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Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

[Exercise] Coding (C) - asked in Chapter 3: Branching, Looping and Functions by (5.9k points)
ID: 30241 - Available when: Unlimited - Due to: Unlimited
| 5.9k views

24 Answers

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Hidden content!
** * *** * * * *
* *** * **
int main(){
int i;
* * ** ** * char a;
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* *** ** * * * *** * *** ** *** *
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}

//INPUT
//Enter your input: A

** *
//Enter your input: A
* * ** ***
50/100 answered by (271 points)
0 0
Case 0: Wrong output
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Hidden content!
** * ** * * *
*** * * * ** * *

/* run this ** * ** the * ** or add your own ** ** * ** * * * * or * loop */

int * * ** * * {
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** *** ** *
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**** ** ** ** ** *
* *** ** * ** * * * ** * if (a == * a == 'E' || a == 'I' || a == 'O' || a == *
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* *
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* * * ** **
}
*** * * *
* * * ** * ***** 0;
}
100/100 answered by (252 points)
0 0
Case 0: Wrong output
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Hidden content!
#include * ** * *
#include * ** * ** * ***

int main(int argc, char *argv[]) {
    char a; ** * * * * * ***** * ** **** ****** ** ** ** *** * * *** * * * ** * ***** *** * * ** * ** * ** ****** * * can be changed
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    return 0;
}
100/100 answered by (268 points)
0 1
Case 0: Correct output
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Hidden content!
#include **** * **
#include **** * * * * *

int main(int argc, char *argv[]) {
** ** * * * char a;
* ** ** * **** your ** * * **
******* **** * * * *** * **** * *****
* ** * ******
** ** ** ** ** * ** *** ** **
* *** *** * ** ** *** * * if * *** *** * * *** * *
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* * * ** * * * * * * ** ** ** ***** ** a);
* * * * * *** * }
* * **** ** *
******* ** *** return 0;
}
answered by (5.9k points)
0 1
Case 0: Correct output
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