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Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

[Exercise] Coding (C) - asked in Chapter 3: Branching, Looping and Functions by (5.9k points)
ID: 30241 - Available when: Unlimited - Due to: Unlimited
| 4.4k views

24 Answers

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Hidden content!
** ** * ** ***
* ** *** * * * **
int main(){
int i;
** ***** * ** char a;
* ** * * * * ** * your input: *** *
**** ** * * * ******** * * ** * * * *
****** ******* * * *
***** * * * * ** * *** ** * * *** **
** * ** * *** ** *** ***** if(i==65 ||i==69 || i==73 || i==79 *
* *** ** * * * * * * *** ** * * * * * ** * *** * **
*** * * * **** ** * * * **** }
** * * *** **** * * * * * ** else{
* * ** *** * ** * * ** * * ** ** * * * ** * * ** * ** ****
*** * * ** * * * * ** * }
* ** ** ** * * ** * }
* ** * ** * }
}

//INPUT
//Enter your input: A

*
//Enter your input: A
* * *******
50/100 answered by (271 points)
0 0
Case 0: Wrong output
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Hidden content!
* * * * * * *
* * ******** * ****

/* run this * * ** the ***** or add your own * *** * **** * ** or *** loop */

int *** * * * *** {
** *** ** * * a; * ******** **** ** * **** * **** * * * ** ** * * ** *** *** ** **** ** * * * **** ** ** **
* * * * **** * * your * *** **
* **** ** *** * **** *** * *
* * * * **
* **** ** * * for (a == 'A'; a **** * **

*** * *** ** ** * * *
* * ** ** * ** ****** if (a == *** a == 'E' || a == 'I' || a == 'O' || a == **
* * *** *** ** * ** * * *** * ** *
**
* ** *** ** * * * ** * ** ** **** ** * *** *
**** * * * *
}
** ** * * **
* ***** ** *** **** 0;
}
100/100 answered by (252 points)
0 0
Case 0: Wrong output
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Hidden content!
#include * **** * *****
#include **** ****** *

int main(int argc, char *argv[]) {
    char a; * ** * ** ** *** ** ** *** *** * ** * * * * ** *** **** * ** **** ** * * * * * *** ******* ** * * * * * can be changed
***   * *** *** *** your ** ** * //DO NOT CHANGE
** * *   * * * * * *** *
   
*** * * ** ***** **** *** ** ***
* * * * ** * ** ** * ***** * *** * * * * * *** * *** * *
*** **** * * ** * * * **** * ** * *
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** ** * * * ** * * ** *** **** **** * * ****** **** * a);
** * *** * ** * ** *
   
    return 0;
}
100/100 answered by (268 points)
0 1
Case 0: Correct output
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Hidden content!
#include * ** ** *
#include * * ***

int main(int argc, char *argv[]) {
** ** * char a;
** * ***** ** * ****** your ** * **
** *** * ** **** * ***** **** **
*** * * ******
* * ** ** ***** *
* * *** * *** * ** * ** ** if ** ** ** ** ** **
***** ** * * * * * ** * * ** * * ** ** * * * * * *
*** *** * ** *** ** }else
* * * ***** * * * * * ***** ** * ** * * a);
* *** * * }
*** * *
******* * return 0;
}
answered by (5.9k points)
0 1
Case 0: Correct output
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