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AC 20161207 exercise 1
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子字串
請設計一個程式，使用者會輸入兩個字串，兩個字串間用一個空格隔開，每個字串的內容只會包含大小寫的英文字母，請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。
輸入範例1：
friEND end
輸出範例1：
There is "end" in "friEND"
輸入範例2：
friEND friends
輸出範例2：
There are no "friends" in "friEND"
asked
Dec 7, 2016
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2016-1 程式設計(一)AC
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Shun-Po
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Hidden content!* * * * * ** ** ***
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* * *** * * * * ** return 0;
}
answered
Dec 18, 2016
by
410523016
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Hidden content! * * ** * ** ** * *
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answered
Dec 18, 2016
by
410523016
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Hidden content!#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include <stdlib.h>
int main()
{
* * * *** * ** * * *** * * ** * ** * *** ** ** * * * * *** **** * * *
* * * * ** ** * ** ** *second_find,number;
* * * *** * ***** * * * first_search[99],second_search[99];
* * ** * *** ** ** * * * ***** * * i;
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answered
Dec 18, 2016
by
Gulang
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points)
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Hidden content!#include <stdio.h>
#include *** * * * * **
#include <ctype.h>
int main()
{
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answered
Dec 18, 2016
by
Gulang
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-122
points)
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
*** ** *** * ***** ** *** * * i,j;
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*** * * * ** **
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* * * * ** * * * ** ** **
** * ** * * *** ** * * * * ** ** ** ** * ** * ** * * * * * * ** * * is %c%s%c in %c%s%c",c,s2,c,c,s1,c);
** * * * *** ***** * * 0;
}
answered
Dec 18, 2016
by
Jim870729
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* * * ** * * * * ** i,j;
** * ** ** * * * *** * * * ****** ** ** * * ** *
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**** ** ** *** * * ** * * * *
*** * ** * *** * * ** * * * ** * **** ** * ***** **** * * * ** * is %c%s%c in %c%s%c",c,s2,c,c,s1,c);
* * * * ** * ** * * * * * * 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include<stdio.h>
** ** ** * * *
#include<ctype.h>
int main ( void )
{
* * * * *** * * * * i,j;
** * * * * * * * * ** * * * * * * **
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* * ** * * *** * * ** * * **** * * * ***** *** = tolower(c2);
* ** *** * ** ** ** * ** ** * * * * * ** * = c2;
* ** * * * ** * ** * **
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* ** * * * * * ** * * * *
* * * * * ** * * * * * * * * ** * **** * * * **** ** * * are no %c%s%c in %c%s%c",c,b,c,c,a,c);
* ** ** * * * * * * ** * * *
* * *** * ** * * * **** * * * * ** * * * * * * * * * * * ** * * * is %c%s%c in %c%s%c",c,b,c,c,a,c);
* *** * * * ** ** ** * * * ** * 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* ** ** * * * * **** i,j;
*** ** * * ***** * * * ** * *** * * **** * * **
* * * * ***** ** ** * **** *** * ** ** * * *
* * *** * ** * ** * * * * * * * *
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*** * * * * * * ** ** ** * * * ** * ** * * * * = s1[i];
*** *** ** * * ** *** * * * * * ** * * * = tolower(c1);
* * * ** * * ** * * * *** ** * ** * ** * *** *** = c1;
** * ** * * *** * **
* * * ** * * * * ** * *** * * * ******
**** * *** * * * *** ***
* ** ** ** * * * ** * * * * * *** * * * ** * * * * * * ** * = s2[j];
** * * *** * *** * ** * ** * * * * * ** * = tolower(c2);
** ***** * ** ** * * ** * * * * *** * ** * * * * ** = c2;
* * ** * * * * *** * * ****
*** *** * ** * ** * * ** ** = strstr(a,b);
** ** * * **** * *** * ** * ** * *
**** * ** * ** ** *** * * * * * * ** * * *** ** * * * ** * are no %s in %s",b,a);
* * * * * * ** * *** *
* *** ** * * ** * * * * * ** **** * * * *** * * * * ** *** ** * is %s in %s",b,a);
* * * * ** * * * * * * * 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* * ** ** * * ** ** * * * i,j;
*** * * * * * * ***** * * * * * * ** * *** * * *** * * *
**** * * * * *** *** * * ** * * * * * * * *
* **** * *** * * ** * * * * * * ******* * * *
* * * *** * * ** * ** * * *** ** *
*** * * ** ** ** ** ***
* * ** * * ** * * * * * ** * * * * * ** ** * * = s1[i];
* ** * * *** ** * * * *** * * ** * *** * * ** = tolower(c1);
** * * * **** * * * * * * ** ** ** ** ** ** = c1;
** * ** * * ** **
* * * * * * * ** ***** * * * * * ** * ** ** *
**** * ** * ** * * ** * *
* ** ** * ** ** ** * * ** * * * * *** = s2[j];
* * *** *** * **** **** ** * * ** * * ** * = tolower(c2);
* * *** * * * * * * * * * * ** * **** * = c2;
** * * * * * * * * * * * *
** * * *** * * * *** * = strstr(a,b);
* ** * ** ** * ** *** * * *** * *
* * * * *** **** * * * *** *** ** * * * * * * are no %s in %s",b,a);
* * * * * * **** ** ** **
* * * * * *** ** * * * ** * * * * * * * * *** * * * * * * * ** ** * is %s in %s",b,a);
*** **** ** * * * * ***** ** ** 0;
}
answered
Dec 18, 2016
by
Jim870729
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-102
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Hidden content!#include * * **** *
#include * * * * ** *
#include ** ** *
#include * ** * * * * ***
#include * * * * * *
int main(void){
* * * * * * * * * * * * * * *** ** * * ** * *
**** * * * *
* * ** ** * * ** ** * * * *
* ** ** * * * * * * **
** ** ** * * * * * * ** * * *
** * * * * * * * *
* * * ***** ** * (i = 0;s[i] != '\0';i++)
* **
** * * *
* * ** ** * * ** * * * ** ** * ++;
* * * * ** *** * * * * ** *
}
* * * * * * ******* * (i = 0;t[i] != '\0';i++)
*
** ** * * * ** * * * **
** * * * *** * ** ++;
* ** * ** ****
}
** *** ** * * * * ** ** * ** * ** * * * * ** *
* * *** *** * ** * ** * * * *
** * * (i = 0;i <= sizes;i++)
*
** * * *
*** * *** ** *** = s[i];
* * * * ** ** **
*
*** * * ** (i = 0;i <= sizet;i++)
* * **
* ** *
* * ** * = t[i];
* **** ** *****
* ** * *
** * ***** * * * * * ** * * **
* * * (i = 0;i <= sizes;i++)
{
* * **
* * ** ** *
* * * ** * * * *** = p[i] - 32;
* * * ** * *
* *
*** * * * ** * * = p[i];
}
** ** * * * *** * **
for (i = 0;i <= sizet;i++)
{
**** ** ** ** *
** **** * * * * * * **
* ** * ** **** = f[i] - 32;
* ** *
* ** ** *
* * * ** *** = f[i];
* ** * *
}
* * * ** * * * * * * *
//asplpSLP slp
* ** (i = 0;p2[i] != '\0';i++)
* **
* ** (p2[i] == f2[0])
* * * * * *
** * * ** * * *
**** ** * ** * ** * * = i;
* * * *
* ** ** **** * * (u = 0;u < sizet;u++)
*** * ** ** *** *
* ** * * * *** ** **** * **
* * * ** * * * ** * * **
* *** * *** * ** * * * * * *** (p2[j+u] == f2[u])
* * ** * * * * *** * ** * ** ** ** **
* *** ** * * * ** * * * * * * * * += 1;
* * * * ** * * * * * *
** * * * ** * * ** **
* *** * *** ** * * * **
** **** ** * *** * * * * ** *
* **** * * ** * ** * * ** * ** * *** ** **
* ** ** * * * **** * ** ** = 0;
* ** ** * * *** * * * * ** * **
** * * * ** * * *** * ** * ** **
* * *** * * * * *** * * * * *
***** * * * *** * * * ** **
** *** * ** *** * ** * *
** * ** * ** ** * * * *
* * ** * * * * *
* * * * ** * * * *
* * ** ** * * ** *
* *
* *** * * * * * **** * *** * (d > 0)
* * * ** * * ** *** * *** * *
** * * * * **** ** * * * * * *** * * ** * is * *** ***** ** in * * * ** * * * * * **
* * * * * ** * ** * * ** * * * * * *
* ** * * * * ** * ** * *
** * * * ****** ** * * *
* ** * *** * * * * ** * * * ** ** * * ** * * * are no * *** * * * ** * * in * *** *** * * * ** ** * *
* *** ** * * * ** * * ** **** 0;
* * * * * * * * * * *
}
answered
Dec 10, 2016
by
蘇瑋朝
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