11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
2k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 2k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

 * ***** *  * *      *****  * * i;
* * * * *  *    ***  *** * * * j;
    *** ** * * ****   ******  *  newNum1;
  * * *   *****    **  *   newNum2;
  **   *****   ****   *** **  gcd;
*  ****   ******   * ** *  * rem;
* * **** ****   *  ***  **    num1, num2;

* *** ****   ******  * *   *  *****  **  **  **  ** *** ** *  * 

 *   **  ** * * ** *** **  ** * *  
**  *  ***    * **  * * *   * **

   * * *   ** * ***     **  **      != 0)
  * ******     ** 
*** ** * ***    * ** * ***  *** * ***  **** *   *   *** = j%i;
 *** ***   * *  * * *     **   *   * *  ***  ** * ***  = i;
  **    * *  *      ** ****  ***     *      **   * *  = rem;
*** *** ** * * ** * 
*    ** * * *           **

****   ******  *** * ****** *** = num1/gcd;
*  * ********    *      *   = num2/gcd;

 * *   ****  **     ** ** ****  **   == 1)
    {
** *****   *   **  ** *   *    *   **  ** * **  * * *        *****  **  **     *  
    }

   *    **  *** ***    * **   *   *
    {
 *    ***** ***     *  * ********     *  ** *  * **** **   * * *  *  * * * * **
 *****  ***        ***   * *** 

 *** * ** *      ****   ***  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
 ** * ****** ******* *   * *  * *  *** * ** **  * *** *   ** *    *  * *

 **   ***   **  * *  ** ** ** ***  
*    ***** *** * *   *  *  *   **  * * *****     *** **  ** *    *  ** * ****

    else{
 *****  **   **  * ******   *  ****  ** ** *  
    {
 * **   *  ***  **    * * **  **  *******
** *     ***    **  ***** ***** ** *   *   *  *   ***   * *   ***** * *      && deno%i==0)
   * ** *   ***  ***  *  ****   *   * ** ** * *  **   **        *  ***  *   * ** 
  *  *    *  *   *****   *  * ** **** *   *****   * ***  **  *****   ****   * *  ** *   *  * ** **    *   *  
  *   ***  *   * ** ** * *     *     *** *     *   *  ** *  * **** *  * *   *     * * ** **** **   ** *
**** *   * * *** *    *****  *    **** *** *  *  ******* * ***   *   * **** ***    
    }

*       *** ** * * *  ****   *  
    {
  * *  **    * * *** * * ** *  ***  **** * ***
*** * *  ***       *  *   *   *  *  *   ** **  * * ** *     ** ****  **  * **  ***          && deno%i==0)
 ** **   ** **  * * *** *  ***    *  * ****   *  * *****   **   **  *** *    ** *
  ******* * ** *  **  * *   *** * * *   * ***      *    **  **   *    ** *  *   ** ****    *** **** 
*          ******  * * ******   ** * * *** * ******* *** *  ** * ** * ****  ** **    *     * ** *** ** 
*   *** ** ** **** *     * * *    * ***      **  *  * ** *     *   *** ** **  * *   * 
    }
*   * ** * ***** * **  **  * *     *    ** **** ***** **  **

    }




*   ** *       **      ** ***   0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  * *  * * ***
#include  ** * ** *     

int gcd(int n, int m)
{
* ** ***** ** *      ***** gcd, remainder;

* * * **  * *  ** * ** ****  *     (n != 0)
* * ** **  *    ***  *  **  **
    * *  * * ** * **  ** *   ***** **  *** *  ** * ******    = m % n;
*  * * * * **      *** * ***   * * * *   *  * * = n;
**  * *** * *  * *  ***** **  ** * * * * *  *  **   **   ** ****** = remainder;
    * *** *  *    *     *

***** **** ***  *  ****** *  = m;

****** * ** ****  **        gcd;
}

int main (int argc, const char * argv[]) {

**    * ***  *  **** ***   *  number1, number2;
***** *** **  * *   ***      *** newNumber1, newNumber2;

*   *  * *        * * * ***   **     ***    ** * *  **        *** * 

 ***  *  ** * *  *   *  * *** *   = number1 /  ******* number2);
   *** * * * * *   *   ** **  *   * = number2 / *** *   ** number2);

 * *   ** *  ** ****   *** ** * ** * *   *   *****    
 ***  *       **** ** *      *    *  **    *  ***** *******  *
*****  *******  *   ******   ***
* ***    ** * ******   ******     ** *  * * *    ***
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
       ** *  *        *
  ****   *    * * *

int  ** *  n, int m)
{
 * ***  *** **   int gcd,  **    

**  **  *   ***    * **  (n != 0)
 *  *   * ** * ** {
* * **** * **    *** * ****  * * * *    = m % n;
**  **    *     * *         m = n;
***  *   * *    * ***   **    *  n = ***** * 
** *** **  * * }

** * *  **    * gcd = m;

*** *       * *   *  gcd;
}

int main (int   *   ** *  char *   * * {

  *   **** **  ** * int  ***    
** *  *    **   int   *****   **  

 * * **  *** ** * * *   ** ** * *** *  * * **** ** *    *      **

   **   ** *  *  * ***  =   ***  / ** **    ***
****    **   ***   **  * = **** /   ** ***   ***** 

 **     ** *  if * *   * **   *** *
***        * **   * *   *  *** *   *  ***   ***    *  **
   ***  ***   else
*     *   **   *  *  *    *   *   **   *   *  ** *   
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
** ***     *    *  *   **   i;
  ***    *  *** * *  ** ***   j;
*** **      **  *  ** *  ***   *  newNum1;
****    *     * * *   ***  *  newNum2;
**  ** * *      * *** **  *     gcd;
     ** * *           ** *  rem;
 ** ***** **   * ***  **   **** num1, num2;
    
* ***** *  **    **  * *   *    **** ***   *   *** * **** *  * ****
* ****  **** * ***    *    ***
** ** * *    ****  * *  *** * **
  ***   *   **  ***   *******    *
*       * **  *  ***  *  
*  * *  *   * **   *  ***** *  * != 0)
 ** ** *   *  *     **  ****  *
*    * * *  ** * *        ***   *   ****  * ***** ** *   = j%i;
*  * ******* **    ** ** ** * * ** ** **  * **** *   = i;
**    * *  **  ***  *       **  * *         * **   = rem;
    *  * *   ***             ***
  * *  * **  *   ***  **** 
    
****  * **  * **  ** ** ** *  = num1/gcd;
 * ****    * ****  ******** * * *  **  = num2/gcd;
    
*       **   *   **** ***** *       == 1)
** * ** * * ** * ** *  **  **
* *        *** *  *  * *** ** **   **   * ********  ** **    *  *  *** ***** **** *
  ********   **** ****  * **
    
**   ***  **** ** **   *   *  
** *  *** *  ** *  * *  
  ** **   **** ** ** * * * *** ** ***  ** * ******* *  *** * * *        ** ** * *  * *
*  ***  ** *    * * * **   *  * 
    
 **  * ** * * ***  *    * *  0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
 ** *** *  * **** *    ** * **  i;
 * *** ***  *  *  ** ******  j;
*** *** ** * ** *   * *      * newNum1;
*     * *  * * *  **      ** newNum2;
*** *  *  *** ** *   **  *** gcd;
 *    *  *  * *    *** **     rem;
 *  **  * * *  * *  ****  **   num1, num2;
    
*  *  **  * * * *    ** **** **    * *** ** **** * * ******* *** *****  
      * * * **    **   * * 
** * * * *  * *** * ******   
  **  * **  ***   * **  * *** 
*** * *      *   **    **   *  
 * **  ****   * **  * * ******    *  != 0)
**  * *  *  ***** **  **** 
  ****  * * *** * ** ***  *** * ** **  ****   *  * *** *  ** = j%i;
* *   ** *  *      ** *       ****  ***  *  *  * **  * = i;
*  * * ****  **  *   *   * ** *   ****** *   *** **  **  ****** = rem;
   ** ** **    *   *  * ***** 
  ** ** *  * **** ** **      
    
**  *  *  **   *******    *  = num1/gcd;
   ** ** **** ** ** **  * *   = num2/gcd;
    
 **  *   ** *  ** ******  ** == 1)
*   **  *****   * ****   **
 ***    * ** * *** * **** * ******** **  *     **** *   *   *  ***  * *  *** **** 
 *  **    **** * *  ***  **
    
**  *   **     ** * *** ** * **  
*** *  * *    * * *  *  * *   
 **      **    *  *** ****    *  * ********** *   **  *  * ***   *  *  *    *    * *
*   *    **    ***    ** * *
    
     * * ** * * *    *** *    *** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
       **   **   **           * **   *  *  * ***** ** 
 ** *  * * *    *** ** **   *** **  ** * *  ** **  **    *    *  ** 
    {
 ** ****** *   **  **  **    *  ***  *  *  **  **   ***  ****  *  *  * **
* **  *    **  * * * **  * * * * *  * * ***  *  ***** *  * **** **
   ***** * * ** *****     * * ***  * **  
**  **** ****  *   *    * **  **** *  **** 
 *    **** *****  *    *    * *   *  * *****   *

* *  * ***   *  ***** *  *** *  
  *   *     *   * ******* **  *   * *  *      ** **    * *** *** *  *    **     * *  ** *******   
  * * * ***  * ***  *    * *  * *  * **  * * ***   *   * *   ** ***  *  * * *


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* *   * *  * ****   **** * ** a,b,GCD;
**   * * *  ** ** *  *    ** **   **  ****** ***  ***   **     **  
        **  ************ *  * **  * *
 ** *  * *    *  *** * *  * *   *
 *** *** ****    ******* **     * **  *  **  ***  * **** ** * *** * ****
 **    *  ** ** **  ** **  ***
     **** *  * *  **   *  ***  ** **  **** ****  ** * ** *  ** * **   * 
 *   **   * * ****  * ** ***** * 0;
}
* *  *    *  *     *    *   ** gcd(int a, int b){
*  ** **** **  ** ***   *  * * ** *  *     *     **  ****   (!b) return (a);
 *** *** ** ***  *    *   * ****      * * *  *  * ** * *   **** gcd(b, a % b);
***  **     * **    * **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  * **  ***  ****
#include   ** *   *  *  

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
    *** ** *    *   *    ***  gcd, remainder;
 ***** * *   ***  *  **   ** 
****  * **   *** **  * *   *    *  (n != 0)
**      ** *** **** ** * *
** *    * **   *   *  * **** *     *** *  ***   *   *** = m % n;
      *  *  **  *   * *  ****   *** *  ***   * **   = n;
**  * ***** * ** ****  ** * *  ** *** *   * *  *** = remainder;
*** * * *  ** ***      * * * 
**  *  *   **  ***    **  * *    
 * *  * **  * * ***** ** *** * = m;
**  ***** ** **  *  ** 
**         *** ** *   **  * gcd;
}
int main (int argc, const char * argv[]) {
 * **          *     *  * * number1, number2;
        **  ****  * ** *****  newNumber1, newNumber2;
   *     *  ****** **     *  **
** ***** * **  * *  ** * **
 *** **** * *   * *  * **   * * **  *   ******** ** **  ****** * * **   *
 **     **   **       * *****
  * * **  * *    * ** *** * ***  *  *** *  = number1 / gcd(number1, number2);
*  *  ** **  **** * *   *  **   = number2 / ** * *  number2);
***     ***   * **** ** ***  *
 ****  ***** *     ******** *
    *   **  *  * **** **    * ***  (   **        
  **  * *****   *  ****     *  * **     *** *   * * *  *    **    ** ** newNumber1);
*    * *  ** **   * * **   ***
 *  * * *  ****   ****
 *  * * **    ** *****      ***    **  *** **  *  **   newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
     * ** *****   *******   * a,b,c,d,e,f;
** *** *   *  *** ***  *     * **   * * * **  **    *  *  
 **  * *  ** *** *  ***      *    
 *  ***** **  * *** ****** * **  * **
      *  **  ** * *****   *  *  **    *
    {
* **    * ****  *       ***      *   *  ******* ***
  ***    ***   **    **  **  *   *  ** *** ***** *****   **
 * ** *** *   *  *     **      * *****  **  **  * *  *
    }
  **    ******* *   * *  *  *** *
    {
**  *  *  * * * **** ***   * *** ** *** *  **** ****   *
 *****  **     *  *  **  ** *   *     *  *** *  *   * **** **  ***
*  **  * **  * **     ** **   * *  ** *  * ** *** ** *****
****** *   **  **  ** **   **  ****** *  *****  ** * *  * *      *  **    *  *** *
    }
  *   *  **  ****  * **   ****  *
    {
     *  * * ** ** ****   ****      * **  **** * **  *  ***   
*     ***  * * *      **  *** ***** *  ** ***  ** **  *   ***   **  *  * 
    * **** *  *  ***    *  * *    ******   *** **   ** * 
 * *  *   **** *** ** *  ******    *********** **   * * **** *  *  * *** ****   **    *** 
    }
     ***  *  * ****   ** *  *  *   *  0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.160
©2016-2024

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 2.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 2.6k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 1.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users