0 like 0 dislike
513 views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 513 views

16 Answers

0 like 0 dislike
Hidden content!
*** * * *** *
** * * * ** *





int main()
** * ****** a, b, c;
*** *** *** * * * * * * * *** ***
* ** ** = a + b;


*** * * ** ** *** ** c);


* * * * * ***** ********* * * *



return 0;
** ***
answered by (-98 points)
0 like 0 dislike
Hidden content!
**** * * * *


* * * * * ** **


* ******* * **


**** ** ** ** *




** * ( * )

{


* ****
* * = *** * *
* * *** *** *** * *




* = + ***




* **** *** ** *** *










*** 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
**** ** *

#include * * * * *

int main (void)

{
** **** c;
* * ** * * a,b;
* * ****** * ** ***** * * * * *
** *** * *** *
** * * **
*** * * * ** *** * * ***
* * * * 0;

}
answered by (42 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** ** * ***** ** ** *

void rect(int ,int,int *);

int main(void)

{
** ** * **** * ** a,b;
** * ** ** * sum;


***** * ** ** * *** * * ** * ** * *** * * *


* * * * * * * * * ** * **
** * * * * ** ** * * **** ** ** *********


* ***** ***** ** *** * * * ****
*** *** * ***** * * 0;

}
*** * *** *** *** * rect(int x,int y,int*p1)
* *** * * ** * ***
** ****** *** ***** ** ** * * * *


* * ***** ** *
answered by (-114 points)
0 like 0 dislike
Hidden content!
*** * *** ***** *
* * * * * ** **



int main()



{
** ** * * * *
* * *** * *** * * ** ** *** * * ***
* * * * = num[i] + num[j] ;
***** * *** * ***** * ** *
* ** * 0;



}
answered by (-50 points)
0 like 0 dislike
Hidden content!
#include ***** **



int main (void)

{
** * * * * ******** ** * num1,num2,sum;
* * * * ** * * * ** * ** * **** ** * ** ** ** *** ***** *
** ***** ** ** * * * * = num1 + num2;


** ** * * * *** ** **** * * * ********
* * ** *** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.27
©2016-2024

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.8k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 1.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 554 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users