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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* ** * * * ** * * *** x=0,i=0;
* * * * * * **
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* * * * * ** ** * * ** * *
}
answered
Oct 27, 2016
by
410523005
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122
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
* * * * * ** * * ** * ** **** *** ** * ***
if(i <= 520000)
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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Hidden content!#include * ** * * *
#include * * *
int main()
{
* * * *** ** * ** * * * num;
** * * ** * *** * * ** * &num);
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**** * * * * **
* * * * * * *** * * * *** = ** * * ****** * 0.4;
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* ** * ** * * ** * *** * * * * * * num+1);
* * * **** * * * * * * * * ** **
* *** ** * * ** 0;
}
answered
Oct 27, 2016
by
610537002
(
-110
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
*** * *** ** * ** * * * i=0,
* ** * * * ** * * * ** * * * ***** * * * * *** ** *
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* * ** * * * * * * ** = i*5/100;
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* * * * ** * * * = ((i-520000)*12/100)+(520000*5/100);
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* * * * ** * * * * * * * * = * * * * * * ** ** * * ** * *** * ** * *** **** ***
** * * * * * * * * * * if(i>=10000001)
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* * * * ** * * * ** ** * * * * * * * * *
* *** * * * * * * ** ** * * * * *
* * * * ** * * * * * * 0;
}
answered
Oct 27, 2016
by
410423016
(
-170
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Hidden content!#include ***** * **
* *** ** ** * * *
int main(int argc, char *argv[])
{
* * * * ** * * ** * * * * i,j,n;
* * * *** ** ** * * * k;
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* * * ** * * * * * * * *
*** * * *** * * * * ** * ** * 520000)
* ** *** ** ** * * ** * ** * * * * * * ** * * ** * * = n*0.05;
* *** * * ** * * * * * if(n ** * * 1170000)
* *** * * * * * * * ** ** * **** * ** ** * * ** ****** = (n - 520000) *0.12 + 26000;
* * ** * ** * * ** * * if(n * * * 2350000)
** * *** * * ** ** ** * ** * * * * * * * * = (n - 1170000) *0.2 + 26000 + 78000;
* * ** *** ** * * * * * * if(n * ** 4400000)
* * * ** ** * ****** * * * * * * * * *** = (n - ** ** *0.3 + 26000 + 78000 + 236000;
* ** ** * * * * * * if(n * * * *
* ** * ** *** * * * ** * * *** ** * ** ** * * *** = (n - * * ** *0.4 + 26000 + 78000 + 236000 + 615000;
* * * ** ** * ** * * *
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* * * *** ** * ** * * * * *** * * **** ** * * **
** * * * * ** ** * * 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
(
-216
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Hidden content!**** ** * ** *** **
int main()
{
* * ** A,B,C,D,E,F;
* * * ***** *** * * *** ** *** * * ** * * **
**** * * * **** * * (A<=520000)
* **** * ** * *
** * * ** * * * if (A<=1170000)
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* ** * *** ** if (A<=4400000)
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* ** ** * * * * if (A<=10000000)
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* * ** ** *
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* * * ** * ** * ** * * ** * *
}
answered
Oct 27, 2016
by
chen
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-102
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Hidden content!#include * * ***** * ** **
#include * * * * * **
int main()
{
* ** * * ** * * * num;
* * ** * * * * * ** * * ** * * * &num);
* ** * *** ** * *
** ** * ** * * * * * * >= 10000001)
* * * ** * * ** ** * *
* ** * * * * ** * * * * * ** = * * * ** * * * * 0.45;
** * * * ** * * *
* * ** * * * ** * * ** * * if (num >= 4400001)
**** * * * * **
* * * * * * * ** ** *** * *** ** = ** * * * ** * * 0.4;
** * * ** *** * * *
* ** * * * ** *** * if (num >= 2350001)
*** * ** * *
** * * * ** * * *** * ** ** * *** * = * * ** * * * *0.3;
* ******** * ** * **
* * ** **** * ** * * * ** if (num >= 1170001)
* * * ** * * *
* * * * ** ** * * ** * * * * * * = * ** *** * * ** *0.2;
* ** ** ** ** **** *
* ** * * * * * * ** if (num >= 520001)
** ** ** ** * ** *** *
* * ** * ** * * ** *** *** * ** ** = * * * * *** * *0.12;
** ***** * * * * * *** *
* * * * **** * * * * if(num >= 0)
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* * * * *** ** * = * * * ** * ** *0.05;
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* ** * * * * *
* * * * * *** * * * * * * * num);
* ** * * ** * * * * * * * ** * *
** * * *** * * * ** * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content! * * * * * ** * * * **
int main()
{
* * * ** * * A,B,C,D,E,F;
* * * * ** * * * * * * *
if (A<=520000)
* *** * * * * ** *
* * * ** if (A<=1170000)
* ** * ** * * * ** ** ** ** *** * * *
** ** * * * if (A<=2350000)
*** * * * ** ** * * * * * * * **
* * * * * ** if (A<=4400000)
* ** * * *** * * * ** * * * * * ** * ** * * * ** * *
* * * *** ** ** if (A<=10000000)
* * * *** * * * * * * ** * * * ** ** * * ** **** * * ** ** * ** * * ** * * *
* * ** * *
* * * ** * ** * * * ** * * ** * * * ** * * * * *** **** * * ** * *
* * * * ** * * ** ** ** * * * * * *
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
**** * ** * * ***
int main()
{
* * ** ** * * * * i;
* *** ** * * ** ** * *** a;
* *** *** * ** **** ** * ** * * * * * * * *
* **** ** * * * ** * ***
** ** ** ** * * *
* * ** * ** ** * * **
* * * * * ** * * * * * * * * * ** * ** ** *
* * **** * * *
** ** *** * * * * *** if(i<=1170000)
{
* * ** ** * * ** * * *** * ****
* * * * * * * * * * * ** * * * * * *
* * * ** * *
**** * * * * ** if(i<=2350000)
****** * ** ** ** * *
* ** ** * * * * * ** * ***** ** * * *
** * * * * * * *** ** * * * * ** *
* ** * * * * * *
* ** * * * * * * * * if(i<=4400000)
{
* ** ** *** * * * ** **** * * ** * * 470000;
* * * ** * * ** * * ** * ** * * ** ** **
}
* *** ** ** *** if(i<=10000000)
* * *
* ******* * * ** * **** * * ** * **
* * * *** * ** * * * *** * * * * * ** *
* * * ** * **
** * * **** * * **** *
{
* ** * *** * * * * * * * * ** * * * ** *
**** * * * * ** * ** ** * * * * * * *
}
** * * * *** *** * 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
* ** *** *** ** *** ** * * * ** * * * * * ****
* * ** ** **** * * * * *
* * * * * * *** * *** * ***
* * * ** ** * * * * * if(in<1170000)
** * ** * ** * * * * * * * * * * ** * ** * * ** **** * ******
* * ** * ** * ** ** * ** if(in<2350000)
* * * * * * * * * ** *** * ** * * * * * * * * * *
* * * * ** * *** * * * * * if(in<4400000)
* * ** * *** * ** * * * * * * * * * * * * * * ** * ** * ** **
* * * ** * * * ** * if(in<10000000)
* *** * * * * ***** ** * * * ** * * * *** ** ** * **** * * * *** * * **
* ** *** * * * * ** * ***
* * * * * * * * * *** * * ** * * * *** *** * **** * * ** *** * * * *** * * **
** ** * ** * * ** * * * * * *** ** *
* ** * * * ** * ** ** * * **** * * * * ***
* ** ** ** * * * ** ** * ** * 0;
}
answered
Oct 27, 2016
by
steven0221
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answers
AD 20161027 期中考 10
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
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(
18k
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ID: 15448 -
Available when:
2016-10-27 18:30:00
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AD 20161027 期中考 9
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2016-1 程式設計(一)AD
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(
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ID: 15445 -
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AD 20161027 期中考 8
[Exercise]
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in
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(
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ID: 15441 -
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AD 20161027 期中考 7
[Exercise]
Coding (C)
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Oct 27, 2016
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2016-1 程式設計(一)AD
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AD 20161027 期中考 5
[Exercise]
Coding (C)
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Oct 27, 2016
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2016-1 程式設計(一)AD
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(
18k
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ID: 15421 -
Available when:
2016-10-27 18:30:00
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