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AC 20161207 exercise 1
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子字串
請設計一個程式，使用者會輸入兩個字串，兩個字串間用一個空格隔開，每個字串的內容只會包含大小寫的英文字母，請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。
輸入範例1：
friEND end
輸出範例1：
There is "end" in "friEND"
輸入範例2：
friEND friends
輸出範例2：
There are no "friends" in "friEND"
asked
Dec 7, 2016
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2016-1 程式設計(一)AC
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Shun-Po
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{
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* * ** * ** return 0;
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answered
Dec 18, 2016
by
410523016
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Hidden content!* *** ** **** * * * * *
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answered
Dec 18, 2016
by
410523016
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Hidden content!#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include <stdlib.h>
int main()
{
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** * * * * ** * * * first_search[99],second_search[99];
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answered
Dec 18, 2016
by
Gulang
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-122
points)
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Hidden content!#include <stdio.h>
#include *** * * ****** **
#include <ctype.h>
int main()
{
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answered
Dec 18, 2016
by
Gulang
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-122
points)
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* * ** * *** * * * * **** ** i,j;
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* * * *** ** * * ** * * * 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* * * * * * ** ** *** i,j;
* * *** * ** *** * * ** ** * * *** * ** * * * *
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* * ** * * **
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** * * * ** * * * * * *
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* * * * * * * * * 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
points)
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Hidden content!#include<stdio.h>
*** * ** ** * *** ***
#include<ctype.h>
int main ( void )
{
* * ** * * *** * * * *** * * i,j;
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** ** * * * ** * ** * *** * * **
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* * * ** * *** *
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** *** ** * * * * **** * * * * 0;
}
answered
Dec 18, 2016
by
Jim870729
(
-102
points)
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* ** * *** ** ** * * * i,j;
* * ***** *** * * **** **** ** ** * * * * * * * *
* * * *** * * * ** * *** * ** **
* * * * * ** * * ** * ** ** *** ** * * ** * * ***
*** ** * * * * * * * * * ***** * * *** *** *
* * * * *** * ** * * **** *
* * ** ** ** * ***** ****** * * * **** * * * = s1[i];
* ** * * *** * * ** * * ** * * * * * * = tolower(c1);
* * *** ***** * * * * * * * ** * ** * ** * * * = c1;
* ** * *** * ** * * * * *
* *** * * * * * * * * * * *
* * * ** * **** ** *
* ** * * * * * ** * * ** * * = s2[j];
* * * * * * * ***** * * ** * * **** * * * ** ** ** = tolower(c2);
*** ** ** * ** * * * ** * ** * * ** ** * * = c2;
** * **** * * ** * * *** *
* *** * ** * * * = strstr(a,b);
* ** * ** * * * *** * *** ** *
** * * * * *** * * * * * ** * *** * * * * ** * ** ** *** are no %s in %s",b,a);
* *** * ** * ** **** * * *****
** * * ** * * * * ** ** ** * * * * *** ** * *** * * * * * * is %s in %s",b,a);
** *** ** **** ** ** * * * * *** 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* * * * * * * * * * * * * * i,j;
** * * * * * ***** ** ****** * * ** * *** * * * *
* * * * * * * * * * ** * **** * * *** *
* * * * * * * * * * ** ** * * ***
* * * * * * * ** * ** * * **** *
* ** * * ** * ** * ***
** * * * * * **** * * * * ** * *** * * ** *** ** = s1[i];
* ** * **** * ** * * *** * * * * * * * * * * * = tolower(c1);
** * ** *** * ** ** * ** * * ** ** ** ** *** = c1;
** * * * * ** ** * ** * *
** * ** * * * *** ** ** * ** * * *
* * * * * * * * * * * ***
* * * * * ** ** *** * * * * * * * * * * * *** * = s2[j];
** ** *** * * * * *** ** **** * * * ****** * * = tolower(c2);
* ** * ** *** ** * * * * ** * * * ** ** * ** * * * = c2;
** * ** * * ** *** * **
* * * * * * * ** * ** * = strstr(a,b);
* * * * * * *** * ** ** * ****
* * * ** * * *** * ** * * ***** * * ** * ** * * * * ** * * are no %s in %s",b,a);
** ** * * * ** * * * ** * ***
* *** ** * * ** *** ** * ** **** ** ** *** * * * ** * * ** is %s in %s",b,a);
** *** ** * *** ** * ** 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include * * * ** * * **
#include * * * * **
#include *** ** *
#include * * * **
#include ** * * ** * *
int main(void){
** *** * *** ** * *** * ** * * * * ** ** ** * * * **
* * * * * *
* * * ***** ** ***** * * * * ** * * *
** *** * * * * * *
** * ** * * * * * * * * * * * * *
* * ** ** * *
** ** * * ** ** * * *** (i = 0;s[i] != '\0';i++)
*
* ** * * *
* * * * ** * **** * ***** * ** ++;
** * * * *** * * * * * *** * * *
}
* ** ** ** * * *** (i = 0;t[i] != '\0';i++)
** ** *
* * ** ** ** * * * * * * * ***
**** ***** ** * * * ++;
** * ** *
}
* ** * * ** * * * * *** * ** ** **** * * ** *
** *** ** * *** * * * * ** **
* * * * * ** (i = 0;i <= sizes;i++)
* * **
* ** * *
* * ** * * ** ** = s[i];
* * * * ** ** *
* **
** * *** ** (i = 0;i <= sizet;i++)
** ** *
* *** **
*** * * * * * = t[i];
** * * ** **
* ** *
* ** * ** * ** ** * ** ** ** * * * * * *
** * * ** (i = 0;i <= sizes;i++)
{
* ***** ** *** **
* * * * * *** ** **
* ** ***** * * = p[i] - 32;
**** * ** *
* * *
* * * **** * = p[i];
}
** ** * * * * * * ** * * * *
for (i = 0;i <= sizet;i++)
{
* ** ***
* * * * * * * ****
*** * *** * = f[i] - 32;
* * * ** *
* * *
* * * ** * * * * * = f[i];
* **** * * *
}
* **** * * * ** * * * **
//asplpSLP slp
* * * * (i = 0;p2[i] != '\0';i++)
* * *
** * * (p2[i] == f2[0])
* * * * * * ** * ***
** ** * * ** ******
* * * ** * ** * * * = i;
* * ** * ** ** * * ***
** * * * * * ** (u = 0;u < sizet;u++)
* * *** ** ** * * *
*** * * ** * * *
* * * * * ** ****** * * ** * *
* * * * **** * ** **** ** * (p2[j+u] == f2[u])
** *** *** ** ** * * * * * * ** *
* * *** * * ** ** * * ** * += 1;
* ** * * * * ** * ** * * * * **
* * * * * * * ** ** ** * * * ***
* * ** * ** ** *** * * * *
** ** * * * **** * * * * * * * * * * *
** * ****** ** * ** * ** * * * **** ** *
* * * * * * ** * * * * * = 0;
** * * ** * * * * * ** ** * * * * *
* ***** ** * *** * * * ** * ** ** *** **
* ** * ** **** ** * ** ** * ** **
* * * * ** * * ** *** *
* ** * * * *** * ** * ** ***
******** * ** * * *
* * * *** * * *
*** ** * * ** * * * *
* * * * * * * * * *
* * *** *
** * * ** ** * * ** *** (d > 0)
** ** * *** * * * * * * *
* * * * **** ** * ** * * ** * * **** is *** * *** * * *** in * ** * * * * * * ** **
** ** * * * ** ** * * ** * *
* ** * ** * ** ** *** *** * * *
** * ** * ** *** *** * * *
* ** * * * *** ** * ** are no * ****** in * ** * * * ** ** *** *
** ** ** *** * ** ** * * *** *** ** 0;
** ** * * *** * * ****
}
answered
Dec 10, 2016
by
蘇瑋朝
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