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Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

[Exercise] Coding (C) - asked in Chapter 3: Branching, Looping and Functions by (5.9k points)
ID: 30241 - Available when: Unlimited - Due to: Unlimited
| 5.9k views

24 Answers

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Hidden content!
** * * * *** *
* * * * * * * **
int main(){
int i;
* * ** char a;
** *** * * * **** * * ** your input: * *
* * * ** ** * * * * *** ** **
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** ** * ** * * * * * * *
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* * * **** * * ****** * ** * else{
* * * * *** *** ** * * * ** ** ** * ** ** * *** ****
***** ** * ***** *** * * ** * }
* * * *** * ** ** }
* ** * * }
}

//INPUT
//Enter your input: A

* * *
//Enter your input: A
**** * ** *
50/100 answered by (271 points)
0 0
Case 0: Wrong output
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Hidden content!
*** * * ** **
* ***** *** * * ****

/* run this * *** ** the **** * * * or add your own * * ** * * **** or * loop */

int * * * * *** * {
* * * * * * a; * ** * ** ******** **** ** ** *** * * ** ** * ** * * * ** ** * *** ***** **** ** ** * * **
* * * ** * **** * ** your ** * * ** *
** ** * * ** ** *****
***** * *
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* * * ** * *** *
* * ** ** * *** * ** ** if (a == ** a == 'E' || a == 'I' || a == 'O' || a == *
** * ** * * * *** ** * * **
****
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*** * **
}
* * *
*** ** * 0;
}
100/100 answered by (252 points)
0 0
Case 0: Wrong output
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Hidden content!
#include * **** *
#include ** **** * * *

int main(int argc, char *argv[]) {
    char a; * * *** **** ******* *** * * *** ** * **** ** * ** ** * * * * ******** * ******* * * *** ** * * ** can be changed
* *   * ** * ** * ** your **** * * * * * //DO NOT CHANGE
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*** * ** *** * * *
   
    return 0;
}
100/100 answered by (268 points)
0 1
Case 0: Correct output
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Hidden content!
#include ** * * *
#include ** *

int main(int argc, char *argv[]) {
* ** ** ** * char a;
*** *** * * * ** * * * your * *** **
* ** * * ** **** * *** *** ***
*** * * *
* * ** * * *** ** **
* ***** ** * * * if ** *** **
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* * * * * ** ** * }else
* ** ***** ** * * * * * * ** * *** ** * *** a);
* ******* }
* * * *
**** *** * * return 0;
}
answered by (5.9k points)
0 1
Case 0: Correct output
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