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Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

[Exercise] Coding (C) - asked in Chapter 3: Branching, Looping and Functions by (5.9k points)
ID: 30241 - Available when: Unlimited - Due to: Unlimited
| 5.3k views

24 Answers

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Hidden content!
* * * ** * ***
* * * ** * ** * *
int main(){
int i;
** * ** * char a;
** ** * * ** * * ****** your input: *** * *
**** ** * ** ** * ** ** ** ** * * * * ****
** * * *** * * * **
*** ** * * ** * * * * ** *** * *** ** *
** * * * * ** * ** *** *** * if(i==65 ||i==69 || i==73 || i==79 * *
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** * * ** **** ** * *** * }
* * ** * * * * ** * }
* *** * ** }
}

//INPUT
//Enter your input: A

** * *
//Enter your input: A
* ** *** * * *
50/100 answered by (271 points)
0 0
Case 0: Wrong output
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Hidden content!
* * * * * * *
* * * * ** * ** *

/* run this ** * the * * or add your own ** ***** ** * ** * * or loop */

int ** * * ***** {
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* * ** *** ** * * *** * your * ** ** **
* *** ** **** * ***** ** * **
***** ** *
** * * for (a == 'A'; a *** * ***

** ***** * *** * ** **
** ** * *** * * * * ** if (a == *** a == 'E' || a == 'I' || a == 'O' || a == *
** *** * * * * * ***** ** * **
*
* * * * * * * * **** * *** ** * * *
* * * * ** **
}
*** **
* * * ** 0;
}
100/100 answered by (252 points)
0 0
Case 0: Wrong output
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Hidden content!
#include * * *** *** *
#include ** * *** * * ***

int main(int argc, char *argv[]) {
    char a; *** **** *** * * *** * **** * ** * * * *** * * * ** ** * ** ** * * * ***** ** **** *** * * * can be changed
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* *****   * * ** ** * **** ** *
   
* *** * *** * * ** ***** * *
* ** * ** * * * ** * ******** * * *** * **** * * ** ** * * *
***** ** * *** * * ** * ** ** * * **
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***** ***** * *** *
   
    return 0;
}
100/100 answered by (268 points)
0 1
Case 0: Correct output
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Hidden content!
#include *** * *
#include **** ** * **

int main(int argc, char *argv[]) {
** * ** char a;
** *** **** * * ****** ** your * ***
* *** ** ** * * * * *** **
****** ** **
* **** * * ** *** ** ** ***
* ** *** * * *** * ** if **** ** ** * ** *** **
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* * * * *** * ** * }else
* * * * ** ** * * * * * * ***** * a);
** * * ** ** }
** * * *
* * * ** return 0;
}
answered by (5.9k points)
0 1
Case 0: Correct output
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