11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
1.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 1.9k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

    * ** * **  * **  * **        ** i;
  *    ****  *   *  ****   *    j;
 ** **  * *       ** *   *  * * newNum1;
* **  * **       * * ** **  newNum2;
 * **     *****  * **   * * gcd;
* * ******** **  *** ***** rem;
*** ** **    *  ** *     num1, num2;

 **    ** *** *** *** **    ***   *   ***   * *   *      * * *** ** * ** *  * 

** ** *** ***   * * ******     
***  ** *  *  * **        *  * *

* * ** *  *  ** ** * *** ** **   != 0)
 **** ** * * ** * ** * **
*  *    *  ** **     * * **** ** *   *  * *** ** ** * ** * = j%i;
 *** **  * * *** * *  **** *  * ** *   * ***   * ***  = i;
  * *    *  **   **  *   * *   **  *        *****  * *   * * = rem;
***** *  * *  **  * * *  *  
*** *  * *  **  *****  ***  **   ** *

  * *   *  ** *  ***   * *   ** = num1/gcd;
**  **      *  * ****** * ****    *** = num2/gcd;

 ** *** * * *** * ***  ** **** * == 1)
    {
 **    * ***       **    **  ** *  *    *    ** ***     **  *** * * * ***** **  * *
    }

** ****  *** ** ** *  *** ** **
    {
  *****    *  * **** *    * **   * ***** ******* **  ********** ** * **** *   *   **   * *
  **  ***  ********** 

**    ****   * **   **   ***    0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
  *  *** **  *  *    *** **  *  *   ***  ** *  * *  *    *****    * ** 

  **  **   ** *     *    * ** * *     
 *** * *** ** * * * * ** * ** **      *****  ** **     ***   **  **** ** * **** *

    else{
** *** **      **     ***    ***** * *  *  **  *
    {
*    *   * *    ** ***    ****** * *   *   ** ******
 ** ***** *     ** * *   **  ***       **   ***  **     *  * **  * * ** ** ** *   * && deno%i==0)
  **    *   *  * * ******* *** ** **  ** ****  *** ** ** * *  **  *   **  *
 **  **  ***  * *   * *    **** **** **        *****  **  *  * ***  *  ** *  **   *** * *    *  *            **   
***   ** *      * **     *    * ***   *     ***  **** ** **** ***  *  ***  *    *    *  *    ******  * ** 
****   **   * *  ***  * * *   * **  *****   *  * * ** **    *   *    **      **  
    }

 ** *  *   *   **  *   **  *     ***   *****   
    {
**** * * * **    * * *** **   ****  * ** *  
 ***  ** * *  ***     *  * * *** *    *  * *  *     * ******    * * *  ** **  *  * * * && deno%i==0)
*  *  *     * * *  * ***         ** *         *  **    **  **** ***  *  * ** **
  ***     * * **    *** * *  ** **  *    ** *    * *** *  *   *    ** *  *     *  * *** *** **   
* * * *   ** *** ** ***  **     **   *** ** *  *** **** *** * ***   *  * *    ** **** *  *     *  ****  **
***  * * **    * *** *** * ****  *    ** *******   *  * *  **     * * *   ***  **    * *
    }
**** * ** *  ** *** *  **   * **    **    ***  **

    }




  * * *  * ******** ***  * *   0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **   *  **** **** **
#include     ** ** * * **

int gcd(int n, int m)
{
  ** * *** * ***  **  *** *** gcd, remainder;

 * * *   *** * **  *   **  *   (n != 0)
   ****   *   *  ***  *
***** **  *   *  * **  * * **  * **  * ** *  * *   **  = m % n;
    *** *** ** ******  ****** *  *      ***   * ** = n;
 ***  **** * *  *        ***   * **  **  * *        = remainder;
  * ***  *   * ** *  * **** * 

*  * **  **  * *   * **        = m;

* **  * *    ***     * *  **    gcd;
}

int main (int argc, const char * argv[]) {

***** * *** ** *    **   number1, number2;
      **  ***  *** *    *** ***  newNumber1, newNumber2;

****    **  * *   **  ** * *  **     * ** * * ** *** ***       * * *** *  *

*  *     *   * ***  * *  * * *** *  = number1 / **  ***  number2);
**  * **   ** * ** * *   * * * ***  = number2 / **** ****  number2);

  ** *  *    **   * *   * *  *  **    **  *** * * * 
    ***  *  ** **  ** *    ** *** ****  *** ***** ***** * **  * 
**  * ***  * * *    *  *  ***  *
*  * * *   *** * *    *   * ***    ****    ** * ****  
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * **** *  ***   **  *
   *** * ***     *    

int ***  n, int m)
{
** *   ******  int gcd,    *  **

*  ** *     *  * ***   *  (n != 0)
 **  *** *   * * {
 *** *** ***  ** * * ***   *  **    *   = m % n;
**    *    *  ** *** * *** * m = n;
* *  *  *  ******     *    n = * ****
 **  ***   ***  **  }

*** **  * * ** **   gcd = m;

 **      *  *   *  gcd;
}

int main (int       char *    ** {

*   *  *  **  ** * int  **   *** 
****  *     *   int      **   ** *  

*     ** ***  **   * ***   *    **  * ** **     ****  *   ** 

** * ** ** ** * * *   * =   /   **** **  *
* **   * **   *  **   = * ** /     **** *  *

**** *   * ** **  if *  * **  ****  ** **  
   *  * *  ***   *   ****  * **     * *   *  * *  ***  **
*   *  **  *  * else
 **  *  ***   ****** ** ****    ****   ***     *   **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
**** ***** * *  **  ** *  *  * i;
****   **          **          j;
 *   *** ***********  *  ** newNum1;
     ** *****    * * ****  * ***** newNum2;
* *   * ****** *  ** **  **** gcd;
** *   *  ***     * *        ** * rem;
   * *** ****     ** *   *  num1, num2;
    
 **  ***  **  *       *     * ** * * * * ***   ** * ****          * * *
 *    ***** ** * ** ***   * **
 **    **  *   *******  ***
   * **** ***  *  * **  ***
* **       **  *   * * *** ****
 *    ** *    ****   *   *** * != 0)
 **  *   ** * *  * *  * 
******  **   **** ***  *  **   **   *** * ** * **  **      ** = j%i;
* ** *** *   * ** *  ** **** ***  * * *  * **  **    ** = i;
**  ** * **  * ** *****  ** *  * **    **   **  ***   * *  = rem;
* * ***   **** **** * *  * **  
   *** * *   *** ***   *  **   ** * 
    
   *  **** * *  *****  * **   * = num1/gcd;
   ***  * ** * * ** * *  ******  * = num2/gcd;
    
*   * *   * ** *** *****  * **         == 1)
* *    ***   * *  *   * ***
 **   *   * * **  * *  * **  *   *   * * **** ** * * *** *      **      ** **  *  ***     *
*  **  *****   ***  
    
  ** * **  ***  **** * *  
  ** *** ****   * ** *** *      
      **  ** * * *   ****    * * * *  * ** * *     **    **    ** ** *  *    *  * *****    *  ***
* *   *    * **  *  ***    
    
 * *   ***** ***  ** *****  ****  0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
***    ***  ** *   * **    *  i;
    * * ***  ***      * j;
* *   *  * * ***   * *   ** * newNum1;
** ******  *  * *  *  * *****  newNum2;
  ** *   * ** *  *  * *   *   * * gcd;
*  **   * *  ***   *  *  ** *  rem;
**   *** * *** *    ***   ***  *** num1, num2;
    
    ** ** *  * * ****  ***  *  *** *  **  ***  ****       *  ** *  **
 *  *** ** ***  ***** *      *
* * *  *  * ***  * *    **  *  * 
    **** * ***  **   * *  *   ***
  * *** ****   * ******    **
*  *** * ** * *  * *  *    *** ****  != 0)
* *  *     * * * ****   * * *
 **   *  **** ***  **   * ***** ** *    *  ** * * * * *   *  = j%i;
** *** **   ****      * ***  ** * ** ** ** ***  *   *** = i;
*   ** *    *** **** *** *   ** ****** **   ** ** ** * = rem;
 *   **  * ** * *** *  **   * 
       * ** *  **  ***** *  ** 
    
* * **  **** ******   *** ** = num1/gcd;
** *** ** *    ** **   *  ***   *   = num2/gcd;
    
***     *** ** * **** * *  ***  *   == 1)
   *  ***** *  ****** *  * 
 ** *       **    * *** ** *    ** **   * ****** * ****    *** * * *  *  ** *  **
  ** * * * **    ******  *
    
** *   ****  *****   ** ** *
*    **  ** * **       *** * ** **
    ** * *  **  ** *    *** ***   *   *** * *  *   **  **  *   *   * **  *  *  *** * ***   * **  
  **   ** ** * *    *
    
  **    *  * **** **** ** ***   *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
*  *** * * *          ** *  * * *  ****  * * * * *
 * * *    ***    ****  * * *       ** ****  * *  *      * *  *  *  
    {
  ** ** *   * *   **  **** ** * * * *   *   * ** *   ***  * ** ** ** * 
 **   ** ***** * **** ***** *        **  * *   *   *   *** *** 
 *   *******   ** ***   **    ** **  *    * * **
* * ****** *   * *   ** ***** *  * ****    *
   * *  *     * *  **  ** *   *  *   ** ** * 

 *** *** *****   *** *  ***     * **
** ****  ** ** * *** * **  ** *** * *     ** *  * * ***  ***         * ****  ** **     *****
 ********  **  **  *****  *** *** *   ** ***   ** * *  * * ***** ** **   * * 


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
***   ** ****  *  *  **** ** a,b,GCD;
 * ***  *   **  *** *  * * * *   *   *** ***   *   *  ****
* * * ****    * *  * **   ****    * ****
* **** *    *  ***   *  * *  **  * 
***    *** *      *    ** ** *  * ***  *  * *** **   *    ** * ** ***  ****  
* **   ******   * * ****   *
*    * **   ** *   *  *   * ** * *   **    * * ****   *** ** ** *  ** *
  ** *  **  * * * ** **  *  * ** 0;
}
****  * ****  ** *******  *  * * gcd(int a, int b){
 * **   ***** **    * * *****    *    **  ** **    *  * (!b) return (a);
*   * * * * *** ***      *   *** **  ****   *  ** ***** * * gcd(b, a % b);
*  *   * ** **    ***    ** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * **    *   *
#include **   *  * *** * **

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
* **     * ** *  ****** ***** * gcd, remainder;
  *****   *  **   *  *** *  ** 
 **** *****  ** * ***    (n != 0)
 *  ** **  *    ***     
   ****   ** ** **   * *** *  **   *    *** * *  *  * ***   * * = m % n;
****** **   *** ******** * **** ** *****   **    = n;
*** **    ** *  * ****** **    **  **    **    *      = remainder;
***    * * *   *     *  ** **
  * *  ** *** *  ** ***  ** **
* ******* ** **   ***** = m;
*** ****  * ** ***  **  *  **    
   *    **     *        *****   ** gcd;
}
int main (int argc, const char * argv[]) {
***  ***   * *** * *   ** * * number1, number2;
   *  **   *  **   ** ***  * newNumber1, newNumber2;
  * *       **  *  *  * ******
*  *     * *           *
* *  *    **  * ** ** *  *   * *****   * * * *  ***  *****   ****  * *  *
** * * * *   *  ** ** ***
  **********  *******  *** ** = number1 / gcd(number1, number2);
*   * *  *     *     ** = number2 /  *** * * number2);
  ***  ***   ** *    ** 
** * * **     *** *  ***  **** 
 * ***** ****   **  *  *  ***  ( *  *   * * 
 *  **    *    *     *   *** *  *   *    ** *  *****  *** * ******  newNumber1);
 ** ***  *** * ** *   ********* * **
***    * ***** **    **** **
***    *   ** * ****   *  *    *   **    *    newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * *     ****     ** ***  *    a,b,c,d,e,f;
 *  ** **  * ** **      *  ***  **   *  * ***    ****   ** * *
* ****** * ** *** **** 
****  * *** *      **   *
 *   *   *  * ***** **  * ** *   ***   
    {
* **** **     *   ** ** *   *               **   ****
*  * * * * *   **** *  **  * **     * *  **   *   **  *  
**  * * **  * *  ******    ** *  * ****** *****   * **    ***
    }
**   * *  * **  *    * ****   *** *  *  
    {
**     *     **      * ** ****  **    *  **  ** *** **  *
  ***  * * **  ** ** *** ****  ***  *    *  *    *     **  * *** **   ** *   * * 
* * **  ** *  * ** **** * ****  *    * * *  * * * ***
 * ** * ** * * *        **  * * ***** * **    * *** *** **   **** **     * * *  * 
    }
  **  * ** *** *****    ** 
    {
 ** ******     *         ****  *  *  * * **  **** ** **  
 **  *  *      ***   * ***  *    * * **   **  * * * **  **    ** ** * **  *
 *   *      ***  ******      *  * *  *    *  **  ** *
**   **   * * * *        **   *  **   *** **** **** ****  * *  ** **  ***  **  ** 
    }
**  **  *  * **   *     *  * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.147
©2016-2024

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 2.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 1.9k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 2.5k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 1.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users