第二次期中考補考-第二題

3 like 0 dislike
6.5k views

若一個正整數的奇數位數字和與偶數位數字和兩者差的絕對值是11的倍數，則這個正整數就是11的倍數，否則就不是11的倍數。

請寫一個程式來判斷輸入的數是不是十一的倍數。

 

輸入說明：

會輸入一個正整數N，N不會超過1000位。

 

輸出說明：

如果輸入的數字是11的倍數就在螢幕上輸出YES，否則就輸出NO。

 

輸入範例：
 

11111111111111111111111111111111111111111111111111



 

輸出範例：

 

YES
[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 38939 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 6.5k views

16 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 ** ** ***  * *** **  *     * arr[1000];
   *  *   *   *   *  * **  *  even=0,odd=0,i,n,sum;
    
** * ********  *  * * **     ** * *  *   * *  **
    
*   *** *  ** *   ** * ****   *  ****   *   
  * *    ***   *  * * *       
 **  **     *   *** * *  *      **   *  **  *
    {
 * ****   *      ***** **   **  *** *     **     *****  * ** **  **** **  ***   ** *        *  *    * **  ** *  * *  *  *    **  *  **    
**      **  *** **     *     *** * * *    ** *    * ** ** ***** **  *  * ***  *  ****  ** *  *  *  *        * ** **  *   *  ** ********* *
**    * **      ***  ***   * * *** * *  ** *** *       ** *   *    *   *  * * **   ***** ** * ** *  ***   *  * *    ** ****   *    
 *  ** * * *  *   * ** * *** **** ** ***  ****     *    *      * *  **   *    *** * *   ** *** *    **   ****  *   * **    * * ***  *  ** *  *  
    }
    
*      * * **  **** * ****       **  
*** * * **  ***   *   *** *
**** * *  ***  ** **  ** *** **  * **** ** * *  ***
* *    *** *** *  ***  **  *  **  *
 *   *  ***   ** *** **** *****   * ** ** * * **
    
   *  ** **  **** * ***  *****  0;
}
answered by (215 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
  **     ***   ***  **  * *  num[1000]={0};
    int k, even, odd, i, j;
* * * *** * * *  ** *** * *  * *    * * *   *   *   ***  **  
 ** * **** ** **   ****** ****
      **  *    *  * *      **    *
** **** **  *** **    * ** *  ** * * *  ** **      **   * *    * * **  *  *  
********   *  ** *    *       **  *     ** ** **   *  *  *****    *
*   *  ***** * * * *     ***** *** *** * ** *** *           *  **
   ******  *  *  ** ****** ** *  * * ****   * *
      ** *  * ************    *   *** 
 ** **    * *  *  *  *  *** * **** ** *    *** *  *****
*  **   ********  **    **** 
 * * * **  ****** *   **  ** ******   ** *       ** *   
  *  * *   *        * *  * * **   0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:23: error: expected expression before ']' token
     scanf("%d",&array[]);
                       ^
prog.c:7:5: error: 'returm' undeclared (first use in this function)
     returm 0;
     ^~~~~~
prog.c:7:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:7:12: error: expected ';' before numeric constant
     returm 0;
            ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
    char c[1000];
* *   *****  *   * *  * * * ** *** **** * * *    ***  
    int a,i,x=0,y=0,z;
 *   *  * * ***   * **  **   ***
*  * * *** ** *      **  **** *** *** *  *    **  *
    {
** * *  *   **  ** **  *  ***  ***  *  *  *   * ** **  *   *
 * *** * **  * ** ***** **  **  **  * ******    *  *
*  *     * ****    *       *     * ******   * **  *** ***   ** **  ***  *  * **    ** *** ****
 *  *  **     *  *****   **** ** *  ****  *  *   **   * **   *  *   * ****** * ***   * ** *  *  
 *   **  **   *  **** *  ** * **  ** * ****   ****
***   ***   ***     ***** **** * *     **** *** ** ** *
 *  * *** **   * *  * * ***** ****** ** ***    * *
* * * *  **** * ***   *** * *   *  **   **     *      **** *  *  **** *** ***  *   ***  
*  * * ***** * **** ****   *** **** *** * * * * * ***   *   ***  *   ***     **  *** **  
     * * ** * ***   *** ***  * * ** *  **   *  * * * **      * 
    }
    *  ** *    *  *   ***** **  * *
*    * ****** *  ** *   ** ****  * ******     ******  *  *   * *   ****  **
    else
*    *    * *  ******* ***   ** * **     **  *** ** * ***   ** *     **  ****** 
}
answered by (100 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main ()
{
**** *****  *   ** ****    ** str[1000]={0};
*  * *  *   *** *  *   *  *  *  * j , n,sum1=0,sum2=0;
   *   ******* ** **  *  *** * * *   * * ****
 ***  ** * **   *  *** *  *  = strlen(str);
  ** *  ***   * ** **  **   * * = 0;j < n;j++)
**** * *  * **   ***     **
 *** *  *** *** **  * ** * * *    *     ******* * * * **  *** ****   * * **    == 0||j%2 == 0)
      *  ** ** *   ** * ** * ** * *  *  *    *  *******     * ***   = sum2 + str[j] -48;
 * *  **  *   **** ** ** *      **    * **** ** **   *  *  * *****     if ( j%2 != 0 )
****   * *   *    *****   * **  * *   * *** *****  *** ** ***  **   *  **** = sum1 + str[j] -48;
   *** * * **   *  **** *   * 
 ** *** * *   **  **  (sum1 > sum2)
 *  **   ** * *    *    ** 
 ** *  *  *  *  ********* * *******  * ******  * *   - sum2) % 11 == 0 )
** * ***  *   *  * * ** ** ** *  *  **   *  ** *  **  ** **   \n");
** *** * * ***  **** ****  * *     *****  ***  ****** 
 *    ***  ** ** ** **   *   *   * * * ** * * **** ** *** **  \n");
* *  * *    ****  * *  * **  
 **   ** ****** ********** ***  ** if(sum1 < sum2)
**   **    *  **     ***  * *
*  **** ***** ***  *   ******  **  * * * **  **    - sum1) % 11 == 0 )
 ** ***** ** * **    *   ** * *   * * **** *** ***  ****  *     \n");
 * * *   ** * *  * **** **  ** **** * ****       
    **     *   ******  *  ***  * *    *** * * ***** ****    \n");
**  * * *  ******* *** *  **
***   * ** *  **  *  * *  * * ** if (sum1 == sum2)
   ***** ** * ** ** * *  ******   * *  **   ** * *   **  \n");
    **          *  **   **  * *   **** ** 
* * ****     *  *  * *  *   * 0;
}
answered by (209 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
prog.c:21:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system ("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(str);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccwAQ4Bd.o: In function `main':
prog.c:(.text+0x3c): warning: the `gets' function is dangerous and should not be used.
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*  * *   ** ****  ***  arr[1000];
* ***** * ***     *** even=0,odd=0,i,n,sum=0;
   
 *    * *  ** **** **  * *   * ** ** ** *   
   
    * *  * ***  * * *     *  *********
***  * ***  *    *   ****
   
 *** **  ****  ***     *   ** * 
**    ** *  *** **  **
 *  ****** *   *  ** ** **  ** *  *   **  * *  
  ** * ** **  *** * ** *      ** * ***  **** * ********   ***      **    **  *****    ** **
 *   **** ***      * *** * * ***   * * ** ** if(i%2!=0)
  * * * * **   **   **  *      ******   **   *  ** *  ** ***  *     ** *** *** ****     **  ** **      ***  ** ***    ****  * *   * **  * *       
 *     * *****  * *    
*   **  **   *       *** ***
   
*         * ** **  * ** *  ***
***** **    *  ** ****  
**  * * * ***   *   ***  * **  ***   * *   ***  * *  * * * * *       *    * * * * *  **  *   * **** ** *** * *  *    * **   **
     ** * * *** *** **
    *  * * *   * ** * * if(sum%11!=0)
* * * * *   *** *  
         **     * **   *  * *    ******  ***  **  *  *       *  * ***  *  *******
 **     ****** **  * ** 
   
  
****** **   *** * ********
* ** **     **   * ***  * **
}
answered by (174 points)
0 0
prog.c: In function 'main':
prog.c:8:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
    scanf("%s",arr);
            ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main(){
 *  *    **  **  *     * ** *** one=0,two=0,i,ans;
  *   *  *  * ***  *  **     ch[1000];
*** * * * *  **  **    ***     *  ** ***  *  * **
    
 ***  *  ** ***     *  * ***** *****        ** *
  *** * * * ** * ** *  **    * **   *  ***  ***   *  ****  *  
** *  * * **      **  ** * *     * ***  ** ** * * *** * * ***      ****** *    *   
 *** ** *  *   * ***     * ** ** * ** ** **
*** **  *  ***    *    * * *     *   *  ** * 
 ***** ** **    ** *****  *  * *  * ** ** *****     ******     * *** * * ** *  *  **
** **** ** *  ** *  * * *  **   ***    ** **  ** ** 
    }
    
**  *  * ***  *****  ** * 
    
    *    *   * ***  *  *      ** **
*** ***** *   *  **       *** * ** ***** *  *** * ** *  ***
    ***  * **  *  ** * ** *   * ** 
    **  *   ****  ****  * ** ** * ****  *  *  *   *
}
answered by (192 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.192
©2016-2025

Related questions

2 like 0 dislike
5 answers
第二次期中考補考-第五題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38942 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 2.2k views
2 like 0 dislike
18 answers
第二次期中考補考-第四題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38941 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 6k views
4 like 0 dislike
16 answers
第二次期中考補考-第三題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38940 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 9.4k views
3 like 0 dislike
12 answers
第二次期中考補考-第一題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38938 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 4.6k views
2 like 0 dislike
3 answers
第二次期中考補考題庫 -10 唐．喬凡尼
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38168 - Available when: Unlimited - Due to: Unlimited | 1.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users