2 like 0 dislike
1.8k views
請依下列的定義完成函數。

 

#include <stdio.h>

 

///

///函數名稱 count

///函數功能 計算字串當中出現特定子字串的次數

///參數說明

///str 要被搜尋的字串

///key 子字串

///

int count(const char str[], const char key[]);

 

int main()

{

   char str[1000], key[1000];

   gets(str);

   gets(key);

   printf(“子字串共出現 %d 次”, count(str, key));

   return 0;

}

 

int count(const char str[], const char key[])

{

 

}
[Normal] Essay (Open question) - asked in 2017-1 程式設計(一)AD by (30k points)
ID: 38147 - Available when: Unlimited - Due to: Unlimited
| 1.8k views

5 Answers

0 like 0 dislike
Hidden content!
#include *** * ***
#include **** * **** ** *

int ** *** * char str[], const char key[]);

int main()
{
* ** ** **** * * * * * str[1000], key[1000];
* **** * * *** * ***
** * * ** ** * * **
* * **** * * ** ** **** *** ** * %d 次", count(str, key));
** *** ********* ** 0;
}

int ** ** char str[], const char key[])
{
** *** *** * * ** * ** * * ** ** **
* ****** * * **** * *** * * * * ** key);
* *** * * ** ** * **** **
** ** **** * * *
* * * * * *** *** * * ** ** ** ***
* * * * * **** * ******* ** ** ** ** ** * *** *
* ** *** * * * *** ** ** * * * ** **** * ** * * key);
* *** ** ** ** * * *
** * **** ** * *** ** count;
}
answered
0 like 0 dislike
Hidden content!
#include * * * ** **** *

#include * * ***



int ** char str[], const char key[]);



int main()

{
** ** *** **** * * str[1000], key[1000];
*** ** * * * *** *
** * ** ** **** * * * ***
* * *** * * ** * * * * * * * * * * %d * ** * count(str, key));
* * * * ** * 0;

}



int count(const char str[], const char key[])

{
* * ** ** *** ** ** *** ** * * ** ** * ** *
* * * * * ** ** *** * key);
* **** * ** * ** ***
*** * *** * ****** ***
* ******** *** * ** * *** * * * * * *** **** *** *
*** **** ***** * ** * ***** ** ****
*** * * * ****** ** ** * *** * *** ** ** ******* key);
******* *** ** * ****
* **** * * * * *** * ** ** * count;

}
answered by (190 points)
0 like 0 dislike
Hidden content!
#include * * ** *** **
#include * * ** * ***

int * * char str[], const char key[]);

int main()
{
** * * ** * *** str[1000], key[1000];
  * * * ** *
  * * *** *
* * ** * *** * * ** ** * * ** **** ** %d ** ** * * key));
* ** ** *** * * * * * 0;
}

int * * char str[], const char key[])
{
** * * ** ** * *** ** * * * * * *
***** * **** * * * * *** * ** * key);
* ** * * ** ** ** ** * ** **
**** ** ** *** **** ** *
** * *** * ** * **** * * ***** * ** *** * * *
* * ********* * ***** *** * *** ** * *
******* * ** * * ** * * * **** *** * * ** * * *** key);
* * *** * ** *
** ****** ** * *** * * ** count;
}
answered by (174 points)
edited by
0 like 0 dislike
Hidden content!
** ** ** *** * ** *



int *** * char * *** * * *



int **



{


* ** ******** *** * * **


* * * ** * * ** * *


* ** * * **** * *


* ** **** * * ***** * ** * ** *** %d ** ****


* * * **** * 0;



}



int ** * char *** *** * **



{



int x=0;


* *p;



do



{


* * * ******* * * ** ***


* ** * * ** * * *** != NULL)



{


* * * *** *** ** *** *** **** * * ***


** **** **** * ** ***** ***** ** ** **



}



}


*** * *


*** x;



}
answered by (160 points)
0 like 0 dislike
Hidden content!
#include ** * * * * *
#include *** * * *

int * ** char str[], const char key[]);

int main()
{
* * * ** ** * * str[1000], key[1000];
* * ** ****** *******
**** * **** *** ** * **
* *** *** *** * **** * * ** ** %d 次", count(str, key));
** * *** **** 0;
}

int ** ** * char str[], const char key[])
{
* * * * * * *** * ** * * *
** * * ** * * * ** * * **** key);
********** *** *** * ** ** ** **
* *** ** **** * *
*** * ********** * * * * * **** * *** ** *
** * *** * ** **** * *** ** ** *** * * *** *
*** * **** * * * * **** ** *** * * *** * * key);
** * * *** ****
* * * ** ** ******* * *** ** count;
}
answered by (30k points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

2 like 0 dislike
8 answers
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38155 - Available when: Unlimited - Due to: Unlimited
| 4.4k views
2 like 0 dislike
6 answers
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38154 - Available when: Unlimited - Due to: Unlimited
| 2.9k views
8 like 0 dislike
3 answers
[Exam] asked Dec 8, 2017 in 2017-1 程式設計(一)AD by Shun-Po (18k points)
ID: 36175 - Available when: 2017-12-08 18:30 - Due to: 2017-12-08 21:00
| 2.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users