0 like 0 dislike
2.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited

edited by | 2.2k views
0 0
12345

27 Answers

0 like 0 dislike
Hidden content!
#include *** *** **
#include * ** ** ***

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
******* ** * ** ****
 
* ** ****** * * * * * ** *** *****
** *** * * ** ** * * ****
** ** ** * * **** * * * **** **** ** ** *** == s2[i])
**** **** **** **** * ** * * * ****
* * **** * **** ** * **** * * * * * ** **** * * * **** ** * * *
** * ** * *** * * ** ** * * * *** * **
 
** ** ** **** * **** * *
 
** ** * ** * * * * ** ** * * ** == length)
* *** * * ** ** * *** ***** *
* * ********** * * * *** ** * * * ** ** * * ** ** **** * is a prefix of %s",s1,s2);
* ****** * * * * * ** **
 
** * ** * ** * * ** **
* *** *** * *** * * * *** * *
* * ***** **** * * * * * ** *** *** ** ****** * * ** * is not a prefix of %s",s1,s2);
* * ****** * ** ** * ** *** *
 return 0;
** * * * **** ** * * * ****
 }

int main(void)
{
** * * **** *** * ** s1[100];
* **** *** ** * * *** *** * s2[100];
***** * * ** * *** * * ** * i,j;
* * *** * **** * **** * *
*** * ** ** * * * ** ** ** ** * * *** s1);
*** * ** ** *** * **** * **** * * ** ** ** s2);
** ***** * ** *
** * **** *** * *** * ****
*** ** ** * * ***** * *
** ** ** *** *** * **** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include ***
#include * * ** ** * *

int prefix (char st1[],char st2[]){
* ***** * **** * * *** len=0, i, cnt=0;
** * ** ** * * * * * * *
* **** * * * * * * * ** = (unsigned)strlen(st1);
***** * * ***** *** * ** *
*** *** ** * * * * (i=0;i<len;i++)
* * *** **** ******
* ** ** * (st1[i]==st2[i]){
* * * * ** * * ** **** * ** **** ********** *** * ** * ** *
***** * ** ** * ** * * * * **** * * *** * * **
* * * * **** * * ***
* ** * ** * * * (cnt == len){
* ** * * ** ***** *** **** * * ** ** * 1;
** ** * **** *** * **
** * ** ** ** ** ***
** ******* ** * * ** ** ** 0;
** * * * * * * *
}

int main(void) {
* ** * * ** ** *** st1[256];
** * *** ******* * ** *** * st2[256];
* * * * * * * ** *** *** * *** * * * ** ** ** st1);
* ** * ** * * * ** * ** ** ** * ** st2);

* *** * ** * ** * (prefix(st1,st2)){
** * * ** ** * * * ***** ** ** * * * ** ** is a prefix of %s", st1, st2);
* * * ** ** * * ** **
** * * ** * * ** ** * *
********* ** * **** * * * * * ** * * * ******* * ** * *** is not a prefix of %s", st1, st2);

** *** * ** * ** ** ** ** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
*** ** * * *** **** *** *** * * ** * **
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
** * ***** ** * * *** * * * * * *** ** ** *
*** * * **** ** ****** * ** ** ** * * **** * ** ** * *** **********
**** ** *** * * ***** *** *** ** * ** ** * * **** ** * *** * * * ** * ** * ** * * *** * *****
* * * ** * * *** * * * ** *** * ** ** ** ** ** ** *** * * * * **** * *** * ** ****** * * * * * * ** * is not a prefix of %s",a,b);
* **** ** ** * * ** ** * *** *** *** * ****** * ***** * *** * ** *** ** **** ** * *** ***** *** * *** ** ** * * *** *
** *** ** ** * ** * ** *** ** * * ******** * ** * * ** * * * *** * ** *** * ** * * *
* * **** ** **** **** ** * * ***** *** * **** * **** * * * ** **
*** * * *** ** * *** *** * ** ** * * ***** * **** * * * ** * * ** * * ** ** ****** *
* ** * *** **** * * **** ********** ** ** *** *** * * *** * ** * ** * **** ** * ** * * ** * * ** * * is a prefix of %s",a,b);
* ** * * ** ** * * ** * * * * * * * * ** ** * ** ** ** ******* * * **** **** * * ************ * ** *
****** ** * *** * ** *** ** * * *** *** ****** ** * * ** * * ** * * *** * ** *** **
* * * ** ** * *** * ** ** * * ** ** * *** *** * *




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
* ** * * ** ** * ** **** * ** *** *
* ** * *** **** **** ** * ** **** ******** *

** * ** ** ** * *** * * ** ***** *** * **** * *** ** ** * **** 0)
** *** * ** * *** ****** * ** * * * **** * * *** * ***
*** ** * * ** *** ** * ** * *** ** * * ** * * * *** ** *** * ** ****** ** ** * * ** is a prefix of %s",pre,str);
* ** **** ** ** * * *** * * * ****** * * * **** * * * ** *****
*** ** * **** * *** * *** ** **** ** * * *
*** *** * ** * * **** * * ** *** * *** * * *** * **** ***** * **
** * ** ** *** * * * **** **** * * * *** ** * * ** * * ** * * *** *** ** *** * *** ****** *** is not a prefix of %s",pre,str);
* ** ** * * * * ** **** ** ** * * * * ** * * ** ** * ** * *

*** ***** ** **** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
* * *** *** ** * * **** a[100];

* * * * ************ *** ** b[100];

*** *** *** * i = 0;

* * * ** * ** * *** prefix = 1;

*** *** ** ** * * * * * * **** * ** a, b);

* * * *** * ** ** *** * len = strlen(a);

* * ** ** *** ** * ** = 0; i < len; i++)
**** * * * **** ***
* *** ***** * ***** *** *** * * * * ** * ** * ** != b[i])
* * *** * *** * * **** ****** * ***** ** * *
* * *** ** * * ***** *** * ** ** ** * * ** ******** * * * *** * **** * * ** = 0;

* *** ** **** ** ** *** * **** * * *** * * ** *** ** ** * * * * *** * ** is not a prefix of %s", a, b);

** * *** * * ***** **** * * ** ** ** ** * * * * * * * ** * ** *
* ** ** * * *** * * * **** * **** *** *
** *** **** * * ********
* * ** ** *** ** * *** * * * == 1)
* **** ** ** ** * **
** * **** * **** * ** * * ** * * * * * ** ** *** is a prefix of %s", a, b);

* * ** * * * ***** *** **
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** ** * ** *
#include * * * * **

int main()
{
**** ** * * ** ** * a[100],b[100];
***** * ** * * * ** i,j,prefix = 1;
* * * * ***** * * *** ** * * * ** %s",a,b);
*** *** *** **** ** ** ** len = strlen(a);
** * * * *** * * *** * = 0 ; i < len ; i++)
* * * * * ****** * **
***** *** ** * * * ** *** * **** ***** ** * * != b[i])
* **** ****** **** * * ** ** * * ** * *
* ** ****** ** *** * ** **** * *** * * * * ** ** ** * *** * * * = 0;
** ** * ** ** ** *** * * *** * ** ** ** ***** ** *** ** *** **** ** *** * * is not a prefix of %s",a,b);
*** ** * **** ** ** * * *** * **** * ** * * ** ** * ****
** **** * * ** * * ** * **** * * * ***

********* * ** * ***
* * ** ** * *** * * == 1)
* **** * ** * * * ****** * ** ** *** **** is a prefix of %s",a,b);

 
* ** *** * * ** *** * 0;
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** * ** ***** * *
#include ** *** * *******

int main()
{
** * ***** ****** *** **** a[100],b[100];
***** * *** *** ***** i,j,prefix = 1;
* * * ** **** *** *** ********** *** * %s",a,b);
**** ** ** * ** ** * * * len = strlen(a);
*** * * *** * ** **** = 0 ; i < len ; i++)
* * * ******* ** * * *
********** * ** ** *** ** * * * ****** *** * * * ** != b[i])
*** * ** * * ** * * * ** ** ** *** **** *
** ** * **** ** * ** ***** * * ***** ** ** ** ** *** * * ** * ******* * = 0;
*** *** * * ** * * ** ** * * * * **** ***** * ***** * **** ** ****** * * * * is not a prefix of %s",a,b);
*** * * * * *** * * *** *** **** * ** * * ** ** ** ** *** **** *** **
** * * *** **** ******* *** * ****** *** ***

*** * ****** * * * ** ** *
* * * ****** * * ** * ** ** == 1)
** ** * * *** ** ** ***** * ** ** ** **** * **** * is a prefix of %s",a,b);


** * ** * * ** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include *** ****
#include ** * * * * **

int prefix(const char *pre, const char *str)
{

* * * * * ** * * * * **** * *
*** * * * * *** ** ** * ** * ***** * *** ** ** * * 0;
* * ** * * * * ** * * ******* ** ** *
* *** ** ** *** * * ** ** ** * *** * ** *** ******* ** 1;
* * * * * ** * * return 0;


}

int main()
{
**** ** * * * ***** ** *** pre[100],str[100];
** ****** ** * * *
** * * *** * ** **** * *** * ** ** * *****
***** *** * *** * * * ** ****
*** * * ** * * * * ** * *** * * ** * ** * ** * * * ** is a prefix of %s",pre,str);
* * * * *** * *
** ****** *** * * ** ** **** ** *** * * * * ** *** * ** is not a prefix of %s",pre,str);
** ** **** ** ** ** * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
* *** *** ** ***** **** * c;
*** * **** *** * * *** * *
** *** * * ** **** * ** *** ** * 0;
* *** ***** *** **
* ******* ******* ***** * *
* * *** ** ** ** ** ** ** * ******* * * ** * **** ** *** ****** * * * of a string
** ** ** **** * * *** ** ** **** * ** * *** ** * *** ** * ** ** *
* ** ** * ***** ** ** ** * * * * * * ** ** **** * * *** **** * ** ** * * ** * *** * 0;
****** * ** * ** ** * ** * ***** ***** *** * * *
* ***** * * * ** * * ** ** ** * * ** **** 1;
    }
}

int main(){
** ** ** *** ** ** a[100],b[100];
* ** * * * * *** ** * * ** %s",a,b);
** ***** * * **** ** * * **
** * * * *** * * ** *** * * ***** **** ** * ** ********* is a prefix of %s",a,b);
** * *** *** *
** ** ** **** * * ****** ** ** ** ** ** * *** * * ** *** is not a prefix of %s",a,b);
* *** * * ***** * ** **** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * **** ** * ***** *** p[100],s[100],a[100]={};
** * * * ** * ** t;
***** ** * ** *** * ** **** **
* * *** * * *** ** * ** **
* * * ** * *** ** ** *** *** ** * %s",p,s);
* ** * * *** ** * ** *
* ** * * **** ** * ** * ** **
* * ****** * *** * * ***
* * * * ** ** * ** * * * ** *****
* *** ***** * *** * ** ***** ****
** *** * * * ** ** * * * ** * * ** ** is a prefix of %s",p,s);
* ** * *** * * *** *
** * * * * * *** * *
* ** ** ********** * ** * * * * * ***** **** * * is not a prefix of %s",p,s);
* * * * *** ********* ** *
* * * *** **** ****** * * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.56
©2016-2024

Related questions

0 like 0 dislike
57 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited
| 2.9k views
0 like 0 dislike
29 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited
| 2k views
0 like 0 dislike
53 answers
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited
| 2.6k views
12,783 questions
183,443 answers
172,219 comments
4,824 users