第二次期中考 -3 稀疏矩陣

6 like 1 dislike
1.3k views
如果在矩陣中，多數的元素並沒有資料，稱此矩陣為稀疏矩陣（sparse matrix），由於矩陣在程式中常使用二維陣列表示，二維陣列的大小與使用的記憶體空間成正比，如果多數的元素沒有資料，則會造成記憶體空間的浪費，為 此，必須設計稀疏矩陣的陣列儲存方式，利用較少的記憶體空間儲存完整的矩陣資訊。

在這邊所介紹的方法較為簡單，陣列只儲存矩陣的行數、列數與有資料的索引位置及其值，在需要使用矩陣資料時，再透過程式運算加以還原，例如若矩陣資料如下 ，其中0表示矩陣中該位置沒有資料：

0 0 0 0 0 0
0 3 0 0 0 0
0 0 0 6 0 0
0 0 9 0 0 0
0 0 0 0 12 0

這個矩陣是5X6矩陣，非零元素有4個，您要使用的陣列第一列記錄其列數、行數與非零元素個數：

5 6 4

陣列的第二列起，記錄其位置的列索引、行索引與儲存值：

1 1 3
2 3 6
3 2 9
4 4 12

所以原本要用30個元素儲存的矩陣資訊，現在只使用了15個元素來儲存，節省了不少記憶體的使用。

 

請寫一個程式用上列的方法壓縮稀疏矩陣。

 

輸入說明：

一開始會輸入兩個正整數M N，代表矩陣的大小。接下來會有M行，每行N個數字。

 

輸出說明：

請輸出壓縮過的矩陣

 

輸入範例：

5 6

0 0 0 0 0 0
0 3 0 0 0 0
0 0 0 6 0 0
0 0 9 0 0 0
0 0 0 0 12 0

 

輸出範例：

5 6 4
1 1 3
2 3 6
3 2 9
4 4 12
[Exam] asked in 2017-1 程式設計(一)AD by (18k points)
ID: 36176 - Available when: 2017-12-08 18:30 - Due to: 2017-12-08 21:00 | 1.3k views

6 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(void)
{
*      * * *      ***  **   * A[m][n];
 ** * ***  ** *  ** * * * ***** *** ****   *            *  
** **  *** *    **** *   * * *****      **  **  **  ****   *  
* *  * *   **    *  * ****  * 
   * ** **   *    **  * *
  **    *   *     * *** * 
***** **** *   * *  **
 * * *** * *   *  *** ****  **        *** **  ** *  
******  **      * *  *      * 
 *  *** *  * * * * * * * * ****    ** * * *** ** *
******   **    ****  **  *
    
    return 0; ***   *      ** *** **** *** ***    * * ****  ******
 }
answered by (144 points)
0 0
prog.c: In function 'main':
prog.c:4:11: error: 'm' undeclared (first use in this function)
     int A[m][n];
           ^
prog.c:4:11: note: each undeclared identifier is reported only once for each function it appears in
prog.c:4:14: error: 'n' undeclared (first use in this function)
     int A[m][n];
              ^
prog.c:11:23: error: expected expression before ')' token
     printf("%d%d%d\n",)
                       ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:4:11: error: 'm' undeclared (first use in this function)
     int A[m][n];
           ^
prog.c:4:11: note: each undeclared identifier is reported only once for each function it appears in
prog.c:4:14: error: 'n' undeclared (first use in this function)
     int A[m][n];
              ^
prog.c:11:23: error: expected expression before ')' token
     printf("%d%d%d\n",)
                       ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main(){
    
**   * * ** *    **        ** * ** * a,b,x,y,i=0;
 * * * ***   ** *   *** *     **** ****** %d",&a,&b);
    
*  *   ***  *** * **  **  *** ch[a][b];
    
*    ** ****  **   *     * ******    *  **  ***
**   ** ** * ******** **    **   * **    *   *** *   * *  * **  * 
* **** ** *    ** * **       **    ** * **    ** * *   **    *** *** *  *** **  *** * ***   *****  * *
 ** * ** **** **** *  **  * * ****** * ** * ***   *  *** *   ** *  * ** *** * *
** **   * *** ****  *   ** * * *  **  ** *** ***** *** **** * **
** *  *     *   **     *  ***    ** *   *   * *  ****    ***    * * *  *
  *** ***  *** **     *** *      *   *   *  **  **
  *****  *  * **  *  *     * *    ** * %d %d\n",a,b,i);
*  ****** * ******    *******  ***  * *   
    **   * **  * *   *** ** **** ** * ** * ***  ***      *** *   
 **   * ****  *** *   *   *      *  ****    ***** *     **** ******    ** 
   **** *  *  * **** *   * *  *** * *  * *  * * *  **** *   *  *  *** *        * * *  * %d %d\n",x,y,ch[x][y]);}
**  *** **  **** *  *     **   *  ***  ***  *** **    *  ****  **   * *
***** *  * ** *   *  *** *    ***  *    **** ** *
   **** **  * **  ***   * *  **  *    ** * system("pause");
}
answered by (192 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  * *  *  * *  * * ** *
answered by (131 points)
0 0
/usr/lib/gcc/x86_64-linux-gnu/6/../../../x86_64-linux-gnu/Scrt1.o: In function `_start':
(.text+0x20): undefined reference to `main'
collect2: error: ld returned 1 exit status
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
******     * *** * ** 
int main ()
{
 ** ** *   * **** *     **  M,N;
    *** *  ***  *  ** *******  *** **   ** **    * * * * ********* *  * 
 *** ** ** * *  *  ** ** *      *   *   ** %d",M,N);
* *    **** * ***   *  *
* ** **  * * ***   *   * ** **   0;
}
answered by (215 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
    int row,col;
    while(scanf("%d %d",&row,&col)!=EOF)
    {
* *  **  * **  **** *  ***    * ** * *****    **  *  array[row][col];
   ****  * * * ** *** * *  ** **** * **** ** *  **  ** save[row*col][3];
 **   *   *** * * * **** *  **** ***  ***  * * ****    **** i,j,count=0;
  * ** *  * **    *     *  * * *    * ** * * ****        *    *** *   *   ** *
        {
**   *   ** ** ** *    * ** *      **   ** *** * * * ***** **  * *** *    *** * * ***** * ***** * *** 
**** ****** *** *  ***  * *** ***** *  *** ******  *  * **   **     **   *  * * * ******* **   *  **  *  *   * * *** * * *    **    *
        }
  ** ** *** *** **  * ** *** * * *** **  ***  *    * ** **  **  *  *  *   ***
        {
 ** ***  ****  *  *  *   * * *  * *  * * * * * ** ********** *       *  ** **  *  * ** *** *
  *  * * * ***  *****      ** *  **  ***  ** ** *   * *     ********* *    **  **
**     * ***  * ***     * **** **** * ***   ***  *** ** ** *** ***** **  *      ** **  ** ** *   **    ****    
  * ** **  * **  * * ** ** *  *    * **** ******   **    *******  **  * **  *  **** ** ** *  *********    ** *
 *      *  * * ** ** ** **  * ***  *** *** *  ** * *  *****   *  ***** * *  **** *** * *  *   *  *******   *   *  **  ** **  *       *  * * * ****  *
 ** *** *   ** *********  *  ** ***** * * *  * * ** * * * ** ****  *    * *   * * *  *   ** **** *** *  *   * ** *   ** *   ** **       ***   * ** *    * * *
  *  * ***    * * *  *  ** **  * * * **  *  *  *  * **  * *    ***     ** **   * * **   ***   * ***  ***   * ** **   *** *   **    *  ** *  ** * *  
     ***    *  ***  * ***    ** **********   *    *** * ****** * * *** *       *  * * *** * **  *   **    *      ***     **** *   * *  ****
        *  *  ** * ****         *  *  ** ********  *  *  ** * * **  **  *  **           *  ***  **   *  ***
   **** *  * *  * * ****   *** * *** ** *****  ******   *   **  *** **    * *  *  *    ** **
****** * *  * *  ****** ** ** **   * **** ******   *
*   ** *   **     *  **    *  * * ** **** * *     * ****  * *  **  *      %d %d\n",row,col,count);
 *  **  **   ** ** **  * * ** * ***  * *  ** * **  ** * ** **  * ** 
        {
* ** *  *  *     *** * *   ***    *** ** ** *  *** *** **  *   * *****  *** *  *   **  **** *
* * * *** ***** *  *** ** ** *  *     * *   * * ***  ** * * *  * *   *  **     * ** ***** *    ** *   **      *****  **    ***    * ** **        *   ",save[i][j]);
****   * *    ***  *   * * * *****  *  ** *  * *   *  * *  *  *   **   ****** ** * ** * ***   * *  *  ** * *
** * *  *   *  * ***** ***   *      *  ** **** ** ** 

    }

    return 0;
}
answered by (114 points)
edited by
0 0
prog.c:1:1: error: expected identifier or '(' before numeric constant
 0 0 0 0 0 0
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
* ****  *** **      *  **  *  a,b;
**  *****  * *** * *   ** *  * *    *  **** %d",&a,&b);
 ***   * **   *** *  ** ** arr[a][b];
    int i,j,count=0;
** *   ****  ******* ** * ** *** ** ****
    {
 * * *  *   **** **  * *    ***  *** * *******  ** ** **   *    **     **
 *****  **  * ** ****** **  *** **  *    * **  ** ****   *
*  *** * *     *** *    * *      * * *   * *   ****** * *  *** **** **  *** **    * *   *      * *** * ******
  ***  * *   *   *    **    ** **       * * **   *** *   *   *** *** *  *  *** * *   * *  * * ** *   ****  * ****   
  ** **** **        *  * * ****   ****  **  * *** 
    }

*  *    *********     * ** **   * *
    {
** ** ***** * *****   * * *** * ** **   * ** *  *     * *** * 
*  *   ** ****** *    ***  *  * * *    ** * *  ** * *   * 
    ***** ***  *  *  * ** * *  ****** *   *  ****   *   ****  ** *** *** **  *  *  **  **  *****
*  * *     *** * * * ***  **  *  *** *******  ** ***  *  * *   *** **** *   *  *  *   * *******      **** *** *** **  ****  
**  *  *      *  * **  *  *    *** ***  **   **
    }
*****  * **   **  **     *        *  * * %d %d\n",a,b,count);
 *  * **    * *** *** * ***  ***** **  *** *
    {
 * * * *  * *   ** *  **  *    *   *  *  *   *     *   *** *  *   * **    *** 
 ***** **  **** *  * ****  *** *** * **** **  * * *  * *
 *  * ** ** ** ** ***** **** * ***      * **  * ** * ****  ****** **   *** **** ***
  * *   *  *  * **  *    **        * *  *  *   ****   ** * * * * *  *****    ** **     **    *   *  *** * *    *** **    *  %d %d\n",i,j,arr[i][j]);
   * ** *  ** **   * * **** * ***    **   *****    * *
    }
  *******   * *  * *    *  *** * * * 0;
}
answered by (100 points)
1 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.241
©2016-2025

Related questions

3 like 0 dislike
5 answers
第二次期中考補考題庫 -3 稀疏矩陣
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38153 - Available when: Unlimited - Due to: Unlimited | 1.2k views
2 like 0 dislike
5 answers
第二次期中考補考-第五題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38942 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 1.3k views
2 like 0 dislike
18 answers
第二次期中考補考-第四題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38941 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 3.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users