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AC 20161207 exercise 1
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子字串
請設計一個程式，使用者會輸入兩個字串，兩個字串間用一個空格隔開，每個字串的內容只會包含大小寫的英文字母，請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。
輸入範例1：
friEND end
輸出範例1：
There is "end" in "friEND"
輸入範例2：
friEND friends
輸出範例2：
There are no "friends" in "friEND"
asked
Dec 7, 2016
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2016-1 程式設計(一)AC
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Shun-Po
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Hidden content!* * * ** * * * * *
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answered
Dec 18, 2016
by
410523016
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answered
Dec 18, 2016
by
410523016
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Hidden content!#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include <stdlib.h>
int main()
{
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answered
Dec 18, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include * **** * * ****
#include <ctype.h>
int main()
{
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answered
Dec 18, 2016
by
Gulang
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-122
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* ** ** * * * * * ** ** * i,j;
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** * * * * * * * * ** ** ** *
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* * * ** ** * * ** ** * * ** * 0;
}
answered
Dec 18, 2016
by
Jim870729
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* * * * * * ** * * i,j;
* * * * * * * * * * * **** * ** * * * * ** * * * *
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* * ** * * ** * * *
* * * * * ** * * * * ** ** * ** * * * * * * ** is %c%s%c in %c%s%c",c,s2,c,c,s1,c);
* * * * * * ** * * * 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include<stdio.h>
* * * ** ** ** *** *
#include<ctype.h>
int main ( void )
{
* * * * * ** * * ** * * * * * i,j;
** * * * * * * ** * ** ** ** * * ** * * **
*** * ** * * *** * * * *** * * * * *****
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* * * * **** * * * * **** ** * * * *** * *** * = c2;
* * * * * * *** ** ***
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** * * * *** * * ** * * *
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* ***** * * * * * ***
* * * * ** * * * ** ** * * ** * * * * ** * * * *** * * * * ** is %c%s%c in %c%s%c",c,b,c,c,a,c);
* * * ** ** * * * * * ** 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
** * * * * * * * ***** * ** * * i,j;
* * *** * ** ** * ** ** * *** ** * * * * * *
* ** ** ** * * ** * * * ** * * ** ** ** ** *** *
*** * ** ** * *** ** **** * * * *** * *
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*** * * **** * ** * * *** ** * * * * = c1;
*** * * * ** * ** * *
* * * * * * * * * *** *** * * **
* ** *** ** *** ** * ** *
** * * * * * ** * ** ** *** ** * * ** * = s2[j];
** ** * * * * * ** * * * * * ** * * * ** * * = tolower(c2);
** * * *** * * * * ** ** * * * ** * * * * * = c2;
** * * * * * * * *
* **** ** *** ** ** * * ** * = strstr(a,b);
* ** * * * **** * *** **
* * * *** * * *** * * * * * * * * * * * * **** are no %s in %s",b,a);
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* ** * * ** ** * * * ** ** * * * * ** * ** * * * * * * ** is %s in %s",b,a);
* * *** * ** * * * * *** 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* *** * ** ** * * * * * * * i,j;
* * *** * * ** ** * * * * * ** ** * **
* ** ** * ** * * * * *** ** * ** **
* *** ** * * **** * * * * * * ** * *
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** * *** * * * * * * * * ** ** * ** * = tolower(c1);
*** * * ** ** * * **** * * * ****** ** *** ** * * = c1;
* * * * ** * ** * *
* ** ** ** * * * * * * ** * *** *
*** ** ** ** * * *
* * * * ** * ** * ** * * * = s2[j];
* * * * * * * * * * * * *** ** * * * * = tolower(c2);
* * *** * * ** ** * * * ** * * * * * * = c2;
** * * * * * **
* ** * * * * * ** * * * * = strstr(a,b);
* ** *** *** * ** ** * * * * * * **
* * *** * ** *** * ** * * * *** *** * * * * * ** * * are no %s in %s",b,a);
* ** ** * *
* * * **** ** ** *** * ** * * * * * * * *** * * * * * * * ** is %s in %s",b,a);
* * *** *** * *** ** * * * * * 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include * * *
#include * ** * ** ****
#include ** * *
#include * ** *** * ** **
#include * ** * * ** * *
int main(void){
*** ** * * * * *** ** *** * * ** * ** * * *
** * * *
*** *** * * * * ** * * * * * *** * * ** ** *
* ** ** * * ** ** **
* * * * * ** * ** * * ** *** *
* ** **** ** * * * ***
** * * * ** * * ** * * * (i = 0;s[i] != '\0';i++)
* * * ***
* * * * * **
** * **** ******* * * * * * ++;
* * * ** *** * * ** * **
}
** * * * * * * * (i = 0;t[i] != '\0';i++)
* **
** * * ** * ** * ** * * *
** * ** * ** ++;
** * * * **
}
* * * * ** * * ** ** * * * ******* * **** * * *
* ** * * *** * **** ** *
* ** * * ** (i = 0;i <= sizes;i++)
****
*** ** * * * *
* * * * * * * * * = s[i];
** * *** * *
**** * *
* *** * * (i = 0;i <= sizet;i++)
* **
**** * ** *
* * ** * = t[i];
* ******
**** ***
* * ** * * * * ** ** * * ** *
* ** * * (i = 0;i <= sizes;i++)
{
* *** * * *
* ** * ** *** * *
* * * * * *** ** * = p[i] - 32;
* * ** * * * *
* *** * * *
* ** * * * ** * = p[i];
}
* ***** * * ** * * ** * * * * *** *
for (i = 0;i <= sizet;i++)
{
* * * ** ** * *
** * * * * * * *
* *** * *** = f[i] - 32;
** ** * ** * *
* * *
** * * ** * = f[i];
* * * ** *
}
* * * ** * * * * ** ** * ** *
//asplpSLP slp
* ** (i = 0;p2[i] != '\0';i++)
* **
** * (p2[i] == f2[0])
* ** * ** * * *
** ** * ** * *
** * * * * * ** = i;
* * * * * * * *
* * * ** * * * (u = 0;u < sizet;u++)
* * *** * *** ** * ****
* ** * ** ** * * * *** *
* ** *** ** ** * * * ** * * * ***
* * ** * ** * * * * ** * *** ** (p2[j+u] == f2[u])
* ** ** *** * ** * * * ** *
* *** * ***** *** ** * * * += 1;
* **** * * ** ** * ** *
* *** ** * * * * ***** * * * * ** *
** ** ** * * * * ** * *** * **
* ** ** * * ** * ** * *** *** **
* * *** * * ** * * * * * * *** *****
** * * * **** * * * * * * * * = 0;
* ** *** * * ** ** * * ** ** ** **
* * * ** * * ** ** * ** * * * ** *
**** * ******* * * * * * * * * *
* ** * * * * ** * * **** ** *
* * *** * * * * * * * * * * * *
* **** ** * * *** ** * * * * **
* * * * * * * ** *
* ** * * * * ** * *
** * * * ** * *
* * **
* * *** * ** * * * * * (d > 0)
* * *** * **** * * ** *
* * * * * *** * * * * * * * is * *** * ** ***** in *** * * * * *
*** * ** ***** * *** * * *** * * *** * * * *
*** *** *** *** ** *** * * *
*** * * * * * * ** *
* * * ** * * * * **** * * * * * *** * ** ** are no ** * *** * ** * *** in * * ** * * **** ** ** **
* * * * * * * ** ** * * 0;
* * * ** * ** * *
}
answered
Dec 10, 2016
by
蘇瑋朝
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