2 like 0 dislike
533 views
請依下列的定義完成函數。

 

#include <stdio.h>

 

///

///函數名稱 count

///函數功能 計算字串當中出現特定子字串的次數

///參數說明

///str 要被搜尋的字串

///key 子字串

///

int count(const char str[], const char key[]);

 

int main()

{

   char str[1000], key[1000];

   gets(str);

   gets(key);

   printf(“子字串共出現 %d 次”, count(str, key));

   return 0;

}

 

int count(const char str[], const char key[])

{

 

}
[Normal] Essay (Open question) - asked in 2017-1 程式設計(一)AD by (30k points)
ID: 38147 - Available when: Unlimited - Due to: Unlimited
| 533 views

5 Answers

0 like 0 dislike
Hidden content!
#include ** * **** *
#include **** * * **

int *** * char str[], const char key[]);

int main()
{
*** * * ** *** str[1000], key[1000];
* * * **** ** * *
* * ** * * * * *
******** ** * * ** ** *** * * * %d 次", count(str, key));
**** * ** * * ** 0;
}

int ** ** char str[], const char key[])
{
** * ** ** * ** ** * * ***** * * ** **
* * * * ** *** ** * * ***** ** * key);
* ** **** * * * * *** * * *
* *** * * * ** ** *** *
***** * ** ***** ** * ** * * * * ** ** * *
* ** **** ** * * * *** * **** ****** * *** * ****
* * * ******* ** ** ** * * *** ** * *** * **** ** ** * key);
** ****** * * * **
* * ** ***** * ** * *** ****** count;
}
answered
0 like 0 dislike
Hidden content!
#include *** ** ***

#include * ***** * *



int * ***** char str[], const char key[]);



int main()

{
** ** * **** **** ** str[1000], key[1000];
**** * ** * *** **
* * * *** * * * **
*** ** ***** *** ** * ** * * *** %d * ***** count(str, key));
** *** * * * * 0;

}



int count(const char str[], const char key[])

{
* ** * ** ** ** *** ** * * ** *
** ** * ** ** * *** * ** ** key);
* *** **** ** * * ** * **** **
** **** * * * ****
* * **** *** * * * *** * ** * * ** * * * **** **
* * * ** ** * *** *** * **** *
** * ** * * **** *** ** * * * * *** * ******* * ** key);
* * * * ** * ****** ****
** * * *** * *** ** count;

}
answered by (190 points)
0 like 0 dislike
Hidden content!
#include ** * ** *
#include * ** * ** *

int *** * char str[], const char key[]);

int main()
{
* ** * * * * * ***** str[1000], key[1000];
  *** ** * ** *
  *** * ******
** ** *** ** * * ** ** * ** ** *** * ** %d * * * * key));
* ** * *** *** 0;
}

int * * ***** char str[], const char key[])
{
** * ** * **** ** * *** **** **
** * ***** ** **** *** * * *** *** key);
** ** * ** * * * * * *
** * ** *** **** *******
**** ** * ** *** * ** * * *** ****** *** ***
** ** ***** ** * **** ** ** * * ** * * * *
** ** * * * ***** ** ** * * * * ** ****** *** * key);
** ** *** ** *
***** ** * * **** * * * count;
}
answered by (174 points)
edited by
0 like 0 dislike
Hidden content!
* * * ** * ** *



int *** char * *** * **** *****



int ****



{


* ***** * * * ** * ** * *


** ** **** ** *** *


* *** * ** *


** ** ** * *** * ** * ** ** %d * * * ** * ** *


* * ** ****** ** 0;



}



int ** char * * *** ** *



{



int x=0;


*p;



do



{


** * *** ******* ** * * *


* * **** ** * ** * * *** != NULL)



{


**** *** * * *** * ** **** * ** * * ***** ** ***


** * * * ** * * ***** * ** *** *** * **** * *



}



}


**** *** * *


* * x;



}
answered by (160 points)
0 like 0 dislike
Hidden content!
#include * * *
#include * ** * *** * * *

int * * * * char str[], const char key[]);

int main()
{
* * *** * **** * str[1000], key[1000];
**** *** * * * *** *
**** * * * ** * * ***
* * ** * * ** * * %d 次", count(str, key));
** *** ** *** *** ** 0;
}

int * char str[], const char key[])
{
* ** **** ******* * ** * ** ** * * **
* ***** ***** ** *** * * *** ** key);
** ** *** ** *** ** * *
* * * *** * *
* * *** ** ** ** * * * * **** ** **** *
** ****** ** ** ** ***** * ** * * * * *
* *** **** * * ***** **** ** **** * * * * * key);
* * ** * * * **
* * * * * ** * ** * count;
}
answered by (30k points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.130
©2016-2025

Related questions

2 like 0 dislike
8 answers
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38155 - Available when: Unlimited - Due to: Unlimited
| 1.4k views
2 like 0 dislike
6 answers
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38154 - Available when: Unlimited - Due to: Unlimited
| 962 views
8 like 0 dislike
3 answers
[Exam] asked Dec 8, 2017 in 2017-1 程式設計(一)AD by Shun-Po (18k points)
ID: 36175 - Available when: 2017-12-08 18:30 - Due to: 2017-12-08 21:00
| 620 views
12,783 questions
183,443 answers
172,219 comments
4,824 users