第二次期中考補考-第二題

3 like 0 dislike
1.4k views

若一個正整數的奇數位數字和與偶數位數字和兩者差的絕對值是11的倍數，則這個正整數就是11的倍數，否則就不是11的倍數。

請寫一個程式來判斷輸入的數是不是十一的倍數。

 

輸入說明：

會輸入一個正整數N，N不會超過1000位。

 

輸出說明：

如果輸入的數字是11的倍數就在螢幕上輸出YES，否則就輸出NO。

 

輸入範例：
 

11111111111111111111111111111111111111111111111111



 

輸出範例：

 

YES
[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 38939 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 1.4k views

16 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
**  *  *** ** * * **    *    **  * arr[1000];
*  *  * **    *   ** ** * * *** even=0,odd=0,i,n,sum;
    
    * * **  * *  * * **  **** *   ** * *  ***  *
    
* ** **  **  **  * *** ***    **** ** * * 
**** * * *    **        *  
* * *    *        *  ** * ** ** * *** * ** * * 
    {
  * *  ******** *  * *   *** * *  ***** ** *** ** *  *  *  * ****  *****   * **  * *  * * ***  *  ** * * * **  **  **  **  *  *** ** * * *  ** *  *   **
 * *        *     *** **** * *     * ** **  **  ***** * ** *  * ***     * * *  ** **** * *  * *** * *** *   **   **   **   **  * ****   *      * * *
*       ******  *** ***   * * * * ***   **     ** **   * *  ****  * **   *  *  * * ** ***   ****** *** **     **  *   *********** ****
  ** * ********  ** * *   ** * ** ***  *  ** *  * ***  * ****   *   **     ** *   *  *** * **  *** * *    ***  ***   * *   *   ** 
    }
    
* *  * ** *** *  *** ** ***  *
**   **   * * *   * ** * ****  
** * * **  *  ******  ** * * *        * * **  * ***  *  
*** *  **** *    *   ** ** *
*  *   **  * * **  ***  ***  ******  **      ** * *
    
 * * ******** **  * *  ** ****   0;
}
answered by (215 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
          *  ***  * *** *  num[1000]={0};
    int k, even, odd, i, j;
 **   *    * *  *    ********* *   **  * *****    *** * *
 **    * *   *    *  * * *  * **
* *   ***     *** *** * *  **   
***** * *     * ** * * ** **  *  **    * ** ** *****    * *  
** * * ******   ** *  * **** * * *   * *****      ** *   ** 
 *   * **   *   *  * * * ***  **     ******  * * * * ***   
  * *   ** * *  * ** *** *  *   *** **   * * *** *
**            * *** ****  **** * ***** * **** *
* * **** ***     ***** *****  **  *  ** ****
   **   ** ** ** * **     * 
  **   **  **    *     ***    * **  * * **  ******   ** *  **   
** * ** ** **  *** * ****  *  * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:23: error: expected expression before ']' token
     scanf("%d",&array[]);
                       ^
prog.c:7:5: error: 'returm' undeclared (first use in this function)
     returm 0;
     ^~~~~~
prog.c:7:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:7:12: error: expected ';' before numeric constant
     returm 0;
            ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
    char c[1000];
 * ** *****  ***  **      *  **    ****    * *** **  **
    int a,i,x=0,y=0,z;
*      * **  * *  *******   * *** **  
*    *  ** *     **      * *  *** * **  **   *
    {
  *  ** * * ****    **  *  * *  ** ** *  * * * **  **  ***  **
 **   *** ***  * ***  ** *  **   * * *   * **   *** *
*** **  *     *  **** *** **     ***    *****  ****   **  ******   ******  *   *   * * 
* * *****    *  **    ***   * **   ** **  ***     **   **    *  * *   * **  ** * ** ** *  
*****    * * *   **   * ***   *** *     ** *    * 
* ****  *  * **  * ****  *  *    *  *   * *  *   **   *
*** *  **   ***  **   * ***  ** * *  ***  *  *    *** 
*  ** ** *      *** * *** *  ** ***   * * *  * ***     *** ** * *** *** *  **  **   *   *   
** *     ***** *    **  ** * *   ** * ** ** ** * *      **   *  **  * * *   
***  * *   ****** *  *** ** ***   **  * *  * *  ** **** **  
    }
 ******  * ***  * ** ** * **  ** **  ***
* **  *  *  ** **  ****  ** * * * * ******* **   **   ** *  * * * ****
    else
* ***       *** *  ***  *   * *** ****       ***   * * * *     *** **** *  *
}
answered by (100 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main ()
{
 ***     ***** * ** * ***  * str[1000]={0};
**  * *    *     *      *  *** j , n,sum1=0,sum2=0;
** ***** *  * ****  **** ****  *    * * ***   * **   ** ** *
**    *  ** **  **** * *  = strlen(str);
****** ** ******     **  **   * *** = 0;j < n;j++)
  **  *****   *  ** ***  
 **  *** **   ******** ***  **   *  ******  * * ****** * *   **** *****  == 0||j%2 == 0)
   *  ***  *  ** **  ***    *   **  *****  *** *   * * ** **   = sum2 + str[j] -48;
*  ***     **** *** **       * **    *   ***** ****    **** *** ** if ( j%2 != 0 )
***   ***  ***   **** *     ***   * *  **** *** *     ** * ** * *  *  *   = sum1 + str[j] -48;
  *** *** ** **    *   ***** **
  ** *  * ***** * ** *  *** * (sum1 > sum2)
*   *    **  * * * * *  
 * * * *     * *  ***  * *  ***     *      * *** ** * - sum2) % 11 == 0 )
*      *    * * ** *  ***** *  *****  * **   * *****   * ****  *** \n");
 * * *     ***** *    **    *   **   ** ** ** ** **** *
   ***   * * *  * *   ** ** **  * *  * ***  * *** * *    ***  \n");
 * **********  **** * *   **  
*    ** ** **** *     *    if(sum1 < sum2)
 *    **  ***** **    *****  
     * * ***  * ****  *   * ** *  ***   *   *   *  *   - sum1) % 11 == 0 )
 * *    * ** ***** * *   **  ** *    * *** * ** * ***** * \n");
*  *** ** ** * ** ****      **     ******* **  * ***  
   *  * * *    ***   * *** * ** ** *** **  *  ***  *  *    *  \n");
 **     *  *** *  **    ** *  
   *  * * ***  *** ***    *   * if (sum1 == sum2)
  **   ***** ***  **** ** *** * **      ** * **  * ** *    \n");
   ******* *   * *   * ***  *  **    ** ** 
******   *     * *  *   **  ***** *** 0;
}
answered by (209 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
prog.c:21:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system ("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(str);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccwAQ4Bd.o: In function `main':
prog.c:(.text+0x3c): warning: the `gets' function is dangerous and should not be used.
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
  *   *  ****  * *  * ** arr[1000];
*** *  ***     **   even=0,odd=0,i,n,sum=0;
   
    *    * ****   *      **  *  * ** *  * ****
   
*     ********  * ** * * ***
* ** ** * * * *****
   
**     *   * ** ***  **  ** *  ** ****
 * * ** * *       ****
*    *        * ****** ** *** * ***  ****** 
* * * *     *   *  **        *** ** *     * *****  * ***     **    ******** * ** ***  * 
*** **  * ***   ** *     ** **  **  **  * *   * * if(i%2!=0)
*  *  *      *    *  **   *  *  *****  *****  **   **       ***   **   ** **  ** ****  ********   *  *** ****  * * *** *  ** ** ** *  **** **  *
 **    ** * ***  ***    
* *  *   ** ****  ** * *** * 
   
 **  **** *  *   * ** * * 
** *** ******* * *******
*   ******** *  ***** ** ** *   *** * * **  * *  *** ** *  *  * ********* ****  *       *   **** * *** * * * *** ***   *  
**** *   * ** * **  *  * 
  *   ** * **    **** * *    if(sum%11!=0)
*   **** **  *  * *  *
* * *         *  **  **      * *  * *** *   * ** * ***** ***   **   **** 
* ** * * ****** ** **
   
  
 ***        *  ***     ***
*          * *** *** **   *   
}
answered by (174 points)
0 0
prog.c: In function 'main':
prog.c:8:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
    scanf("%s",arr);
            ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main(){
* *  *** ***  * * *   *    *** * one=0,two=0,i,ans;
 ** **  ** * * *      ** *   ch[1000];
**** *** * **  ** **   ****** *  ** * ****   *** *  * 
    
  *** * * ***** * ** **   ****  * *  *  * * 
   *     ***  ** ** *  *** **       **   *     **  *  *
*  * ***    ***  *   * * *  *** * *** *   *****  *    *  *********** **  * **  
 ** *  *** *** * * **   * *  ** * *  * ***  *** 
*  **         *  * ** *   ***   * *****   *   *  *  * 
*      * ** ****  *  ** *   ** **       ** *    * * *  *   * *   *** *****
 *  ****  * * *    **   * **  **   *    
    }
    
** * *** ** * *****  *  * *** ** *
    
**** *** ** ******     **    ** * * ** 
******  **  ****   *  *  ** **** *  **** ****  * 
* * ** *** *****  *** ** * ***
 * * **** *** *** ** * ***  **   **** ** ** **  *  *** 
}
answered by (192 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.131
©2016-2024

Related questions

2 like 0 dislike
5 answers
第二次期中考補考-第五題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38942 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 383 views
2 like 0 dislike
18 answers
第二次期中考補考-第四題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38941 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 1.1k views
4 like 0 dislike
16 answers
第二次期中考補考-第三題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38940 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 1.8k views
3 like 0 dislike
12 answers
第二次期中考補考-第一題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38938 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 959 views
2 like 0 dislike
3 answers
第二次期中考補考題庫 -10 唐．喬凡尼
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38168 - Available when: Unlimited - Due to: Unlimited | 288 views
12,783 questions
183,443 answers
172,219 comments
4,824 users