2 like 0 dislike
1.4k views
請依下列的定義完成函數。

 

#include <stdio.h>

 

///

///函數名稱 count

///函數功能 計算字串當中出現特定子字串的次數

///參數說明

///str 要被搜尋的字串

///key 子字串

///

int count(const char str[], const char key[]);

 

int main()

{

   char str[1000], key[1000];

   gets(str);

   gets(key);

   printf(“子字串共出現 %d 次”, count(str, key));

   return 0;

}

 

int count(const char str[], const char key[])

{

 

}
[Normal] Essay (Open question) - asked in 2017-1 程式設計(一)AD by (30k points)
ID: 38147 - Available when: Unlimited - Due to: Unlimited
| 1.4k views

5 Answers

0 like 0 dislike
Hidden content!
#include **** * * * ***
#include *** ** * ** *

int * ***** char str[], const char key[]);

int main()
{
* **** * *** * * str[1000], key[1000];
* **** ** * * **** *
*** * * ** *** * * **
* ** ****** *** * ** * ** * * * * %d 次", count(str, key));
** * ***** * * 0;
}

int * * char str[], const char key[])
{
** ** ** * ** ** ** *** * * ** ** ** *
*** **** **** ** * ******* * * * key);
** * * * ** **** *****
* ** ** *
** **** *** * * * **** ** *** ** * * * * ** **
* * * * **** * **** *** *** ** ** * **
* *** *** *** * * * * * **** **** ** * * ** * * * key);
** ****** ** **** *** * *
* *** *** * * * ** * count;
}
answered
0 like 0 dislike
Hidden content!
#include *** ** ***

#include **** * *** *



int * ** * char str[], const char key[]);



int main()

{
** ** * *** * * str[1000], key[1000];
* *** ** * *
** * * ** *
*** ** * ** **** * * *** *** * ****** %d ** * count(str, key));
* **** ** *** * 0;

}



int count(const char str[], const char key[])

{
* * ** * * * ** ******* ***** * *** * *
** * ** ** * * * ** * *** *** key);
**** * * * * *** ** * **
** * * * ** *** *
* * ** ****** * * *** * ** *** ** ** ** * *** ** *
* * *** ** *** * * *** * ** * * ***
* * * ******** ** * **** * ******* * *** key);
* * * ****** * ***
* *** * ** ** ** * count;

}
answered by (190 points)
0 like 0 dislike
Hidden content!
#include * * ** ****
#include * ** ** * ***

int * **** char str[], const char key[]);

int main()
{
****** *** ** **** *** str[1000], key[1000];
  ** ** *** **
  * * ** * ** **
** * * ** * * ********* * **** * * %d * *** ** *** key));
* * * ****** 0;
}

int * * char str[], const char key[])
{
** * * * * * *** ***** ** * * * *****
*** * ** * **** * *** ** key);
*** * * ** ***** * ** ** *
* ****** * ****
* * *** *** * ** ***** ** ** * * * ** *
*** * *** **** **** ** **** *** ****
** * * * * * * * ** ****** **** ****** * * * ** * *** key);
* * *** ** * ****
** * *** * *** * * ** * count;
}
answered by (174 points)
edited by
0 like 0 dislike
Hidden content!
* * ** ** * *



int *** char * * *** **** **



int ** *



{


* *** * ** * ** ** * * **


** ** * * * *** * *** *


* ** * ** ** * * * * *


* * ** * * ** ** * ** * * ** *** %d * * * ** ** ****


* * * *** * 0;



}



int ** char * * * * * *** **



{



int x=0;


*** *p;



do



{


* *** *** **** *** * * * **


** * * * **** ** != NULL)



{


* * * ** ** ** **** * ** * ** ** ***** * * *


* * *** ** ** ** * * * *** ** * * *



}



}


* *


* x;



}
answered by (160 points)
0 like 0 dislike
Hidden content!
#include * ** **** * *
#include ** * ***** *

int *** char str[], const char key[]);

int main()
{
* * * * *** *** str[1000], key[1000];
**** * **** *** *
*** * ** *** ** ** * ** *
** ** ******* * ** * %d 次", count(str, key));
** ****** *** * *** 0;
}

int * * char str[], const char key[])
{
*** **** *** * * * ** * *
* ** * ***** * * * ** * * *** * key);
*** ** * * * *** * **
* * * * **** * * ** * * * *
** *** ** * * *** * * *** * *** *** * *** *
* ** ** * *** ** ** * * ** ** ****** * * * * ***
* ** ** ** * * *** * * ***** ***** * * ** * *** ** * key);
* *** * * *
** *** * * ** **** * * count;
}
answered by (30k points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.92
©2016-2025

Related questions

2 like 0 dislike
8 answers
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38155 - Available when: Unlimited - Due to: Unlimited
| 3.5k views
2 like 0 dislike
6 answers
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38154 - Available when: Unlimited - Due to: Unlimited
| 2.3k views
8 like 0 dislike
3 answers
[Exam] asked Dec 8, 2017 in 2017-1 程式設計(一)AD by Shun-Po (18k points)
ID: 36175 - Available when: 2017-12-08 18:30 - Due to: 2017-12-08 21:00
| 1.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users