2 like 0 dislike
1.4k views
請依下列的定義完成函數。

 

#include <stdio.h>

 

///

///函數名稱 count

///函數功能 計算字串當中出現特定子字串的次數

///參數說明

///str 要被搜尋的字串

///key 子字串

///

int count(const char str[], const char key[]);

 

int main()

{

   char str[1000], key[1000];

   gets(str);

   gets(key);

   printf(“子字串共出現 %d 次”, count(str, key));

   return 0;

}

 

int count(const char str[], const char key[])

{

 

}
[Normal] Essay (Open question) - asked in 2017-1 程式設計(一)AD by (30k points)
ID: 38147 - Available when: Unlimited - Due to: Unlimited
| 1.4k views

5 Answers

0 like 0 dislike
Hidden content!
#include *** * * * * *
#include *** * *

int * * char str[], const char key[]);

int main()
{
**** ******* * * * str[1000], key[1000];
*** * * * ** ** **** **
* * ** ****** **
* * * * * *** ** ** %d 次", count(str, key));
* * * ** ** *** * * *** 0;
}

int ** char str[], const char key[])
{
* ** * *** ***** ***** ** * * **** *
* * * * ** * * ***** * ** ** key);
* *** ******** * *** * *
********* **** *** * *
* * ** ** * * ** ** * * * *** * ** ** **
** **** * *** * * * * *** * * *** * ***
******* * ** *** ** ** *** ** * ** * ** * *** *** ** *** key);
**** ** ******** ** ** * *
** * * * ** ** **** ** count;
}
answered
0 like 0 dislike
Hidden content!
#include * * ** * ***

#include *** * *** ******



int ** * * *** char str[], const char key[]);



int main()

{
* *** *** * * * ***** * str[1000], key[1000];
* ** *** * * * ** * * ***
* * * *** * * ** * **
** ** * * **** *** * * * *** ** %d **** count(str, key));
* *** * * ** * 0;

}



int count(const char str[], const char key[])

{
* ** ** * ** *** * * ** * *
* ** ** ** *** ** *** ** * * * * key);
* * **** * * *** * ** ******
** **** * * * ***
* * *** ** * * * * ** ** ** *** ******** *
* ** * ****** *** * * * * * ** ** * ***
* ** *** *** ** * ** ** *** * ****** ** * ** ** key);
*** ** * ***** ****
* **** * ** * * * ** count;

}
answered by (190 points)
0 like 0 dislike
Hidden content!
#include *** ****
#include **** ** * ** *

int * *** * char str[], const char key[]);

int main()
{
* ** * **** ** * str[1000], key[1000];
  * * * * ** *
  ****** * **
**** ******** * ** * * * ** * *** %d * * * key));
**** *** ****** ** * 0;
}

int **** * char str[], const char key[])
{
* * * * * *** * * * * *** *** * *
* ** ** * * * * * * ** ****** * *** * key);
*** ****** ***** * *** ** * *
** * **** * *** * *
* * ** ** * * * **** * *** * *** * ** ** *
* ** ** * * **** * * ** ** * ***** *** *** * *
* * * * ** * * * * ** ****** * * *** * * * key);
* * * * **** * ** * *
** * ** * * ** * count;
}
answered by (174 points)
edited by
0 like 0 dislike
Hidden content!
* * * * ** *



int ** char * ** ** * ** * **



int ** *



{


*** ** * * * * * * ***** * **


** * *** * *


* * * *** * *** *


*** * ** **** * *** * *** * **** %d * ***** *** ***


* * ** * ** * * 0;



}



int * * char *** * **** *



{



int x=0;


** *p;



do



{


*** ***** *** ** * *


**** * ******* * * ** **** != NULL)



{


* * ** * ** *** *** * *** *** * *** ***** *


* * ****** * * * * **** *** ** *** ***** * ****



}



}


* * **


*** * x;



}
answered by (160 points)
0 like 0 dislike
Hidden content!
#include * *** *
#include ** ** ** ***

int *** * * char str[], const char key[]);

int main()
{
* ** * *** * * ***** str[1000], key[1000];
** ** * ****** ***** *
* ** * * ** ** * ***
* * ** ***** * * ******* * %d 次", count(str, key));
* *** *** **** 0;
}

int ** * char str[], const char key[])
{
* * ** * *** ** * * ** *** ***
* * * ** * *** * ** * ** key);
** ** **** * ** * * * ** ***
* ** *** * * * ***
* * * ** ** * ** *** ** ** *** * * * * * * **
* *** * * * * ** **** ** *** *** * ** * * * *
* * * *** *** *** **** *** *** ** * * ***** key);
********* * * *** * *
* *** * * * * ** * ** ** *** ** count;
}
answered by (30k points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.4
©2016-2026

Related questions

2 like 0 dislike
8 answers
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38155 - Available when: Unlimited - Due to: Unlimited
| 3.6k views
2 like 0 dislike
6 answers
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38154 - Available when: Unlimited - Due to: Unlimited
| 2.4k views
8 like 0 dislike
3 answers
[Exam] asked Dec 8, 2017 in 2017-1 程式設計(一)AD by Shun-Po (18k points)
ID: 36175 - Available when: 2017-12-08 18:30 - Due to: 2017-12-08 21:00
| 1.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users