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Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

[Exercise] Coding (C) - asked in Chapter 3: Branching, Looping and Functions by (5.9k points)
ID: 30241 - Available when: Unlimited - Due to: Unlimited
| 5.1k views

24 Answers

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Hidden content!
*** ** * * * ***
** ** *** * *
int main(){
int i;
*** * * char a;
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* ** * * * *** *
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* *** **** * * ** ** * * * ** **** }
** ** * * * * * * * * * *** }
* ***** * * }
}

//INPUT
//Enter your input: A

* * **
//Enter your input: A
*** * ** **
50/100 answered by (271 points)
0 0
Case 0: Wrong output
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Hidden content!
**** * *** * * ***
** * **** * * *

/* run this * * the * * * or add your own * **** * ** * * or loop */

int **** ** * * * *** {
** ** **** ** a; *** * *** * * * ***** ** * ** ** * * ** **** *** * * ** * *** ** * * **** *** ** * * * **** *
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* **** * * ***** ** *** ** * * *
*** *** **
* * * * for (a == 'A'; a ** * * * * *

* *** * *** * ** ** *
* * *** * ***** **** if (a == * a == 'E' || a == 'I' || a == 'O' || a == *
** * * * * ** * * ***** *** ** * *
**
* ****** * ** * * * * * ***** * * **
*** * * *
}
** ** * **
* *** ** **** 0;
}
100/100 answered by (252 points)
0 0
Case 0: Wrong output
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Hidden content!
#include * ** * * *
#include *** * * ***

int main(int argc, char *argv[]) {
    char a; ******* *** * *** ** *** * * ** * * * * **** * * * **** ** * * * ** ***** * * * * ** * ** * * can be changed
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* *** **   * *** * * ** *****
   
* * * *** * * * * ** ** * * *
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* **** * * * * ** * * ***** *******
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** * * ** * ** * ** ** **** * * **** * * ** ** * * a);
** * * ** * **
   
    return 0;
}
100/100 answered by (268 points)
0 1
Case 0: Correct output
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Hidden content!
#include * ** * *
#include ** ** *

int main(int argc, char *argv[]) {
*** * * ** * char a;
** * **** * ** * * ** your ** ** *
* * ** * ** * * * * ***** **** ** ****
**** * **
** * * *** * *** * **
* * * * *** *** if *** * ** * * * * * ***
**** * **** **** * *** * * ** * * * * * ** **
****** ** ** }else
* ** * * **** * * * ** * *** ** a);
** **** ** }
*** ** ** * *
* * return 0;
}
answered by (5.9k points)
0 1
Case 0: Correct output
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