11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
1.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 1.9k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

 ** ****   *   *    * **    * ** i;
   ** ** * *    *   * ** *  * j;
  *  ** *   **  ** * *  *    newNum1;
  **** **    ** **  *      ** * * newNum2;
*  * * **  **** * * *  ***  * *     gcd;
***** * *  * *** *     * *  rem;
 ** * **  *   *** ***       num1, num2;

 *    ***  *  ****** * *    * *  ** ** ***  ** *     *   *  

 *  ***    ***   ***     * * ***
*    *  *** *  *  ** * *   *

**     *   ****** *   **  **** != 0)
***  * *  * **    ****  **** * *
**  * * *** *  ***  * * ** * **   ******* **  *  ** = j%i;
    *******  *   * *    ** *  ***   *  *  * * *** ** = i;
* ** ** *** *    **  ***   *** **    * ***** ****** = rem;
**  * * **   * ** *  *   *
   * * ********* *  *  *    ***   **

 *  *   *  **   *  ***    = num1/gcd;
* *     ** ** ****  ** * **   = num2/gcd;

 *  * * * ** *    **   *** * ** ** == 1)
    {
 **  * * * * **  **   *** **     *     * **      *  *  *       ** * *** *
    }

***** **  * ** ** **  ***  * 
    {
 ** *       ** * * ****  *** *   * * **  ***  ***  *   ******** ** * *  *   * *****    *
*  * ****  *  * * *  ** ** 

 * * * ***  ***    *****  * **  * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
  **** *** *   *     * ** ****  *  ***  * *** **** * ** *** ** **  *

***          ***  *** **   **** ***   *
     **    ******  *******      * *  *  * *   ***   *  **   ***  **** ***      * *    

    else{
*  *  * *** * * * **  *  * * * *   *    
    {
*  *      **** **   ****  ** * *   ***** * **
*  * ** * *** *   *   **   * * ***** *   **    *   *  *  *    ** *  ** ** ** **  * *  *  * && deno%i==0)
** *   ***    *****       *   *  *** * **    ** *   * *********        **  
 **   *** ****** * *    ***  *****   ** *  ** *   *  *** ** **     **** **     **   * ** *  *  * **  **   *
   ** **   **      **  **  * * * ** *   ***   ** **   * * *** * *  * *** * ** *  * ** ** * **   *****
    *  ** ** ** *  * *  * ***  ** *  **  *** *  ***  *  *  *   **    **  ***  ***** * ***
    }

* *** ** **** ** * ****    ** *  **
    {
 ***  *******     *  ** *  *    ** 
****** *   *   * *    **     * *     ** **   *  *****  ****   **** *  * ** *     *  * && deno%i==0)
* **  **** *  ***   *   **   **   *     **   * ** **  *  **** * **** ***** ***    **
  *  **  *  **  * **  *          *    **      * * ***  *  *********** ***   * ** **   *    *   
**      ***     * ** *    *   * ** **  ***  * *  ** *  ** ***      **  *     **** * ****  **      *
 ******    **** **   ** *****   ***  **** * *     * *** *** **  **** *** ** ** *  *  **
    }
  ****  ** *  *      * * *** ** *   *  **   * **  *  *** *** 

    }




      *  * **  ** **  * *** * * * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * ****    ****
#include  * *** * *  **  

int gcd(int n, int m)
{
*   * *****    *  * *****   *   * gcd, remainder;

* * *  ***   ***    ** * ***  (n != 0)
 ***   ***    ** * * **  *
 **   *** * ***** **   ****    **   **  * *** *****   = m % n;
*   ** *****  * * *     * *      **  * **** * *  * *  ** = n;
 **  * *  *  ** ** ** *    **    *****        **  **   = remainder;
*** *   *    **  *  ** **    *

* **  * ** * *   * ***** *  *   = m;

* * **  ** *  * * ***  *  **  gcd;
}

int main (int argc, const char * argv[]) {

** **   ** **    **   **    * * * number1, number2;
 * ** *** *       * ****   * * newNumber1, newNumber2;

** * ** **  ** * * * *   * **   *   *    * * *   * * **   ***    * *   * 

 *  ***  * * * *  * **** * **     = number1 /   *    *    number2);
*  * **  *  **   ** *** *  ****   * * = number2 / ***  **** number2);

*** *     *   * *  * *     ****    ** * **  ***** *** **
* **   ****  * *  ******** **** * *  ** *******     * *****    *
*    * * * *  *****  ***** ***
** * **      * * ** *****  *****    * *** * **     **  *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  *** *  *  *** **    * 
 ***    * ** *  ***  * *

int * ***  n, int m)
{
**  * *  **    *  int gcd,        

   **    *  **    *  (n != 0)
*   **   *  **  {
   **     * *     *  *  *  *  *    = m % n;
* *    *  * ** *  ***  *   *  m = n;
* **    *  *   *  *     *  * * *** n = *** * 
**  *  *  ***  }

    * ** **     gcd = m;

* **     *   **  ** gcd;
}

int main (int **    *** char *  *   {

** *   ** * ***  int ** *      * 
 * *   * ** int  **      ********

* ****  **    * ***     **  *  *        *  * *  *   * * *  ***  * * *    * *

   **  *** ***  * * *  =  **  /  * *   * *      
*   * * *  *  * ** ** =  *  / *  *** * *    *****

**  * **** * if * *  ***   *** ** *  * *
  **  **  **  *  * *  *        **   ***  *    ** **
  * **   **** else
 ***  * **  * ***   **    * * * ****  **  ***  ** *   **  
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
*   *  ***  * *  ** *  * *  *   i;
  *  * *    * * *** *    *   *  j;
 **  *  * *  *   *  * ** ** newNum1;
 *****   ***** ****   ** * * *** newNum2;
   **  ***       *  ***   **   gcd;
 *  *  *   **      *    ****  rem;
*   **   * *       ** ***  ** num1, num2;
    
 **  ****  **   ****   **  *** *        *  *    * ** **  ** *    * * ** 
**  *      *    **  * 
   *** *  *      * *** ** **  *** 
***** *****  ** * ***   *  * * 
**  * *    *  * ****   * **  
*   **  **    *   **  *    * ** * != 0)
   *  *  **      *  
*   **  * *****  *   ** *     *  **  *  *  ****** *    = j%i;
**  *   * *    *    * ** ** *** **    ****** ** **** *  = i;
**    *   ******  **  **    * *  ** **** **  **   ****     *  = rem;
 ***  * *        *** ***  
   * * ***  * **    *  ****  *****
    
 *  *** ****  * *   * * ***    = num1/gcd;
  **** * *  ** * *   *  **  *    = num2/gcd;
    
**** * *   **  *    *** ** ** == 1)
    * **     ****     *  ****** 
*  * **** *   *** **** **   ** *  * **   ***    *  *    **  ** **    *  *** ****  
* * ***   *  ** *****   ***
    
 *   *****    ** * * * *  *** 
* * *** *    ****   **     *
 ** **   * ***   ***** * **  * *      **  ***     *    *  ** **  * ** ***  *  ** *    ***   *
**** **** **  *  *  *** 
    
*     *  **   * *   ** ****   * 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
  ** *  ** ** ** * *    i;
 ** ** *  * *   *      *  *** j;
** ***** **** **  *  ** * * *  newNum1;
** * *   * **** **   *   ** newNum2;
******* ** ***  **   *** **  *  * gcd;
**  ****** *    *  * *** ** rem;
  ** * * * * * ** ** *   **     *   num1, num2;
    
   **    * *** * ** ****   *    *    *      ***  *  *      *
 *  *     *  ***  ****     
*   * ***   ***   * ** ** *  **  *** *
***   *  ***  **** *   *    * *****
 *  *******  ******* *  *  
*  *****  **** *  * *****   *  != 0)
*******   **  **     * **
****  ****  *   * ***    *        **  ** * *    * *** *    *   = j%i;
*  **** * ***   *     * *   *   * *  *****  ** * **** ** = i;
* ** * ***      **   *  * * * * *  *     * * ***** *   = rem;
**     *  ** *     **   **   
    ***  * **       *** * **   ** **
    
 *    *   *** *** * * ***  **   = num1/gcd;
** * * * *    ***     * **** *** *  = num2/gcd;
    
  ** **  ***   * * * *    ****** == 1)
* * *   ***  ****   * **   ** *
* * *  **   * *  *   * * * *  *   * *  **  *  ***    **   *** * *  * *   
* *** **     * ** ** *    
    
 ** ****    ** ***     *    *    *
 *  * *   *   ** *     ** 
***** ****  ** ****** **   * ** ***   * * *  **** *     ***   *  *      *   **  **  *   *** ***
*******     *  * **  *   * *
    
* ************  **  *   **  * * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
  **  ****  *****          *  ****    **   * ** *  ***   * *  **  *
* * *  ***   ** * ** *** *** **  ****    **  *   **   * ***  
    {
 * ***  ***** **** *  ** *  **  *  ****  ** * **   * *  *         *  **** *  
*** * * *      * *  ****   ***  ** *****      *    ** * *** *
  **    *  ** *  * **   *  *   *  **   * * **
**   **     * **   * *    * * *** ****** *
     ***   *** * ***** ***    * * **  **    *  * * 

*  **  ** *****  *  *****    * * * *
 ** * *  *    ***   *  * * **  ** *   *  ** ** *   * * *  *     * ** * **** * * *****  *   ***  *    *   
* * * ** ** ******* ** *     *  *  *   * **   ** ********* *   ******** * * 


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* * ***** **** **  *    * *** ** a,b,GCD;
  ** **   ** **** ***  *  * * * *   *** ** ** *   * *   *** ** **
 ***  ***  * *  **   ** * * ** ** ** ** * *
 ** **  *  *** * *** * * *** * 
*    ***     ** * ** *  * ******    * ** ******  *  **** *  ***  ****
 * * ** * **** *****  **  * *  
** * ** ** *  *** **  ** *     **** **    **** ** **  ***** ****    *
*      *  **   *  * * *   **  * * * 0;
}
****      * * ** **  * *    * gcd(int a, int b){
          ** * * **  * **  *  **     *  * *** *  *** *** (!b) return (a);
  ** *  *   *      *  *** *** ****    **  *  * *** * * *** * gcd(b, a % b);
 * **   ** *** *** *** ** **** *
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ****   *** * *  ** *
#include *    *  *** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
** * *  * *******  ****   **** *  gcd, remainder;
*** ***** ****   **** ** *
** *    ** * ** ****  * *** (n != 0)
    *   *  *   *    * * * **
  * * *  ****  ** **   ****        ***** * * **  **  **    = m % n;
 * ** ** **** * *   * ****    **    *   **  ***   **** *** **** = n;
* *** ** ***  *  * *     ****   ***  *** *  * * ** ** = remainder;
  *   *    *** * * *    
****  ** *    * *  **** * ** **
*   *****      * *  * ***** ** = m;
* **   * * * **   ***   **
** ********* *** **   * * ** ** gcd;
}
int main (int argc, const char * argv[]) {
* ******   **   **   ***** number1, number2;
* * *  * * *     *  * *   * ** * * newNumber1, newNumber2;
 ***** * ** * * *      * ** 
  **** **** ** *  **   * ** **
 ** *     ** ** *****  *      *  * *     *  * *     **  ******  **   * **  **
******    ** *   **** ** *  ***   
  **** *  *    **** * ** * **** = number1 / gcd(number1, number2);
***  *    *       ***  *** ***   * = number2 / *  * number2);
 *  *  *  * *  **   *  ***** *
   * *** **  * *    * **   
****    * *  ** * **     * (   *****
****  ****   *  ** ***     * **  *       * ***  ***** * ***     ** * * * *****  newNumber1);
  * * *******     * *         *  
***  ***     **    ***   
*  **** ** * *   *  ***   *       *    * * * **  ***  newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 **        *** *  ** *  **  a,b,c,d,e,f;
  ******   ****   *** ****   ** * * * *   * *** *   *  *    *  **  * 
  *     **  **  ****   *****
  *** **** ****** * ***  
  *   *          *  **   ****** *****
    {
* **  * *    * **     *   *  ** * *   * ** *  ** * **
*  ** * ** * ** *****  *   ** **** *   **    ** * *    
* *    *** * * *       **  * *     *** *  * *** ** **   *
    }
* ******* **   * **** *  *  *  **   ** 
    {
**  *  *    **   *    **  **** **      **  * *  * *  *****  
* **      **    ** ** *****    ** ** ** * *     * ** ** **** *** *** *** **    *   
**  * * *  * *  *****  ** ***** * **   * ** ***  * *****
  *  * ** *  ***     * *     **** * *  ** *  *  ***** * * * *    *   * **  **** **
    }
  **     ** ** *** * **** * *    
    {
**      **** *  *    * ******** ** *  **   *  * *  *        
 **   *     **** **    * * * *  * *  * *  * ** ***** *** *   *** *      *  * *
   * ***     *   **   *  *    ***    ****  *  * *        ***
 *** *   *** **  *  ***** **  * ** ** **   *****     *     *    ****  *  ****  * * * *
    }
*  * *    ** **  ** * *          0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.71
©2016-2024

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 2.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 1.9k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 2.4k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 1.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users