0 like 0 dislike
3.2k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 3.2k views

16 Answers

0 like 0 dislike
Hidden content!
**** ** *** * ** *
* * ** **** * * ******





int main()
* ** a, b, c;
* * *** * *** ** ** * * ** ** ** **
* *** = a + b;


* ** * ** * ** c);


* ***** * ***** ** * *** ** *



return 0;
**** * *
answered by (-98 points)
0 like 0 dislike
Hidden content!
*** **** **** ****


* *** * ** * *


* * * ** ***


*** * * ** * *******




* ** ( )

{


*** *
= * ** *
* *** ****** ** ** **




= + *




* * * * * * ***










* * ** 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
* ** * * * *****

#include * * * ** *

int main (void)

{
* * * * c;
* * ** a,b;
* **** * ** * **** * ******* ****
** *** * **** *
* ** *
* *** ** * * * ** *
* ** *** 0;

}
answered by (42 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * * * **** ** *

void rect(int ,int,int *);

int main(void)

{
* * * ** ** **** * a,b;
* *** * ***** sum;


*** * ** * ****** * **** * * ** * * * * *


** ** ** * * ** * **** * *
* ** * ** ** * ** * ** * ** ** * * * **


** * * * * * ** * * *** * * *
**** * *** * ** * 0;

}
* * ** * **** rect(int x,int y,int*p1)
** *** * *
* ** * * * * * * *** * *** ** * *


* *** * ***
answered by (-114 points)
0 like 0 dislike
Hidden content!
* * * * * *** *
* ** * ** * * ****



int main()



{
** * * * * * ** *
* * ** *** ** * * ** * * * * *
** ** ** = num[i] + num[j] ;
* *** ** * * ** * ** *
** * 0;



}
answered by (-50 points)
0 like 0 dislike
Hidden content!
#include ** ** * **



int main (void)

{
**** * ** ** ** ** num1,num2,sum;
* * **** * * * * ** * ** * ***** ** * *** * * *** ***
* * *** * ** ** * ** = num1 + num2;


* ******* **** * *** **** * * * ** *** * *
* * * * ** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.78
©2016-2025

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.9k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 6.2k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users