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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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41
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * ** * * * ** * * x=0,i=0;
* * * * * ** ** ** * ** * **
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* * * * * *** * * *** * 0;
* * * * * * * * * * **
}
answered
Oct 27, 2016
by
410523005
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
* * ** * *** * ** * * * * **** * ** * * * *
if(i <= 520000)
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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Hidden content!#include * *** * * *
#include * * ** * *
int main()
{
* * **** * * ** * * * num;
* * * * * * ** * ** ** * * * &num);
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}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
*** ** * *** * * * * * ** *** * i=0,
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* * * * ** * * ** * ** * * 0;
}
answered
Oct 27, 2016
by
410423016
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-170
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Hidden content!#include ** * * ** ** *
** *** * * * ** *
int main(int argc, char *argv[])
{
* * * *** * * * * ** ** * * *** i,j,n;
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* ** * * * * ** * * *** *** * * * ** **** * ** **** ** * ** * = n*0.05;
* * *** *** * *** * ** * * if(n ** * 1170000)
* *** * * ** *** * * ** ** * * **** ** ** ** * *** * * * *** * ** ** = (n - 520000) *0.12 + 26000;
** * *** * ** * ** * * * if(n ** 2350000)
* * * * * * * * * ** * *** * * * * ** ** *** = (n - 1170000) *0.2 + 26000 + 78000;
*** * * * * ** * * * * if(n * * 4400000)
* * * * * * * * ** * * * * ** * * * * = (n - ** * *0.3 + 26000 + 78000 + 236000;
*** * *** * *** * * * * if(n * * * ** * **
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** ** * * * *** * * * 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
(
-216
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Hidden content!** * * ** * * *
int main()
{
** * * *** * * A,B,C,D,E,F;
** ** * ** * ** *** * * ** ** * * * * * *
* ** * ** * (A<=520000)
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** * * ** * ** * * ** ** ***
}
answered
Oct 27, 2016
by
chen
(
-102
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Hidden content!#include * *** ** *
#include *** * *
int main()
{
* * ** ***** * * * * * * num;
* *** * * * * * ** * * * ** ** &num);
* * * * * ** * *
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* * * * * * ** *** * * * = *** ** * * * * * 0.45;
* ********* * **
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* * * **** * *
** **** * ** ** * * * **** ** ** ** num);
* * ***** * ** * * * ** *
** **** * * **** * * * 0;
}
answered
Oct 27, 2016
by
610537002
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-110
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Hidden content! * * * * * * *
int main()
{
* * * ** A,B,C,D,E,F;
* * * * * * * *** * * * * * *
if (A<=520000)
* * * * * * * *
*** * ** * * * * *** if (A<=1170000)
*** * * * * ** ** *** * * * * * * **
**** * * * if (A<=2350000)
* **** * ** **** *** * * * * * * * *
*** * ** * if (A<=4400000)
* * ** * ** * * * * * *** * * * * ** * * ** * * **
* * * ** * * * * if (A<=10000000)
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*** * ** * * *
* * * ** * * * * * ** ** * * ** *** * ** * ** ** ** *** * ** * **
* * *** ** * * **** * * ** ***
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
* ** * * * * * *
int main()
{
* ** ** * * * ** i;
* * ** ** * * a;
* ** * * * * * * * * * * * ** **
** * * * * ** ** * **** *
* * * *** * * *
* * ** * ** * **** **** *
* * * * ** * * * * * * * * ** **** * * ** * * ** ***
* * * *
* * * * * * * **** if(i<=1170000)
{
* * * * * * * * * ** ** ** ** * ** ** * *
* * * * * * ** *** * * * * ** *** * * * ***
* * * ** * ** * * * **
* * * ** * * * if(i<=2350000)
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* ** * * * ** * *** * * *
** * * ** * ** * * **** ** * * ** ** * * * **
** * * ** * *
* * ***** * * * * if(i<=4400000)
{
* ** ** * ** * * * *** * * *** * ** * 470000;
** * *** ** * ** * * * ** ** * * * * **
}
* * * ** * * * * ** ** * if(i<=10000000)
* ** * * *
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* * ** * * *
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{
**** ** * * * *** ** * * * *** * ***** * * ** *** *
* * * * ******** * * * * ** ** ** * * ** * *
}
* * * ** ** * ** * * * * 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
* ** *** ** ** * *** * * * * * * * ** * * * * * *
** * * * ***** * * * * * * * *
* * ** * * * * * *** ** *
*** * * ** * ** * ** ** if(in<1170000)
* * * * * * ** * * * * * * ** * * *** **
** * * * * * * * ** * if(in<2350000)
* * ** ** * ** ** ** *** ** * * *** * * ** * * ** *** *
* *** * * **** * * if(in<4400000)
** * * * * *** * * * ** * ** * * * *** * * * ** * *** * *
* ** * * * * * * * ** * if(in<10000000)
* * ** * * * * * * * * * ** ** ** * * * * * ** * * * * ** * *
* ****** ** ** ** ****
* ** ** * * *** * * ** * * * * ** * * * * * ** * **** * ** * * ** * * * ** ** * * *
* * * ** * * * * * * *
* ** * * * * * ** * * * * ** * * *
** * * * * ** * ** * ** * * 0;
}
answered
Oct 27, 2016
by
steven0221
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answers
AD 20161027 期中考 10
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
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ID: 15448 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
|
187
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33
answers
AD 20161027 期中考 9
[Exercise]
Coding (C)
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asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
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(
18k
points)
ID: 15445 -
Available when:
2016-10-27 18:30:00
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Due to:
2016-10-27 21:00:00
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494
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11
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AD 20161027 期中考 8
[Exercise]
Coding (C)
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in
2016-1 程式設計(一)AD
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(
18k
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ID: 15441 -
Available when:
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73
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AD 20161027 期中考 7
[Exercise]
Coding (C)
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asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
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(
18k
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ID: 15439 -
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2016-10-27 21:00:00
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AD 20161027 期中考 5
[Exercise]
Coding (C)
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Oct 27, 2016
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2016-1 程式設計(一)AD
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(
18k
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ID: 15421 -
Available when:
2016-10-27 18:30:00
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2016-10-27 21:00:00
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