2 like 0 dislike
439 views
請依下列的定義完成函數。

 

#include <stdio.h>

 

///

///函數名稱 count

///函數功能 計算字串當中出現特定子字串的次數

///參數說明

///str 要被搜尋的字串

///key 子字串

///

int count(const char str[], const char key[]);

 

int main()

{

   char str[1000], key[1000];

   gets(str);

   gets(key);

   printf(“子字串共出現 %d 次”, count(str, key));

   return 0;

}

 

int count(const char str[], const char key[])

{

 

}
[Normal] Essay (Open question) - asked in 2017-1 程式設計(一)AD by (30k points)
ID: 38147 - Available when: Unlimited - Due to: Unlimited
| 439 views

5 Answers

0 like 0 dislike
Hidden content!
#include ** ** * * * *
#include * ***** ** * * *

int ** * ** char str[], const char key[]);

int main()
{
* * * * *** ** ** * str[1000], key[1000];
* * * * ** ****** **** *
****** *** ** * ****
* *** *** ****** **** *** ****** * * * %d 次", count(str, key));
* * ** * * * *** ** 0;
}

int *** ** char str[], const char key[])
{
*** *** *** ** * * * * ** * * * ***
* * * *** ** * ** ** *** key);
** ** **** * ** ** ** * *
** * **** **** ** **
* ** ******* * * *** ** ** ** *** ** *** * *
* * * **** * * ** * *** ****** * ******* ** *** ***
**** ** *** *** ** *** * ** ** * * ** ** ** key);
* **** *** *** * * *
** * ** * * ** * ** count;
}
answered
0 like 0 dislike
Hidden content!
#include ** * * *

#include *** * ** *



int * char str[], const char key[]);



int main()

{
***** **** * ***** str[1000], key[1000];
*** ** * **** **** *
****** * * ** ** * *** **
* * ** * ***** * *** ***** ** %d ***** count(str, key));
***** * ***** * * *** * 0;

}



int count(const char str[], const char key[])

{
* * * * * *** * ** * * * *** *
** * *** ** * ** ** *** * * ** key);
* ** ** ** * * ** ** **** * * **
** **** ** * * * * * *
* *** * *** * *** * * * * * * *
* * * * ** * * * * ******** * ** **** ** * *
* ***** * * * ** * * * * * ** ** * ** **** * * key);
* * *** *** ** **
*** * * *** ** * * count;

}
answered by (190 points)
0 like 0 dislike
Hidden content!
#include ** ** *** *
#include * * ** * *

int ** char str[], const char key[]);

int main()
{
* * * * * * str[1000], key[1000];
  * *** * ** * **
  * ** *****
* * * ** ***** ** * ** **** **** %d * * *** key));
* * * ** ** *** 0;
}

int ** * * * char str[], const char key[])
{
* *** *** * * ** * ** *** ** *
****** ********* *** * * ***** key);
***** * ***** * ** * *
** ** * * *** *** **
* *** * * * ** * * ***** * * * * ***
** ** * *** * ** ***** ** ****** * * ** ***** ** *
* * *** * ** ** * * * ** ** ** * * * * key);
* *** **** * *** *
* * *** * * * * * *** * ** count;
}
answered by (174 points)
edited by
0 like 0 dislike
Hidden content!
*** ** ***** * * ** *



int * char * ** * * * *



int ***



{


* * **** * * * * ** **


* * ** ** ** * ****


** * * * *** *** ** *


****** *** *** * ** * ** ******* ** ** ** %d ** * * * **


* * ** * ** ** 0;



}



int * char * ** * *



{



int x=0;


*p;



do



{


** ** * * ** ****** ** * * **** * *


***** ***** ** * * ** != NULL)



{


* * *** * **** * * **** * * * * * * * * ****


* *** ** * **** *** * ** ** * * ** *** **



}



}


* ** **


*** * x;



}
answered by (160 points)
0 like 0 dislike
Hidden content!
#include ** * * ***** **
#include ** * ** **

int * * char str[], const char key[]);

int main()
{
** * * * str[1000], key[1000];
** * * *** *** * * ***
**** * * * * *
* * * * * ** * * * * * ** * * %d 次", count(str, key));
* * * ** * ** ** 0;
}

int * ** char str[], const char key[])
{
* ******* ** * * * ** * ** * ** ** * * *
* * ** *** * * ** ****** ** * ** * * key);
* *** * *** ** *** ** * * *
** * *** * * * *** **
* ** * * * ** ** ***** *** ** * *** * ** **
** *** *** **** * * * * * * *** * * *
** * * * ** ** * * ** *** * * * * ** *** * *** key);
* * * * ** * *
* * * ** ** * * count;
}
answered by (30k points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.186
©2016-2024

Related questions

2 like 0 dislike
8 answers
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38155 - Available when: Unlimited - Due to: Unlimited
| 1.3k views
2 like 0 dislike
6 answers
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38154 - Available when: Unlimited - Due to: Unlimited
| 831 views
8 like 0 dislike
3 answers
[Exam] asked Dec 8, 2017 in 2017-1 程式設計(一)AD by Shun-Po (18k points)
ID: 36175 - Available when: 2017-12-08 18:30 - Due to: 2017-12-08 21:00
| 432 views
12,783 questions
183,443 answers
172,219 comments
4,824 users