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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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41
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* *** * ** ** * * * * * * x=0,i=0;
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}
answered
Oct 27, 2016
by
410523005
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
* *** * **** ******** * * * * ** * *** * * * * * * ** ***
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
(
-202
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Hidden content!#include * * * ** * *
#include * * ** * **
int main()
{
* ** ** ** * *** *** ** num;
* **** * ** ** * ** ** * * * * * * &num);
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}
answered
Oct 27, 2016
by
610537002
(
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
* * * * * * * * * * * ** ** i=0,
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* * ** *** * * * * * ** * 0;
}
answered
Oct 27, 2016
by
410423016
(
-170
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Hidden content!#include * * * * * *
** * * * * ** * **
int main(int argc, char *argv[])
{
** * * * * * * * * * i,j,n;
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* ** * ** * * ** *** * ** * * * * ** ** * * * * * * * ** = n*0.05;
**** * * * * * * * *** * if(n ** 1170000)
* ** * * **** * * * * * * ** ** * * ** * ** * * = (n - 520000) *0.12 + 26000;
** * **** * * * * * ** * if(n * 2350000)
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* * * * * *** ** * * * ** 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
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-216
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Hidden content!*** ** * * * ** * *
int main()
{
* * ** * * * A,B,C,D,E,F;
** * ** * * * * * * ** * ***
* ** * * * ** (A<=520000)
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}
answered
Oct 27, 2016
by
chen
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-102
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Hidden content!#include * ** ** * * *
#include * * * *
int main()
{
* * **** * * num;
* ** * *** * * *** ** ** ***** * * * &num);
** * * ** * * * * *
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* ** ** ** *
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**** * * ** *** * ** * * * * * *
* * * * * ** ** * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content! * * * *** *
int main()
{
* * ** * **** * A,B,C,D,E,F;
* * ** * * * * ** *** ** * *
if (A<=520000)
* * * * * * *
* * * * * * * * *** if (A<=1170000)
* ** * ** * * * * * * *
* * * * *** ** if (A<=2350000)
* * * ** * *** ** * * * * * * ** * * * * ***
* ** * * ** * if (A<=4400000)
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*** **** * * ***** *
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** * * ** * * * ** * * ** *
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
* * * **** *** ** * * *
int main()
{
* ** ** * **** ** ** i;
* * * * * * ** * * * * a;
** * ** * ** ** * * ** ** * * * * * * *** *
* * * *** * ** * ** ** * * *
* * * ** ** * *
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{
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{
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* * **** * ** ** * ** * * * * * * * * *
}
** ** * * * * *** if(i<=10000000)
**** * *** ** ** ** *
****** * * * ** * * * * ** * * * * ** ** * *
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* * * * * * ***
** * * * * *
{
**** ** * * * *** ** ** ** * * * * ***
* * * * * * ** * * * ** * * * *
}
* **** * * * * * * * 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
*** * * * * * ** * * * * * * * * * **** ** * **
* * * * ** * * ** ** * * ** * * *
*** * * * *** * *** ** * * ** *** * * *
* * * *** *** * * **** ** * * * if(in<1170000)
* ** * * * * * ** *** *** ** * *** ** ** * *
** **** * * * * *** *** *** * if(in<2350000)
* * ** ** * * * ** * * * * * * * **** * * * * ***
* * * ** ** * * * ** * * * * if(in<4400000)
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*** * * * ** * *** * * if(in<10000000)
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* * ** * ** * * * ** ** ** ** *** ** **
* **** ** * * *** * ** * ** * * * ** * * *
* * ** * * * * * *** * * * ** ** * * 0;
}
answered
Oct 27, 2016
by
steven0221
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AD 20161027 期中考 10
[Exercise]
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asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
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(
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Available when:
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AD 20161027 期中考 9
[Exercise]
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2016-1 程式設計(一)AD
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(
18k
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ID: 15445 -
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AD 20161027 期中考 8
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2016-1 程式設計(一)AD
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(
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ID: 15441 -
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AD 20161027 期中考 7
[Exercise]
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Oct 27, 2016
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2016-1 程式設計(一)AD
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AD 20161027 期中考 5
[Exercise]
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Oct 27, 2016
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2016-1 程式設計(一)AD
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18k
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ID: 15421 -
Available when:
2016-10-27 18:30:00
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2016-10-27 21:00:00
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