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Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

[Exercise] Coding (C) - asked in Chapter 3: Branching, Looping and Functions by (5.9k points)
ID: 30241 - Available when: Unlimited - Due to: Unlimited
| 3.4k views

24 Answers

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Hidden content!
** * * *** * *
* *** ** **** * *
int main(){
int i;
* ** *** * char a;
* * *** ** **** * ** ** your input: **** **
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* ** * ** }
}

//INPUT
//Enter your input: A

** * *
//Enter your input: A
* *** * * *** *
50/100 answered by (271 points)
0 0
Case 0: Wrong output
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Hidden content!
***** ** *** * *
*** * *** * ****

/* run this * the * ** or add your own *** * * ****** or **** loop */

int * * * ** * * * {
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* * * for (a == 'A'; a *** * * ***

* *** * ** * *** **** *
* ** * *** ** ** if (a == * a == 'E' || a == 'I' || a == 'O' || a == **
* *** * *** * *** ***** ** **** * * * **

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** * *** *
}
* ** * * **
* *** ** * *** 0;
}
100/100 answered by (252 points)
0 0
Case 0: Wrong output
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Hidden content!
#include ********* ** **
#include * **

int main(int argc, char *argv[]) {
    char a; **** * * ** **** * ** * ** * ** * * * ** ** * * * * *** * * * ***** ***** * * ** * * * ** * *** * *** * ******** *** *** can be changed
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* * *** * ** * **
   
    return 0;
}
100/100 answered by (268 points)
0 1
Case 0: Correct output
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Hidden content!
#include * *
#include ** * * * **

int main(int argc, char *argv[]) {
*** ** * ** char a;
**** **** ** ** **** *** your ** * *
* ** * * ***** * * ** ** * *** * *
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**** ** ** * * * }else
*** * * ** * ** ** * ** * * * * a);
* * * **** }
* * *** * * **
** * * ** return 0;
}
answered by (5.9k points)
0 1
Case 0: Correct output
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