Toggle navigation
Courses
Questions
Tags
Users
AC 20161207 exercise 1
0
like
0
dislike
3.9k
views
子字串
請設計一個程式，使用者會輸入兩個字串，兩個字串間用一個空格隔開，每個字串的內容只會包含大小寫的英文字母，請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。
輸入範例1：
friEND end
輸出範例1：
There is "end" in "friEND"
輸入範例2：
friEND friends
輸出範例2：
There are no "friends" in "friEND"
asked
Dec 7, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
|
3.9k
views
answer
comment
Please
log in
or
register
to add a comment.
Your answer
Your name to display (optional):
Email me at this address if my answer is selected or commented on:
Email me if my answer is selected or commented on
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please
log in
or
register
.
Add answer
Cancel
44
Answers
0
like
0
dislike
Hidden content! ** * * * ** * **
* ** * * ** *
* * * * * * ** *** *
** ** * * * * * ******
int main ( void )
{
* * ** * ** char * * ** ** * ** * ** *
** * char * * * *
* * * ** * * ** ** * * * i,j;
* * * * ** * * **** * **
* * ** * * ** **** ** ** * *
* ** * ** ** * * * * * *
* ** * * * *** *
* * * * ** * * ** * * *** *
* * * ** * {
*** * ** * * * *** * * c1 = a[i];
* * * * ** *** * * * ** c1 =
** * * ** * * * * d[i] = c1;
**** }
***
* ** *** ** * * ** *** *
**** * * {
* * * * ** ** * * * c2 = b[j];
* * * * ** * ** c2 = ** *
* ** ** * * * * * * *** ** ***** e[j] = c2;
* * * ** }
* * *
* * ** * * ** ptr = ** *
*** * * * *
** *** * * * * ** * * *
* * * * * * * * ** * * * * * * * * are no %c%s%C in * ***** ** * * * *
* * * ** * * ** * * *
* *** * * * else
* * * * *** * ** * * **** * **** *** **** is %c%s%C in * * * * ** ** **** * **
*** ** ** * * return 0;
}
answered
Dec 18, 2016
by
410523016
(
-136
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!* ** * * * * * *** **
* ** ** * *
** ** * ** ** * * * **
** ** * * * *
int main ( void )
{
** * *** char ** * ** * * *** * * *
* * * * ** char **** * *
* ** ** * * * * * * * i,j;
* ** *** ** * * *** *
*** ** * * * * * ** * * *
** * * * ****** *
* * * * ** * * ***
** * * ** * {
** *** * * * * ** * * * c1 = d[i];
* * ** * c1 = *** * **
** * **** * * * * * * * d[i] = c1;
** * * * * }
* * * ** **
** * * * * * * * * * * * ** * *
* ** *
* * * * * * *
** * * {
** ** * ** * * * * * * * ** * c2 = e[j];
* * ** * ** * * ** ** * c2 = * **** * *
* ** * * * * ** * * ** e[j] = c2;
*** * * * }
* * * **
* * * * * ** * ptr = * *** ***
* **** * *
** * * * * * * ** * *
* * * ** * *** * * **** ** * * * * are no %c%s%C in ** * * ** * * **
** * * * * * * **
* * * * *** * else
** * * * * * *** * * * * * * * * is %c%s%C in * * * * ***
* * ** * * return 0;
}
answered
Dec 18, 2016
by
410523016
(
-136
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include <stdlib.h>
int main()
{
** ** * ** * * * * ** ** * * * * * * * * * * *** * * * **** * *
** ** * * * * * * ** * * *second_find,number;
* ***** ** * * * first_search[99],second_search[99];
** * * ** ***** ** * ** ** i;
* *** * * * * ** * * * * *
* * *** * ** ** * * *** * *** * ** * * * * **
* * * * * ** * * * * ** * * * * *
** ** * * * * * *
* * * * ** ** * ** * ** **** * *
* * ** * ** ** ** * * * * **** * * *** * *
** * * * ** * * * *** * * * * * * * * * * * *
* * * * ** * * ** * * * * *
* * * * ** * ** ** * ** * *** = * * * * * * ** * ** ***
* * ** * ** * * * *** * (second_find==NULL)
** * * * * * ** * * * *** * *** * * * are no %c%s%c in * ** ** * ** * **** * ** * ** **** *
* * * ** * * *
** ** *** * * ** ** * * * ** * *** is %c%s%c in * * * * * * * * * * * * * **
**** * ** * ** *** * ** ** * 0;
* * ** * * * * * * ** *
* * ** * * ** * * *
answered
Dec 18, 2016
by
Gulang
(
-122
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include <stdio.h>
#include * ** *** ** ***
#include <ctype.h>
int main()
{
* * ** * * ** * * ** * * * * * ** * * * * * * * * **
* * ** * ** * * ** * * *second_find,number;
* ** ** * * *** * * ** * *
** * * * ** * * * * *** ** ** * * ** *
* * * **** ** *** * ** * * * * * *** *** * * *
* * * * * **** * * * ** * ** *
* * ** * * * * * ** * * * * * * = strstr(chang_first, chang_second);
** *** * *** * * * *** * * * (second_find==NULL)
* ** * ** * * * * * * ** * * * * * are no %c%s%c in * * * * **** * * **** * * * * ** * * **
* ** ** * * *** ** * *
** * * ** * *** *** *** * * ** ** * ** is %c%s%c in * *** * * ** * * * ** * ** *
* *** * ** ** ** * * * 0;
** * ** ** * ** * *
* * * ***** * ***
answered
Dec 18, 2016
by
Gulang
(
-122
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* * * * * * * * * * * ** i,j;
* ** ***** * ** * * * *** * ** * ** ** * * *** * **
* * * * ****** ** * * * ** * * * * * *
*** * * * ** * * * **** ** * *** * *
* * * * ** ** * * * * * * *** * * * *
** * ** ** ** * *
*** * ** *** *** * * * * * ** * ** ** * * * * ** * * = s1[i];
* *** *** * **** * * * **** *** * * * * * ** * = tolower(c1);
* ** ** * * * ** ** * ** * * ** *** * * ** * = c1;
* * * * ** * *
* *** ** * *** * * *** *** * * *
* * * * * ** * ** * *
* * *** ** * * * * * *** *** ** ** * ** * * = s2[j];
* * * * ** * * * *** * * * ** * ** * **** * * = tolower(c2);
**** * * * * ** * * *** ** * * * * * * ** * * = c2;
* * * * ** * * * * *
** * * * * * * * * = strstr(a,b);
* * * **** * * ** * **** ** *
* ** * **** * * ** *** ** * ** ** * * ** * ** * * * * * * ** are no %c%s%c in * ** * * * * ** * *
* * * * ** ******* **** *
* * *** * * * *** ** ** ** * * * * *** * * * ** * ** * * ** * * is %c%s%c in %c%s%c",c,s2,c,c,s1,c);
* * ** * * * ** ** * * ** * 0;
}
answered
Dec 18, 2016
by
Jim870729
(
-102
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
** * * ** * **** ** i,j;
* * * * * * * * ** * * * * * * * * * * * * * * *
* * ** * * * * ** * * ** * * * *** * **
* ** *** * ** ** * * * * * **
** ** * * * * * * ** * * * ** * ** * *
* * *** * * * **** * *
**** ** * ** * * ** * ** * * * * * * * * * = s1[i];
* * * ** * * * ** * * * * * * * ** ** * * * * = tolower(c1);
* * * **** * * * * ** ** * *** ** ** * * * = c1;
** * * * * ** *
* ** * * * * * * * * * ** ** *
* ** * ** * * * ** *** * ** *
* * ** * * * **** * * * *** * * * * * = s2[j];
* * * ** * *** * ** * * * * * * * ****** ** * = tolower(c2);
****** * * * * * ***** * * * * * * ** * ** ** * * = c2;
* * * * ** * * * * * * * *
* * * * * * ** * * * * ***** * = strstr(a,b);
* * * ** * * * * *** * *
* * * ** * * * ***** * * * ** * * * * ****** * * * * *** * are no %c%s%c in * ** * * * * *
** ** * *** * * **** * * * * *
* * * * * * * * * ** ** * *** * * * ** * * * * * is %c%s%c in %c%s%c",c,s2,c,c,s1,c);
* ** * * * * * * * ** 0;
}
answered
Dec 18, 2016
by
Jim870729
(
-102
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include<stdio.h>
* * * * * *
#include<ctype.h>
int main ( void )
{
* ** * *** * * * * ** *** ** i,j;
* ** ** * *** * ** * * ** * * * *** * * * * * * ** ** * *
* * * ** * * * * * * *** * ** * * * * *
* * * * * * * * * ** ** * * * * * *** * *
**** * * * ** * * *** * ** * ** *
* * * * * ** ** * *
* ** *** **** * * * * * ** * * * * = s1[i];
* ** * * ** *** ** * * ** ** * * ** * * * * = tolower(c1);
* ** * * * ** ** ** * * * ** * * **** = c1;
* * * **** * * *** * ** ***
* * * * * * *** * * * * *
** ** * ** * * * ** *
* * * * * * * * *** * * * * * * ** * * = s2[j];
* * ** ** * * * * * * * * ** * * * * * ****** * * = tolower(c2);
** * * * * *** * *** * * ** * * * * * * = c2;
* * ** * * ******* * * * * *
* * ** * *** * * ** *** ** * = strstr(a,b);
*** ** *** * * * * * * * *
* * * * ** **** * * * * * * * * * * * * ** * are no %c%s%c in %c%s%c",c,b,c,c,a,c);
* ** * * * ** *
** * * * * * *** * ** * * * * * * * * * * * * ** ** is %c%s%c in %c%s%c",c,b,c,c,a,c);
* ** * * ** ** * ** 0;
}
answered
Dec 18, 2016
by
Jim870729
(
-102
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* * * * * ** ** *** *** i,j;
* * * * * * * * *** *** * * * * * * * * * *
* * * * *** * * ** * * * * * * **** * * ** **
** * ** ** * * * ** * ** ** ** ** * ** * ** *** *
* * * **** ** * ** ** * ** ** * * *
* * ** ** * * * * ***
** ** * * * * * * ** * * * * ****** * = s1[i];
* * * *** * ** * * ** ** * ** * * ** * ** * *** = tolower(c1);
*** ** * * * * * ** * * * * * * ** *** = c1;
*** * * *** * * * ***
** * * ** *** * * *** * * ** *
* * ** * *** * ** *** **
** ** * ***** ** *** * * * * ** * * * *** ** * * = s2[j];
* * * ** *** ** * * * * ** * * * ** ** * * = tolower(c2);
* ** * * ** *** ** * * ** * * ** ** *** = c2;
* * * **
* ** * ** ** * *** *** ** = strstr(a,b);
** ** * * ** ** * ***** *** ** **** *
* * **** * * * ** * ** * * *** * * * * ** * * * ** * are no %s in %s",b,a);
* ** ** ** ** * * * * * ** * * *
* ** * ** * *** * ** * *** * * * * * * * * * * * * is %s in %s",b,a);
*** *** * * ** * ** * ** ** * 0;
}
answered
Dec 18, 2016
by
Jim870729
(
-102
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include<stdio.h>
#include<string.h>
#include<ctype.h>
int main ( void )
{
* * * * * * * * * * *** ** * * i,j;
** * * * * * *** ** * * ** * * * * ** * * **
* * * ** ** * ** * * ** ** * ** * ** ***** * ***
* * * * * * * * * ** ** ** * * ** *** * *
* * ** * * ** * ** * * * *** * * * *
** *** * ** * * * * *
* * ** ** * ** * * * * * * * * * ** * = s1[i];
* * * ** * * ** * *** * * * * ** *** * * * = tolower(c1);
* *** * * * * ** ** * ** * * * ** * *** * * ** * = c1;
* ** * * ** ** ** * *** *
* *** * * ** * * * ** * **** *
** ** * ** * ***** *** *
* * * * * * ** * * * ** * * * ** * * * = s2[j];
* ** *** * *** * *** * * * ** ** ** ** ** ** ** = tolower(c2);
* ** ** * * * * * ** * ** * * * * * ** * ** = c2;
** * * ** ** * *
* ** * ** ** ** * * ** * *** * ** = strstr(a,b);
* ** * * * * * ** *** ***
** * ** * * * ** * * *** * * ** * *** ** * ** ** ** * * *** * are no %s in %s",b,a);
* ** **** * ** ** * * * **
* ** * * * ** * * * * ** ** * * * * **** * * * *** * ******** is %s in %s",b,a);
* * * * * ** * * ** * * * 0;
}
answered
Dec 18, 2016
by
Jim870729
(
-102
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include * ** * * *
#include *** * ** **** **
#include * * * * * * * *
#include ** * * * *** *
#include * * * * *
int main(void){
* ** * * * ** * * * *** ** * **
** *** ** * **
** * * * * * * * **** * ** * ** * * **
* * * ** *** * ***
* * ** ** * ** * *** ** * ** * ** **
* * * ** * * ** * *** *
** * * * * * * * * * (i = 0;s[i] != '\0';i++)
*
*** ** *** * *
***** *** ** * * * ** * ** * * * ++;
** * * * ** * * ** * * *
}
** * * * * * * (i = 0;t[i] != '\0';i++)
* *
** ** * * * * * * * ***** * **
* * * ** * * * * * ++;
* * * * *
}
* * ***** * * * * * * * * * ** **** **** ** ** ** *
* * * * **** * ** **
* * * * (i = 0;i <= sizes;i++)
** ** *
* ***** * ** *
** * ** * ***** = s[i];
* *** * * * *
** * *
** * * (i = 0;i <= sizet;i++)
* *
* * ** * *
* * * ** * * * = t[i];
**** * *** * *
* * * *
* ** * * * * * *** **** * ** * *
* * (i = 0;i <= sizes;i++)
{
* ** *
* * * * * *
* ** * * * ** * ** = p[i] - 32;
*** ** ** *
* ** * *
* ** * ** ** * * = p[i];
}
* * * * * *** ** * ** *
for (i = 0;i <= sizet;i++)
{
* * * * ***
* * ** * *
** * * * * * = f[i] - 32;
* * * ** ***
* * * *
* * *** * * ** = f[i];
*** * * * * *
}
* * * ** * ** **
//asplpSLP slp
*** * (i = 0;p2[i] != '\0';i++)
* * ** * *
** * *** * (p2[i] == f2[0])
* * ****** * *
** * * * * *
** * * * * *** * = i;
* *** ** * * **
* * ** * ** * (u = 0;u < sizet;u++)
**** * * * * **
* * * * * *** *
** ** ** * *** ** *** * * ** *
** ** ** * ** * * * *** ** * * ** * (p2[j+u] == f2[u])
* * * * * *** * ** * * *** **
* * * ** * * * ** * * * * * += 1;
* * ** * * * * * * *** *
* * * ** * * * *** ** *
* * *** * **** * * ** *
** * * * ** *** * * * ** ** *
* *** * * * * * * ** ** ** * **** *
*** * ** * ** * * * * * = 0;
*** * * * ** * * * ** * * ***** * ** * * *
* ** * *** * * * * * * **** * **
*** * * * * * *** * * * *** *
* * * * *** * **** *** * * * *
* * ** ** ** *** * *** * * ** *
* * * * * ** * * *** * *
*** * *** * *** * * * * *
* * * * * **
* ** * * * * * * * ********
**
* ****** ** ** * **** * ** * (d > 0)
* * * * * *** ** * * * *
* ** ** **** ** * * * * * * * * is ** ** in * * ** ** * ** ** *
* * * ***** * * * ** ** ** * * * ** **
* * *** * * * *
* ** * * * ** * *
* *** ** * * ** * * * * **** * ** ** * are no ** * * ** in * ** * *** * * ** * *
**** ** ** ** ** ** *** * * 0;
** *** * * * ** * *
}
answered
Dec 10, 2016
by
蘇瑋朝
(
-8
points)
ask related question
comment
Please
log in
or
register
to add a comment.
Page:
« prev
1
2
3
4
5
next »
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English
中文
Tiếng Việt
IP:172.70.179.51©2016-2025
Related questions
0
like
0
dislike
0
answers
AC 20161207 上課投影片
[Resource]
asked
Dec 7, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18872 -
Available when:
Unlimited
-
Due to:
Unlimited
|
46
views
0
like
0
dislike
10
answers
AC 20161207 exercise 2
[Exercise]
Essay (Open question)
-
asked
Dec 7, 2016
in
作業
by
Shun-Po
(
18k
points)
ID: 18876 -
Available when:
Unlimited
-
Due to:
Unlimited
|
1.3k
views
0
like
0
dislike
0
answers
Programming AC 檔案的存取教學影片1 (有六個影片）
[Resource]
asked
Dec 31, 2016
in
2016-1 程式設計(一)AC
by
laich
(
937
points)
ID: 20298 -
Available when:
Unlimited
-
Due to:
Unlimited
|
38
views
1
like
0
dislike
102
answers
AC 20161027 期中考 1
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 15378 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
|
8.2k
views
0
like
0
dislike
39
answers
AC practice 1
[Normal]
Coding (C)
-
asked
Oct 11, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 13020 -
Available when:
Unlimited
-
Due to:
Unlimited
|
4k
views
12,783
questions
183,442
answers
172,219
comments
4,824
users