AC 20161201 第二次期中考 第二題

0 like 0 dislike
3.5k views
時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。

輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。

輸出說明：請輸出時針與分針間較小的那個夾角。

輸入範例：

12 31

輸出範例

170.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
reshown by | 3.5k views

62 Answers

0 like 0 dislike
Hidden content!
#include ** * ***

#include * **** ** * *

#include **** ** * *

#include * * ** ***

int main1(void)

{
* ** ** * **** *** * i,j,h,m,r,a;
** * * ** * ** *** * **** * ** * * **
* * *** *** **** * * ** ,&j);
* * * **** * * * **** **


** * *** * ** * ** ** *
** * ** ** * ** * ***


* * **** * *** ** * * * * **** * ** **** ***

return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** *** ** * *****

#include * * **** * ***



main(){

int **** ** ***
* **** ****** * ** * * **** ****
* *** * ******* ** * **
* * * ** ** * * *** ***

sa=6*b;
*** * **

g=ha-sa;


* **
** *
*** * ** * **** * **

else if * * ** *
* ******* *** * * * *

else
* * **
* ** * * ****



return 0;





}
answered by (54 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
**** * *** **** * a,b;
* ****** ***** ****** q,w,e;
* **** ** * * * ** * * * * * * **** * ** * * ****
* ** * **** * ** ** == 0)
* ** ** * **** ** * * *** ******** ****** ** = b/2;
* ****** * * ** ** * ** * if(b%2 != 0)
*** * * * * **** ** * *** ** * * ** * * = b/2 + 0.5;
** * * * * * * ** * (a != 12)

    {
*** * * * *** ** * *** * ** ** * **** * (a*5 >= b)
** * * * ** *** * * * * **** * **
* * * ** * *** * * ** * * * * * * * ** * ** * * *** * ** * ** * * = a*30 + e - 6*b ;
*** *** ***** * * ** * ** **** * * * * **
** * *** ** *** * * *** ***** **** ****** ** * if (a*5 <b)
**** ** **** * * ** ** * * * * *
* ** * ** * *** *** **** ** * * * *** ** * * * * * * * = 6*b - e - a*30 ;
* * ***** * *** *** * * * **

    }
** ** * * ** * * if (a == 12)

    {
* ** ** * *** ** ** * * ** ***** * ** *** (b < 10)
* *** * ** * ****** **** ** ** *** **** ** *
**** **** * ** *** ** ******** * * * *** ** * * ** *** *** = e - 6*b ;
* *** ** * *** ** ** * * ** * ** * **
* * * ** ** * * **** *** * **** ** *** *** ****** if (b >= 10)
* ****** *** * * ** ** * * * **** * **** *
* * * **** *** **** * ** ***** * * ** * *** * * *** ** * ** = 6*b - e ;
* **** **** ** * * * *** ******* * * ** * **

    }
* * ****** **** * * * * *** ** ** * * ****
*** **** ***** *** * * * * ** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
** * * * ** * **
******* * *
** * ** ** * * *** *




*** * ** * main()



{


** ***** h=0, m=0, i=0;


*** *** * ** *** ,&h);
* * * * ** ****** * ** *
* * ** * * ** *** ,&m);
* ***** * *******
*** **** 5.5*m-30*h;
**
** * * * * * **** *


** * * * ******
** * ** **** * * * ** * * * * ,i);

 else
** * *** ** **** * *** ** * **** ,360-i);


** 0;

}
answered by (-34 points)
0 like 0 dislike
Hidden content!
//  Created by HoMingJui on 2016/11/3.

//



#include * *** ** * *

#include *** * ***

#include * *** *****

#include <math.h>





int main(){
**** * ***** *** ** * a,b;
**** * *** * *** * xa=0,xb=0,ans=0;
**** * * * *** **** * ** *** * ** *** ** *
* ** * ** * ** * ** * *
*** ** * * * **** *** * * ** *** * ****
** * **** * ** * ** *
* ** * * * ** * *
* ** * ** * ** * *** * *** *** * ***
** * **** * **** * ***** ****
** ** * ** * *** ***** **** ** * * ***
* * * * ** *** ***** ** * * 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
//  Created by HoMingJui on 2016/11/3.

//



#include <stdio.h>

#include *** ** ***

#include *** ** ** ***





int main(){
* ** * ** * * * ****** a,b;
** * * ** * * * **** xa=0,xb=0,ans=0;
* ** ** * *********** * * **** * * * **** *** * ***
* ** ** * ** * * *** *** *
** **** * *** * ** ******* * *** * **** *
* *** *** ** * ****
* * * * * * ** ** * *
**** * * **** ** * *** *** *** * *** * *****
** * ****** * ** * *** ** * * *
**** * * ** ** **** *** ** ** ** ** * ****
* ** ** ** *** * **** ** ** * * 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
//  Created by HoMingJui on 2016/11/3.

//



#include <stdio.h>

#include ** * * ** ***

#include **** ** * *





int main(){
* ** * *** * a,b;
* *** * ***** * * * *** *** xa=0,xb=0,ans=0;
* * ** *** *** **** *** ** ** * * * *** *** ** * **
** ** * **** ** * ** ** ****
* ***** ** ** * *** * *** ** ** ** * * * * *
*** ** * ** * ** * * *
* ** * ** * * *** * * ** *
* * * * **** ** * * * **
*** ** * * *** ** *** *** * **
** * * * ** * **** * * *** * ** * *** %f ** ****** * *
* * **** * *** *** * * * 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>



int main ()

    {
** * ***** * ***** * * ** * ** *** * ** ****** ** m,h,a;
* * * **** ** * * * ** ** * **** * * * ("%f%f",&h,&m);


** ** * ** ** ** * * ** * * * ******** ** * ***


* * * *** *** * ***** * * * ** * * *** * *
* * ** * *** * ****** * * * *** *
* *** * * * *** * ** ** * * ******* * *** ***** ** * * * * * ** **** *
** * * ** ** **** ***** **** *** ***
* ** * * * * * ** * ** * ***** ** ** * *
** * ** *** ** * * * *** ******* * * ** * *
*** ** *** * ** ** *** * * * * ** **** ** * * * *** *** ********** * * ******
* * ** ** * ** ** ** *** * *** ** *** * **
*** *** * **** ** * * * * * * ***** * * ** ** *

    }
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include * ***** *

#include ******* * * * *

#include ***** * * *

int main()

{
* ** * * * * ** ** a, b, c, d, e, f, g;
* *** ***** **** * * ** * * ** * ** ***** **** *** *
*** ** *** ** (a = 12)

{
***** * * ** * * ** **** * ** **** = 0;

}
* * ** ** ** **

{
*** * * * ** * * * *** = a * 30;

}
**** * * ** * = c + b/2;
** * * * ** ** * * = b * 6;
* ** *** * ********* * = abs(d - e);
**** *** * * = abs(360 - f);
* * * * * (f > g)
** ******* ** ** *** ** * * ** ** * * * * * * ** ** g);
* *** * ** * *
* ***** ** * * * * ** *** ** *** ** ** ** f);
*** * * * * ** 0;

}
answered by (46 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>



int main ()

    {
*** ** *** * * ** ** * **** ***** * * **** m,h,a;
* ** ** * ** ** ** ** ** ** *** * ******** ("%f%f",&h,&m);
* * * ** * ******* ** ** *** * * *** * * * (h=12)
* * * *** *** * *** * * * * ** *** ********
* * * ** **** * ** *** *** ** * * * * * * ** ** ** * ** ** ** * * * ** *** *
* * * ** * * ** * **** * * **** * ** ***


* *** * ** ******* *** **** *** * ** ***** * * ****


***** ***** * *** * * ** *** * ** ** ** *** *** * **
** ** ***** * * * * ** ***** *** ** *** *
* ********** ** * * * * * * * ** ** ** * ** *** * * * * * *
** ** ** * *** * * *** ** ** * * ***
**** **** * * ** *** *** **** * ** * ** * **** ** ** * * ** * * ** *

    }
answered by (-162 points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.223
©2016-2025

Related questions

0 like 0 dislike
16 answers
AC 20161201 第二次期中考 第五題
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00 | 1.4k views
0 like 0 dislike
86 answers
AC 20161201第二次期中考 第四題
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00 | 4.6k views
0 like 0 dislike
49 answers
AC 20161201 第二次期中考 第三題
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited | 2.7k views
0 like 0 dislike
21 answers
AC 20161201 第二次期中考 第一題
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00 | 1.5k views
0 like 0 dislike
0 answers
AC 20161201 第二次期中考公告
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited | 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users