0 like 0 dislike
11.4k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 11.4k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
**** * ** * ** * ****** i=0;
* * ** * * **** * *** ** * *
******* ** ** * * *** * * ** * ****** * *
* * * *** *** *** **** ** ** ****** *** **** * *
** ** * * **** ***** * * * * * **
**** *** * * ** * *** i;

}



int check2(char c)

{
* ** *** ******** *** **** * j=0;
* ** ** ** * * * * * * * * * *
* ** *** ** * ** ****** * **** *
* * * ***** ** * ***** * ** **** *** ** ***** *
* ** *** * *** * * *** * ** ** *****
* ** *** * * ***** ** * ** j;

}

int main()

{
** * *** ** *** * **** * c;
* *** ** ** ** * ** * * * i=0,j=0;
* ** * * *** * ** **** * * ** * * ***
* ** * * * * * ****** ** c!='.')
*** *** * * ****** **


* ** **** ** ** * * *** * * **** * **** * **
** ** ** ** ** ** ** * *** * * * ** ** * *
*** * * ** **** * * * * * * * * * * * ** * ** **** * * ***** * ****

    }
* * *** ****** ** * *** * ** ** * * *** * ** ** * ** ***** * * **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
**** * **** ** * *
*** ** * ** ***** *



int ** *

{

int ** ** *

char c;
*** * ** ** ** * *


* * ** *

{
* * *

i += 1;
***** **

z+= 1;
****** *
** **** * ** * * *** * * += 1;
* ** ***** ***** * **

}
* * * **** *** * ** * *



if


*** ***

}
answered by (-383 points)
0 like 0 dislike
Hidden content!
#include * *** * *

#include ** ** * *

#include ** * ** ** *


* main(void)

{
** * * * ** ** * ** *** count=0;
** * * * *** *** ** * * c;
* **** ** * ** ** **** * * * *** * *****
* *** ** *** * * * * ** * * (c != '.')
* * ** ** * * * *
** ***

count++;

else if ** *** *

count++;


** * ***** ** ** * *** * ** * ***** * ** * **
** *** ** ****** ** *
* * *** * *** * * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
# include ** **

# include * * ****  

int n;

void check (char c);

int main ()

{
* * *** ****
* * * **** ** * c;
*** ** ** * * ** * * **
* *** * ** ** * ( * ** *** * **** * * * );
* * * ***** *** *** ( c!= '.' )

** * ** ** ****
* ** * * * ** ***** * * (c);
* ***** ** ** * * *** * ( *** *** * ** );
** * * * ****
*** ***** ** * * ****** ( c==',' )
* ** * * **
* * ** ** **
* *** * ****** ***
* ** **** ** * * ***** * **
* * ** * * ** * * * *** 0;

}

void check (char c)

{  
* * *** * ** *** ** * * * ** * *** *
* ****** * * ** *
* * *** ** * ***** * *

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * * * * **

#include ***** * ** *

#include ** * * ** * * *


*** main(void)

{
*** ****** *** * ** count=0;
* ** *** *********** c;
*** * * **** *** ** *** ** **** ** * **** ** &c);
* *** ** * ** ** (c != '.')
* * ** ******* *
** * * *

count++;


*** *** * * ** * **** * * * ** * * * ** * * *****
**** ** * ** ** *** ***
****** * * * **** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
*** ** * ** ** * * *** ** * a=1,b;
******* * *** **** * ** c;
* * ** ** ** * *** ** * ** ** ** *
*** *** * ** * * * ***** **** * * !='.')
* * ***** * * * * ** * *
* * **** *** ** * * ** **** ** * *** ** * ** ** * *
** **** * * ** ** * * * * **** ** * * * * ***** ** ** * * ** * ** **
* ** **** ** * * ** ** **** ****** ** ** * * ** * *
** * *** ** * * * * ** ** * *** ***** ** ** * ** * * **** *
* * * * *** * *** ** * *** * * ** * * * * * * * ** ** **** ***

    }
**** ********* ** * **** ** * ** * * * ***
* ** * * * * * * * * **** 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
#include * * ** ** *

#include ***** * *

#include *** * ***


** *** * main(void)

{
** * ** *** ** count=0;
* **** ** * * * *** * c;
** ** * * * * *** * ** ** * * * * &c);
** * * * *** *** ********* (c != '.')
* ** ** * * * * * * *** *
* ** *

count++;


** * * *** *** ** * *** * * **** *** **
* ** **** * *** * *
**** **** *** **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <ctype.h>



int check(char c)

{

    int i;
* **** * **** ** *** *
* * * * ** * ** ***** *
** ***** * * * **** * *** * * ** * *** * * ****
*** ** * ** ****** ** * i;

}



int check2(char c)

{

    int j;

    j=0;
* * * * ** ** * *** ** * *
* * * ***** * *** ** * * * * * **** ****
* ** ** ****** * ** ** * j;

}





int main ( void )

{

    char c ;

    int l,i;
*** ** * * ** * * ** * * ** ** * **

    l=0;

    i=0;




* ** * ** *** ** * ** * * * != '.')

    {
* ** ***** * ** * ** ** *** * * *** * *** ** *
* * * * ** * * * * *** * ** * ** * * *** ***


* * * * * * * * * *** * * ** * * ** *** * **
* **** ** ** ** ** ***** ** * * *** * * * ** *** ** * * ** * *


* ** * *** * * **** ** ** * * * * * *** ** *** * **** * * *
*** ** * * **** ** * **** ** * **** * *** * *** * *
** * ** *** **** * **** ** * *** * * * ** *** ** **** * * *** **** * *
* * * *** **** *** * *** * ******** * * * **** * *
* * * ******** * *** * * ** * * *** * **** ** *** * * *** * ***** *** * * *** *** ** * *** *
* ***** * * ** * * *** * *** ******** ** *** ** * ** **** ** **** * * ******* **
* *** *** ** *** * * ****** ** * ****** ****** ** * *** ** * *** *


* ** * ** * ** **** ** * * * *** * ** *** * *** * * ** ** *
* **** ** * ** ** * * **** * * ** **** * * **** * * ** * * * *** ** *** *** **** ** ****
*** **** *** * **** ** * *** *** * * *** *


**** ** ***** * * ***** * ** * ** ****** ** * * ** ** **

    }


** ** *** * * * *** ***
* *** ** *** *** * * ****** **** ** **** *






** ** ***** ** * * ** 0;

}
answered by (-186 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** *** * * * ** **

#include<ctype.h>

int main(void)

{
* ** *** *** * ** * * ***** c;
* **** * ****** ** *** ** sum=1;


* * * * * ***** * * * * **** &c);
**** * *** * ******* * * * c != '.')
* ******* * * ** * *
***** ** *** *** * * ** * * *** * ** * * * **
*** * ***** ** * * *** * * * * ***** ** ****


***** **** **** * * * * * ***** ** ** ** * ** ** *** **** * * * * * &c);
*** * *** ** ******* ** **


* **** *** * * * **** ** * * **** * sum);


****** *** * * ** * * * ** * * * **** * ** 0;

}
answered by (-64 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * * ****

int strlength(char[]);



int main()

{
*** * **** * *** * str[300];
* * ** **** ** *** **** * **** * ** **** str))
* * **** ** *** * * * * * * ***** ** ** * * * ** ** * *** ****** * * *****
* ** * * ******* * * * ** * * *
**** * * * **** **** * *** 0;

}

int strlength(char s[])

{
* **** * * **** ** * i=0;
*** *** * ** * ** *** *** **** **
* * ** ** * ** * * ** * *** ** * * ** ** ******
* * *** * * ** ** i;

}
answered by (-90 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.92
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.3k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 6.4k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.9k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.9k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users