1-11 Exercise 3: Prefix of a string

0 like 0 dislike
2.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 2.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include ** **  *  *****
#include **     *** *** * 

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
* * **** ** *    *** ***
 
**  **  **** ******   ****** ** * * ****** ** ** *
  ***** ****     ****** ** ** * ** 
   ** ***** * *  ** ****      *  *  *     * ** *****   *********  *  == s2[i])
**     **   * **  * *   **  ****  ** *  ***** **  * ** **
*  *  *  *   *  ** *  **      *     ***  ***** *** *   ** *   ** ** * * *  * * ** * *  **
** **  *** *** *      **   *** ***** *  **  ** *
 
*** ***         ** ***  ** *  
 
  * * *****         *   * **  ***  *  ***  == length)
 **  ***** * ** * **** *  * *    
*****   *** **  ****  *****   ** * **** * ** *  * *** *** * *   * * ******* is a prefix of %s",s1,s2);
 ***** **  ** **  *     *  * * * *** 
 
**   *  ****  *  *   **  * ** *           
 ** *        *  * **    ******** *** *
** ***   *   *   *****   *  **  ***  * * ****  * *  * *  * ** ** *   * *    is not a prefix of %s",s1,s2);
 ****  ****   ****   * ****   
 return 0;
****    **  * * *  **     **   *
 }

int main(void)
{
** * *  *** *  **  **   ***  *  s1[100];
 *    *  * * ** ** ****** **   s2[100];
****   **   *   *  *  ****  ***** i,j;
*   *** *** *   **   * *  *
      *     *** *   * * **** ** *  ***** * s1);
  *  ** *  *** **  ** * * ******          * s2);
 ***  * *  * ****** **  **
*** * *   **** ***     *  **   
 * **  * * *  ** *   *  * *
 **** **   *    * * *   * **  * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *  * *** ***  
#include  *     ** ** ***  

int prefix (char st1[],char st2[]){
  ******* ***** **      **  * len=0, i, cnt=0;
 *****  ****   *   ***  *  
*  *  **  ***  ** *  ** **     *  = (unsigned)strlen(st1);
*****  *  ***     **** *****
**  ** **  * *** * *  ******   (i=0;i<len;i++)
******* *  * *  **    **   * *
     *  **  * * (st1[i]==st2[i]){
 ***   ** ***** ******** *** ** ** * *  ****  *  *   *   * ** *     * * * *  * *   *    **** 
   **    ****** *  * ***  *   *** **** * ** ***  
*** **** **    * * *  * *  
 *  *    ** *  *  ** *  **   * (cnt == len){
*    ********* *  *   *   *** *   ** ***  * ***  *     *   * * 1;
   ***  *  ****** **  **   
 ****    *    *  ** ** *** ** 
* ** * *    **    **    ** 0;
  * ** ** *  ** *  *  * 
}

int main(void) {
 *   * *   * *  **  ** **  ** st1[256];
** *  *** ***** ** *****   *   st2[256];
****   *   ** *** * *   **  ***** * * *** * * **  *  ****  *   st1);
 **  *      * ***   * **  * *   *  ** *** *   *  st2);

*   * ***** * ** * ***  * ** * (prefix(st1,st2)){
 ***  * ***   *    *  *****  **    *** * * * * **   ** *** is a prefix of %s", st1, st2);
  ** ** *   *  ** **  ** * *
       * *   *  *****   **   *
  **** **** *    ** *** *  **** * * *  *   * *    *  ** * *****    * is not a prefix of %s", st1, st2);

  * * * * * ** *    ** * * **  0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
*    *  **     * **** *  **    **  ***  ** * 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
 * *   * * * ** **   *  *** *    ** *   ** * ****   
  *   ** *    **   * ****        ***  **  * **  ** **  *           ** *  ***    *  **  **   *    
***  * ** ***     *    ****  *** * ** * *** * * **  * * * **  ** **** **         * * ****  *  *  ** ** * * *** 
*   ** ***    *  ***       ***   ****  *  ****   * * **  * * ***** *  **      * **** ** *  ** *   **  * **** * *   *    ***   *  * * **  **  *  ** ***   is not a prefix of %s",a,b);
 ** *  *  * ** *** *  * ***    * **  ***  * ***  *    **   *** *  * * **        ** ** ***  *   ** * **   **  **  * *   ** *** *  **  *     * * **
    *   ** *  * ** * ******  **  **  * *  *******  *  ********* *****   *  ** *   *  *  **** *
   *     *   * ** **    * ****       **  *  ***  ** *     *    **          **  ******    
 ****   ****     *  ** **** *   *  *  **  *    *    *  * * ** * * ** * ** *   ** *** **  *    **  *** ****  ** **** 
****  *     *  *    ***  *   ******  ** *  **       ** ***** ****  *  ** **  ** *** * *  **   * **** *    * *  * * * *** * ** *  ** * * *   * ** ******  is a prefix of %s",a,b);
**    *** *    *   ***** **   *  **  *  ** **  **** *    ****  ****    **     ***** ***  * ** ***  **     ** **  **    ***  ** * **    * 
*  *    *     ***** * ***   ** ** *  * *** *    * **    **  * ** ***  ****  *             **    ** *
**   * *   *  **       *  *     ** *        *** **   ***




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
  ** * ********** *   **  **** **      *  * *    * ***
 **  ** * ** ** **   ***   ** *        ****     ** * *

*  ** ** **  ***   *  ** *** ****    ***  *** *  *** ******  ***** *  * *  ***** 0)
 ** ** *    * * *** **** ** * * **   *** **   *    ********* * * ****  *
   **      *** *     ****  * *  *********   *    ** **  ** * ** **  ***** ** *  *   ** ***** ** **  **   *    ** * **** is a prefix of %s",pre,str);
****    *  *  *  **   *** *  **   * *  *** *   ***** * *   *****  * 
 * ** * *** ** **  ***      **  **  ***** *
****      *  *** *  * *    *  ** ** **    * **   *       **   * *  *  ** * * 
****  *****  ** **  *** *   * **    **  * **   *  **** * ** ***  * *** *  **  ****  ****  * *   **   ***   *    *   * **  * is not a prefix of %s",pre,str);
 * * *  ** ** ****   **  **  * *  ** * * **  * *   *****   **  *  * * *

 * *   ***** * ** *   ** **   0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
     **  * * *   *   * * *  a[100];

 **** ** * ***  ** **      b[100];

 *  ******   *    *  *** *  * ** i = 0;

* **  **** * * * ******* ** prefix = 1;

   ** *  * *** ** *     * ****  ** * * **      a, b);

 *  *     *  ****  *  *   * **   len = strlen(a);

 **** ****    **   *** ***  ** = 0; i < len; i++)
*        *   *** *** * * 
****  * ****   ** **  *  **  * ***     **   *** **   **      != b[i])
** *** *   ***  *  * ** ** * *** **     * *   **** *  *    **
 *  ** ***  **  * *  *****  ***  **** *  ** *   *** * * *   **        ** **        = 0;

 * *******   ***  ** * * *  *   ***  *** * *   ** *  ***  *  **    ****          * **    *  * is not a prefix of %s", a, b);

*   ****** * *     ** *** *** *   **  *  **   *      **   ** *   *** ** 
 ** * * **  ***** * * * ** * *** *   * ********* ** * ***  **
**    ***      * * ***  *  *    
 * **** *  * ****   *   *** *** * *   == 1)
    * * *  * ***    ** **
**    * * * ****  ******      *  ** * **  * *** *  *   **     *   is a prefix of %s", a, b);

 **   **    * *  * ***  ***** ** * 
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include      *  *   ***** 
#include **  **     * ****** 

int main() 
{ 
 *    **  **  *     * ******  a[100],b[100]; 
  **    *** * **  **   i,j,prefix = 1; 
  *   ** *    ** * **  *      * * ***  %s",a,b); 
 ** *   *     *** ******  ** *  len = strlen(a); 
  *    * ***** * **** ***** *   **** = 0 ; i < len ; i++) 
 ***       ***  *  *  * ****   *  
  * *  *** ** ***   *  ***      **  ***** *   * ** ***    * * *  *  * != b[i]) 
 *   *******  *   * **  *     *  *  *    ** * * * * *  
** *      * *    *  *  * * ******  ** ** **** **** * * **  **  *  * * **  * **** *   *  = 0; 
***    * **   ** ***    ** ****  **    ** * * * ****   ** ** ** ***  ***   *  *** **  ***   *  *   is not a prefix of %s",a,b); 
 **  * *  ** ****   * ***     ****  **  ******* ***   ***        * *  *    *  **     ** ** ** 
***  * * ****  *******                ** * *  * *** **   * 

* **  *     *** **  *  *  **  ** 
 *  ***** *         **  **    *  == 1) 
** **   *      ********   *    ***  *   *** *  *  ***      *   ** is a prefix of %s",a,b); 

 
*  * **   *    ** **   **   **    0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ** * *   * **  **
#include  * *  *  ** *  

int main()
{
  **     * * **  *  ****    *** a[100],b[100];
   *  **  *  * *  ****  ** i,j,prefix = 1;
  *  * *****      *** **** * * ** ***  * %s",a,b);
*** ** * **   * *  *  * *    *   len = strlen(a);
      *    *  *    ***  ** ***** *  = 0 ; i < len ; i++)
 * * ** ** **  *  *****  
* ** *  * **    *** *  **** * ***  *  * *** **    ***  != b[i])
*    *   ** *** ******* *******         * *   * *** ** *
 **    *** **** ***  *** *** ** * * ** * * *   *   ** * *  **   *  ** ** **  *    * ** **    = 0;
   *   * **  *    *      * *  *  ***** *   *   ***  *       *  *   * * ***  ****** *  *  * *  is not a prefix of %s",a,b);
**  *  * *** *  *   *     ***    ***   ************  ***   *  * * **    * *   **    * **
    *        * *     *    * **** **     *   **** * *  *

 ***** *     * * ***         *
 *  ** *  **  * *  *        == 1)
       * **** * *  * * *  * ***  **   **  *      **      *  * ** **   is a prefix of %s",a,b);


   ** * * * ***  *** ** **** * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  * ** ***     
#include * **  **   *  

int prefix(const char *pre, const char *str)
{

* *   **  ** **  *       * *   *****  ***   ** 
 * *** *  *   ******   **     ** * **  * *  *   **  ** *** 0;
*    *** **  *** ****  * *   **** *     ** * * ****  **
*  **    ** * * *** *  * * *   *  **   * * **  * * ** * 1;
 ***    *** **  ** **  *    *  ***** return 0;


}

int main()
{
  * * *** *      *  * ***  * ** pre[100],str[100];
 * ***** **  *     ***
****  * *  * *** * ***** **** ****   *  **  ***  
***** * **  * * ****   * ***  * * **
*** * * * ***** *    *  **   * ***    * **  **  *    *     * *       is a prefix of %s",pre,str);
* *  **    ****    * *** 
*  ****  **   ***** **  * * * ** *  * * *    **            **  * * *  * is not a prefix of %s",pre,str);
 *  *        ******     *   *   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
* *****  * *  **  *** * *  * * c;
*   ***    **  ***   *     *  *      *    ***   
*  ***   ***  *  **     * * *    * **   ***** * ***** * ** * * 0;
  *****   **  *   *  ** ** 
   *** **   **    *  *     *  **
*** * * ***   *  **  **   **    * ** *** * * ** * ** *** ******  * *** ***  * * of a string
 ** * *   ** ******    * ** ** ** *  *  *** ***      *** * *** *   *****  *** * * 
** * ***    **    * * ** * * ***  ****  *  *  **  * *** *    ** *** **  ***   **  ** * *  * ***** * * *  * *****  *  0;
**  * *  * ** * * *  * **** ***   *  **    *   * *** *
 *  ** * * ** *  *****   * * ** ** * *   ***  *** *   ***  1;
    }
}

int main(){
** **** * **** ** **   *** ** *** * a[100],b[100];
  ** * *  *** ****     ***** * **  %s",a,b);
****  ** ** *  *       ***    * ** * *    
       *   * * **** **  *     *  *  ** **** *********   ** * *      is a prefix of %s",a,b);
* **  * **   *  **  *****
*  *****     ***  * *** *  * * *****  *  * *  *    ****  *  * **   * * is not a prefix of %s",a,b);
*  *      *  *   * ***  ***      * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
***  * *  ***** **     ******  p[100],s[100],a[100]={};
 * *  **    *  *      *   * t;
* ** *   *  ****  *  **    * * * ****** *
 **** * * *   *  *  ***** *    ****** *   *
* ** *   * **    * ** * * **** *****  *   %s",p,s);
**  * ** *    * * * *   * *  ***  
*   **   *  ******   *  *  ** * **
 ** ***       ***    ****   ****  *
  *   * *  **    **  *  *   **  * ** * * **  
* **     *   *    *   ** * *  *  *    
* * **** ****  **** **   **  **  *  ** * * ***  * **   *  ***** is a prefix of %s",p,s);
***   ******* ***  *  * **
* ** *  *** *** ***       * *** **
 *        *** ** ** * * *   ** ************  * * *** * **  *  * ******* is not a prefix of %s",p,s);
 ** **** **    *****  ***
**** *  *    *   *  ****  ***  0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.186
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 2.9k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 2k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 2.7k views
12,783 questions
183,443 answers
172,219 comments
4,824 users