2 like 0 dislike
797 views
請依下列的定義完成函數。

 

#include <stdio.h>

 

///

///函數名稱 count

///函數功能 計算字串當中出現特定子字串的次數

///參數說明

///str 要被搜尋的字串

///key 子字串

///

int count(const char str[], const char key[]);

 

int main()

{

   char str[1000], key[1000];

   gets(str);

   gets(key);

   printf(“子字串共出現 %d 次”, count(str, key));

   return 0;

}

 

int count(const char str[], const char key[])

{

 

}
[Normal] Essay (Open question) - asked in 2017-1 程式設計(一)AD by (30k points)
ID: 38147 - Available when: Unlimited - Due to: Unlimited
| 797 views

5 Answers

0 like 0 dislike
Hidden content!
#include * ** ** * **
#include * * ** ****

int * **** char str[], const char key[]);

int main()
{
* * * * ** * * * * str[1000], key[1000];
* ** * * * * ** **
* * * ** * ** *
* ** * ** ** * * * ** * ** %d 次", count(str, key));
** * ***** ***** 0;
}

int * char str[], const char key[])
{
** *** ** *** ****** *** *** * *****
* ** * * *** ***** **** * * **** *** key);
** ***** * ** * * *** * **
* ** * ** * * *********
* * ***** * * * * **** * *** * ** *** * *** * ** *
***** ** * * * * ** ** *** * ** ** * *
* ** ******* * ** ** ** ** * ** * * ** ** *** * key);
* ******** * * * ***
****** * * **** * * * ** * count;
}
answered
0 like 0 dislike
Hidden content!
#include **** * * ****

#include ** * * *** **



int * char str[], const char key[]);



int main()

{
*** * * ** * ** ** * str[1000], key[1000];
**** * **** ** *
* ** ***** *** *** * * *
****** * *** * **** ** ** * * **** * %d * * ** count(str, key));
** * *** * * * *** 0;

}



int count(const char str[], const char key[])

{
*** ** * ** * * * * * ** ** * ** **
* * ** * ** ** * * * *** ** * * * key);
** ** *** * ****** * ****** ****
* *** * * * *****
** *** * * * * *** * *** ******* ** ** *** **
* *** ** ** * * **** * *** ** * * * * *** *
** * * ** ** * **** * * * * ** ** ** **** * * * * key);
**** ** * *** ** ** **
****** ***** *** ** * * count;

}
answered by (190 points)
0 like 0 dislike
Hidden content!
#include * *** *
#include **** *******

int ** char str[], const char key[]);

int main()
{
***** * * * str[1000], key[1000];
  * *** ** **
  ** ** *
* * * * *** ** ** * * **** %d * * * * key));
** *** *** **** * * 0;
}

int * *** * char str[], const char key[])
{
* *** * * * *** ** ** ****** *
* * ** * *** ** * * * * * *** * * key);
* * *** * * *** ********
* ** ****** * *** ** * * **
** * * * ** * * *** **** * ****
**** * * * ** * * * * ** * **** * * * ***** *** *
*** * * * *** ******* * * * * * * * ****** * * *** key);
*** * ***** * ** * *
*** ** * * * * * *** count;
}
answered by (174 points)
edited by
0 like 0 dislike
Hidden content!
**** * **



int * * char ** **** *



int *



{


** * *** * * * * * *


* **** * ** * **** * ** **


* ***** * * * **


* * * ****** ** * ** * *** *** %d ** *** * * * **


* * **** *** * ** 0;



}



int ** char * * ** * * *



{



int x=0;


*p;



do



{


* * * ** ** * ******** *** * ***


* ** ** **** * *** * * ** * * ** != NULL)



{


** ** * *** ** ** **** ** * ***** ** ** ***


*** * ** * * ** * * ** * ** *** *



}



}


* **


** * x;



}
answered by (160 points)
0 like 0 dislike
Hidden content!
#include ** *** ***** *
#include ** *** **** *

int *** * * char str[], const char key[]);

int main()
{
** * * * **** * ** str[1000], key[1000];
** * * * ** **** * **
* ** * ** * ** * * ** *
** ** ** *** * * ** **** * %d 次", count(str, key));
*** * * ** ***** * 0;
}

int ** ** char str[], const char key[])
{
* ** * * *** ******* * ** ***** *****
* * ** *** * ** ** * ****** ****** key);
* * * * ****** **** ** ** * * *
* * * * *** *
* * * *** ** * ** * *** ** * * * * *
* ***** *** * * * ** **** ** * **** * * *
*** * ** * **** * *** *** * *** ***** ** key);
***** * *** * * ** *
* ** * * * ** * ** * * count;
}
answered by (30k points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.233
©2016-2025

Related questions

2 like 0 dislike
8 answers
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38155 - Available when: Unlimited - Due to: Unlimited
| 2k views
2 like 0 dislike
6 answers
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38154 - Available when: Unlimited - Due to: Unlimited
| 1.3k views
8 like 0 dislike
3 answers
[Exam] asked Dec 8, 2017 in 2017-1 程式設計(一)AD by Shun-Po (18k points)
ID: 36175 - Available when: 2017-12-08 18:30 - Due to: 2017-12-08 21:00
| 1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users