * *
*      * ***** * *****   **** ***  * 
    * * *** *** *  ** * **    *  ** * ** *  *  * *
    
**  * *** ****   ********   * 0;
}
answered by (215 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 *  **   **  *  **  * *** * num[1000]={0};
    int k, even, odd, i, j;
* * *  **  *   **** **** * *       *  **    ** ** * **
* *  *  * * *****  *** * **   
     ***   * *  **** ********* * ** *
* * ***  **       **   * ***** **  *  **** **    **  **         *    ***  * *
***** ** **   *   * * ** * *** *  * ***  *    **  *      *   
 *     * ***** *  ** ****  *******  *   ***** ********  * 
 *   *    * *  *** * * ******** ** ****  **  *  
   * **** *  * ** *** ***  ** *       *** 
 * *   * ** *  *** *****   * ***  *   **  * ** *  **
   ****** * **  *** ** * 
*  * *  **  * *   * * * * **  *  *  *  * **  *   * ****   
* *** ***      **    * ****  *  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:23: error: expected expression before ']' token
     scanf("%d",&array[]);
                       ^
prog.c:7:5: error: 'returm' undeclared (first use in this function)
     returm 0;
     ^~~~~~
prog.c:7:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:7:12: error: expected ';' before numeric constant
     returm 0;
            ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
    char c[1000];
     *   **  * * * *  *     *   **** * ** *  **** * 
    int a,i,x=0,y=0,z;
 *** * *  ** ** *   * * ***  * 
 *****      ******   *  *  * **  **   *   
    {
***   ***  **  *  **** * *** *  ***   * * * *  ** * *  *** *  *** 
 **** *    *  ** **  ** **** **  * ** *  *  *  ** **
 **** * * * *     *    *     **   *       *      ** *** *    *  **   **  * *** **** * * *
 *** **   ****** *     **    * **** ** *      * ** **** * **  *  ******* ** 
 * ** * * ***   *** *****  **   *   * * * ****   *** * * 
* ****    ****     * * ** ***  ** ***    ***  *   *    **
 **   *** ** *  ** * * ***    **     **  *   * **  ***  * **
**** ** * ** *** ** * *** *** ** **   *     * * * * ** *   * * **  *  * **  ** ********** **
 * *  *** *** ** * ****     ****   ** **** *** * ** *  ** *   ** **   * *** * * **  * 
** **      ****  *  *     **   *   ** ** *     *    ** **   *****
    }
     * **   **  *   * ** ******   *  *   *
* * *** * *  **      ** *** ** *  **** **** **  * *  *   * *  *   * *** *
    else
  **  ** *   *   ***  *****   * ** *  ***** *  ** * ****** * ** ***  ******
}
answered by (100 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main ()
{
  ***   ** ** ****   *   str[1000]={0};
***** * * ** **  *** ** * * j , n,sum1=0,sum2=0;
  * ***  **    * *     * *****  ******   *** **   *  * 
*  ** ****    **** *   * * * = strlen(str);
* *  ** *   ***  *   *  ** * *  = 0;j < n;j++)
  *       ** *****   *     
  ** **  *   ****  * *  *** *   **  ***** *        *   ** *  *  *   == 0||j%2 == 0)
 * **  ** *    ***  * *  *   ** ***  *** *    * * *  *  *  * ** *     = sum2 + str[j] -48;
    ** ** ** ******  * * **   *  **    ** * **  * *  ***  ***** if ( j%2 != 0 )
**     * ****   ** * ** *  * ** ** *** *** *  *  ***** * ***** * ** = sum1 + str[j] -48;
** *  ****  * *  *** **** **
    *     **  ****  * * * * ** (sum1 > sum2)
     **      ****  **   ******
* *   ** ** ***  **** *  *    * *******  * ******  *** ** - sum2) % 11 == 0 )
  ******  ***  **   *** *    **  * ** * ** *** *  ** ** **  * \n");
*  *** * * * **  **  *****    **  * * **      ***  
  * ***  * **     **** ** * **** *   *** *  ** ******** \n");
  **  *  *  *** *    ** 
* ** *  * ***    ****  ********* **** if(sum1 < sum2)
*** *   *** **   *    ***
**      *** * ****  *   *  **** * **  **  **    **  * - sum1) % 11 == 0 )
  ***** ** ****    *   ************** *** * * **     * **** **  \n");
   ** *  ********  ** **  ** ** *   *  * ** *  *** **
 * * * ***  * * * * **    **** *  **   *  ** ***** ** *   \n");
 *  *      * *** *** *  * ***
 * * *     **   *******  *  *      if (sum1 == sum2)
 *     **** ** ***  *    ** * * *****  * **   *  ***  *  \n");
  *** * **     *    ***  **  ***  *   *  * * ** **
**  * *****    * *** *  ** *   * 0;
}
answered by (209 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
prog.c:21:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system ("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(str);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccwAQ4Bd.o: In function `main':
prog.c:(.text+0x3c): warning: the `gets' function is dangerous and should not be used.
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*       * ** *  * * arr[1000];
*   *     * *** *    ***  even=0,odd=0,i,n,sum=0;
   
  * * *           *   * ** *  **  ** * ******
   
** **** *   **  * ****  *** * *    ******
 *  * **  *  * *  
   
* * * ***** ****  ** * ** *    ** **  * 
  *     **  * ****
*  ***** **   **  * *****  ***** **  * **** 
 *****  **  **** *        *  * *    *** **  *    * * * ** * **      *   * **
   **   * *  *****    * * * ***   *  **     if(i%2!=0)
  *   *  **  *    *   ********   * ** *   *    ** *  * * *** *** **  ****     *  *   *     ** * * **  *   **   ** *  **    *    **  *** ** *     *** ****  ****
 * ***** *         ****     
  **   ** * ** * *  *******
   
 *    * *  * *  ** *** *****  *
** * ****       **  ***
  *  ** ****  ** ** * **   *** *******  *** *  * ****  * ****** ** * **  * *     **** ***** **  * ** *  *    *      *  * *** ***
*        *  ** ** **   
    * **     **  *   if(sum%11!=0)
***   ***  *  **  * *
   *  ** * ** ***   *** *  * ***  * * ***  *   * * *********  *   ***  **   *
  *  *  *  **     *
   
  
 * * ** * *    ***   * **
**** ***       *     *** **     
}
answered by (174 points)
0 0
prog.c: In function 'main':
prog.c:8:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
    scanf("%s",arr);
            ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main(){
  ** * *   * *  * **   **  one=0,two=0,i,ans;
* * *  ** ** **  *** * ** ** *   * ch[1000];
 **  ***        *       *  * ** ****  * ***  *   *   
    
**** * * ***  * *   **   ** ** **  **  ***  
**** **  * * * ** ** ** * ***  * *  *    *  *  * **
* * **   *  *  **   *  **** * **  * *  ****** *  * *** *  ** **     ** ***   *  ** 
*  ***  * ** *   *****   **    * * * *  * *** * ***
* *****   ******* * ** *   **     *    * **   * * *    *  *
 ** ** * *** *    * *** ***   *  * * *  ** * ** **** * ***   ***    ***** *
*  *  *     ** ***  * * ** *****  *
    }
    
* *   *  **   * ******* *  *
    
*   * * ***  **  **** **     *  *
 **   ** * *** ****   *   ** * *  *   ** **** ** 
 ***  *      * ***  **  * * * * **
 ** ** ** ***   **  *   **** *****    ****  *  **     
}
answered by (192 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.17
©2016-2024

Related questions

2 like 0 dislike
5 answers
第二次期中考補考-第五題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38942 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 828 views
2 like 0 dislike
18 answers
第二次期中考補考-第四題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38941 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 2.2k views
4 like 0 dislike
16 answers
第二次期中考補考-第三題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38940 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 3.8k views
3 like 0 dislike
12 answers
第二次期中考補考-第一題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38938 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 1.9k views
2 like 0 dislike
3 answers
第二次期中考補考題庫 -10 唐．喬凡尼
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38168 - Available when: Unlimited - Due to: Unlimited | 468 views
12,783 questions
183,443 answers
172,219 comments
4,824 users