0 like 0 dislike
2.1k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 2.1k views

16 Answers

0 like 0 dislike
Hidden content!
* * * ** *** ****
** ** * * * *** ***





int main()
* a, b, c;
* * ** * * * * * **** * *** **
* ** * = a + b;


******* * c);


* * * *** * **** **** * *** * * ***



return 0;
** * **
answered by (-98 points)
0 like 0 dislike
Hidden content!
* ** * * *


***** ** * * ** * **


*** ** * * ** * *


* **** ** ** *****




** ( ** )

{


* *** *
= * *
* * * * * * ***




= * * +




* ********** * ***










** 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
* ** * ** * * *

#include *** ***** * ** *

int main (void)

{
*** * * * c;
* **** a,b;
* * * * * * * *** * ** ** * *
* *** * **** ** * *** * ****
* * ** *
* ** ********* ** * *
** * * 0;

}
answered by (42 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** * ** **** ** *

void rect(int ,int,int *);

int main(void)

{
**** * **** * * * * a,b;
* * * ** * ** sum;


**** * * *** * * * * * ** *** * * * * *** *


* *** **** *** * ** * *
** * * ** * *** * ** ** * * * ***


** ***** *** ** *** * *** **** **
* * **** ** ** *** * ***** 0;

}
** *** * *** ** rect(int x,int y,int*p1)
** * ***** * ** *
* ** * * * **** *** *** ** * * ***


** ** ** * * ***
answered by (-114 points)
0 like 0 dislike
Hidden content!
* ** * **** ** ***
* * * * * *



int main()



{
* * *** *** ** **
* * ***** ***** **** **** * *** ** ****
* ** = num[i] + num[j] ;
* ********** ** * * ** *
* * * 0;



}
answered by (-50 points)
0 like 0 dislike
Hidden content!
#include * ** *



int main (void)

{
**** * ** * ** * ** * num1,num2,sum;
******* *** * * **** ** *** ***** ** * * **
*** * **** * ******* = num1 + num2;


*** * * * * ** *** **** * * ** ***
** * ***** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.179
©2016-2025

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.3k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 3.7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.2k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users