1-11 Exercise 3: Prefix of a string

0 like 0 dislike
2.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 2.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include *  *  ***   *  
#include     *** *  * *   *

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
* * ** **    ** ** ******** * 
 
   *   *****  * * *   * *** ** **  ** *   ********* *
* * *** *** ** **   **    *   *  *  **
** *   ***   * * **  **** ****** ** * * **  * ** * **   == s2[i])
   ****   * ** * ***     **   *  ** *   *  *   * 
  **  ***   *   *  ** *****  *** * *  ******  **  ***    *  **  * ***** *****   **     * *** 
   ** *  * * ** ***  * ***  **    ******* * ***** * *
 
 *  **  ***  * *  ** ******     * *  *
 
*       * ** *** * * ** * * * *       == length)
*** *  * *****  ** ****** * *** **** * ** 
**   ** ** * *  **** * * * **  * ******  *     ***** **  ** *  ** **      * **** is a prefix of %s",s1,s2);
* * * *     *  ***   * **   
 
  ** * ** *** ***  ********* *** *
      ** **  * * * **  *    *** *   
 * ** *    *   * ** * *  ********* ** ***     ***    * *  **  * * ** *   ** is not a prefix of %s",s1,s2);
  *       ***      *  *  * * ** ** * 
 return 0;
 * * ***  * **   *****  *  * *** **     
 }

int main(void)
{
 ** *  *** * * ********* *** s1[100];
 * *** * ***  *   *    ****** *   s2[100];
  * **     *** *     ***** * *  i,j;
* ** *  **      ***  *     *
  ** *  *  *****   ** **  * * * * *  ***  s1);
*  ** ****  ****  *   *    ** *  * * ***** *   * s2);
** ** ***  ***  *** **** *  
 *    ***   * **** ***   * ****  **  *
*     * *** **   *** *  * 
***** **  * * ****  ****** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *   ***  *  *  
#include  ** *   * ** ****

int prefix (char st1[],char st2[]){
**** **** * ****** *   ** *** ** *  len=0, i, cnt=0;
** **   ***    **  * * *  * * *
*  ** *   * * *   *** ** ** = (unsigned)strlen(st1);
 * *** *   **    **     * **  
 **    ***** ** * *** **   (i=0;i<len;i++)
  ** **** *** *  * *** *  
  ****  **       (st1[i]==st2[i]){
 **** *    ***   * * ***      *   * ** *******    ** *  * ***  * **  * **** **     * **
 * ** *   * **** **  ***  * ** ** ****** ****  ** * * 
***  * * ** **    * * ** *   *
  *** *  *** **** **  *  *  (cnt == len){
 * *  * **** * *    *      *  * * *  *** **** **  *  * * **   1;
 ***   *  **  ** *   ** **
       *       ***  ** *** * 
 **** *  * * ***** * *  ******* 0;
** ****   *  *   *** * * * * 
}

int main(void) {
 *   **  * ****  **** *  *  st1[256];
  * ***** *** * *     * * * ** st2[256];
* ** *   *   *** **   **  *  *** **      * *****    st1);
 * ***  *   * *** * **      *      ***  st2);

 ** *  ** ***     ******   *    ** (prefix(st1,st2)){
* ** ** **** *  **     **  *** ****  *  * ** *  *  ** **  *  ** **   **** is a prefix of %s", st1, st2);
 * ** *    **  *  ** **  *   **
* *  *** **   * *****  *** * *  
***** *  * ** ***  *** ***  ** ** ***    **  **  **   * *  **    **   ***  is not a prefix of %s", st1, st2);

 * ***   ** ** **  **   ** ***  0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
 **   *** ** ***  * ****  **   **   ** **********   ***  
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
* *** *  *  * * * *    * ** ** * ***  ***  *  *  * **   * 
 **** ****  **  * ** * ** *   ***** **** ***     *   * * **** * *      *    ********  * *    
**    ** ***       **  *   *    *  * *** **   *    *****  *** * ** *   * **  * *    ****** **  ****  * *  * ** **  *
** *** *     *  ****  ** ** * * ** **** *  *    **   * *****  ****  * * * * ** **  ***     * *  ** **   * *****   * ******* * *     *  **    ** is not a prefix of %s",a,b);
**     ** ******  **    ********  ***   * **  **  *  **     * *  **  ** * ** * **    **  ** * ******* ** * ** ***   ** * * ** ** *   * *   ****   
*** *** * ******   *  ** *    * * *  * ** *  **  ***   *  * *** ** * * ** **  *  *  ***    ** *  *     ** **
  ** **    *    * *            * * * *   **  **** ****** * ******    ** ***** * * *  *   * 
 *   * ***        * ***      **  **  * *     *  ** ** *   *****   *  * ***  * *  *    *** * *  ** *** 
**    **    ** ** ** *  **    *  ****   ****   ***  **  ** **   * ** ** ** *  * * ** ** ** **** ** * *  *** *   **   *   *  ****  **** ** * ****  *   **  is a prefix of %s",a,b);
 ** ***  *     *  ** * ** **** ** *  ***  ** ***  ** * **  *  **  *   *   ********** ** **  * *    *    *  ***  *   ***  ******   * *   *
******* *     * * *     ****   **** * *  * *  **         *   * *    *  ** **   *  **** * ***  ******  **   *   *  
**  * **       *****   * ***       * **  *****    **** **




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
***  ****  ** **   ** *  *   *** *   *  *  ** 
 * **  * ** *      ** *** ***  **  *  * ** ***    *   

***   ****  ** * * * * *         * *    *  ****  * **     **** ***** * ****    0)
***    *   ** * *** * *    **  * **   ***  **   ***  **    * ** *
*** *  * *     * *   **  *    * * *     **   * * * * ****  *  *  *** ** * ** ***    ** *  *   * * ** *   *      ***   * ****      is a prefix of %s",pre,str);
* * ****  **     ***    *** ** * ***    *** * * *** ****    *  *   * * **   ***  *
 * *  **   *  * *  ***  **   * * **  * *   * * *  **   **   * 
* ** **      **     **** **  ****   *   ** ** *   ******* ****    *  ****** ** *    *** *   *   
** * * * **  ** ***  *** * ***** ** *** ***  *********  *      * *   **  *     *  ****   *   *********** **    *   *  * *   is not a prefix of %s",pre,str);
  ** **   * ** ***  * *** * * **** *   **  *  ****  *    * ***  ** * *  *    **  *

  *  *** **      **  * * *   * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
* ****     **** *   *******    a[100];

 *** *** ****** *** *** **    **  b[100];

*   *** * *   **  * *  *   *** *   i = 0;

* * **  ** * **  * ****   prefix = 1;

*   ** ***  *  **** *  *** *****    **   **   a, b);

  **    * *** *    **  *  *   len = strlen(a);

 ** * * *  *  *   * ***   ***  ** = 0; i < len; i++)
 * *** ****  *** **  **  *
*  ** * * **  * ** *  *   * *** ***** * * * *    ** ** *** * * != b[i])
*  *   ** *   ***  **   *** *   ** *** *  ** ** *   
  **** *   *    *** ** ****** *   * ** * *** ** *  * **  **   *  *** ** **** ** = 0;

*   ****  *   *  ** **  * ** **    ***  **** * *  *** ** ****** **   * ** * *  **    * *** ** ** * is not a prefix of %s", a, b);

****  ****   *  ** * ** ** ******  *** ******* * *** **  *  * *  **  *  *  * *    ****  
*  * **    *  *   ** *  * ****** *** ** **  **      **  
******   ** ** **    *** ** 
* * **  *  ***** ***   **   * ** == 1)
** * ******* * *     ** **** * **
  * *  **  **  **  **      *  ******  * * ***       *   ** ***  is a prefix of %s", a, b);

****  *   *  ** **** **** **
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *   * *   ** 
#include ****  **  *   ** 

int main() 
{ 
  * *    **  ***    ** **   a[100],b[100]; 
**   * *** *  * * * * * i,j,prefix = 1; 
 **** ** * *   *  ******* *  *    ***    %s",a,b); 
  *** **** *  * ****    *** ** len = strlen(a); 
 ** ** ********* *** **  **   ******* = 0 ; i < len ; i++) 
    **  * ******* *   **   *  * 
***** * **  * * **** **  *    *  * *** * *   * ** *   *     != b[i]) 
 *   * *   * * *  * ** **   * ***     *****   * **  * *  * 
**   *  **     **  *  **** **** * ***** ** ** *    ***     *  * **   * ** ***** ** = 0; 
 ******   ** *     *  *  *** *   * *  ***   ****  *    ***   * * ***** ***   *** * ** *        *** is not a prefix of %s",a,b); 
**** * ****  * *   *  * ** *    ******        *  * ***  * * *  **** * ***       ********  
 **** ****  *   ****  *  * *      ***    **   **** * **   

  **  *  *** **     ****   
 ** * *****   * **  * * *   *  == 1) 
* *     * **        **** ** ** * *** **** *****     * *   * ****** **  is a prefix of %s",a,b); 

 
 * * * *  *** *    ***       *    * * 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *   *     **** *
#include  *** *     * *   *

int main()
{
 *   **  *******  *  *   *** * *  a[100],b[100];
  *  *** ** *** *  * ****  **   * i,j,prefix = 1;
**   *   * ** ** ******* *   ** ** * *  * %s",a,b);
*   *** *** *  **      ** *   * len = strlen(a);
***** *  **      *    ** **  *   = 0 ; i < len ; i++)
*   * **      *  * **  *   *
**    *   *  ***       *    * ** * * *  *  ** ***  *  *  != b[i])
 ****** ****    *  * *  * ** * * *     * **  ** **  * * *
 ***** ***  * * **  ***   ** *  ****  * * ***  ***   ***  ** *****    *    *   *  **   **  ***  = 0;
**  **            *   * * * * *        **  ****  * * **    **  * * ** *  *   *     * *  * * ***  is not a prefix of %s",a,b);
 ***    * *    *    ** *  ***   *  *  ****  *** **** ***  *** ***  * * *  ** *   *    
 **        *** *  **  *  * *  **       *   * *  

****** ***   *** ** *   **** *
       *** * * ** * * *   *  *       == 1)
 *       *      * *  *   *     * *** * *   *  ***** **     *  * ***   is a prefix of %s",a,b);


* ** ** * *  *      * * * * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ***  ** *** *** 
#include **   *** ** *  *

int prefix(const char *pre, const char *str)
{

 ***  *  ***  * * * *** * ****     ****** * ** **  
*     *  * *  * * ** *** *    ***** **** * **       *  0;
** *  **       **      * *  *  *  *   * **  *  *  *** 
*  **  ***  * ****   *  **  ** ***** * *  ******** *     1;
 *   ***** ** **  **** *** *  * return 0;


}

int main()
{
  **   * * ***   **    ** *   pre[100],str[100];
*  ** *     **** *** *
* * * *    **  **  **** ** * * * *   * *** **  *  *** ***
 ***      **  *** ** *  *   ** *  **
 **         ****  * *   **   * ***** *  ***  ** * * **  ***   **  is a prefix of %s",pre,str);
*   *   * **  *   *      * 
 **  **  *   **   ** ***  *** * ** **  ****   **   *  **  **   * is not a prefix of %s",pre,str);
* * *   * **  ** **  ***   ***   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
       * * *  *   * * ** * *  *  c;
**    *  *   ****  *** *    * **  * **  ****
*** * *  * *    * ***** ****  * ****     *** * * ** **** * * 0;
* *** ***   * * ** **   
 **** **    ** * *****       
* ***    *** ** * *       *** ***** *****  *  * * *   * **   *** * * ** * *   *  *** * of a string
  *  *  ***  ****  *   ** * *  **** *******      ****  ** *     * **   ***  *** ****      * 
 **  ***** *        * ** * *** **  * *  ***   **** ** ***   *** ** * *  *    *****  ***** *   *    ** *   ** 0;
**  * **   *****  *   * *** * *      * *** * * ** ***
***  *      ******   *      *** *** *  ***  * * ***   ** * * * **  1;
    }
}

int main(){
  **   * *  * ***  ***     *  a[100],b[100];
  *** * **    *     ** ** * **    **********  %s",a,b);
   *    * * ***** ** **  ***      *
*  *  * *** **    *   ***  *  **   * **   **        ** *   **   *** is a prefix of %s",a,b);
 * *  * *   * *    * **   *     
  **** *      * ** ** ** *  ** ** ***** **   ** * ***   **** is not a prefix of %s",a,b);
 *  *  * ***  ** ***  **  * **    0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
**   *** *  *   *     ** ** p[100],s[100],a[100]={};
 **  *   **  * *** **   *    t;
*  * * *   *    * ** * ** **    *   *  * 
 * ***  * *  * * *  ** * * **    *    *   
 ***** *     *   *   ** * *  * * %s",p,s);
*  ** *   ***  * * **   **** *** *  * * *
 **   * *** ** *   * ** * * ***
 * **  ******* * ** * * ** **   ****  
* **   **   **     ******** *** ** ** *  ** *** 
 ** **** ***   **  ***      *    ********
  * * * *  * *********       ** * ** **   *   * * *  ***  *  *    is a prefix of %s",p,s);
 * * ***  *    *  *    *  
** *  * ** **   *  * ****     
**   * * * ** ****    * **** *  ****  **  ** ** * ***   * *** ** is not a prefix of %s",p,s);
****** * *     *   * *  *  *   
     * * * **  ***  *  ** *** *  0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.53
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 3k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 2.1k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 2.7k views
12,783 questions
183,443 answers
172,219 comments
4,824 users