Toggle navigation
Courses
Questions
Tags
Users
AC 20161207 exercise 1
0
like
0
dislike
7.5k
views
子字串
請設計一個程式，使用者會輸入兩個字串，兩個字串間用一個空格隔開，每個字串的內容只會包含大小寫的英文字母，請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。
輸入範例1：
friEND end
輸出範例1：
There is "end" in "friEND"
輸入範例2：
friEND friends
輸出範例2：
There are no "friends" in "friEND"
asked
Dec 7, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
|
7.5k
views
answer
comment
Please
log in
or
register
to add a comment.
Your answer
Your name to display (optional):
Email me at this address if my answer is selected or commented on:
Email me if my answer is selected or commented on
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please
log in
or
register
.
Add answer
Cancel
44
Answers
0
like
0
dislike
Hidden content! * ** * * * * * **
* * * * * * *
* ** ** * *** * * * *
** * ** * ** * * *
int main ( void )
{
* * * * * char * * * * *
* * * * char **** * *
* * *** ** * * * ** ** ** i,j;
* ** *** * *** * ** * * ** *
* * * * ** *** **** ** * *** * * * * *
*** * *** * * * ** * * *
* * * * ** *
** * * * * * * ** * *
* ***** * {
* *** * * *** * * * * * ** * c1 = a[i];
* * * * ** * ** * * * c1 =
**** * * * **** * * * * ** d[i] = c1;
** ** }
* *
* * * * ** ** ** *** *
* ** * {
* * * * * * * * c2 = b[j];
* * * * c2 = *** *
* * * * ** * ** * * e[j] = c2;
* ** * **** }
* * ** *
* * * * * ptr = * * *
* ** ** * *
* *** * ** ** ***** *
* ** * ** * * * * **** * * **** * * * *** are no %c%s%C in * * ** ** *
* * * * ** * *** * *
** * * * ** * else
* ** * * ** **** * * ***** * * * * * ** is %c%s%C in * * * ** ** * * * *
*** ** * ** * return 0;
}
answered
Dec 18, 2016
by
410523016
(
-136
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content! ** * *** ** ** * * **
* * * ** * * ** *
* * * * ** * * * * * **
** * * **** ** *
int main ( void )
{
** ** * char * *** * **
* * ** * * * char * * *
* * ** * * * * *** ***** * * i,j;
** * * ** ***** * * ** ******
* * **** * * ** *** * ** * ** ** * *
** * * ** **
** * * ** *** ** ***
* ** ** * ** * {
* * * ** * * * * ** * * * * * c1 = d[i];
* * * * * ** ** * ** ** c1 = * **
* ** * * * * ** * * * * d[i] = c1;
* * * * ** }
**** ** * **
* **** * * * ** * * * * * *
* ** * *
* * * * * * **
* * ** * * {
* * * * ** * ** ** c2 = e[j];
* * * * * * * * * ** c2 = *** *
* * * * ** * * * e[j] = c2;
* * * }
* * * * ***
* * * * ** ptr = * * * *
** ***** ** **
* * * * * * * * *
* *** * * * * *** * * ** * * * * are no %c%s%C in * *** * **
** * * *** ** * * ** *
* * * ** ** else
** * ** * * * * * * ** * * * ***** * * is %c%s%C in *** ** * * ****
* ** * return 0;
}
answered
Dec 18, 2016
by
410523016
(
-136
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include <stdlib.h>
int main()
{
* ** * * ** * * * * * * * ***** ** * * * *** * * ** ***
* * * * * ** * *second_find,number;
* * * * * * * * * * * first_search[99],second_search[99];
** ** ** * * * **** * * * i;
** ** ** ** * ** ** * * * ** * **
** * ** ** * ** ** * * * ** ** * * *** *
* ** ** * ** * ** ** * * ** * ** * * *
* ** * * * * * **
*** * * * ** ** * * * ** * * * * *
** * *** ** *** * * * * * * * *******
* ** *** * * * * * ** * * * *** * ** * *
* * * * *** ** ***** **
*** * * ** * * * * * * ** *** * = * * * * * * ** * *
* ** * * ** * ** * *** * * (second_find==NULL)
* **** * * *** * * * *** * * * * *** * * are no %c%s%c in ** ** * * ** * *** ** ** *** ** * *
* *** ** * * * *** ** * * *
** * ** ** ** * *** ** * * **** *** * * is %c%s%c in * * ** ** * * **** ** * * * * *
** * **** * * ** * * * 0;
* * ** * * * *** * *
* * * * * * * * * * *
answered
Dec 18, 2016
by
Gulang
(
-122
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include <stdio.h>
#include * * *
#include <ctype.h>
int main()
{
* * * * ** ** * * *** ** * * * * * * ** * * * ** ** ** ** ** **
* * * * * * * * * * *second_find,number;
* * *** * * ** * ** * * ** ** ** *
* * * * * * * *** ** * * * * * * * ** * ***
* ** * * ** * * ** * * ** * * * *** * ** *
* * * * * ****** * **** * * * * * * ** * ** **
* *** *** ** * ** * * *** *** ** = strstr(chang_first, chang_second);
*** * * * ** * ** * * * (second_find==NULL)
* * * * * *** * * * * ** * * * are no %c%s%c in * * * * * *** ** * * *** * * *
* *** * * ** * *** * * *** *
* *** * * * * * * ** ** * * * ** * *** *** is %c%s%c in * * * *** ** * * ** **** * * ** *
*** **** * * *** *** ** * ** 0;
*** ** * * ** * **
* ** ** ** * * *** * * **
answered
Dec 18, 2016
by
Gulang
(
-122
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* * ** * ** ** ** ***** * i,j;
** * * *** * * * * *** * * * *** ** * * ** **
* ** * * * * * ** ** *** ** * * * ** * *
* ** * * * * ** ** * **** * *** ** *
** * * ** * * * * * * * * **** * ** * *
** * * ** ** * ** * ** *
** * ** ** * * * ** * ** * * * **** * *** * * * * * = s1[i];
** * * *** ** * * ** ** ** * ** * ** = tolower(c1);
** ** * * * * ** **** * * * ** * * * = c1;
** * * * * * * ** ** * * *
* ** * * ** * *** * *** *** *** ** *
* * * ** * ** *** * *
** * * ** * * * * * ** * * * ** ** * ** * = s2[j];
** * * ** * ** * **** *** * ** * * ** *** * * = tolower(c2);
* * * ** *** * * * * * ** * * * ** ** ** * = c2;
* * * * ** ** * ** *
** * ** *** * * ** * * * = strstr(a,b);
* ** * * * * * * ** * * * *
*** * * * ** * * * * * ** * * * *** ** * * * **** **** * *** are no %c%s%c in * * ** * * *
* * * *** **** ** * *
** * * ** *** * * * ** * * * ** * * * * * * * * * * ** * * is %c%s%c in %c%s%c",c,s2,c,c,s1,c);
* * ** ** ** * * ** * * 0;
}
answered
Dec 18, 2016
by
Jim870729
(
-102
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
*** ** ** * **** * * * * i,j;
* ******* * * * * ** * * * * ** ** * * ** * ** * ** *
* * * * * * *** * ** * * ** * * *** * ** * * *
* **** * * ** * * * * * * * ** ** * ***
* * * * ** ** *** * ** * * ****
** * * ** ** *** ** *
*** ** *** * ** * * * * * * * ** ** ** * = s1[i];
* * * * ** * ** * * * * ******* * * * * = tolower(c1);
** * * * * * ** ** ** * * ** * ** * * = c1;
* * * *** * * * * * *
* * ** ** * * ** * * * ** *
* *** *** * ** * * * ** **** *
* * *** ** ** * * * ** ** * * * * * * * * * * * = s2[j];
* *** * * * * ** * ** * ** * * ** ** * ** * * * * * * = tolower(c2);
* * ** * * * * ***** * ******* * ** * ** * *** * * = c2;
** * ** * ** ** * * ** ** *
* * ** **** * *** * * ** = strstr(a,b);
* *** * ** * * ** *** *
* * * **** * * *** * * **** * * * * * * ** * are no %c%s%c in * * * ** * ** * ****
* * * ** * **** * **** *
** * * * ** * * * * ** * * * ** * * ** ** * * * * * * * * * is %c%s%c in %c%s%c",c,s2,c,c,s1,c);
** * * * ** *** ** ** * ** ** * * 0;
}
answered
Dec 18, 2016
by
Jim870729
(
-102
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include<stdio.h>
* * ***** ** * * **
#include<ctype.h>
int main ( void )
{
* * * * **** * * * * ***** i,j;
* ** * ** * * * * ** * ** * * * * ** * **
* * * ** * * *** ** * ** ** * * * *
* * * * ** ** * ** * * * *** * * *
* * * **** * * * * **** * * ** **
* ***** ** *** ** * * * * *
**** ** * * ** * **** ** * * * ** * * * *** = s1[i];
* * * ** * * ** * * ** * ** * ** * * * = tolower(c1);
** *** * * * * * ** * * * * ** *** ** * = c1;
* *** *** * * ****
* * *** * * * **** **** * * * ** * *
***** ** * * * * * *
* * * ** * ** * * * ** * * * * * * *** * * * = s2[j];
** * ** * * * * * * ** ** * * * * * ** = tolower(c2);
* ** * * * * * * * * * * *** * * ** * ** * * = c2;
* * * ** * * * ***
** * **** * * = strstr(a,b);
* * * * * * * * * ** * *
* * * * * * * * * *** * * * ** * ** * ***** ***** * * * ** * are no %c%s%c in %c%s%c",c,b,c,c,a,c);
* * ** * ****** * * * *** ** *
** * * * * ** * * * *** * * * * * * ** * *** * is %c%s%c in %c%s%c",c,b,c,c,a,c);
* * * * * * * * ** * *** * * 0;
}
answered
Dec 18, 2016
by
Jim870729
(
-102
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
**** * *** *** * * * * i,j;
* * * * * * * * *** *** * ** * * ** * * * * *
*** ** ** *** * ** ***** ** * * * * *** ** * **
* ** * ** * * * * * ** * *** * * * * * * * * * *
** * * * * * * ** ** * * ** * *
** * * * * * * * * **
* * * *** * * * * * ** * ** * ** ** ** ** * **** * * = s1[i];
**** * * ** ** ** * ** * * * ** *** * ** = tolower(c1);
* *** * ** * * ** * * ** * ** * * ** * * * * * * ** * = c1;
* *** * * * *** * * *
* ** * * * * ***** * * * * * * ***
** * * ** * * ** * *** * *
*** * **** ** * * * * * ** * * * = s2[j];
** * * * * * * * * * * * * * * * * * * ** * **** = tolower(c2);
* * * * * * * * * * * * * * * * *** ***** **** * * = c2;
* * ** * *** * * *** * * * ** *
* * * * * * * * * = strstr(a,b);
** * **** *** *** ** ** *
* * * * **** * * * *** * * * ** ** * * * * ** * are no %s in %s",b,a);
*** * ** * * *** *
* * * * * * ** * * ***** * * * * ** * * * * * * * ** ** * * * is %s in %s",b,a);
* * * ** * * *** * 0;
}
answered
Dec 18, 2016
by
Jim870729
(
-102
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* ** * ** * * * * ** * ** i,j;
* ** * *** * ** * * * * *** * * * * * * **
* * *** *** * * * * * * ** * * * * * * ***
* * * ** ** * * ** *** **** * * * ** *
* * * **** ** * * * * * * ***
* * * * * * * * **** *
* * ** ** * * * * * ** * ** * * * * * * * = s1[i];
* * * * *** ** ** * * * ** * * * ** ** *** * * = tolower(c1);
* ** ** * * ** ** *** * ** *** *** ** * ** ** * * * = c1;
* * *** * *** * * * *
*** * ** ** * *** * * * ** ** ** *
* ******* * **** * ** * * *
*** * * ** * * * * * * * * ** * * * * * * ** = s2[j];
** * * *** * ** * ** * * * ** * = tolower(c2);
* **** * ** ** * * *** ** *** ** * * ** = c2;
*** * *** ** * * ** **
** ** * * * *** * * * * = strstr(a,b);
** * * * * * *** ** ** ** *
* * ** ** * * * ** * * * * ** * * * ** * ** ** * are no %s in %s",b,a);
* * * * * * * * * * *
* ** * * ** *** * ** ***** ** * * * * * ** **** * is %s in %s",b,a);
* * * * * * * ** ** * * * 0;
}
answered
Dec 18, 2016
by
Jim870729
(
-102
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include * * *** * *
#include *** * * * * *
#include * * ***
#include * * * * ** * **
#include * * * ** * *** **
int main(void){
* * * ** ** ** *** * * * * * * ** * ** *
* ** * * * ** *
* * * ** ** ** * * * ** * * * *** * * * * * * ***
** *** * * * * * *
** * *** * ** ** * * ** * ** * * * * * * *
* * * ** * * * * * * * * * *
* * * * ** * * * * * * (i = 0;s[i] != '\0';i++)
** *
* * * * ** *
* * * **** ** * * * * * ++;
*** * * * * ** * * * * ***
}
* * * * ** * * * ** * * (i = 0;t[i] != '\0';i++)
** * *
* *** *** * ** ** * * * * * *
*** * * ** * ++;
* * **** *
}
* * * * * ** ** * * * * * ** * * ** ** * *** * *
** * * * * ** * * * *** *
* ** (i = 0;i <= sizes;i++)
** * * ** *
* * * * * * *
** * * ** * * = s[i];
* ** * * *
** ** ***
* * * * ** (i = 0;i <= sizet;i++)
*** * ***
****** * * * **
* * * ** ** = t[i];
* ** * *** * ** *
* ** **
* * * * * ** ** * ** * ** **
* * (i = 0;i <= sizes;i++)
{
* **** *
* * ** * * *
* * * * * * = p[i] - 32;
* * *
* * * *
* ** ** * * * = p[i];
}
* * * * *** * ** * * ** * *
for (i = 0;i <= sizet;i++)
{
* * * * **
* * * * * ** * *
**** *** ** * = f[i] - 32;
** ** ** *
* * *
** * * ** * = f[i];
* ** * * * * * **
}
* * * *** * * *
//asplpSLP slp
* * (i = 0;p2[i] != '\0';i++)
* **
* (p2[i] == f2[0])
** * * * * * * **
* * * * * * * ***
* * * * * * * * = i;
* * * * ** * ** * * **
* * ** * ***** * (u = 0;u < sizet;u++)
* ** * * * ** ****
* * * * * * * * *
* * **** * ** * * * * *
* * *** ** * * * * * * * * * (p2[j+u] == f2[u])
* * * * ** * * * * *** * * *
* ** * * * *** * * * **** * += 1;
* * * ** * *** * * ** * ** ** ** *
* * * * ** ** ***** ** ** * * *
* ** * * * * * ** * *** ***** ** *
* * *** * * * * * * **** * *
* ** ** * ** * ** * * * **
* * * ** ** * * ** ** ** ** **** = 0;
** * **** * * ** ** * * ** * *
*** * * * ** * * **** ** ** ** *
* ***** ** * * * ** * **** * ** *
* * * *** * * * * * *** * *
* **** * * * * ** ****
* * **** * ** * ***
** * * **** ** * * * *
* * ** * * ** * * * * *
**** ** * *** * *
* * *
* ** * ** * ** * * (d > 0)
* * * * * * * ** * * * ** * *** **
* * * * * * * * ** * * * ** * * is ** **** **** *** * in * * ** * * * ** **
* * * ** * * * **** ** ** * * * * * * ** * ** *
** ***** ** ** * * ** **
* ** **** * * * * *
**** * * ** * ** ** * * are no * ** ** * * * in ** ** * * * **
* * * * ** * *** * * **** * * * 0;
* * * * * * *** * *
}
answered
Dec 10, 2016
by
蘇瑋朝
(
-8
points)
ask related question
comment
Please
log in
or
register
to add a comment.
Page:
« prev
1
2
3
4
5
next »
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English
中文
Tiếng Việt
IP:104.23.243.108©2016-2026
Related questions
0
like
0
dislike
0
answers
AC 20161207 上課投影片
[Resource]
asked
Dec 7, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18872 -
Available when:
Unlimited
-
Due to:
Unlimited
|
46
views
0
like
0
dislike
10
answers
AC 20161207 exercise 2
[Exercise]
Essay (Open question)
-
asked
Dec 7, 2016
in
作業
by
Shun-Po
(
18k
points)
ID: 18876 -
Available when:
Unlimited
-
Due to:
Unlimited
|
2.4k
views
0
like
0
dislike
0
answers
Programming AC 檔案的存取教學影片1 (有六個影片）
[Resource]
asked
Dec 31, 2016
in
2016-1 程式設計(一)AC
by
laich
(
937
points)
ID: 20298 -
Available when:
Unlimited
-
Due to:
Unlimited
|
38
views
1
like
0
dislike
102
answers
AC 20161027 期中考 1
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 15378 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
|
15k
views
0
like
0
dislike
39
answers
AC practice 1
[Normal]
Coding (C)
-
asked
Oct 11, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 13020 -
Available when:
Unlimited
-
Due to:
Unlimited
|
7.6k
views
12,783
questions
183,442
answers
172,219
comments
4,824
users